I'm trying to understand how to count mysql row's according to HAVING.
SELECT COUNT(*),
SUM(CASE WHEN sentby='$user_id' AND hiddenbysentby=0 THEN 1 ELSE 0 END) as sentbyuser,
SUM(CASE WHEN sentto='$user_id' AND hiddenbysentto=0 THEN 1 ELSE 0 END) as senttouser
FROM cb_users.user_pm
WHERE title LIKE '%$search%'
HAVING senttouser = 1 OR sentbyuser = 1
I want to count rows that are matching these criteria
SUM(CASE WHEN sentby='$user_id' AND hiddenbysentby=0 THEN 1 ELSE 0 END)
SUM(CASE WHEN sentto='$user_id' AND hiddenbysentto=0 THEN 1 ELSE 0 END)
I have second function that display this data without COUNT(*), and it works fine.
But this query selects all rows no matter if hiddenbysentby = 1 or 0 AND hiddenbysentto = 1 or 0
You should change your HAVING clause to:
HAVING senttouser >= 1 OR sentbyuser >= 1
When you are summing rows, your values are going to equal the total number of rows located for each, therefore, unless you only had exactly one row that meets your criteria, you won't get the result you're looking for.
You should move condition by hiddenbysentby and hiddenbysentto fields in WHERE clause and add a condition by user id
SELECT COUNT(*),
SUM(CASE WHEN sentby='$user_id' THEN 1 ELSE 0 END) as sentbyuser,
SUM(CASE WHEN sentto='$user_id' THEN 1 ELSE 0 END) as senttouser
FROM cb_users.user_pm
WHERE title LIKE '%$search%' AND (hiddenbysentby=0 AND sentby='$user_id') OR (hiddenbysentto=0 AND sentto='$user_id')
HAVING senttouser = 1 OR sentbyuser = 1
Related
Im trying to write a query that returns a count depending on the value of a feedback field that ranges from 0-5 (0 meaning that it was not rated).
I want:
Count of all rows ( anything rated 1 or greater)
Count of all rows rated as 1 (anything = 1)
And all rows rated as 1 and also is the first iteration of a given task (anything rated =1 and iteration = 0)
I have written this query but I am getting the same value for all counts:
select
DATE_FORMAT(created_at,'%M') as Month,
COUNT(CASE WHEN rate > 0 THEN 1 ELSE 0 END) AS total,
COUNT(CASE WHEN rate = 1 THEN 1 ELSE 0 END) AS Rated_1,
COUNT(CASE WHEN client_feedback = 1 AND index = 0 THEN 1 ELSE 0 END) AS first_iteration_rated_1
from tablexxx
where created_at between date('2022-04-01') and date('2022-10-01')
GROUP BY Month
Try to use SUM() instead of COUNT().
Count() will count up regardless of the value being 0 or 1.
you can have two approaches:
method 1: use NULL in else part of the CASE
select
DATE_FORMAT(created_at,'%M') as Month,
COUNT(CASE WHEN rate > 0 THEN 1 ELSE null END) AS total,
COUNT(CASE WHEN rate = 1 THEN 1 ELSE null END) AS Rated_1,
COUNT(CASE WHEN client_feedback = 1 AND index = 0 THEN 1 ELSE null END) AS first_iteration_rated_1
from tablexxx
where created_at between date('2022-04-01') and date('2022-10-01')
GROUP BY Month
method 2: use sum instead of count
select
DATE_FORMAT(created_at,'%M') as Month,
SUM(CASE WHEN rate > 0 THEN 1 ELSE 0 END) AS total,
SUM(CASE WHEN rate = 1 THEN 1 ELSE 0 END) AS Rated_1,
SUM(CASE WHEN client_feedback = 1 AND index = 0 THEN 1 ELSE 0 END) AS first_iteration_rated_1
from tablexxx
where created_at between date('2022-04-01') and date('2022-10-01')
GROUP BY Month
I have a table in my database from which i want to fetch data on the basis of count
my table name is syncbill and columns are Cancelled and Noofprints i am trying to write a query to fetch the count of cancelled and count of noofbills using single query
For cancelled i want to fetch count of cancelled where cancelled<>Y
for Noofprints i want to fetch count of noofprints where noofprints>1
I am using
select count(CANCELLED) as canceledbill,count(NOOFPRINTS) as duplicatebill
