I'm trying to create a background for a banner using css where one side has a color and on the other side has another one with a 45° cut like this
I've been able to recreate the above image except for the drop shadow that doesn't stay in the right position.
Any advice would be greatly appreciated.
This is my code code:
#container {
height: 100px;
width: 400px;
overflow: hidden;
background-color: #2962ff;
}
#triangle-topleft {
width: 0;
height: 0;
border-top: 100px solid #2196f3;
border-right: 400px solid transparent;
-webkit-box-shadow: 5px 5px 20px 0px rgba(0,0,0,0.75);
-moz-box-shadow: 5px 5px 20px 0px rgba(0,0,0,0.75);
box-shadow: 5px 5px 20px 0px rgba(0,0,0,0.75);
}
<div id="container">
<div id="triangle-topleft"></div>
</div>
The CSS triangle trick with border can not be used for this, as a shadow will still be applied to the box, and not only to the triangle.
You will have to create a pseudo element, rotate it and THEN apply shadow to it.
#container {
position: relative;
height: 200px;
width: 200px;
overflow: hidden;
background-color: grey;
}
#container:before {
content: '';
position: absolute;
left: 20%;
width: 100%;
height: 200%;
background-color: rgb(255, 255, 255); /* fallback */
background-color: rgba(255, 255, 255, 0.5);
top: 0;
-webkit-transform: rotate(45deg);
-moz-transform: rotate(45deg);
transform: rotate(45deg);
box-shadow: inset 0 0 20px 10px #333;
}
<div id="container"></div>
Basically you create a rectangle which is larger than the parent, then rotate it and apply a shadow. You can tweak the colors and rotation-degree for your needs
Demo: http://jsfiddle.net/b5TnZ/2032/
You can add multiple color stops in Linear Gradients. Use two color set.
Gradient generated using Shapy
.canvas {
display: flex;
height: 100vh;
align-items: center;
justify-content: center;
min-height: 100%;
min-width: 100%;
}
.gradient-canvas {
max-height: 100%;
max-width: 100%;
width: 100%;
height: 100%;
background: linear-gradient(127deg, rgb(31, 163, 209) 0%, rgb(31, 163, 209) 50%, rgb(25, 64, 208) 0%, rgb(46, 101, 223) 52%) 50% 50% / 100% 100% no-repeat;
}
<div class="canvas"><div class="gradient-canvas"></div></div>
You can try gradient like below:
#container {
height: 150px;
background:
linear-gradient(135deg,#2962ff 49.8%,rgba(0,0,0,0.75) 50%, #2196f3 calc(50% + 10px));
background-color:#2196f3;
}
<div id="container">
</div>
And simply replace the deg with to bottom right if you want the diagonal result:
#container {
height: 150px;
width:50%;
background:
linear-gradient(to bottom right,#2962ff 50%,rgba(0,0,0,0.75) 50%, #2196f3 calc(50% + 10px));
background-color:#2196f3;
}
<div id="container">
</div>
Related
I want to make a card look like this, the border or the sides of the card are semi-circular, is it possible to make it with css? if yes, how? Thank you in advance
.wrapper {
}
.content-card {
width: 315px;
height: 131px;
left: 0px;
top: 0px;
background: #FFFFFF;
box-shadow: 4px 8px 12px rgba(0, 0, 0, 0.12);
border-radius: 8px;
}
<div class="wrapper">
<div class="content-card">
</div>
</div>
Multiple background can do it:
.content-card {
width: 300px;
height: 150px;
background:
radial-gradient(8px at left ,#0000 98%,#fff) left ,
radial-gradient(8px at right,#0000 98%,#fff) right;
background-size: 50.5% 25px;
background-repeat:repeat-y;
filter: drop-shadow(4px 8px 12px rgba(0, 0, 0, 0.12));
border-radius: 8px;
}
body {
background: pink;
}
<div class="content-card">
</div>
The old way - border-image
It permits you to use the willing image for borders, it was widely use for this kind of cases. You can have repeat option on it to allow different box's sizes with the same style.
