Does anyone know the solution to this problem ?
There are 3 Tables: orders, order_groups and stores.
I want to list the orders, with the names of the stores where the order was placed, and where the order is going to be delivered.
I keep the from_store_id, and to_store_id in the order_groups table
Listing these orders would be simple, i just left join the order_groups to orders, and select the name, from_shop_id and to_shop_id, but the problem is i want the name of the stores not the id, and the store names are placed in a different table (stores)
Here is what im talking about:
Table orders
id group_id name madeup_id
1 11 johnny cash 1
2 12 billy bob 1
LEFT JOIN order_groups on order_groups.id = orders.group_id
Table order_groups
id from_store_id to_store_id
11 55 56
12 56 55
Table stores
id store_name
55 thisstore
56 thatstore
The result im looking for is:
name from_store to_store
1.johhny cash thisstore, thatstore
2.billy bob thatstore, thisstore
The statement i have yet:
SELECT
orders.name, something as from_store, something as to_store
FROM orders
LEFT JOIN order_groups on order_groups.id = orders.group_id
somehow join stores on the order_groups.from_store_id = stores.id
WHERE orders.madeup_id = 1
Any idea how to select and join the store names to the query ?
One more question. I actually want to list two kind of orders in one query from different tables too, im on the right track with this structure ?
SELECT a,b FROM a LEFT JOIN b ON b.something=a.something WHERE something
UNION ALL
SELECT a,b FROM c LEFT JOIN c ON c.something=a.something WHERE something
You only need to join 2 times the same table!
SELECT
orders.name, fromStore.store_name as from_store, toStore.store_name as to_store
FROM orders
LEFT JOIN order_groups on order_groups.id = orders.group_id
left join stores fromStore on the order_groups.from_store_id = fromStore.id
left join stores toStore on the order_groups.to_store_id = toStore.id
WHERE orders.madeup_id = 1
Related
I'm learning MySQL and I couldn't find a solution to this problem.
I have three tables:
Companies:
CompanyID (PRIMARY KEY)
EntryDate
CompanyName
6
2000-01-01
foo
13
2000-01-02
bar
CompaniesAndFunds:
Company
1
23
NatureOfCompanyDefs:
NatureOfCompanyID (PRIMARY KEY)
NatureOfCompany
12
foo
88
bar
How can I modify this query so the result will also include unmatched records, I mean - include "Companies" without assigned "Nature":
SELECT
Companies.EntryDate,
Companies.CompanyName,
NatureOfCompanyDefs.NatureOfCompany,
CompaniesAndFunds.Company
FROM
CompaniesAndFunds
INNER JOIN Companies ON CompaniesAndFunds.Company = Companies.CompanyID
INNER JOIN NatureOfCompanyDefs ON Companies.NatureOfCompany = NatureOfCompanyDefs.NatureOfCompanyID
This is because you are using an inner join instead of a Left Join. Inner Joins will exclusively show matches, whereas left will show even unmatched rows. Try:
SELECT
Companies.EntryDate,
Companies.CompanyName,
NatureOfCompanyDefs.NatureOfCompany,
CompaniesAndFunds.Company
FROM
CompaniesAndFunds
INNER JOIN Companies ON CompaniesAndFunds.Company = Companies.CompanyID
LEFT JOIN NatureOfCompanyDefs ON Companies.NatureOfCompany = NatureOfCompanyDefs.NatureOfCompanyID
The main table has 4 columns:
User Activity Table
userActivityId userId therapistId activityId
1 1 1 1
Each of these columns is a table and these values are all foreign keys.
Basically im trying to run a query that will join to the users table and pull their first and last name based off the user Id.Same thing with therapist - join to the therapist table, pull first + last name.And finally Join to the Activity table and pull the activity name and path from the activity Id
The other tables look like this:
User Table
userId fName lName
Therapist Table
therapistId therapistFirstName therapistLastName
Activity Table
activityId activityTitle activityPath
So far my query looks like
SELECT
User_Activities.userId,
User_Activities.therapistId,
User_Activities.activityId,
Activities.activityTitle,
Activities.activityPath,
Users.fName,
users.lName,
Therapists.therapistFirstName,
Therapists.therapistLastName
FROM
User_Activities
INNER JOIN Users
ON User_Activities.userId = Users.userId
INNER JOIN Therapists ON
User_Activities.therapistId = Therapists.therapistId
INNER JOIN Activities ON
Activities.activityId = User_Activities.userActivityId
WHERE
User_Activities.userId = 1;
When I run this query It only returns 1 row as a result. However there are two activities in the User_Activites table assigned to userId 1.
If I change : INNER JOIN Activities ON
Activities.activityId = User_Activities.userActivityId
from an INNER JOIN to the LEFT JOIN it will display the second row, however the activityTitle and activityPath will be displayed as NULL in the second row.
userActivityId userId therapistId activityId activityId activityTitle activityPath fName lName therapistFirstName therapistLastName
1 1 1 1 1 Brain GZZ0zpUQ S C M D
11 1 1 1 NULL NULL NULL S C M D
You have pretty much answered your question. The second activity does not have a valid ActivityId.
If you want all activities for a user, then you should phrase the query as:
SELECT . . .
FROM Users u LEFT JOIN
User_Activities ua
ON ua.userId = u.userId LEFT JOIN
Therapists t
ON ua.therapistId = t.therapistId LEFT JOIN
Activities a
ON a.activityId = ua.userActivityId
WHERE u.userId = 1;
You want to start with the table where you want to keep all the rows. Then use LEFT JOIN to bring in other tables.
