SQL Inner Join With Sum - mysql

Question

I´m trying to sum a value with the inner join. There is 4 tables that i´m using the inner join on the another table.
Table 1 = mov_estoque
Table 2 = saidas
Table 3 = produtos
Table 4 = movimento
Table 5 = nf
On table 1, there is a column EMPENHO, data I wanna sum if the column PRODUTO is the same.
My code:
select m.DATA
,n.NOTA
,p.COD_PRODUTO
,p.DESCRICAO1
,p.FATOR_CA
,sum(m.EMPENHO) as Total
from mov_estoque as m
inner join saidas as s on m.origem = s.saida
inner join produtos as p on m.produto = p.produto
inner join movimento as t on m.origem = t.cod_operacao
inner join nf as n on s.saida = n.cod_operacao
where m.DATA>'2018-10-01'
and s.filial='3'
and p.tipo_prod='AC'
and (t.evento='21' or t.evento='35')
and m.tipo_origem ='S'
and s.cancelada='F'
and n.cancelada='F'
group by m.produto
order by m.data
But this code doesn´t work, I need the sum of empenho based on the produto column.
The output that I need:
http://prntscr.com/l9gk94
DATA NOTA COD_PRODUTO DESCRICAO1 EMPENHO FATOR_CA TOTAL
02/10/2018 00:00 164406 900809 SAL DO HIMALAIA FINO (GRANEL 1KG) -1 1 0

Answer 1

We can use an inline view to aggregate, to precompute, a total, and then do a join.
For example, we could write a query like this, to get sum of EMPHENHO grouped by produto.
SELECT sm.produto
, SUM(sm.EMPENHO) AS sum_empenho
FROM mov_estoque sm
WHERE sm.DATA > '2018-10-01'
AND sm.tipo_origem = 'S'
GROUP
BY sm.produto
The specification for the total is unclear in the question. This is likely not the total that is desired. But this does demonstrate how we could get a sum, a single row for each value of produto.
Assuming that the rest of the query returns the detail rows that we want returned, that is, of we leave off the GROUP BY clause and the SUM aggregate:
SELECT m.DATA
, n.NOTA
, p.COD_PRODUTO
, p.DESCRICAO1
, p.FATOR_CA
FROM mov_estoque m
JOIN saidas as s on m.origem = s.saida
JOIN produtos as p on m.produto = p.produto
JOIN movimento as t on m.origem = t.cod_operacao
JOIN nf as n on s.saida = n.cod_operacao
WHERE m.DATA > '2018-10-01'
AND s.filial = '3'
AND p.tipo_prod = 'AC'
AND (t.evento='21' OR t.evento='35')
AND m.tipo_origem = 'S'
AND s.cancelada='F'
AND n.cancelada='F'
ORDER BY m.data
If that gets us the rows we want to return, and we just want to add a "total" column.
Then we could use the first query as a rowsource. Wrap it in parens and reference it the FROM clause as an inline view, with appropriate join conditions, and reference the column with the pre-aggregated total in the SELECT list. Something like this:
SELECT m.DATA
, n.NOTA
, p.COD_PRODUTO
, p.DESCRICAO1
, p.FATOR_CA
, s.sum_empenho AS total
FROM mov_estoque m
JOIN saidas as s on m.origem = s.saida
JOIN produtos as p on m.produto = p.produto
JOIN movimento as t on m.origem = t.cod_operacao
JOIN nf as n on s.saida = n.cod_operacao
JOIN ( SELECT sm.produto
, SUM(sm.EMPENHO) AS sum_empenho
FROM mov_estoque sm
WHERE sm.DATA > '2018-10-01'
AND sm.tipo_origem = 'S'
GROUP
BY sm.produto
) s
ON s.produto = m.produto
WHERE m.DATA > '2018-10-01'
AND s.filial = '3'
AND p.tipo_prod = 'AC'
AND (t.evento='21' OR t.evento='35')
AND m.tipo_origem = 'S'
AND s.cancelada='F'
AND n.cancelada='F'
ORDER BY m.data