How to count rows from an inner joined table - mysql

Question

I am pulling all of the information for solutions using cross referenced tables.
SELECT
s.*, u.forname, u.surname, u.email, u.tel, p.type
FROM _user_solution s
INNER JOIN _users u
ON s.uid = u.uid
INNER JOIN _payment_plans p
ON p.pid = s.payment_plan_type
Which works fine and my results are as expected. However, I have another table which holds tasks for that solution, each task has a progress. I want to bring out how many tasks that solution has, I have tried:
SELECT
s.*, u.forname, u.surname, u.email, u.tel, p.type,
(SELECT COUNT(*) FROM t WHERE t.progress < 100 AS task)
FROM _user_solution s
INNER JOIN _users u
ON s.uid = u.uid
INNER JOIN _payment_plans p
ON p.pid = s.payment_plan_type
INNER JOIN _solution_tasks t
ON s.sid = t.assigned_for_solution
But I am getting this error:
You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'AS task) FROM _user_solution s INNER JOIN _users u ON s.uid = u.uid' at line 3
Any ideas on how I can count all of the tasks that are incomplete to this solution would be much appreciated.

Answer 1

You need to move the AS task aliasing part outside the subquery; outside the closing bracket.
SELECT
s.*, u.forname, u.surname, u.email, u.tel, p.type,
(SELECT COUNT(*) FROM _solution_tasks WHERE progress < 100) AS task
FROM _user_solution s
INNER JOIN _users u
ON s.uid = u.uid
INNER JOIN _payment_plans p
ON p.pid = s.payment_plan_type
INNER JOIN _solution_tasks t
ON s.sid = t.assigned_for_solution

Answer 2

you can try like below
SELECT
s.*, u.forname, u.surname, u.email, u.tel, p.type,
(SELECT COUNT(*)
FROM another_table tt1
WHERE tt1.taskID=t.taskID --assume taskID is join key
and tt1.progress < 100
) AS task
FROM _user_solution s
INNER JOIN _users u
ON s.uid = u.uid
INNER JOIN _payment_plans p
ON p.pid = s.payment_plan_type
INNER JOIN _solution_tasks t
ON s.sid = t.assigned_for_solution

Answer 3

I managed to figure out how to do it, I needed to put the progress in the WHERE clause at the bottom since that is what I am trying to query it all against and then I need to select COUNT(*)
SELECT
s.*, u.forname, u.surname, u.email, u.tel, p.type, COUNT(*) as tasks
FROM _user_solution s
INNER JOIN _users u
ON s.uid = u.uid
INNER JOIN _payment_plans p
ON p.pid = s.payment_plan_type
INNER JOIN _solution_tasks t
ON s.sid = t.assigned_for_solution
WHERE t.progress < 100
This is now giving me how many tasks are allocated to that solution. After doing abit of research, the first COUNT comes out as 0, like an array index starts at 0, so in this case, the solution row itself brings out 0 and then each task associated with the solution adds 1 giving me the correct multiple of tasks.

Answer 4

I've changed your query to this and it works:
SELECT
s.*, u.forname, u.surname, u.email, u.tel, p.type,
(SELECT COUNT(WRITE_AUTOINCREMENT_ID) AS task FROM t WHERE t.progress < 100)
FROM _user_solution AS s
INNER JOIN _users AS u
ON s.uid = u.uid
INNER JOIN _payment_plans p
ON p.pid = s.payment_plan_type
INNER JOIN _solution_tasks AS ttable
ON s.sid = ttable.assigned_for_solution