I'm trying to create a query that lists staffID, staffName and staffDOB, but only of staff that first and last names begin with the same letter. So I have both staffFirst and staffLast as individual columns, will join them together. I will not be customising staffID and staffDOB. I would like it to return the name of staff like adam apple = a apple, so the output would look like:
staffID | staffName | staffDOB
------------------------------
1 | A Apple | 12/10/99
.... | .... | ....
All columns are in the same table "N_Staff". I am using HeidiSQL which I believe uses MySQL. I know how to grab the data of each column, though it is selecting the first letters of both first and last names and comparing them which is confusing me as it is not an specific letter I am looking for but any letter that is common on both tables of index [0].
Thus far:
SELECT staffID FROM N_Staff,
SELECT staffFirst, staffLast AS staffName
FROM N_Staff WHERE ... , --perhaps should be using LEFT ?
SELECT staffDOB from N_Staff;
How about:
SELECT staffID, CONCAT(LEFT(staffFirst,1), ' ', staffLast) AS staffName, staffDOB
FROM N_Staff
WHERE LEFT(staffFirst,1) = LEFT(staffLast,1)
use this:
SELECT * FROM NS_WORDS;
mani
nikhil
sugandh
mining
_lkdnsad
_lkdndsadnjas
_lk
_ja
_ls
_lsa
nikhil nikhil
nikhil name
SELECT * FROM NS_WORDS
where not( to_char(SUBSTR(a,1,1))=to_char(substr(a,instr(a,' ',1,1),1)));
output:
nikhil nikhil
nikhil name
your where will go like:
where not( to_char(SUBSTR(staffName ,1,1))=to_char(substr(staffName
,instr(staffName ,' ',1,1),1)));
Related
I have a database table called 'Customers' like this:
Sl Name Profession
1 ABC Doctor
2 QWE Engineer
3 ERT null
4 DEF Doctor
5 JGJ null
I want to order this table as all the names with professions are at the beginning and names without profession(null) at the bottom, like this:
Sl Name Profession
1 ABC Doctor
2 QWE Engineer
4 DEF Doctor
5 JGJ null
3 ERT null
Is there any query to do this? Thanks in advance..
NULLs in MySQL (and most flavors of SQL) sort first by default, not last. One general way to force NULL values to the bottom is to use a CASE or IF expression:
SELECT
Sl, Name, Profession
FROM yourTable
ORDER BY
IF(Profession IS NOT NULL, 0, 1),
Sl;
use order by
select * from table_name
order by case when Profession is not null then 1 else 2 end
NO DB engine provide you order rows without using order by
I have a column in a static table like this:
Vehicles
-------------
Bike
Truck
car_2018
car_2019
car_2020
car_2021
Bus
The select query needs to fetch only the car row based on the year of query (for example now its 2018, if I run this next year, it should get back _2019) long with the rest of the rows that's not based on years. Need a solution for this.
So far I have this:
SELECT Vehicles
FROM VehicleMaster
WHERE 'some where clause based on other columns'
select Vehicles
from table_name
where Vehicles like '%2018'
union all
select Vehicles
from table_name
where Vehicles not like '%car%'
You can use substring_index to split that field by underscore _ and query based on that:
CREATE TABLE vehicles(f1 varchar(30));
INSERT INTO vehicles VALUES ('Bike'),
('Truck'),
('car_2018'),
('car_2019'),
('car_2020'),
('car_2021'),
('Bus');
SELECT f1
FROM vehicles
WHERE
f1 NOT LIKE 'car%'
OR (f1 LIKE 'car%' AND substring_index(f1, "_", -1) = YEAR(CURDATE()));
+----------+
| f1 |
+----------+
| Bike |
| Truck |
| car_2018 |
| Bus |
+----------+
SqlFiddle here
You can use regex to exclude all car_#### rows, except for the current year. Assuming that your Vehicles column is called name, this should work for you:
select *
from Vehicles
where
(
-- Exclude all car_####
not trim(name) REGEXP '^car_[0-9]{4}$'
-- Except for the current year
or name = concat('car_', year(now()))
)
I think you want:
select t.*
from t
where t.vehicle = concat('car_', year(curdate())) or
t.vehicle not regexp '[0-9]{4}$'
If you want a general purpose "any current year or any without a year", then:
select t.*
from t
where t.vehicle like concat('%_', year(curdate())) or
t.vehicle not regexp '[0-9]{4}$'
I have recently taken over a email campaign project and need to generate a report for the customer. However the data has been stored very strangely.
Basically the client wants a report of the subscribers first name and last name that have subscribed to a emailing list.
Example table data.
------------------------------------------------------------
id | owner_id | list_id | field_id | email_address | value
------------------------------------------------------------
1 10 1 137 me#example.com John
2 10 1 138 me#example.com Doe
So as you can see, John Doe has subscribed to mailing list 1, and field_id 137 is his first name and field_id 138 is his last name.
The client is looking for a export with the users first name and last name all is one field.
I tred the following sql query
SELECT value
FROM Table_A AS child
INNER JOIN Table_A AS parent
ON parent.email_address = child.email_address
WHERE child.owner_id = '10'
But unfortunately the query gives me the results in many rows but not appending the first name and last name into one field,
If anyone can provide some assistance that would be awesome.
Thanks.
