I have a comma separated string like
1,2,3,4,5 or
1,2,3,4,5,5,8 or 1,2,2,6,6,7,8
I want anything that is between the third comma and last comma leaving out the last element.
The result of 1,2,3,4,5 should be 4.
The result of 1,2,3,4,5,5,8 should be 4,5,5.
The result of 1,2,2,6,6,7,8 should be 6,6,7.
I tried with the below. But it fails when the 3rd value is same as 1st or 2nd value.
SUBSTRING( LEFT(string, LENGTH(string)
- LOCATE(',', REVERSE(string)))
, LOCATE(SUBSTRING_INDEX(SUBSTRING_INDEX(string, ',', 3), string ))
Hmmmm. To get rid of the last element:
select substr(string, 1, length(string) - substring_index(string, ',', -1) - 1)
Then to get rid of the first three:
select substr(substr(string, 1, length(string) - substring_index(string, ',', -1) - 1),
substring_index(string, ',', 3) + 1
)
Finally this is what I did to resolve. Comments are welcome.
select SUBSTRING(#String,length(SUBSTRING_INDEX(#String,',',3))+2,
(length(#String) - length(SUBSTRING_INDEX(#String,',',-1))-length(SUBSTRING_INDEX(#String,',',3)) -2));
Related
I would need to get value from given regexp.
For example:
> :"postalCode";s:4:"3150";
Is there any way I can extract 3150, from this part of column value. Column value stored serialized objects, so postalCode variable can be null type, that way I should check if positive integer follows ;s:POSITIVE_INT:"postalCodeValue
Use SUBSTRING_INDEX:
SELECT
SUBSTRING(SUBSTRING_INDEX(col, '"', -2), 1,
INSTR(SUBSTRING_INDEX(col, '"', -2), '"') - 1) AS num
FROM yourTable;
This query will extract the last quoted number in your string.
Demo
avoiding regexp you could use some string function eg:
SELECT LENGTH(':"postalCode";s:4:"3150"') - LOCATE(':', REVERSE(':"postalCode";s:4:"3150"'))+1
from dual ;
or
SELECT LENGTH(col_name) - LOCATE(':', REVERSE(col_name))+1
from my_table ;
It also work with 2 times SUBSTRING_INDEX
SELECT
SUBSTRING_INDEX (SUBSTRING_INDEX( ':"postalCode";s:4:"3150";', '"',-2) , '"', 1);
I currently have the following:
if (SUBSTRING(data, 3), FIND_IN_SET ('"', data), REPLACE(data, '"', '')) AS column
But the result is always 0.
I want to use select SUBSTRING(data, 3) and if the substring contains comma then replace it with " ".
How can I do that?
SELECT REPLACE(SUBSTRING(data, 3), ',', ' ') FROM your_table;
I have a query which returns a field with a set of comma separated values. I would like to get the first three of these values into separate columns in the query result.
I can get the first, using SUBSTRING_INDEX but how can I get the other two?
SELECT
'aaaaa, bbbbb, ccccc',
SUBSTRING_INDEX('aaaaa, bbbbb, ccccc', ',', 1) AS column_one
EDIT - Oops, sorry forgot to mention. The value I want to split could have more (or less) than three strings to extract.
For example, the above string could easily be 'aaaaa' or 'aaaaa, bbbbb, ccccc, ddddd, eeeee'.
In each case, I only need the first three (or however many exist).
Any advice appreciated.
Thanks.
You could use SUBSTRING_INDEX twice, the second one with -1 parameter:
SELECT
'aaaaa, bbbbb, ccccc',
SUBSTRING_INDEX('aaaaa, bbbbb, ccccc', ',', 1) AS column_one,
SUBSTRING_INDEX(SUBSTRING_INDEX('aaaaa, bbbbb, ccccc', ',', 2), ',', -1) AS column_two,
SUBSTRING_INDEX(SUBSTRING_INDEX('aaaaa, bbbbb, ccccc', ',', 3), ',', -1) AS column_three
If the parameter is negative, everything to the right of the final delimiter (counting from the right) is returned. Eg.
SUBSTRING_INDEX('aaaaa, bbbbb, ccccc', ',', 2) will return aaaaa, bbbbb
SUBSTRING_INDEX(aaaaa, bbbbb, ',', -1) will then return bbbbb
You also might want to use ', ' as a delimiter, or TRIM the result.
Please see fiddle here.