from syncbill where CANCELLED<>'Y' and NOOFPRINTS>1`
this query but it is giving me the same no of counts for both
any one out-here please guide me
you can use sum() with case expreseeion
SELECT
sum(CASE WHEN CANCELLED <> 'Y' THEN 1 else 0 END) AS canceledbill,
sum(CASE WHEN NOOFPRINTS > 1 THEN 1 else 0 END) AS duplicatebill
FROM table_name;
Use conditional aggregation:
SELECT
COUNT(CASE WHEN CANCELLED <> 'Y' THEN 1 END) AS cancelledbill,
COUNT(CASE WHEN NOOFPRINTS > 1 THEN 1 END) AS duplicatebill
FROM yourTable;
If you are actually using MySQL, then the above can be simplified to this:
SELECT
SUM(CANCELLED <> 'Y') AS cancelledbill,
SUM(NOOFPRINTS > 1) AS duplicatebill
FROM yourTable;
USE CASE WHEN Expression
select
sum(case when CANCELLED <> 'Y' then 1 else 0 end) AS cancelledbill,
sum(case when NOOFPRINTS > 1 then 1 else 0 end) AS duplicatebill
FROM tablename;
I am new in sql. I want to count something like:
Select count(*) from table where col1= x and col2=x and Col3=x.
I need to count the same value in all different column.
Any help will be appreciated.
You can use conditional aggregation :
Select sum(case when col1='x' then 1 else 0 end) as count_col1,
sum(case when col2='x' then 1 else 0 end) as count_col2,
sum(case when col3='x' then 1 else 0 end) as count_col3
from tab;
If you want to have sum of these count values, consider the above query as an inner and use the following :
Select q.*,
q.count_col1 + q.count_col2 + q.count_col3 whole_sum
from
(
Select sum(case when col1='x' then 1 else 0 end) as count_col1,
sum(case when col2='x' then 1 else 0 end) as count_col2,
sum(case when col3='x' then 1 else 0 end) as count_col3
from tab
) q
Rextester Demo
I have two tables as below
tbl1
id qNum
1 1
2 2
3 3
tbl2
id qNum displayNum
1 1 3
2 2 1
3 2 2
4 2 4
Ideally I need a sql results to look like this
qNum display1 display2 display3 display4
1 0 0 1 0
2 1 1 0 1
3 0 0 0 0
I have tried the following sql but this was not correct
SELECT
tbl1.qNum,
CASE when tbl2.displayNum=1 then 1 else 0 end AS filter1,
CASE when tbl2.displayNum=2 then 1 else 0 end AS filter2,
CASE when tbl2.displayNum=3 then 1 else 0 end AS filter3,
CASE when tbl2.displayNum=4 then 1 else 0 end AS filter4,
CASE when tbl2.displayNum=5 then 1 else 0 end AS filter5
FROM
tbl1
Left Join tbl2 ON tbl1.qNum = tbl2.qNum
GROUP BY
tbl1.qNum
Could anyone help a little please!!
You have use MAX function to pivot the table
Try this:
SELECT tbl1.qNum,
MAX(CASE WHEN tbl2.displayNum=1 THEN 1 ELSE 0 END) AS filter1,
MAX(CASE WHEN tbl2.displayNum=2 THEN 1 ELSE 0 END) AS filter2,
MAX(CASE WHEN tbl2.displayNum=3 THEN 1 ELSE 0 END) AS filter3,
MAX(CASE WHEN tbl2.displayNum=4 THEN 1 ELSE 0 END) AS filter4,
MAX(CASE WHEN tbl2.displayNum=5 THEN 1 ELSE 0 END) AS filter5
FROM tbl1
LEFT JOIN tbl2 ON tbl1.qNum = tbl2.qNum
GROUP BY tbl1.qNum
Your query is almost correct, you're just missing an aggregate function:
SELECT
tbl1.qNum,
MAX(CASE when tbl2.displayNum=1 then 1 else 0 end) AS filter1,
MAX(CASE when tbl2.displayNum=2 then 1 else 0 end) AS filter2,
MAX(CASE when tbl2.displayNum=3 then 1 else 0 end) AS filter3,
MAX(CASE when tbl2.displayNum=4 then 1 else 0 end) AS filter4,
MAX(CASE when tbl2.displayNum=5 then 1 else 0 end) AS filter5
FROM
tbl1
Left Join tbl2 ON tbl1.qNum = tbl2.qNum
GROUP BY
tbl1.qNum
The columns you select should always be either in the group by clause or an aggregate function should be applied to them. A group by "collapses" a group of rows and if you don't have an aggregate function on a column (which is not in the group by) a random row of that group is displayed.
