MySQL: Enumerate and count - mysql

Question

I have two tables, table1 and table2.
Example of the table1 table.
^ invoice ^ valid ^
| 10 | yes |
| 11 | yes |
| 12 | no |
Example of the table2 table
^ invoice ^ detail ^
| 10 | A |
| 10 | C |
| 10 | F |
| 11 | A |
| 11 | F |
| 10 | E |
| 12 | A |
Want to select from table 2 all rows that:
Have a valid invoice in table 1
And enumerate:
the detail for each invoice
the invoice
Here the desired result
^ invoice ^ detail ^ ordination ^ ordinationb ^
| 10 | A | 1 | 1 |
| 10 | C | 2 | 1 |
| 10 | F | 3 | 1 |
| 11 | A | 1 | 2 |
| 11 | F | 2 | 2 |
| 10 | E | 4 | 1 |
The sentence should valid for use in phpMyAdmin 4.8.4

Answer 1

Here is the MySQL 8+ way of doing this:
SELECT
t2.Invoice,
t2.`lines`,
ROW_NUMBER() OVER (PARTITION BY t2.Invoice ORDER BY t2.`lines`) line_order,
DENSE_RANK() OVER (ORDER BY t2.Invoice) ordination
FROM table2 t2
WHERE EXISTS (SELECT 1 FROM table1 t1 WHERE t1.Invoice = t2.Invoice AND t1.valid = 'yes');
Demo
If you are using a version of MySQL earlier than 8, then you might have to resort to using session variables. This can lead to an ugly query. If you have a long term need for queries like this one, then I recommending upgrading to MySQL 8+.
Edit:
It just dawned on me that we can use correlated subqueries to simulate both your ROW_NUMBER and DENSE_RANK requirements. Here is one way to do this query in MySQL 5.7 or earlier:
SELECT
t2.Invoice,
t2.detail,
(SELECT COUNT(*) FROM table2 t
WHERE t.Invoice = t2.Invoice AND t.detail <= t2.detail) ordination,
t.dr AS ordinationb
FROM table2 t2
INNER JOIN
(
SELECT DISTINCT
t2.Invoice,
(SELECT COUNT(*)
FROM (SELECT DISTINCT Invoice FROM table2) t
WHERE t.Invoice <= t2.Invoice) dr
FROM table2 t2
) t
ON t.Invoice = t2.Invoice
WHERE EXISTS (SELECT 1 FROM table1 t1 WHERE t1.Invoice = t2.Invoice AND t1.valid = 'yes')
ORDER BY
t2.Invoice,
t2.detail;
Demo