How to get hotel total room and booked room in single query - mysql

Question

How to get hotel total room and booked room in single query.
I used 2 queries get result. I need this in single query.
The issue I am experiencing since all counts are in this table htl_room_information.id_hotel
Booked room:
SELECT x.hotel_name
, count(i.id_hotel) room
FROM htl_booking_detail d
JOIN htl_branch_info_lang x
ON x.id=d.id_hotel
JOIN htl_room_information i
ON d.id_room=i.id
group
by x.hotel_name;
+------------------------------------------+------+
| hotel_name | room |
+------------------------------------------+------+
| hotel | 3 |
| hotel1 | 1 |
| hotel2 | 4 |
| hotel3 | 13 |
| hotel4 | 9 |
| hotel5 | 3 |
| hotel6 | 3 |
| hotel7 | 2 |
+------------------------------------------+------+
Total Rooms
SELECT (htl_branch_info_lang.hotel_name) as hotel_name,count(htl_room_information.id_hotel) as total_room FROM htl_room_information ,htl_branch_info_lang where htl_room_information.id_hotel=htl_branch_info_lang.id group by htl_branch_info_lang.hotel_name;
+------------------------------------------+------------+
| hotel_name | total_room |
+------------------------------------------+------------+
| hotel | 219 |
| hotel2 | 25 |
| hotel3 | 16 |
| hotel4 | 5 |
| hotel5 | 55 |
| hotel6 | 27 |
| hotel7 | 56 |
| hotel8 | 52 |
+------------------------------------------+------------+

Answer 1

Use dependent subqueries.
SELECT x.hotel_name,
(
SELECT count(i.id_hotel)
FROM htl_booking_detail d
JOIN htl_room_information i
ON d.id_room=i.id
WHERE x.id=d.id_hotel
) as room,
(
SELECT count(i.id_hotel)
FROM htl_room_information i
WHERE i.id_hotel=x.id
) as total_room
FROM htl_branch_info_lang x
I assume that the hotel_name is unique in the htl_branch_info_lang table. If not, you have to put distinct behind the first SELECT.

Answer 2

Hoping, I understood your question correctly.
Please check below query.
select b.hotel_name hotel_name, a.room ,
b.total_room
from
(SELECT htl_branch_info_lang.hotel_name,
count(htl_room_information.id_hotel) as room FROM htl_booking_detail,
htl_branch_info_lang, htl_room_information WHERE
htl_branch_info_lang.id=htl_booking_detail.id_hotel and
htl_booking_detail.id_room=htl_room_information.id group by
htl_branch_info_lang.hotel_name ) a RIGHT join (SELECT (htl_branch_info_lang.hotel_name) as
hotel_name,count(htl_room_information.id_hotel) as total_room
FROM htl_room_information ,htl_branch_info_lang
where htl_room_information.id_hotel=htl_branch_info_lang.id
group by htl_branch_info_lang.hotel_name) b
on a.hotel_name = b.hotel_name
;

Answer 3

You can use subquery
try this:
SELECT (a.hotel_name) as
hotel_name,count(htl_room_information.id_hotel) as total_room, (SELECT
count(htl_room_information.id_hotel) as room FROM htl_booking_detail,
htl_branch_info_lang b, htl_room_information WHERE
b.id=htl_booking_detail.id_hotel and
htl_booking_detail.id_room=htl_room_information.id and
b.hotel_name = a.hotel_name), count(htl_room_information.id_hotel) - (SELECT
count(htl_room_information.id_hotel) as room FROM htl_booking_detail,
htl_branch_info_lang b, htl_room_information WHERE
b.id=htl_booking_detail.id_hotel and
htl_booking_detail.id_room=htl_room_information.id and
b.hotel_name = a.hotel_name) as available FROM htl_room_information
,htl_branch_info_lang
a where htl_room_information.id_hotel=a.id group by
a.hotel_name;