Here you can read about the different aggregate functions: GROUP BY (Aggregate) Functions
The MAX() function in our case here returns the greatest value (note: not the row with the greatest value. You can also have a query like this: select min(col), max(col) from whatever).
I just want to point out that in MySQL, you can simplify the expression. It doesn't need a case statement because booleans are treated as integers with values of 0 and 1:
SELECT tbl1.qNum,
MAX(tbl2.displayNum = 1) AS filter1,
MAX(tbl2.displayNum = 2) AS filter2,
MAX(tbl2.displayNum = 3) AS filter3,
MAX(tbl2.displayNum = 4) AS filter4,
MAX(tbl2.displayNum = 5) AS filter5
FROM tbl1 Left Join
tbl2
ON tbl1.qNum = tbl2.qNum
GROUP BY tbl1.qNum;
Normally, I prefer going with ANSI standard syntax. I do, however, find this easier to read than the case syntax.
Also, you may not need tbl1 for the query, if all values you are interested in are already in tbl2.
I have a table which looks something like the following...
id price condition sell
21039 20.40 new 0
21039 20.41 used 1
12378 10.40 new 1
12378 5 used 0
45898 30.30 new 1
45898 12.20 used 0
(note: there will only ever be 1 new and used value for each id)
What I am trying to do is group all rows with the same id number but in the process creating new columns for each condition, which should look something like...
id new_price new_sell used_price new_sell
21039 20.40 0 20.41 1
12378 10.40 1 5 0
45898 30.30 1 12.20 0
All that I have come up with is the following query, which looks silly
SELECT id, price, condition,
IF(price > 3, 1, 0) AS sell
FROM products
GROUP BY id
How can I get the desired affect of the 2nd table.
This is known as a pivot table. It is done with a series of CASE statements for each column you need to produce, along with an aggregate MAX() or SUM() to eliminate NULLs and collapse it down to a single row.
SELECT
id,
SUM(CASE WHEN `condition` = 'new' THEN price ELSE 0 END) AS new_price,
SUM(CASE WHEN `condition` = 'new' THEN sell ELSE 0 END) AS new_sell,
SUM(CASE WHEN `condition` = 'used' THEN price ELSE 0 END) AS used_price,
SUM(CASE WHEN `condition` = 'used' THEN sell ELSE 0 END) AS used_sell
FROM
products
GROUP BY id
Without the SUM() and GROUP BY, you would still get 2 rows per id, with each having half its columns (not matched by condition in the CASE) as NULL. The SUM() (could also use MAX() in this case) eliminates the NULLs and produces one row since aggregate functions exclude NULL values while the GROUP BY groups the rows by id.
Here is a working sample on SQLFiddle.com
Update after comment:
To calculate sell based on the price, just replace the condition in the sell CASE statements:
SELECT
id,
SUM(CASE WHEN `condition` = 'new' THEN price ELSE 0 END) AS new_price,
SUM(CASE WHEN `condition` = 'new' AND price > 3 THEN 1 ELSE 0 END) AS new_sell,
SUM(CASE WHEN `condition` = 'used' THEN price ELSE 0 END) AS used_price,
SUM(CASE WHEN `condition` = 'used' AND price > 3 THEN 1 ELSE 0 END) AS used_sell
FROM
products
GROUP BY id
(Updated sample...)