The mozilla doc is quite explicit with good examples of it : https://developer.mozilla.org/en-US/docs/Web/CSS/border-image
The recent way - without image
You have the possibility to use pseudo-element :after and :before and stylize those elements with a repeated background using radial-gradient.
body {
background-color: #ffaaaa;
}
.ticket {
position: relative;
width: 300px;
height: 170px;
margin: 10px;
border-radius: 10px;
background: white;
box-shadow: 4px 8px 12px rgba(0, 0, 0, 0.12);
}
.ticket:before,
.ticket:after {
content: '';
position: absolute;
top: 5px;
width: 6px;
height: 160px;
}
.ticket:before {
left: -5px;
background: radial-gradient(circle, transparent, transparent 50%, #FBFBFB 50%, #FBFBFB 100%) -7px -8px/16px 16px repeat-y;
}
.ticket:after {
left: 300px;
background: radial-gradient(circle, transparent, transparent 50%, #FBFBFB 0%, #FBFBFB 100% ) -3px -7px / 16px 16px repeat-y;
}
<div class="ticket"></div>
I've added a normal square image to my website and made it into a circle with border-radius and then have tried to add a circle border around it but it only seems to work on Chrome. Any suggestions on how I can fix this?
.face {
display: block;
margin: auto;
border-radius: 100%;
border: 5px solid #ff675b;}
Here is a screenshot of the issue:
https://www.dropbox.com/s/4xy26phkjgz9te0/Screen%20Shot%202013-05-01%20at%2001.15.02.png
See this JsFiddle
http://jsfiddle.net/z3rLa/1/
.avatar {
width:128px;
margin: 10px;
border:10px solid red;
border-radius: 500px;
-webkit-border-radius: 500px;
-moz-border-radius: 500px;
}
That is the way I use:
CSS:
.avatar {
display: block;
border-radius: 200px;
box-sizing: border-box;
background-color: #DDD;
border: 5px solid #cfd8dc;
}
img {
height: 200px;
width: 200px
}
HTML:
<img class="avatar" src="..">
create a new class:
.circleborder {
width: 300px;
height: 300px;
border-radius: 150px;
-webkit-border-radius: 150px;
-moz-border-radius: 150px;
background: url(URL) no-repeat;
box-shadow: 0 0 8px rgba(0, 0, 0, .8);
-webkit-box-shadow: 0 0 8px rgba(0, 0, 0, .8);
-moz-box-shadow: 0 0 8px rgba(0, 0, 0, .8);
}
and this would be your html code:
<div class="circleborder"><img src="URL"/></div>
The HTML:
<div class="circleborder"><img class="face" src="img/face.jpeg" alt="face" width="130" height="130"></div>
CSS:
.face {
border-radius: 100%;}
.circleborder {
border: 5px solid #ff675b;
border-radius: 100%;
display: inline-block;}
Thanks for your help guys! I'm testing my solution as we speak and sofar it's worked on Chrome & Safari on my Mac and iPhone! :D
http://www.css3.info/preview/rounded-border/
Border radius doesn't work the same way in every browser. You need different approaches.
Try this one it will be help for you.
.clip-circle {
clip-path: circle(60px at center);
/* OLD VALUE example: circle(245px, 140px, 50px); */
/* Yep, even the new clip-path has deprecated stuff. */
}
.clip-ellipse {
clip-path: ellipse(60px 40px at 75px 30px);
/* OLD VALUE example: ellipse(245px, 80px, 75px, 30px); */
}
.clip-polygon {
clip-path: polygon(5% 5%, 100% 0%, 100% 75%, 75% 75%, 75% 100%, 50% 75%, 0% 75%);
/* Note that percentages work as well as px */
}
First of all, this question might be similar to this, but the shape in my case is different, so it couldn't really help me out.
