join mysql select queries as 1 then group by - mysql

Question

Using information of this site I have been able to do the join but im having the issues doing the group by
is there a way to get the below statements to run as 1
Query1
SELECT count(location),date
from `filter`
where location != "red"
group by date
Query2
SELECT count(location),date
from `filter`
where location = "red"
group by date
I did try the below but it outputs the wrong data
Query3
SELECT
date,
(select count(location) from `filter` where location != "red") AS indoor,
(select count(location) from `filter` where location = "red") AS outdoor
from `filter` group by date;
SQL Fiddle for each query
http://sqlfiddle.com/#!9/17ebea/4 (query1)
http://sqlfiddle.com/#!9/17ebea/6 (query2)
http://sqlfiddle.com/#!9/90c945/1 (query3)

Answer 1

SELECT
date,
COUNT(CASE WHEN location <> 'red' THEN location ELSE NULL END) AS indoor,
COUNT(CASE WHEN location = 'red' THEN location ELSE NULL END) AS outdoor
FROM filter
GROUP BY date;
https://dev.mysql.com/doc/refman/8.0/en/control-flow-functions.html#operator_case

Answer 2

You can do conditional aggregation using CASE.. WHEN expressions.
SELECT
date,
COUNT(CASE WHEN location = 'red' THEN location END) AS outdoor,
COUNT(CASE WHEN location <> 'red' THEN location END) AS indoor
FROM `filter`
GROUP BY date;
View on DB Fiddle
Result
| date | outdoor | indoor |
| ---------- | ------- | ------ |
| 2018-11-14 | 1 | 4 |
| 2018-11-15 | 1 | 0 |
| 2018-11-16 | 0 | 3 |
| 2018-11-17 | 1 | 1 |
| 2018-11-18 | 0 | 1 |
| 2018-11-19 | 0 | 2 |
| 2018-11-20 | 0 | 1 |
You can also use the following other variants, like using COUNT(1) instead, or using SUM(..) function.
Alternative #1
SELECT
date,
COUNT(CASE WHEN location = 'red' THEN 1 END) AS outdoor,
COUNT(CASE WHEN location <> 'red' THEN 1 END) AS indoor
FROM `filter`
GROUP BY date;
Alternative #2
SELECT
date,
SUM(CASE WHEN location = 'red' THEN 1 ELSE 0 END) AS outdoor,
SUM(CASE WHEN location <> 'red' THEN 1 ELSE 0 END) AS indoor
FROM `filter`
GROUP BY date;

Answer 3

In MySQL, I would use the shortcut that allows you to sum() boolean variables:
select date, sum(location = 'red') as red,
sum(location <> 'red') as not_red
from filter
group by date ;
Notes:
Use single quotes for string and date constants -- not double quotes. Single quotes are the standard delimiter.
<> is the SQL inequality operator, although != is also supported by most databases.
This does not count NULL values.
To handle NULL values, you might want:
sum(not location <=> 'red') as not_red