Removing an ID from a NOT IN - mysql

Question

I'm trying to write a query to calculate the total charged on a per client basis, where a client has a registered property in one table, where they have not been invoiced in another, but I am not sure how to write the 'Not In' portion of the query so that it does not have to reference a specific ID.
The query listed below is part of a larger query to calculate overall totals, but I am struggling with this particular piece.
I have tried to modify the 'Not In' portion of the query to remove the reference to a specific ID and do a Group By the client_id, but this did not return any results. I also tried a GROUP_CONCAT, but I'm not sure I implemented that properly.
I'm not sure if a) what I'm trying to do is possible, or b) if there's a much better way to go about doing what I'm trying to accomplish, but I feel like if I could write this in another subquery, I'd be in much better shape, but I can't wrap my head around how to write it or even another way to approach the problem.
SELECT
clients.client_id,
clients.first_name,
clients.last_name,
SUM(total_charged) AS total_charged
FROM
clients
LEFT JOIN
(SELECT
clients.client_id,
route_property_reg.route_property_reg_id,
route_property_reg.rate_charged AS total_charged
FROM
clients
LEFT JOIN properties ON clients.client_id = properties.client_id
LEFT JOIN route_property_reg ON properties.property_id = route_property_reg.property_id
WHERE
route_property_reg.route_property_reg_id NOT IN (
SELECT DISTINCT
invoice_lines.route_property_reg_id
FROM
clients
LEFT JOIN invoices ON clients.client_id = invoices.client_id
LEFT JOIN invoice_lines ON invoices.invoice_id = invoice_lines.invoice_id
WHERE
clients.client_id = 1)
GROUP BY clients.client_id)
AS charged ON clients.client_id = charged.client_id
GROUP BY clients.client_id
SQL Fiddle
An alternative Fiddle with another attempt but similar results: SQL Fiddle
Expected/Anticipated Output would be:
| client_id | first_name | last_name | total_charged |
|-----------|------------|-----------|---------------|
| 1 | John | Doe | 200 | - (route-properties # 1 and 4)
| 2 | Jane | Doe | 200 | - (route-property #5)
| 3 | John | Smith | (null) |
| 4 | Jane | Smith | (null) |

Answer 1

After a lot of guess and check, the following works for me:
SELECT
clients.client_id,
clients.first_name,
COALESCE(SUM(total_charged), 0) AS total_charged
FROM
clients
LEFT JOIN (SELECT
c.client_id,
a.route_property_reg_id,
COALESCE(SUM(ROUND((a.rate_charged * (1 + (tax_types.rate / 100))), 2)), 0) AS total_charged
FROM
route_property_reg a
LEFT JOIN properties ON a.property_id = properties.property_id
LEFT JOIN clients c ON properties.client_id = c.client_id
LEFT JOIN tax_types ON a.tax_rate_charged = tax_types.tax_type_id
WHERE
NOT EXISTS( SELECT
NULL
FROM
invoice_lines b
LEFT JOIN invoices ON b.invoice_id = invoices.invoice_id
LEFT JOIN clients d ON invoices.client_id = d.client_id
WHERE
b.route_property_reg_id = a.route_property_reg_id
AND d.client_id = c.client_id)
GROUP BY client_id) AS charged ON clients.client_id = charged.client_id
GROUP BY clients.client_id