Two other changes of note:
Table aliases are used to simplify reading and writing the query. The SELECT needs to change to use the aliases.
The WHERE clause refers to the Users table rather than UserActivities.
I have this query:
SELECT suppliers.id, count(*)
FROM suppliers
INNER JOIN supplier_addresses
ON suppliers.id = supplier_addresses.supplier_id
GROUP BY suppliers.id;
this gives my a table of supplierId and count of its addresses in the supplier_addresses table. But it only shows me suppliers that have at least 1 address.
I want to see in the result also count of 0 addresses...for example:
supplier.id | count(*)
1 3
2 0
3 1
4 9
in my query I dont see the second record.
Use LEFT JOIN
SELECT suppliers.id, count(supplier_addresses.supplier_id )
FROM suppliers
LEFT JOIN supplier_addresses
ON suppliers.id = supplier_addresses.supplier_id
GROUP BY suppliers.id;
Problem:
I'm having trouble finding a solution building a query with QueryBuilder (perhaps getting it done with regular sql query first will help):
Trying to retrieve all customers for a user (has shop credits at one of the shops user is linked to), need the total credits (sum of credits at shops belonging to that user) as virtual column (to be able to order on), using paginate().
Database structure:
Table customers
id email other_fields
1 1#email.com f
2 2#email.com o
3 3#email.com o
Table users
id email other_fields
1 1#user.com b
2 2#user.com a
3 3#user.com r
Table shops
id name other_fields
1 Shop 1 m
2 Shop 1 o
3 Shop 1 o
Table user_shops
user_id shop_id
1 1
1 2
3 3
Table customer_shop_credits
customer_id shop_id credits
1 1 55
1 2 45
2 2 3
3 3 44
Expected result:
When retrieving customers for user 1, I'd expect to get back customer 1 with 100 credits and customer 2 with 3 credits
Closest I got:
$credits_query = CustomerShopCreditQuery::create()
->useShopQuery()
->useUserShopQuery()
->filterByUserId($user->getId())
->endUse()
->endUse()
;
$customers = CustomerQuery::create()
->addSelectQuery($credits_query, 'credits_alias', false)
->useCustomerShopCreditQuery()
->useShopQuery()
->useUserShopQuery()
->filterByUserId($user->getId())
->endUse()
->endUse()
->endUse()
->withColumn('sum(credits_alias.credits)', 'credits')
->groupById()
->orderBy($order_by_column, $direction)
->paginate($page, $page_size);
Which results in the following query:
SELECT customers.id, customers.email, sum(credits_alias.credits) AS credits
FROM customers
CROSS JOIN (
SELECT customer_shop_credits.id, customer_shop_credits.customer_id, customer_shop_credits.shop_id, customer_shop_credits.credits
FROM customer_shop_credits
INNER JOIN shops ON (customer_shop_credits.shop_id=shops.id)
INNER JOIN user_shops ON (shops.id=user_shops.shop_id)
WHERE user_shops.user_id=159
) AS credits_alias
INNER JOIN customer_shop_credits ON (customers.id=customer_shop_credits.customer_id)
INNER JOIN shops ON (customer_shop_credits.shop_id=shops.id)
INNER JOIN user_shops ON (shops.id=user_shops.shop_id)
WHERE user_shops.user_id=159
GROUP BY customers.id
ORDER BY customers.id DESC
LIMIT 25
But gives me results with wrong sum of credits.
Not to sure about the CROSS JOIN. When I edit this query and make it a JOIN and use ON (credits_alias.customer_id = customers.id) as a condition, the sum of credits is better, but seems to have the classic join problem of doubling the sum
ive been searching for hours but cant find a solution. its a bit complicated so i'll break it down into a very simple example
i have two tables; people and cars
people:
name_id firstname
1 john
2 tony
3 peter
4 henry
cars:
name_id car_name
1 vw gulf
1 ferrari
2 mustang
4 toyota
as can be seen, they are linked by name_id, and john has 2 cars, tony has 1, peter has 0 and henry has 1.
i simply want to do a single mysql search for who has a (1 or more) car. so the anwser should be john, tony, henry.
the people table is the master table, and im using LEFT JOIN to add the cars. my problem arises from the duplicates. the fact that the table im joining has 2 entries for 1 id in the master.
im playing around with DISTINCT and GROUP BY but i cant seem to get it to work.
any help is much appreciated.
EDIT: adding the query:
$query = "
SELECT profiles.*, invoices.paid, COUNT(*) as num
FROM profiles
LEFT JOIN invoices ON (profiles.id=invoices.profileid)
WHERE (profiles.id LIKE '%$id%')
GROUP BY invoices.profileid
";
try this
select distinct p.name_id, firstname
from people p, cars c
where p.name_id = c.name_id
or use joins
select distinct p.name_id, firstname
from people p
inner join cars c
on p.name_id = c.name_id
If you only want to show people that have a car, then you should use a RIGHT JOIN. This will stop any results from the left table (people) to be returned if they didn't have a match in the cars table.
Group by the persons name to remove duplicates.
SELECT firstname
FROM people P
RIGHT JOIN cars C ON C.name_id = P.name_id
GROUP BY firstname
SELECT DISTINCT firstname
FROM people
JOIN cars ON cars.name_id = people.name_id;
If this doesn't work you might have to show us the full problem.
The way to propose it there's no need for a left join since you need at least a car per person. Left join is implicitely an OUTER join and is intended to return the results with 0 corresponding records in the joinned table.