I have a data set like that:
Data Set Contents
From To Comment
----+---+--------
0 50 Bad
50 70 Good
70 100 Excellent
If I have a value of 75, I need to get Excellent by searching the Dataset.
I know about the lookup function but it is not what I want. How can I do that?
The values should be in percentage.
Note : the value (75) is Average of a column (Calculated) it
calculate student grade from max and student mark Version SQL Server
2016
Note 2 : the dataset is from database not static values
Thank You
Assuming you only ever have a fixed number of 'grades' then this will work. However, I would strongly recommend doing this type of work on the server where possible.
Here we go...
I created two datasets
dsGradeRange with the following sql to recreate your example (more or less)
DECLARE #t TABLE (low int, high int, comment varchar(20))
INSERT INTO #t VALUES
(0,49,'Bad'),
(50,69,'Good'),
(70,100, 'Excellent')
SELECT * FROM #t
dsRandomNumbers This just creates 30 random numbers between 0 and 100
SELECT *
FROM (SELECT top 30 ABS(CHECKSUM(NEWID()) % 100) as myNumber FROM sys.objects) x
ORDER BY myNumber
I added a table to the report to show the grades (just for reference).
I then added a table to show the dsRandomNumbers
Finally I set the expression of the 2nd column to the following expression.
=SWITCH
(
Fields!myNumber.Value < LOOKUP("Bad", Fields!comment.Value, Fields!high.Value, "dsGradeRange"), "Bad",
Fields!myNumber.Value < LOOKUP("Good", Fields!comment.Value, Fields!high.Value, "dsGradeRange"), "Good",
True, "Excellent"
)
This gives the following results
As you can see we only need to compare to the high value of each case, the first match will return the correct comment.
Right click on your dataset and add a calculated field. Go to Field Properties > Fields > Add and add the following expression, which descripes your scenario:
=IIF(Fields!Number.Value < 50, "Bad", "Good")
Related
I was doing a query with MySQL to save all objects returned, but I'd like identify these objects based in statements of the block WHERE, that is, if determined object to satisfy the specific characteristic I'd like create one column and in this column I assignment the value 0 or 1 in the row corresponding the object if it satisfy or not satisfy these characteristic.
This is my script:
SELECT
s.id, al.ID, al.j, al.k, al.r, gal.i
FROM
datas as al
WHERE
AND s.id = al.ID
AND al.j between 1 and 1
AND al.k BETWEEN 15 and 16
AND al.r BETWEEN 67 and 72
The script above is working perfectly and I can to save all objects which it return.
So, I'd like to know if is there a way add in the query above, on block WHERE, the following statement,
( Flags & (dbo.environment('cool') +
dbo.environment('ok') -
dbo.environment('source')) ) = 25
and ((al_pp x al_pp1)-0.5/3=11
and determined the objects that satisfy or not these condition with 0 or 1 in a new column created in Table saved.
I read some tutorials about this and saw some attempts with IF, CASE, ADD COLUMN or WHEN, but none of these solved.
Thanks in advance
MySQL has if function, see here
So you can simply use it in your query:
SELECT IF(( Flags & (dbo.fPhotoFlags('SATURATED') +
dbo.fPhotoFlags('BRIGHT') +
dbo.fPhotoFlags('EDGE')) ) = 0
and petroRad_r < 18
and ((colc_u - colc_g) - (psfMag_u - psfMag_g)) < -0.4
, 1 --// VALUE IF TRUE
, 0 --// VALUE IF FALSE
) as conditional_column, ... rest of your query
I have a MySQL view called Balance created from 2 tables order and income with PHPMyAdmin and contains some calculated fields ex: CustomerBalance the decimal place become automatically 8, I mean the field Type is decimal(50,8)
How can i make it 2 only ?
You can use truncate
SELECT TRUNCATE(1.999,2);
return 1.99
select TRUNCATE(your_column,2) from your_table;
In the select list where you calculate the CustomerBalance expression, explicitly truncate or round (depending on your requirements) the result to 2 digits:
select ... round(..., 2) as CustomerBalance ...
Hey is there any way to create query with simple formula ?
I have a table data with two columns value_one and value_two both are decimal values. I want to select this rows where difference between value_one and value_two is grater then 5. How can i do this?
Can i do something like this ?
SELECT * FROM data WHERE (MAX(value_one, value_two) - MIN(value_one, value_two)) > 5
Example values
value_one, value_two
1,6
9,3
2,3
3,2
so analogical difs are: 5, 6, 1, 1 so the selected row would be only first and second.
Consider an example where smaller number is subtracted with a bigger number:
2 - 5 = -3
So, the result is a difference of two numbers with a negation sign.
Now, consider the reverse scenario, when bigger number is subtracted with the smaller number:
5 - 2 = 3
Pretty simple right.
Basically, the difference of two number remains same, if you just ignore the sign. This is in other words called absolute value of a number.
Now, the question arises how to find the absolute value in MySQL?
Answer to this is the built-in method of MySQL i.e. abs() function which returns an absolute value of a number.
ABS(X):
Returns the absolute value of X.
mysql> SELECT ABS(2);
-> 2
mysql> SELECT ABS(-32);
-> 32
Therefore, without worrying about finding min and max number, we can directly focus on the difference of two numbers and then, retrieving the absolute value of the result. Finally, check if it is greater than 5.
