MySQL query help require - mysql

Question

I am using MySQL database. I have employee leave table which having information about employee leave.
Please find table details:
CREATE TABLE IF NOT EXISTS `APPLY_LEAVE` (
`ID` int(11) NOT NULL AUTO_INCREMENT,
`EMP_ID` varchar(100) NOT NULL,
`TYPE_OF_LEAVE` varchar(100) NOT NULL,
`DAYS` varchar(100) NOT NULL,
`REASON` varchar(200) NOT NULL,
`START_DATE` date NOT NULL,
`END_DATE` date NOT NULL,
`STATUS` tinyint(2) NOT NULL,
`CREATED_ON` date NOT NULL,
PRIMARY KEY (`ID`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1;
--
-- Dumping data for table `APPLY_LEAVE`
--
INSERT INTO `APPLY_LEAVE` (`ID`, `EMP_ID`, `TYPE_OF_LEAVE`, `DAYS`, `REASON`, `START_DATE`, `END_DATE`, `STATUS`, `CREATED_ON`) VALUES
(1, 'EMP001', 'SL', '2', 'Sick Leave', '2018-11-30', '2018-12-01', 1,'2018-11-06'),
(2, 'EMP002', 'EL', '1', 'Personal', '2018-12-13', '2018-12-13', 1,'2018-11-09'),
(3, 'EMP003', 'CL', '2', 'Casual Leave due to Birthday', '2018-08-31', '2018-09-01', 1,'2018-08-20'),
(4, 'EMP001', 'CL', '3', 'Casual Leave', '2018-12-04', '2018-12-06', 1,'2018-11-27'),
(5, 'EMP002', 'SL', '4', 'Sick Leave', '2018-09-10', '2018-09-13', 1,'2018-10-04'),
(6, 'EMP003', 'SL', '3', 'Sick Leave', '2018-10-30', '2018-11-01', 1,'2018-11-25');
Require Output:
I want to generate Report/excel to receive information as month wise employee leave data based on leave type i.e (Month wise, Leave type data)
Format should be below:
Requirement: I want MySQL query to fetch attached result month wise, Leave type data(SL/CL/EL) which took by Employee.
Query tries:
SELECT EMP_ID,
SUM(CASE WHEN TYPE_OF_LEAVE = 'EL' AND MONTH( START_DATE ) =11 THEN DAYS ELSE 0 END ) AS EL_NOV,
SUM(CASE WHEN TYPE_OF_LEAVE = 'CL' AND MONTH( START_DATE ) =11 THEN DAYS ELSE 0 END ) AS CL_NOV,
SUM(CASE WHEN TYPE_OF_LEAVE = 'SL' AND MONTH( START_DATE ) =11 THEN DAYS ELSE 0 END ) AS SL_NOV,
SUM(CASE WHEN TYPE_OF_LEAVE = 'LOP' AND MONTH( START_DATE ) =11 THEN DAYS ELSE 0 END ) AS LOP_NOV,
SUM(CASE WHEN TYPE_OF_LEAVE = 'EL' AND MONTH( START_DATE ) =12 THEN DAYS ELSE 0 END ) AS EL_DEC,
SUM(CASE WHEN TYPE_OF_LEAVE = 'CL' AND MONTH( START_DATE ) =12 THEN DAYS ELSE 0 END ) AS CL_DEC,
SUM(CASE WHEN TYPE_OF_LEAVE = 'SL' AND MONTH( START_DATE ) =12 THEN DAYS ELSE 0 END ) AS SL_DEC,
SUM(CASE WHEN TYPE_OF_LEAVE = 'LOP' AND MONTH( START_DATE ) =12 THEN DAYS ELSE 0 END ) AS LOP_DEC
FROM APPLY_LEAVE
GROUP BY EMP_ID
Facing Issue:
I.e One employee look leave on Friday and Saturday (i.e EMP001 took SL on 2018-11-30 to 2018-12-01) (Friday is month of last date and Saturday is first date of month and I am inserting single record into table. When employee applied leave from application. Here result should be
EMP001 - SL
November - 1 leave
December - 1 leave
How can I write this MySQL query?

Answer 1

Dear Dipti Kindly find below query for required result.
SELECT
*
FROM
(
SELECT
EMP_ID,
START_DATE as date_day,
TYPE_OF_LEAVE,
SUM(
if(
MONTH(START_DATE) <> MONTH(END_DATE),
(
day(
last_day(START_DATE)
)+ 1 - day(START_DATE)
),
days
)
) as DAYS
FROM
APPLY_LEAVE
GROUP BY
MONTH(START_DATE),
MONTH(END_DATE),
EMP_ID
UNION ALL
SELECT
EMP_ID,
END_DATE as date_day,
TYPE_OF_LEAVE,
SUM(
if(
MONTH(START_DATE) <> MONTH(END_DATE),
DAY(END_DATE),
0
)
) as DAYS
FROM
APPLY_LEAVE
GROUP BY
MONTH(START_DATE),
MONTH(END_DATE),
EMP_ID
) as a
WHERE
a.DAYS > 0;