When I use a left join on different databases, it works but not when I use inner join. Why ?
SELECT tkblue_tklabel_dev_data.EmailContent.*, tkblue_tklabel_dev_archdata.EmailTracking.*
FROM tkblue_tklabel_dev_data.EmailContent
FULL JOIN tkblue_tklabel_dev_archdata.EmailTracking ON tkblue_tklabel_dev_archdata.EmailTracking.idEmailTracking = tkblue_tklabel_dev_data.EmailContent.idEmailTracking
Unknown table 'tkblue_tklabel_dev_data.EmailContent'
But when using
SELECT tkblue_tklabel_dev_data.EmailContent.*, tkblue_tklabel_dev_archdata.EmailTracking.*
FROM tkblue_tklabel_dev_data.EmailContent
LEFT JOIN tkblue_tklabel_dev_archdata.EmailTracking ON tkblue_tklabel_dev_archdata.EmailTracking.idEmailTracking =
tkblue_tklabel_dev_data.EmailContent.idEmailTracking
I have not this error message, but I can only have the results of the left table. Or, I wish all the results like an full join.
Full join don't exists in mysql but you can produce the same result using both left join and right join in UNION
SELECT tkblue_tklabel_dev_data.EmailContent.*
, tkblue_tklabel_dev_archdata.EmailTracking.*
FROM tkblue_tklabel_dev_data.EmailContent
LEFT JOIN tkblue_tklabel_dev_archdata.EmailTracking
ON tkblue_tklabel_dev_archdata.EmailTracking.idEmailTracking = tkblue_tklabel_dev_data.EmailContent.idEmailTracking
UNION
SELECT tkblue_tklabel_dev_data.EmailContent.*
, tkblue_tklabel_dev_archdata.EmailTracking.*
FROM tkblue_tklabel_dev_data.EmailContent
RIGHT JOIN tkblue_tklabel_dev_archdata.EmailTracking
ON tkblue_tklabel_dev_archdata.EmailTracking.idEmailTracking = tkblue_tklabel_dev_data.EmailContent.idEmailTracking
Related
I have the code below:
SELECT
*
FROM
produto_unidades
join produto_notas on produto_notas.id = produto_unidades.produtoNota_id
join produto_licitacoes on produto_licitacoes.id = produto_notas.produtoLicitacoes_id
where produto_unidades.unidade_id = 2
This code work correctly, but I need to get ALL records of the produto_licitacoes.
Any idea?
Use left join instead of inner join. Make produto_licitacoes table as your left-most table; this would ensure that all the rows of produto_licitacoes table do appear in the result.
When using Left Join, you will need to shift the where conditions on the tables (except leftmost one) to the join on condition.
Try the following:
SELECT
*
FROM
produto_licitacoes
left join produto_notas
on produto_licitacoes.id = produto_notas.produtoLicitacoes_id
left join produto_unidades
on produto_notas.id = produto_unidades.produtoNota_id and
produto_unidades.unidade_id = 2
Two RIGHT JOIN will do:
SELECT
*
FROM
produto_unidades
right join produto_notas on produto_notas.id = produto_unidades.produtoNota_id
right join produto_licitacoes on produto_licitacoes.id = produto_notas.produtoLicitacoes_id
and produto_unidades.unidade_id = 2
However, to me it's a lot easier to read using LEFT JOIN syntax. Please note the tables show up in inverted order:
select *
from produto_licitacoes l
left join produto_notas n on n.produtoLicitacoes_id = l.id
left join produto_unidades u on u.produtoNota_id = n.id
and u.unidade_id = 2
I have a query where I am using a full outer join. But in some instance,
it gives me a syntax error.
What could be the reason for this? I don't see any miscode in my query.
MySQL does not support full outer join, but you can simulate it as a union between a left and right join query:
SELECT * FROM pbsdev3.item t1
LEFT JOIN pbsdev3.item_ledger_entry t2 ON t1.No_ = t2.Item_No_
UNION ALL
SELECT * FROM pbsdev3.item t1
RIGHT JOIN pbsdev3.item_ledger_entry t2 ON t1.No_ = t2.Item_No_
WHERE t1.No_ IS NULL
Note that in general if you find yourself doing full outer joins often, it could imply that your keys and data model are not well defined. One reason why MySQL does not support full joins could be that you should not have to use it.
