I am trying to write an SQL query which will select records of a student within 3 tables that have the same column_I'd.
This is what I wrote but the the records selected are not accurate:
select
Nov_DEC_billing.*,
Nov_DEC_students_portfolio.*,
admission_form.academic_year
from
Nov_DEC_billing,
Nov_DEC_student_portfolio,
admission_form
where
Nov_DEC_billing.ID = Nov_DEC_student_portfolio.ID=admission_form.ID
AND
admission_form.Program ='Nov/dec'
I get a records selected alright but its not accurate. Please what's the right way to join 3 tables that share the same column_id.???
Use JOIN in your query
SELECT b.*, p.*, a.academic_year
FROM Nov_DEC_billing b
JOIN Nov_DEC_student_portfolio p ON p.id = b.id
JOIN admission_form a ON a.id = b.id
WHERE a.Program='Nov/dec'
You need to join tables something like this:
SELECT Nov_DEC_billing.*,
Nov_DEC_students_portfolio.*,
admission_form.academic_year
FROM Nov_DEC_billing AS ndb,
LEFT JOIN Nov_DEC_student_portfolio AS ndsp ON ndsp.ID=ndb.ID,
LEFT JOIN admission_form AS af ON af.ID=ndb.ID
WHERE af.Program='Nov/dec'
You should join all the tables to a single one.
What you will is join all the tables to a single one and then select from it.
Since you have 2 tables you should first join 2 and then join another one on the result.
See here left join example for the exact syntax.
Nov_DEC_billing.ID=Nov_DEC_student_portfolio.ID=admission_form.ID
doesn't do what you expect. It takes the first part, Nov_DEC_billing.ID=Nov_DEC_student_portfolio.ID and evaluates it. If the values match, that part becomes a 1, if they don't match, it becomes 0. Then the 0 or the 1 is compared against admission_form.ID. That is very likely to give strange results.
So you'd have to split that into:
Nov_DEC_billing.ID=Nov_DEC_student_portfolio.ID
AND Nov_DEC_student_portfolio.ID=admission_form.ID
Or just use explicit join syntax, as the others already advised (and which I do too). That forces you to split this anyway.
Related
I am studying select queries for MySQL join functions.
I am slightly confused on the below query. I understand the below statement to join attributes from multiple tables with the ON clause, and then filter the results set with the WHERE clause.
Is this correct? What other functionality does this provide? Are there better alternatives?
The tables, attributes, and schema are not relevant to this question, specifically just the ON and WHERE interaction. Thanks in advance for any insight you can provide, appreciated.
SELECT DISTINCT Movies.title
FROM Rentals
INNER JOIN Customers
INNER JOIN Copies
INNER JOIN Movies ON Rentals.customerNum=Customers.customerNum
AND Rentals.barcode=Copies.barcode
AND Copies.movieNum=Movies.movieNum
WHERE Customers.givenName='Chad'
AND Customers.familyName='Black';
INNER JOIN (and the outer joins) are binary operators that should be followed by an ON clause. Your particular syntax works in MySQL, but will not work in any other database (because it is missing two ON clauses).
I would recommend writing the query as:
SELECT DISTINCT m.title
FROM Movies m JOIN
Copies co
ON co.movieNum = m.movieNum JOIN
Rentals r
ON r.barcode = co.barcode JOIN
Customers c
ON c.customerNum = r.customerNum
WHERE c.givenName = 'Chad' AND
c.familyName = 'Black';
You should always put the JOIN conditions in the ON clause, with one ON per JOIN. This also introduces table aliases, which make the query easier to write and to read.
The WHERE clause has additional filtering conditions. These could also be in ON clauses, but I think the query reads better with them in the WHERE clause. You can glance at the query and see: "We are getting something from a bunch of tables for Chad Black".
Ordinary inner JOIN operations only generate result rows for table rows matching their ON condition. They suppress any rows that don't match. That means you can move the contents of ON clauses to your WHERE clause and get the same result set. Still, don't do that; JOINs are easier to understand when they have ON clauses.
If you use LEFT JOIN, a kind of outer join, you get rows from the first table you mention that don't match any rows in the second table according to the ON clause.
SELECT a.name, b.name
FROM a
LEFT JOIN b ON a.a_id = b.a_id
gives you are result set containing all rows of a with NULL values in b.name indicating that the ON condition did not match.
How can I unite two select statement in one table result?
For instance in the first table I want to get everything however on my 2nd table I only want the corel name that is equal to the corel_id and id of my 2nd table?
SELECT *
FROM garage
UNION
SELECT c.name
FROM corel as c
WHERE EXISTS (SELECT 1 FROM garage as g WHERE c.id = g.corel_id
I tried to execute this but this did not work. Is this right? or is there a better way to do this?
Sorry newbie here.
UPDATE EXPECTED RESULT :
https://anotepad.com/notes/b6662w
Give this a try:
SELECT g.*, c.name
FROM garage g
LEFT JOIN corel c
ON c.id = g.corel_id
Matching two tables in a database is called a join. An inner join, the default, returns only the rows that match from both tables.
A left join returns all the rows from the first table whether or not they match the second, and any data from the second table that matches. The right join does the inverse, returning only non-matching data from the second table. There is also the full join that returns all data regardless of match.
A join statement is what you need. A join puts columns from multiple tables into rows together based in the matching conditions in the where clause.
A union requires 2 or more queries to have the same columns. The union puts the sets of rows together into a longer set or rows.
