I need to write SQL query for "average number of particular product sold by date. On each day is sold min one product".
SELECT AVG (COUNT (PID))
FROM SOLD
GROUP BY DATE, PID;
P.S. PID means Product ID.
Is this query okay?
Should this give right answer?
Consider Using distinct count of date columns
SELECT PID,
COUNT(PID)/COUNT(distinct date_) as "Avg.Product Sold By Days"
FROM SOLD
GROUP BY PID;
You can try this sql query below. Basically, it will return the average number of 'SALES' for each product you have. It will group by each distinct product ID. Please provide us the data structure your of table and etc.
SELECT product_ID, trans_date
Sum(sales_of_product) / COUNT(DISTINCT sold_transaction) AS 'avg'
FROM SOLD
GROUP BY product_ID
Related
Three table are given:
customer(cust_id, name, address, sales_id)
orders(order_id, cust_id,date, sales_id)
salesman(sales_id,commision)
and you have to write an MySQL query to "count the salesman by their order_id and date". Is the question is correct? if yes, how can I solve this.
The question is not clear, but the codes below will give you an idea of how to get aggregated results and you can play around / adjust based on your needs
select
date,
sales_id,
count(order_id) as total_orders_per_date_and_sales_id
from orders
group by 1,2
if you need the total salesman per date then you can do this:
select
date,
count(sales_id) as total_sales_man_per_date
from orders
group by 1
if one order has multiple sales owners, then you can find total salesman per order id
select
orders_id,
count(salesman) as total_sales_man_involved_per_order
from orders
group by 1
if you need total commission per salesman per date:
select
orders.date,
orders.sales_id,
sum(salesman.comission) as total_comssion_per_salesman_per_date
from orders
left join salesman
on orders.sales_id = salesman.sales_id
group by 1,2
total number of distinct salesman
select
count(distinct sales_id) as total_unique_salesman
from salesman
I want to write a sql query to get best product of each year from a table . I have grouped the product-id and sum the qty to get the total number of products per id.
I converted the datetime function into year to get the year but output is wrong..
Anyone can help me with this?
SELECT Year(ModifiedDate), ProductID, SUM(OrderQty) AS TotalQuantity
from Sales.SalesOrderDetail
GROUP BY ProductID, year(ModifiedDate)
having count(*) > 3000
ORDER BY SUM(OrderQty) DESC
From your comment:
query is working fine if the set having condition to 2000. but if i
set it to 3000 it return nothing. if i use this "having count() >
2000" so i get two records. first of 2013 which return total quantity
3913 and record of 2014 with total quantity 2902. but when i change
condition to this "having count() > 3000 " it return nothing. but it
should return the 2013 record
You select the sum of OrderQty, yet you filter on the count and expect it to be the same. Count is the number of records, it doesn't care about the actual values in the records.
When you filter with
having sum(OrderQty) > 3000
you will only get the 2013 record.
We can do it in two-part.
I) create a temporary table for year-wise, id wise sum of qty.
create table tempSaleOrderDetail as select year(ModifiedDate) year,sum(OrderQty) orderqty, ProductID from Sales.SalesOrderDetail group by year(ModifiedDate), productId order by 1 desc,2 desc;
II) Fetch the data.
select A.* from tempSaleOrderDetail A inner join (select year ,max(orderqty) orderqty from tempSaleOrderDetail group by year) B on A.year=B.year and A.orderqty=B.orderqty ;
If any year has more than one Id's performance is same so this query will give both results.
I have the following ORDERS table
I know query to select the customer that has ordered the greatest quantity. However, how would it work, if say, two customers have the same quantity. What query should I write to show both the customers?
You can use a subquery which checks that the quantity for a given record matches the largest quantity observed in the table:
SELECT *
FROM yourTable
WHERE qty = (SELECT MAX(qty) FROM yourTable)
This will return multiple records if there are more than one customer sharing the maximum quantity.
If you only wanted to get back a single record, even in the presence of ties, you could use this approach:
SELECT *
FROM yourTable
ORDER BY qty DESC
LIMIT 1
I think you want sum of qty per custNum.
If so you can try like:
select custNum,
sum(qty) as qty
from Orders
group by custNum
order by sum(qty) desc;
Fiddle here:
http://sqlfiddle.com/#!9/47931b/10
SELECT custnum,sum(qty) as total
FROM orders
group by custnum
having sum(qty) = (SELECT MAX(qty) FROM orders);
This will return both values.
i have a sales table which contain customer_id time_id
i want to count the products bought by a customer at one time_id.
i am running query
select customer_id,time_id,count(time_id) as count from sales where customer_id=2094 group by time_id.
this query runs and give the result but i have different customer_ids in another customer table then i run this query
select customer_id,time_id,count(time_id) as count from sales where customer_id in (select customer_id from customer) group by time_id.
but it is not showing exact result.
I'm stuck on crafting a MySQL query to solve a problem. I'm trying to iterate through a list of "sales" where I'm trying to sort the Customer IDs listed by their total accumulated spend.
|Customer ID| Purchase price|
10 |1000
10 |1010
20 |2111
42 |9954
10 |9871
42 |6121
How would I iterate through the table where I sum up purchase price where the customer ID is the same?
Expecting a result like:
Customer ID|Purchase Total
10 |11881
20 |2111
42 |16075
I got to: select Customer ID, sum(PurchasePrice) as PurchaseTotal from sales where CustomerID=(select distinct(CustomerID) from sales) order by PurchaseTotal asc;
But it's not working because it doesn't iterate through the CustomerIDs, it just wants the single result value...
You need to GROUP BY your customer id:
SELECT CustomerID, SUM(PurchasePrice) AS PurchaseTotal
FROM sales
GROUP BY CustomerID;
Select CustomerID, sum(PurchasePrice) as PurchaseTotal FROM sales GROUP BY CustomerID ORDER BY PurchaseTotal ASC;
Just by having a little Google search, I managed to find a page doing exactly what you're doing (I think). I have tailored the query below to fit your circumstance.
SELECT CustomerID, SUM(PurchasePrice) AS PurchaseTotal
FROM sales
GROUP BY CustomerID
ORDER BY PurchaseTotal ASC
Link to Page with Tutorial on SQL Groups