How to achieve the effect (shown in the attached image) in CSS - html

I would like to achieve the following effect in a div box. What CSS would do the trick? Thank you in advance for your answers!

Using the linear-gradient function in CSS3, the code will be +- like this:
.box{
height: 100px;
width: 100px;
background: linear-gradient(to top, blue, white, blue)
}

as stated in the first answer, use css gradients, and combine with border-radius for your rounded corners.
.box{
height: 200px;
width: 150px;
background: linear-gradient(to top, #4690ff, #ffffff, #4690ff);
border-radius:15px 0px 0px 15px;
}
<div class="box"></div>

You can use CSS3 with linear gradient. Something like this:
.demo {
width: 150px;
height: 150px;
}
.gradient {
background: #508cf4; /* Old browsers for fallback */
background: linear-gradient(to bottom, #508cf4 0%, #ffffff 50%, #508cf4 100%);
}
<div class="gradient demo"></div>
You could also google for "css3 gradient generator" to have a GUI. For example cssgradient.io

You might test run a few css gradient tools like ColorZilla and GradientFinder to work with gradient colors.
Also, by combining a low opacity radial gradient with a linear gradient you can get a more rich look that might get closer to your original image.
.box {
display: block;
width: 182px;
height: 229px;
background:
radial-gradient(ellipse at center, rgba(252,253,255,.2) 54%,rgba(212,229,255,.2) 66%,rgba(212,229,255,.2) 66%,rgba(153,193,255,.2) 79%,rgba(153,193,255,.2) 79%,rgba(57,136,255,.2) 100%),
linear-gradient(to top, rgb(57, 136, 255) 0%, rgb(153, 193, 255) 13%, rgb(212, 229, 255) 23%, rgb(252, 253, 255) 43%, rgb(252, 253, 255) 57%, rgb(212, 229, 255) 77%, rgb(153, 193, 255) 87%, rgb(57, 136, 255) 100%);
border-radius: 16px 0 0 16px;
}
<div class="box"></div>
<p>original <img src="https://i.stack.imgur.com/OJ5Z6.png" /></p>

Related

linear gradient css with deg with rest color to bottom and top

I did linear 115deg for doing 2 colors, but for the rest, I can't make them be nested gradient from top to bottom, here is my result gradient , the colors are : white and #F5F5F5 ( grey )
I want the grey that has linear also from bottom to top to be white
is that possible?
the result might like this
i did my own linear like the expected but with rgba to opacity it, using like this
background: linear-gradient(115deg, #ffffff 68vw, rgba(245, 245, 245, 0.5) 30vw);
i did this gradient for background color so i can put content inside the div
here is what i did => https://codepen.io/lpllplp222/pen/vYWPdBe
You can use clip-path to cut out the part of the gradient you want to be visible.
body {
background: black;
}
#do-linear {
width: 100%;
height: 300px;
background: linear-gradient(15deg, rgba(255, 255, 255, 1), rgba(255, 255, 255, 0.25));
clip-path: polygon(50% 100%, 70% 0%, 100% 0%, 100% 100%);
}
<div id="do-linear"></div>

How do I put two linear-gradients on the left and right border?

I'm looking to create a yellow div with wide left and right borders. Towards the outside edges of the div, the left and right borders taper in colour down to white to simulate transparency.
So far I've been able to construct the div, but not the gradient:
.fade {
margin: 2em 2em; padding-top: 2em; padding-bottom: 2em;
background: rgb(242,242,194);
border-right: 3em black solid;
border-left: 3em black solid;
border-image: linear-gradient(90deg, rgb(255, 255, 255) 0%, rgb(242, 242, 194) 100%);
{
<div class="fade">Text</div>
What happens can be seen above: the linear gradient correctly overrides the black to make a yellow border, but there's no fade to white that I'm looking for. There's no gradient at all, in fact.
The final product should look like this:
Where am I going wrong?
If you aren't familiar with gradients and you don't want to mess with them you should use Colorzilla gradient tool: http://www.colorzilla.com/gradient-editor/
.fade {
margin: 2em 2em; padding-top: 2em; padding-bottom: 2em;
background: linear-gradient(90deg, white 0%, rgb(242, 242, 194) 5%, rgb(242, 242, 194) 95%, white 100%);
}
<div class="fade">Text</div>
Maybe something like this can be useful?
I will explain what I did.
I deleted every attribute that contains border and I only used background.
background: linear-gradient(90deg, white 0%, rgb(242, 242, 194) 5%, rgb(242, 242, 194) 95%, white 100%);
This gradient has 4 steps:
The first step tells that the gradient has to start in white.
The second step (5% of the width of the element) tells that the gradient follows yellow.
Until third step (95% of the width of the element).
Then, in fourth step it ends with white again.
Note that this percentages are for the width because you have rotated the gradient 90 degrees, with 0 or 360 you will affect the height part of the gradient.
A last detail, you will need some padding inside the div to make the text looks exactly like your photo.
div {
background: linear-gradient(90deg, white 0%, rgb(242, 242, 194) 8%, rgb(242, 242, 194) 92%, white 100%);
padding: 15px;
margin: 30px;
}
p {
padding-left: 50px;
}
<div><p>Text</p></div>