Full outer join is quite a pain in MySQL. The first thing I would note is that it should not be needed. The items should match in the two tables, so an inner join or left join should be sufficient:
SELECT i.*, ile.*
FROM pbsdev3.item i LEFT JOIN
pbsdev3.item_ledger_entry ile
ON i.No_ = ile.Item_No_;
If you really need full outer join, then gather together all the items and use left join:
select it.*, ile.*
from (select i.No_ from item i union
select ile.Item_No_ from item_ledger_entry ile
) i left join
item it
on it.No_ = i.No_ left join
item_ledger_entry ile
on ile.No = i.No;
I have 3 tables:
First "placement"
Second "user_info"
Third "user_placements"
I want to get all placement data with user infos,
How to do it?
I tried this, but result it not what I expected:
SELECT *, user_placements.id AS user_placements_id, placement.id AS placement_id
FROM placement
LEFT OUTER JOIN user_placements ON placement.id = user_placements.id_placement
you need to one more join with user info
SELECT placement.*,user_info.id as user_info_id,user_info.name as user_name,user_info.mobile as user_mobile
FROM placement LEFT OUTER JOIN user_placements ON placement.id = user_placements.id_placement
LEFT OUTER JOIN user_info ON user_info.id = user_placements.id_user
You are missing the second join:
SELECT *
FROM placement AS p
JOIN user_placements AS up ON p.id = up.id_placement
JOIN user_info AS u ON up.id_user = u.id
Replace the wildcard with the data you want.
You will of course get duplicated data with this query.
I have two queries that result two result sets i need to compare both the result sets and need to display the differences between them.Hope i will get good support.Thank you.These are my queries
Query:1
SELECT distinct c.sid_ident,c.fix_ident from corept.std_sid_leg as c INNER JOIN (SELECT sid_ident, transition_ident, max(sequence_num) seq, route_type FROM corept.std_sid_leg WHERE data_supplier='J' AND airport_ident='KBOS' GROUP BY sid_ident,transition_ident) b ON c.sequence_num=b.seq and c.sid_ident = b.sid_ident and c.transition_ident =b.transition_ident WHERE c.data_supplier='J' and c.airport_ident='KBOS';
Query:2
SELECT name,trans FROM skyplan_deploy.deploy_sids ON d.name=c.sid_ident WHERE apt = 'KBOS' AND name != trans;
Comparison is to be done on fields sid_ident in corept.std_sid_leg and name in skplan_deplay.deploy_sids. As Mysql does not support full outer join,I thought of using left join and right join and combine both the results.But i stuck up with this.Please help.I am getting syntax error while using left and right join.Thank you.
The following query should simulate a FULL OUTER JOIN in MySQL.
SELECT *
FROM A
LEFT OUTER JOIN B
ON A.NAME = B.NAME
WHERE B.ID IS NULL
UNION ALL
SELECT *
FROM B
LEFT OUTER JOIN A
ON B.NAME = A.NAME
WHERE A.ID IS NULL;
Compare the results of the with an actual FULL OUTER JOIN in SQL Server and you'll see it works.
I have this cross-database query...
SELECT
`DM_Server`.`Jobs`.*,
`DM_Server`.servers.Description AS server,
digital_inventory.params,
products.products_id,
products.products_pdfupload,
customers.customers_firstname,
customers.customers_lastname
FROM `DM_Server`.`Jobs`
INNER JOIN `DM_Server`.servers ON servers.ServerID = Jobs.Jobs_ServerID
JOIN `cpod_live`.`digital_inventory` ON digital_inventory.jobname = Jobs.Jobs_Name
JOIN `cpod_live`.`products` ON products.products_pdfupload = CONCAT(digital_inventory.jobname, ".pdf")
JOIN `cpod_live`.`customers` ON customers.customers_id = products.cID
ORDER BY `DM_Server`.`Jobs`.Jobs_StartTime DESC LIMIT 50
it runs fine until I make them LEFT JOINs. I thought that by not specifying a type of join it was assumed to be a LEFT JOIN. Is this not the case?
I thought that by not specifying a type of join it was assumed to be a LEFT JOIN. Is this not the case?
No, the default join is an INNER JOIN.
Here is a visual explanation of SQL joins.
Inner join
Left join
No. When a type isn't specified, an INNER JOIN is used. To read up on differences; wikipedia
I believe the default is INNER JOIN if you just specify JOIN.
If you just mentioned JOIN in query by default it will be considered
as a INNER JOIN.
Left join:Left join will take all the elements from Left table and only matching records from the Right table as Follows.
example:
SELECT column_name(s)
FROM table_name1 #(Left table)
LEFT JOIN table_name2 #(Right table)
ON table_name1.column_name=table_name2.column_name
Hope this helps.