So, the final query becomes:
SELECT *
FROM data
WHERE abs(value_one - value_two) > 5;
You can also do complex operations once the absolute value is calculated like adding or dividing with the third value. Check the code below:
SELECT *
FROM
data
WHERE
(abs(value_one - value_two) / value_three) + value_four > 5;
You can also add multiple conditions using logical operators like AND, OR, NOT to do so. Click here for logical operators.
SELECT *
FROM
data
WHERE
((abs(value_one - value_two) / value_three) + value_four > 5)
AND (value_five != 0);
Here is the link with various functions available in MySQL:
https://dev.mysql.com/doc/refman/5.0/en/mathematical-functions.html
No, you would just use a simple where clause:
select *
from data
where abs(value_one - value_two) > 5;
I have been trying to resolve this calc field issue for about 30 mins, it looks like I have the single field conditions correct in the expression such as [points] and [contrib] but the combined ([points]+[contrib]) field is not meeting the requirement that sets the field to the correct member type, so when these are added it returns some other member type as basic. Might I use the between operator with the added fields...? I tried it, but there is some compositional error. So in other words if you got 45 points it sets you to basic only named in the points field, if you have contrib of 45 you are set to basic in the calc field as expected, but if it were 50 + 50, instead it is setting to basic when it should be "better" member label. Otherwise this simple statement should seem to be correct but the computer is not reading it so when adding. It must not be recognizing the combined value for some reason and calc fields do not have a sum() func.
Focus here: (([points]+[Contrib]) >= 45 And ([points]+[Contrib]) < 100),"Basic",
IIf(([points] >=45 And [points]<100) Or ([Contrib] >=45 And [Contrib] <100) Or (([points]+[Contrib]) > = 45 And ([points]+[contrib] < 100),"Basic",
IIf(([points] >=100 And [points] <250) Or ([Contrib] >=100 And [Contrib] <250) Or ((([points]+[Contrib]) >=100) And (([points]+[Contrib])<250)),"Better",
IIf(([points] >=250 And [points]<500) Or ([Contrib] >=250 And [Contrib] <500) Or ((([points]+[Contrib]) >=250) And (([points]+[Contrib])<500)),"Great",
IIf(([points] >=500) Or ([Contrib] >=500) Or (([points]+[Contrib]) >=500),"Best","Non-member"))))
Here is a data sample from an Access 2010 table which includes a calculated field named member_type:
id points Contrib member_type
-- ------ ------- ----------
1 1 1 Non-member
2 50 1 Basic
3 200 1 Better
4 300 1 Great
5 600 1 Best
If that is what you want for your calculated field, here is the expression I used for member_type:
IIf([points]+[Contrib]>=45 And [points]+[Contrib]<100,'Basic',IIf([points]+[Contrib]>=100 And [points]+[Contrib]<250,'Better',IIf([points]+[Contrib]>=250 And [points]+[Contrib]<500,'Great',IIf([points]+[Contrib]>=500,'Best','Non-member'))))
In case I didn't get it exactly correct, here is that same expression formatted so that you can better see where you need changes:
IIf([points]+[Contrib]>=45 And [points]+[Contrib]<100,'Basic',
IIf([points]+[Contrib]>=100 And [points]+[Contrib]<250,'Better',
IIf([points]+[Contrib]>=250 And [points]+[Contrib]<500,'Great',
IIf([points]+[Contrib]>=500,'Best','Non-member'
))))
Note if either points or Contrib is Null, member_type will display "Non-member". If that is not the behavior you want, you will need a more complicated expression. Since a calculated field expression can not use Nz(), you would have to substitute something like IIf([points] Is Null,0,[points]) for every occurrence of [points] and IIf([Contrib] Is Null,0,[Contrib]) for [Contrib]
It would be simpler to prohibit Null for those fields (set their Required property to Yes) and set Default Value to zero.
The BETWEEN operator returns TRUE if the value you are testing is >= or <= the limits you have for BETWEEN.
If you are looking at 50+50 then that total = 100 and you are Between 44 and 100. That would result in an answer of "Basic". Change the range for ([points]+[Contrib]) Between 44 And 100) to be ([points]+[Contrib]) Between 44 And 99)
I am working on an application that requires me to validate if 3 randomly generated numbers match a 3 digit string that has been entered into a database from user input. I also need to preserve the exact order that the user enters the string, so sorting on input is not an option.
For example, the randomly generated digits may be 6 4 0, and in the database a string may show as '406'.
Is there an easy way this can be accomplished in a single query without enumerating the options or adding an extra column/view?
maybe you could try
create table y (z varchar(10));
insert into y values ('406');
insert into y values ('604');
insert into y values ('446');
insert into y values ('106');
insert into y values ('123');
and then
SELECT * from y where FIND_IN_SET(Substring('640',1,1),MAKE_SET(7,Substring(z,1,1),Substring(z,2,1),Substring(z,3,1))) and FIND_IN_SET(Substring('640',2,1),MAKE_SET(7,Substring(z,1,1),Substring(z,2,1),Substring(z,3,1))) and FIND_IN_SET(Substring('640',3,1),MAKE_SET(7,Substring(z,1,1),Substring(z,2,1),Substring(z,3,1)));
returns
406
604
Sum the three random digits
Something like
Select * From Triplets Where (Ascii(Substring(Number,0,1)) - 48) + (Ascii(substring(Number,1,1)) -48) +
(Ascii(substring(Number,2,1)) -48) = MySumOfNumber
easy is a state of mind isn't it, Storage requirement of an extra "CheckSum" int, versus the high cost of a query like this.