SELECT
concat( parent.value,' ',child.value)name
FROM mytable AS child
left JOIN mytable AS parent
ON parent.email_address = child.email_address
WHERE child.owner_id = '10'
and parent.field_id=137 and child.field_id=138
Check at-http://sqlfiddle.com/#!9/199b4b/45
I think you have to use a variable to put in there everything you have to and then select the variable with the desired name of yours.
For example:
DECLARE #yourvariable VARCHAR(MAX)
SELECT #yourvariable = COALESCE(#yourvariable + " ") + value
FROM table_A
WHERE owner_id = 10
SELECT #yourvariable as FullName
Try that, it might help.
You can try this code(column name equals value in your original DB):
select a.name
from
table_a a inner join table_a b
on a.email_address = b.email_address and a.field_id <> b.field_id
where a.owner_id=10
order by a.field_id
Here is the example link:
http://sqlfiddle.com/#!9/5fbdf6/25/0
As per assumptions, first name has the field id 137 and last name has the field id 138.
You can try the following query to get the desired result.
SELECT CONCAT(SUBSTRING_INDEX(GROUP_CONCAT(`value`),",",1)," ",SUBSTRING_INDEX(GROUP_CONCAT(`value`),",",-1)) AS client_name
FROM Table_A
WHERE owner_id = 10
AND field_id IN (137, 138)
GROUP BY email_address;
I have fields like this:
-----------------
id | name
-----------------
1 | name123
-----------------
2 | name
-----------------
3 | name456
-----------------
4 | name
I want to extract rows which have digit in name and a field that contains the number like this
------------------------------
id | name | number
-----------------------------
1 | name123 | 123
-----------------------------
3 | name456 | 456
how can we find the records that have digit and extract digit as a new field?
Here is another way to do with mysql
SELECT
id,
name,
SUBSTRING(
name,LEAST (
if (Locate('0',name) >0,Locate('0',name),999),
if (Locate('1',name) >0,Locate('1',name),999),
if (Locate('2',name) >0,Locate('2',name),999),
if (Locate('3',name) >0,Locate('3',name),999),
if (Locate('4',name) >0,Locate('4',name),999),
if (Locate('5',name) >0,Locate('5',name),999),
if (Locate('6',name) >0,Locate('6',name),999),
if (Locate('7',name) >0,Locate('7',name),999),
if (Locate('8',name) >0,Locate('8',name),999),
if (Locate('9',name) >0,Locate('9',name),999)
),LENGTH(name)
) as number
from users
having number <> '' ;
you can use MySQL's string conversion on an int to strip out the name like so
SELECT
t.id,
t.name,
REVERSE(REVERSE(t.name)+ 0) AS num,
REPLACE(t.name,REVERSE(REVERSE(t.name)+ 0),'') AS actualname
FROM foobar t
HAVING num <> 0
the trick with this is by adding a 0 mysql is comparing the numeric value in the name... however the name has to start with a number... so I reverse it do the calculation and then reverse again... NOTE all of your names have to start with the name and end with a number for this to work for all of them
FIDDLE DEMO
EDIT:
since you say that some can start with a number and others end with a number.. then try this
SELECT
t.id,
t.name,
REVERSE(REVERSE(t.name)+ 0) AS num,
REPLACE(t.name,REVERSE(REVERSE(t.name)+ 0),'') AS actualname
FROM foobar t
HAVING num <> 0
UNION ALL
SELECT
t.id,
t.name,
t.name + 0 AS num,
REPLACE(t.name,t.name + 0,'') AS actualname
FROM foobar t
HAVING num <> 0
ANOTHER DEMO
Another way, assuming the number you want is at the end of the string. REVERSE() to put the number part in front, then CONVERT() to make it a number and strip off the text, then REVERSE() again WHERE name ends in a number. Feels like a kludge though:
select id, name, reverse(convert(reverse(name),signed ))
from tbl
where name REGEXP '[0-9]+$';
SQL Fiddle Example
assume that we are performing search using keywords: keyword1, keyword2, keyword3
there are records in database with column "name":
1: John Doe
2: Samuel Doe
3: John Smith
4: Anna Smith
now Query:
SELECT * FROM users WHERE (name LIKE "%John%" OR name LIKE "%Doe%")
it will select records: 1,2,3 (in this order)
but i want to order it by keyword
in example keyword1=John, keyword2=Doe
so it should be listed by keywords: 1,3,2 (because i want to perform search for "Doe" after searching for "John")
I was thinking about SELECT DISTINCT FROM (...... UNION .....)
but it will be much easier to order it somehow in another way (real query is really long)
are there any tricks to create such order?
order by case
when name LIKE "%John%" then 1
when name LIKE "%Doe%" then 2
else 3
end
To build on RedFilter's answer, you could make the rows that have both keywords to be at the top:
order by case
when (name LIKE "%John%" and name LIKE "%Doe%") then 1
when name LIKE "%John%" then 2
when name LIKE "%Doe%" then 3
end
Read up on Boolean Fulltext Searches, with which you can do ordering.
SELECT *
from
(
SELECT u.*, 1 OrderNum
FROM users
WHERE (name LIKE "%John%")
UNION
SELECT u.*, 2 OrderNum
FROM users
WHERE (name LIKE "%Doe%")
)
Order by OrderNum
My example will Order all of the John's Alphabetically followed by the Doe's.
ORDER BY CASE
WHEN name LIKE "John%Doe" THEN CONCAT('a',name)
WHEN name LIKE "John%" THEN CONCAT('b',name)
WHEN name LIKE "%Doe" THEN CONCAT('c',name)
ELSE name
END