Edit
If you want to consider strings that might have less than three values, you could use something like this:
SELECT
s,
SUBSTRING_INDEX(s, ',', 1) AS column_one,
CASE WHEN LENGTH(s)-LENGTH(Replace(s, ',', ''))>0
THEN SUBSTRING_INDEX(SUBSTRING_INDEX(s, ',', 2), ',', -1)
ELSE NULL END AS column_two,
CASE WHEN LENGTH(s)-LENGTH(Replace(s, ',', ''))>1
THEN SUBSTRING_INDEX(SUBSTRING_INDEX(s, ',', 3), ',', -1)
ELSE NULL END AS column_three
FROM
strings
Please see fiddle here.
I have a column that has comma separated data:
1,2,3
3,2,1
4,5,6
5,5,5
I'm trying to run a search that would query each value of the CSV string individually.
0<first<5 and 1<second<3 and 2<third<4
I get that I could return all queries and split it myself and compare it myself. I'm curious if there is a way to do this so MySQL does that processing work.
Thanks!
Use
substring_index(`column`,',',1) ==> first value
substring_index(substring_index(`column`,',',-2),',',1)=> second value
substring_index(substring_index(`column`,',',-1),',',1)=> third value
in your where clause.
SELECT * FROM `table`
WHERE
substring_index(`column`,',',1)<0
AND
substring_index(`column`,',',1)>5
It seems to work:
substring_index ( substring_index ( context,',',1 ), ',', -1)
substring_index ( substring_index ( context,',',2 ), ',', -1)
substring_index ( substring_index ( context,',',3 ), ',', -1)
substring_index ( substring_index ( context,',',4 ), ',', -1)
it means 1st value, 2nd, 3rd, etc.
Explanation:
The inner substring_index returns the first n values that are comma separated. So if your original string is "34,7,23,89", substring_index( context,',', 3) returns "34,7,23".
The outer substring_index takes the value returned by the inner substring_index and the -1 allows you to take the last value. So you get "23" from the "34,7,23".
Instead of -1 if you specify -2, you'll get "7,23", because it took the last two values.
Example:
select * from MyTable where substring_index(substring_index(prices,',',1),',',-1)=3382;
Here, prices is the name of a column in MyTable.
Usually substring_index does what you want:
mysql> select substring_index("foo#gmail.com","#",-1);
+-----------------------------------------+
| substring_index("foo#gmail.com","#",-1) |
+-----------------------------------------+
| gmail.com |
+-----------------------------------------+
1 row in set (0.00 sec)
You may get what you want by using the MySQL REGEXP or LIKE.
See the MySQL Docs on Pattern Matching
As an addendum to this, I've strings of the form:
Some words 303
where I'd like to split off the numerical part from the tail of the string.
This seems to point to a possible solution:
http://lists.mysql.com/mysql/222421
The problem however, is that you only get the answer "yes, it matches", and not the start index of the regexp match.
Here is another variant I posted on related question. The REGEX check to see if you are out of bounds is useful, so for a table column you would put it in the where clause.
SET #Array = 'one,two,three,four';
SET #ArrayIndex = 2;
SELECT CASE
WHEN #Array REGEXP CONCAT('((,).*){',#ArrayIndex,'}')
THEN SUBSTRING_INDEX(SUBSTRING_INDEX(#Array,',',#ArrayIndex+1),',',-1)
ELSE NULL
END AS Result;
SUBSTRING_INDEX(string, delim, n) returns the first n
SUBSTRING_INDEX(string, delim, -1) returns the last only
REGEXP '((delim).*){n}' checks if there are n delimiters (i.e. you are in bounds)
Building on #Oleksiy's answer, here is one that can work with strings of variable segment lengths (within reasonable limits), for example comma-separated addresses:
SELECT substring_index ( substring_index ( address,',',1 ), ',', -1) AS address_line_1,
IF(address_parts > 1, substring_index ( substring_index ( address,',',2 ), ',', -1), '') AS address_line_2,
IF(address_parts > 2, substring_index ( substring_index ( address,',',3 ), ',', -1), '') AS address_line_3,
IF(address_parts > 3, substring_index ( substring_index ( address,',',4 ), ',', -1), '') AS address_line_4,
IF(address_parts > 4, substring_index ( substring_index ( address,',',5 ), ',', -1), '') AS address_line_5
FROM (
SELECT address, LENGTH(address) - LENGTH(REPLACE(address, ',', '')) AS address_parts
FROM mytable
) AS addresses
It's working..