CSS Parallelogram-Cut Border Pattern

I would like insight as to whether or not it is possible to develop a border pattern like the one displayed here through CSS code. I've considered making the pattern through a Photoshop-like program and then setting the background of the border to the url of the photoshop-made pattern. How I run into browser compatibility issues if I wish to pursue this through coding?
Able to make a pretty similar border using straight css.
First, in before, generated a box with 3 striped lines- one red, one blue, one beige. Also added the beige border to this.
Then, in the :after pseudo element, just gave the box a beige background (probably could look better with a gradient background too).
Check it out:
<!DOCTYPE html>
<html>
<head>
<style>
p.box:before{
content: '';
position: absolute;
z-index: -1;
width: 100%;
height: 100%;
background:repeating-linear-gradient(
45deg,
hsl(60, 56%, 81%) 0px,
hsl(60, 56%, 81%) 4px,
red 5px,
red 14px,
hsl(60, 56%, 81%) 15px,
hsl(60, 56%, 81%) 20px,
hsla(247, 83%, 37%, 1) 21px,
hsla(247, 83%, 37%, 1) 30px
),
linear-gradient(
to bottom,
rgba(48, 26, 255, 1),
rgba(85, 66, 255, 1)
);
border: 5px solid hsl(60, 56%, 81%);
}
p.box:after{
content: '';
position: absolute;
right: -.5%;
bottom: -2.5%;
background: hsl(60, 56%, 81%);
z-index: -1;
height: 97%;
width: 97%;
}
</style>
</head>
<body>
<p class="box"></p>
</body>
</html>

CSS Fade Out HR Line issue

So I am trying to setup the fadeout css3 hr tag, it works on JSFiddle but I can't solve it on my site.
My CSS class on site:
.about-sidebar{
margin: 25px 0;
height: 1px;
background: black;
background: -webkit-gradient(linear, 0 0, 100% 0, from(#1F1F1F), to(#FFD700), color-stop(50%, black));
}
HTML:
<hr class="about-sidebar" />
I have tried taking the class out of the HR tag and surrounding it with a div but doesn't solve.
Site: http://travisingram.net/ it is the "Welcome to my Blog" on the sidebar.
Jsfiddle working:
http://jsfiddle.net/ZTz7Q/1633/
The reason it wasn't working on your website was because the <hr> didn't contain the class with the gradient styling. Currently, you just have <hr> which should be changed to <hr class="line"> or whatever class you're using.
Aside from that, the linear-gradients needs some tweaking and cross browser prefix vendors for more support.
jsFiddle example
I don't know what colors you want.. but here is black to transparent.
.line {
margin: 25px 0;
height: 5px;
background: black;
background: -moz-linear-gradient(left, rgba(0,0,0,1) 0%, rgba(0,0,0,0.98) 2%, rgba(255,255,255,0) 90%);
background: -webkit-linear-gradient(left, rgba(0,0,0,1) 0%,rgba(0,0,0,0.98) 2%,rgba(255,255,255,0) 90%);
background: linear-gradient(to right, rgba(0,0,0,1) 0%,rgba(0,0,0,0.98) 2%,rgba(255,255,255,0) 90%);
}

Gradient that stops at a particular height and continues further with a solid color