The trapezoid code is the following:
#light {
/*setting the element*/
border-bottom: 164px solid grey;
border-left: 148px solid transparent;
border-right: 165px solid transparent;
height: 0;
width: 80px;
}
<div id="light"></div>
Just to clarify, I am trying to add the shadow effect, similar to the following example:
#bulb {
/*setting the element*/
background: grey;
width: 200px;
height: 200px;
border-radius: 50%;
/*adding "light" (shadow)*/
box-shadow: 0 0 100px 10px rgba(128, 128, 128, 0.5);
}
<div id="bulb"></div>
When I try to add the regular box-shadow:, my trapezoid becomes a regular rectangle with white parts.
Instead of a box-shadow you could use a drop-shadow filter, e.g.
filter: drop-shadow(0 0 40px #222);
#light {
/*setting the element*/
border-bottom: 164px solid grey;
border-left: 148px solid transparent;
border-right: 165px solid transparent;
height: 0;
width: 80px;
filter: drop-shadow(0 0 40px #222);
}
<div id="light"></div>
More info on MDN
I would create the shape differently using pseudo element with a blur effect:
#light {
width:400px;
height:160px;
position:relative;
}
#light:before,
#light:after{
content:"";
position:absolute;
top:0;
left:0;
right:0;
bottom:0;
background:
/*triangle on the right*/
linear-gradient(to top right,grey 49.5%,transparent 50%) right/150px 100%,
/*triangle on the left*/
linear-gradient(to top left, grey 49.5%,transparent 50%) left /150px 100%,
/*rectangle at the center*/
linear-gradient(grey,grey) center/100px 100%;
background-repeat:no-repeat;
}
#light:before {
filter:blur(20px);
}
<div id="light">
</div>
based on css-tricks Double-Box Method you can "have a container box with hidden overflow and another box inside it which is rotate and hangs out of it"
.light {
width: 350px;
height: 135px;
position: relative;
overflow: hidden;
box-shadow: 0 16px 10px -17px rgba(0, 0, 0, 0.5);
}
.light:after {
content: "";
position: absolute;
width: 300px;
height: 300px;
background: #999;
transform: rotate(45deg);
top: 25px;
left: 25px;
box-shadow: -1px -1px 10px -2px rgba(0, 0, 0, 0.5);
}
<div class="light"></div>
In your example, you can't add a proper box-shadow without having these white parts on each side. That is because the CSS border colouring the grey shaped trapeziod DIV.
In the example above, they are using an .SVG file (image), since it is an image, the original shape of it is a trapezoid, not a rectangle with white side like yours.
You will need to draw an .svg in the shape and color you want, and then add a shadow to the element itself.
Here are more informations about SVG.
I hope it helps.
In the following fiddle I successfully have made the spotlight stay in the same place (horizontally centered) except for when my zoom factor is too large. In other words, when I zoom in my spot light does not stay in the center of the horizontal view port.
Please note the use of .spotlight-2:before to fill the left portion of the shadow on the viewport. This is what I needed to prevent non shaded region from appearing.
How do I make the spotlight stay in center horizontally and not shift to the right when zooming in closely in the browser?