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(
SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(col,'1', 1), '2', 1), '3', 1), '4', 1), '5', 1), '6', 1)
, '7', 1), '8', 1), '9', 1), '0', 1) as new_col
FROM table_name group by new_col;
I am trying to extract a certain part of a column that is between delimiters.
e.g. find foo in the following
test 'esf :foo: bar
So in the above I'd want to return foo, but all the regexp functions only return true|false,
is there a way to do this in MySQL
Here ya go, bud:
SELECT
SUBSTR(column,
LOCATE(':',column)+1,
(CHAR_LENGTH(column) - LOCATE(':',REVERSE(column)) - LOCATE(':',column)))
FROM table
Yea, no clue why you're doing this, but this will do the trick.
By performing a LOCATE, we can find the first ':'. To find the last ':', there's no reverse LOCATE, so we have to do it manually by performing a LOCATE(':', REVERSE(column)).
With the index of the first ':', the number of chars from the last ':' to the end of the string, and the CHAR_LENGTH (don't use LENGTH() for this), we can use a little math to discover the length of the string between the two instances of ':'.
This way we can peform a SUBSTR and dynamically pluck out the characters between the two ':'.
Again, it's gross, but to each his own.
This should work if the two delimiters only appear twice in your column. I am doing something similar...
substring_index(substring_index(column,':',-2),':',1)
A combination of LOCATE and MID would probably do the trick.
If the value "test 'esf :foo: bar" was in the field fooField:
MID( fooField, LOCATE('foo', fooField), 3);
I don't know if you have this kind of authority, but if you have to do queries like this it might be time to renormalize your tables, and have these values in a lookup table.
With only one set of delimeters, the following should work:
SUBSTR(
SUBSTR(fooField,LOCATE(':',fooField)+1),
1,
LOCATE(':',SUBSTR(fooField,LOCATE(':',fooField)+1))-1
)
mid(col,
locate('?m=',col) + char_length('?m='),
locate('&o=',col) - locate('?m=',col) - char_length('?m=')
)
A bit compact form by replacing char_length(.) with the number 3
mid(col, locate('?m=',col) + 3, locate('&o=',col) - locate('?m=',col) - 3)
the patterns I have used are '?m=' and '&o'.
select mid(col from locate(':',col) + 1 for
locate(':',col,locate(':',col)+1)-locate(':',col) - 1 )
from table where col rlike ':.*:';
If you know the position you want to extract from as opposed to what the data itself is:
$colNumber = 2; //2nd position
$sql = "REPLACE(SUBSTRING(SUBSTRING_INDEX(fooField, ':', $colNumber),
LENGTH(SUBSTRING_INDEX(fooField,
':',
$colNumber - 1)) + 1)";
This is what I am extracting from (mainly colon ':' as delimiter but some exceptions), as column theline255 in table loaddata255:
23856.409:0023:trace:message:SPY_EnterMessage (0x2003a) L"{#32769}" [0081] WM_NCCREATE sent from self wp=00000000 lp=0023f0b0
This is the MySql code (It quickly did what I want, and is straight forward):
select
time('2000-01-01 00:00:00' + interval substring_index(theline255, '.', 1) second) as hhmmss
, substring_index(substring_index(theline255, ':', 1), '.', -1) as logMilli
, substring_index(substring_index(theline255, ':', 2), ':', -1) as logTid
, substring_index(substring_index(theline255, ':', 3), ':', -1) as logType
, substring_index(substring_index(theline255, ':', 4), ':', -1) as logArea
, substring_index(substring_index(theline255, ' ', 1), ':', -1) as logFunction
, substring(theline255, length(substring_index(theline255, ' ', 1)) + 2) as logText
from loaddata255
and this is the result:
# LogTime, LogTimeMilli, LogTid, LogType, LogArea, LogFunction, LogText
'06:37:36', '409', '0023', 'trace', 'message', 'SPY_EnterMessage', '(0x2003a) L\"{#32769}\" [0081] WM_NCCREATE sent from self wp=00000000 lp=0023f0b0'
This one looks elegant to me. Strip all after n-th separator, rotate string, strip everything after 1. separator, rotate back.
select
reverse(
substring_index(
reverse(substring_index(str,separator,substrindex)),
separator,
1)
);
For example:
select
reverse(
substring_index(
reverse(substring_index('www.mysql.com','.',2)),
'.',
1
)
);
you can use the substring / locate function in 1 command
here is a mice tutorial:
http://infofreund.de/mysql-select-substring-2-different-delimiters/
The command as describes their should look for u:
**SELECT substr(text,Locate(' :', text )+2,Locate(': ', text )-(Locate(' :', text )+2)) FROM testtable**
where text is the textfield which contains "test 'esf :foo: bar"
So foo can be fooooo or fo - the length doesnt matter :).