I want to have a gradient in HTML/CSS.
Assume some DIV is always more than 400px tall. I want to add the gradient so that it is #FFFFFF at the top and #EEEEEE at 300px. So the first 300px (height-wise) is a nice 'white to grey' gradient. After 300px, regardless of how tall the DIV goes, I want the background color to stay #EEEEEE.
I guess this has something to do with gradient stops (?)
How can I do it?
P.S. If it is not possible in IE I don't care. I am fine if gecko and webkit browsers show this properly.
background-color: #eee;
background-image: linear-gradient(top, #fff 0%, #eee 300px); /* W3C */
background-image: -moz-linear-gradient(top, #fff 0%, #eee 300px); /* FF3.6+ */
background-image: -webkit-linear-gradient(top, #fff 0%, #eee 300px); /* Chrome10+,Safari5.1+ */
This is according to the current Mozilla documentation: https://developer.mozilla.org/en/CSS/-moz-linear-gradient.
I've confirmed that it works in Firefox 3.6 and Chrome 15.
Alternative way
background-color: #eee;
background-image: -webkit-gradient(linear, 0 0, 0 100%, from(#fff), to(transparent));
background-image: -webkit-linear-gradient(top, #fff, transparent);
background-image: -moz-linear-gradient(top, #fff, transparent);
background-image: -o-linear-gradient(top, #fff, transparent);
background-image: linear-gradient(to bottom, #fff, transparent);
background-repeat:no-repeat;
background-size:100% 300px;
height: 400px;
background: -webkit-gradient(linear, left top, left bottom, from(#fff), to(#eee), color-stop(0.75, #eee));
You might have to play with 0.75 as it's a percentage of your height, but that should do the trick.
First, it's good to know that you can use more than 2 color-stop on gradients, but you can't use fixed pixels as coordinates, it has to be a percentage.
In your case, you can simply define your first color-stop at 0% and the second one at 50% or so. I suggest you to use a gradient generator because the implementation depends on the browser.
I came up with
background: #FFFFFF; /* old browsers*/
background: -moz-linear-gradient(top, #FFFFFF 0%, #EEEEEE 50%); /* firefox */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#FFFFFF), color-stop(50%,#EEEEEE)); /* webkit */
filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='#FFFFFF', endColorstr='#EEEEEE', GradientType=0); /* ie */
background: -moz-linear-gradient(top, #d7d7d7 0px, #f3f3f3 178px);
background: -webkit-gradient(linear, left top, left bottom, color-stop(0px,#d7d7d7), color-stop(178px,#f3f3f3));
background: -webkit-linear-gradient(top, #d7d7d7 0px,#f3f3f3 178px);
background: -o-linear-gradient(top, #d7d7d7 0px,#f3f3f3 178px);
background: -ms-linear-gradient(top, #d7d7d7 0px,#f3f3f3 178px);
background: linear-gradient(top, #d7d7d7 0px,#f3f3f3 178px);
this works for me
The easiest solution for the problem is to simply use multiple backgrounds and give the gradient part of the background a defined size, either in percentage or in pixels.
body {
background: linear-gradient(to right, green 0%, blue 100%), green;
background-size: 100px 100%, 100%;
background-repeat: no-repeat;
background-position: right;
}
html,
body {
height: 100%;
margin: 0;
}
Mix and match with browser prefixes as necessary.
You could do a:
<div id="bgGen"></div>
then
#bgGen{
height: 400px;
background: -webkit-gradient(linear, left top, left bottom, from(#fff), to(#eee), color-stop(0.75, #eee));
margin-bottom:-400px;
}
It is kinda cheating, but it works...
I had the same thing just now. I wanted to put a gradient on the main content div which varied significantly in height from page to page.
I ended up with this and it works great (and not too much extra code).
CSS:
.main-container {
position: relative;
width: 100%;
}
.gradient-container {
/* gradient code from 0% to 100% -- from colorzilla.com */
height: 115px; /* sets the height of my gradient in pixels */
position: absolute; /* so that it doesn't ruin the flow of content */
width: 100%;
}
.content-container {
position: relative;
width: 100%;
}
HTML:
<div class="main-container">
<div class="gradient-container"></div> <!-- the only thing added for gradient -->
<div class="content-container">
<!-- the rest of my page content goes here -->
</div>
</div>
I highly recommend using colorzilla's gradient-editor to generate the CSS. It makes cross-browser optimizing really easy (especially if you're used to Photoshop or Fireworks).
this worked for me
background: rgb(238, 239, 240) rgb(192, 193, 194) 400px;
background: -webkit-linear-gradient(rgba(192, 193, 194, 1), rgba(238, 239, 240, 1) 400px);
background: -moz-linear-gradient(rgba(192, 193, 194, 1), rgba(238, 239, 240, 1) 400px);
background: linear-gradient(rgba(192, 193, 194, 1), rgba(238, 239, 240, 1) 400px);
background-repeat:repeat-x; background-color:#eeeff0;
Also someone commented why not just make a gradient image and set it as the background. I prefer to go mostly css now too, with mobile design and limited data usage for visitors, try to limit as much images as possible. If it can be done with css than do it