Fiddle
https://jsfiddle.net/u0onf23y/
Resulting Output
https://jsfiddle.net/u0onf23y/embedded/result/
CSS
td .div{
height: 400px;
}
.extend-full {
padding-left: 3000px;
margin-left: -3000px;
padding-right: 3000px;
margin-right: -3000px; }
.spotlight-2{
top: 0px;
margin-left:-80px;
float: left;
display: block;
background: radial-gradient(10px 10px at 560px 400px, transparent 0, transparent 150px, rgba(0, 0, 0, 0.5) 160px);
background: -moz-radial-gradient(10px 10px at 560px 400px, transparent 0, transparent 150px, rgba(0, 0, 0, 0.5) 160px);
background: -webkit-radial-gradient(10px 10px at 560px 400px, transparent 0, transparent 150px, rgba(0, 0, 0, 0.5) 160px);
background: -o-radial-gradient(10px 10px at 560px 400px, transparent 0, transparent 150px, rgba(0, 0, 0, 0.5) 160px);
margin-left: 0px;
height: 100%;
position: fixed;
width: 100%;
min-width: 100vw;
min-height: 100vh;
z-index: 10;
};
position: absolute;
width: 100%;
z-index: 10; }
.account-settings-confirm-container-overlay {
z-index: 10;
background-color: white !important;
height: 99px;
position: absolute;
margin-top: 10px;
width: 250px;
font-size: 12px;
box-shadow: 0px 1px 1px 1px rgba(0, 0, 0, 0.1); }
.spotlight-2:before {
content: "";
position: absolute;
display: block;
left: -100%;
height: 100%;
width: 100%;
background: rgba(0,0,0,0.5);
}
Try flexbox. See example fullpage http://codepen.io/rhroyston/full/qadGgd/
html, body {
height: 100%;
margin: 0;
}
#viewport{
height:100%;
display: flex;
align-items: center;
justify-content: center;
z-index: 1;
background-color: rgb(0,0,0);
background-color: rgba(0,0,0,0.4);
}
.a{
box-shadow: 0px 0px 5px grey inset;
margin: auto;
padding: 20px;
background-color: #fefefe;
border-radius: 50%;
}
<div id="viewport">
<div class="box">
<div class="a"></div>
</div>
</div>
I've added a normal square image to my website and made it into a circle with border-radius and then have tried to add a circle border around it but it only seems to work on Chrome. Any suggestions on how I can fix this?
.face {
display: block;
margin: auto;
border-radius: 100%;
border: 5px solid #ff675b;}
Here is a screenshot of the issue:
https://www.dropbox.com/s/4xy26phkjgz9te0/Screen%20Shot%202013-05-01%20at%2001.15.02.png
See this JsFiddle
http://jsfiddle.net/z3rLa/1/
.avatar {
width:128px;
margin: 10px;
border:10px solid red;
border-radius: 500px;
-webkit-border-radius: 500px;
-moz-border-radius: 500px;
}
That is the way I use:
CSS:
.avatar {
display: block;
border-radius: 200px;
box-sizing: border-box;
background-color: #DDD;
border: 5px solid #cfd8dc;
}
img {
height: 200px;
width: 200px
}
HTML:
<img class="avatar" src="..">
create a new class:
.circleborder {
width: 300px;
height: 300px;
border-radius: 150px;
-webkit-border-radius: 150px;
-moz-border-radius: 150px;
background: url(URL) no-repeat;
box-shadow: 0 0 8px rgba(0, 0, 0, .8);
-webkit-box-shadow: 0 0 8px rgba(0, 0, 0, .8);
-moz-box-shadow: 0 0 8px rgba(0, 0, 0, .8);
}
and this would be your html code:
<div class="circleborder"><img src="URL"/></div>
The HTML:
<div class="circleborder"><img class="face" src="img/face.jpeg" alt="face" width="130" height="130"></div>
CSS:
.face {
border-radius: 100%;}
.circleborder {
border: 5px solid #ff675b;
border-radius: 100%;
display: inline-block;}
Thanks for your help guys! I'm testing my solution as we speak and sofar it's worked on Chrome & Safari on my Mac and iPhone! :D
http://www.css3.info/preview/rounded-border/
Border radius doesn't work the same way in every browser. You need different approaches.
Try this one it will be help for you.
.clip-circle {
clip-path: circle(60px at center);
/* OLD VALUE example: circle(245px, 140px, 50px); */
/* Yep, even the new clip-path has deprecated stuff. */
}
.clip-ellipse {
clip-path: ellipse(60px 40px at 75px 30px);
/* OLD VALUE example: ellipse(245px, 80px, 75px, 30px); */
}
.clip-polygon {
clip-path: polygon(5% 5%, 100% 0%, 100% 75%, 75% 75%, 75% 100%, 50% 75%, 0% 75%);
/* Note that percentages work as well as px */
}