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So I have a table for biddings, you can win the bidding by posting the lowest unique bid. So if 2 people place a bet of $1, none of them win, if 1 person places a bet of $2, this guy wins. But how can I check this in MySQL?
Assume your table has the bid value stored in the field name bet, then below is a worked solution:
SELECT * FROM YourTableName
WHERE bet = (SELECT MIN(bet) FROM YourTableName)
GROUP BY bet
HAVING COUNT(*) = 1;
Related
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I have a simple entry in the oracle, there are 3 columns, date, API name and status. I want that in the answer I had not all history, and only the last on each of Names of API (only 7). I will be grateful for your help. I know that asked of the very difficult but I'm just new to oracle.
select l.log_date,l.job_name,l.status from user_scheduler_job_log l
could be you want the related status for name and last log_date
select u.job_name, u.status, t.max_date
from user_scheduler_job_log u
INNER JOIN(
select MAX(l.log_date) max_date, l.job_name
from user_scheduler_job_log l
GROUP BY l.job_name
) t on t.max_date = u.log_date
AND t.job_name = u.job_name
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i have a problem with MySQL. My table has a ID, but when i select the data and order by ID ASC, the id is out of order.
As you can see, after WI10 the ID is WI100, the ID should be WI11. Any solutions? Sorry for my bad eng, thank you!
The column cid is sorted alphabetically because it is not a number.
If its pattern is always like WIXXX you can sort the table like:
order by substr(cid, 3) + 0
This extracts the numeric part after the first 2 chars and implicitly converts it to a number.
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SELECT location,special,price FROM `tickets`
WHERE event = 'food' GROUP BY location
I think you want, (assuming its mysql) the following:
SELECT location, ANY_VALUE(special) special, ANY_VALUE(price) price
FROM tickets
WHERE event='food'
GROUP BY location ;
ANY_VALUE is strange aggregate function out of normal db standards that returns one of the values arbitarily.
If you wish to not have duplicate results in your rows you can choose only distinct result set.
SELECT DISTINCT location,special,price FROM tickets WHERE event = 'food' GROUP BY location
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I have one table with 3 fields e.g.
Name, Team Name, Player_Number
there is multiple team and I want to fetch 2 member from each team.
Please share with fast solution.
Try this
select * from TableName s where (select count(*) from TableName a where a.TeamName = s.TeamName and a.Player_Number >= s.Player_Number) <= 2
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I am having a database with 2 columns employee and job.Job column contains character in each record.In that,I have to list the employees whose job is having last 3 characters as 'man'.I have to use only functions in SQL Query.
Use LIKE with wildcard:
SELECT *
FROM your_table
WHERE job_column_name LIKE '%man'
or using RIGHT
SELECT *
FROM your_table
WHERE RIGHT(job_column_name, 3) = 'man'
Answer For Question 4 is
SELECT *
FROM emp
WHERE SUBSTR(job,-3,3)='MAN';