SQL doesn't see alias - mysql

Question

SELECT name,
manufacturer,
prize
FROM products AS p
GROUP BY manufacturer
HAVING prize = (
SELECT Max(prize)
FROM products p1
WHERE p.`id-product` = p1.`id-product`
GROUP BY p1.manufacturer DESC
LIMIT 1
)
And the error is:
#1054 - Unknown column 'shop.p.id.product' in 'where clause'

Answer 1

I think you need correlated subquery instead :
SELECT p.name, p.manufacturer, p.prize
FROM products AS p
WHERE p.prize = (SELECT MAX(p1.prize) FROM products p1 WHERE p1.manufacturer = p.manufacturer);
By this way, you will get manufacturers with highest price.
EDIT : If one product has same prize then you will need PK (Primary/Identity) column that specify unique sequence :
SELECT p.name, p.manufacturer, p.prize
FROM products AS p
WHERE p.pk = (SELECT p1.pk
FROM products p1
WHERE p1.manufacturer = p.manufacturer
ORDER BY p1.prize DESC
LIMIT 1
);
If you are running with latest version of MySQL, then you can also use ranking function :
SELECT p.*
FROM (SELECT p.name, p.manufacturer, p.prize,
ROW_NUMBER() OVER (PARTITION BY p.manufacturer ORDER BY p.prize DESC) AS Seq
FROM products AS p
) p
WHERE Seq = 1;

Answer 2

Your query has nothing of that form. I would recommend writing the query by qualifying all column references:
SELECT p.name, p.manufacturer, p.prize
FROM products p
GROUP BY p.manufacturer
HAVING p.prize = (SELECT MAX(p1.prize)
FROM products p1
WHERE p.`id-product` = p1.`id-product`
GROUP BY p1.manufacturer DESC
LIMIT 1
);
MySQL allows the syntax with extra columns in the SELECT that are not in the GROUP BY, so that would not (normally) generate an error. It is not correct, though, by the rules of SQL.
I'm not sure what the subquery is supposed to be doing. If you want the manufacturers with the highest price, then you would not use the GROUP BY in the subquery.
If you want the highest priced product for each manufacturer:
SELECT p.name, p.manufacturer, p.prize
FROM products p
HAVING p.prize = (SELECT MAX(p1.prize)
FROM products p1
WHERE p.manufacturer = p1.manufacturer
LIMIT 1
);