I need to fetch data from 5 tables(all columns of each table) all have FK, which is PK of single table.
But some of the tables may have record may be empty.If data is present on the respective column/table it should return otherwise null/default value
There is one to many and one to one relations on the child tables with parent table.
I have tried so far
- UNION which has concern of same number of columns
- CROSS JOIN not returning any data
- SELECT ALL_COLUMN FROM ALL_TABLE WHERE TABLE.FK=ID Not returning any data
- LEFT JOIN working for 2 tables but not more than that
SELECT A.GENDER, B.BLOCKED_USER FROM t_macroworld_registration AS A
LEFT JOIN t_macroworld_blacklist AS B ON 1=1 WHERE A.ID=15
What are the possible ways I can implement this in a view in MySQL.
Outer join operations are the normative pattern...
SELECT ...
FROM a
LEFT JOIN b ON b.a_id = a.id
LEFT JOIN c ON c.a_id = a.id
LEFT JOIN d ON d.a_id = a.id
WHERE a.id = 15
It's important for the predicates on the outer joined tables to be in the ON clause and not the WHERE clause. If there's any predicate in the WHERE clause requires that a value from one of the outer joined tables be non-NULL, that will negate the "outerness" of the join, making it into an inner join.
The "big rock" problem with this the result when there are more than one matching rows in b, c and d. If there's five rows from b that match, and three rows from c that match, and two rows from b that match, it's going to look like a lot of duplicates. (5x3x2 = 30 rows to be returned, with a lot of duplicated data on those rows.)
Finally I have solved It,
I broke the whole thing into many select query based on FK from each table, so number of additional row returns and mapping has become easy.
Who ever is getting this kind of problem, if it is possible then break it into many select query instead of one.
SELECT
w.id,w.name,a.address,i.name,i.quantity
FROM
warehouse w
LEFT JOIN address AS a ON a.warehouse_id = w.id
LEFT JOIN item AS i ON i.warehouse_id = w.id
LEFT JOIN order AS o ON o.item_id = i.id
WHERE
w.id = 1
GROUP BY 1,2,3,4;
Will give you an overview of your stock and orders for your warehouses. This will also duplicate some results.
Assuming 2 warehouses, 1 address for each, 3 items per warehouse, 2 orders by item = 2 * 3 * 2 = 12 lines
I recommend adding your LEFT JOIN stage by stage and visualizing the result for each stage. You'll quickly understand why lines are multiplying.
Note the usage of foreign keys and ids in the tables to link the tables.
Good luck
I have two tables.
Table A:
root_id, root_text
Table B:
word_id , word_text,root_text
Now Some of the records of Table B has root_texts which might not exist in Table A.
So for that I am trying to use left join.
select *
from A a , B b
where a.root_text=+b.root_text
I only get the records which has matching root_text.
If I use the new way
Select
*
from
A left join B on a.root_text= b.root_text
I get so many extra records. I am Using MySQL 5.6.1.7
UPDATE :
http://sqlfiddle.com/#!9/7b32a/2
Query I am running
select * from word_detail w left join roots r
on r.root_text =w.root
and w.surah_no=1
and w.verse_no=1
and w.word_no=1
What I am doing wrong ?
As in result you see so many records which are not needed. The filter verse_no , word_no not working.
Update
The issue was after the left join we have to use where
select * from word_detail w left join roots r
on r.root_text =w.root
where w.surah_no=1
and w.verse_no=1
and w.word_no=1
If you want all records from TableB that are not present in table A you should use this:
Select *
from
B left join A
on a.root_text= b.root_text
where
a.root_text is null
or if you want the opposite - all records from tableA that are not present on tableB:
Select *
from
A left join B
on a.root_text= b.root_text
where
b.root_text is null
btw, this is not a left join on MySQL:
select * from A a , B b where a.root_text=+b.root_text
but will result as a simple INNER JOIN
The += operator is not standard SQL, but specific to the Oracle RDBMS, so it will not work as expected on MySQL.
The LEFT JOIN syntax is correct, the "many extra records" stem from the data in your tables. You might want to use some sort of WHERE as a filter or an aggregate to group the result set to make it more managable.
Your first example is an inner join which explains why you are not getting as many results as when you are left joining. Left joining can also be thought of as a left outer join.
I have write a search query that will joining two different table. i have putted left join on both. Now first table contains 60records while based on that second table has only 30. Now i wanted if i search query should return all 60records. right now it is returning 30.
query same.
select A.,B. from A left join B on A.Id=B.AId where
A.name=IfNull('tst',A.name) AND B.class=IFNull('c',B.class).
Please guide me, Thanks.
It's wise to remember that JOIN operations (all kinds of JOIN operations, LEFT, RIGHT, INNER, OUTER) have the purpose of creating a new, virtual, table that is assembled from the tables joined together.
What is this JOINed virtual table supposed to have in it? In your case, what is the meaning of your column A.ID, and your column B.AID?
Are there rows in your A table with A.ID column values which occur no times in B.AID?
Are there rows in your B table with B.AID column values which occur no times in A.ID?
If the answer to question 1 is Yes and question 2 is No, then a LEFT JOIN will give you want you want. But simplify your query. Try this.
SELECT A.*, B.*
FROM A
LEFT JOIN B ON A.ID = B.AID
If you happen to want only the rows from A where there is no corresponding row from B, try this.
SELECT A.*
FROM A
LEFT JOIN B ON A.ID = B.AID
WHERE B.AID IS NULL
If the answer to both questions is Yes, then you may want this:
SELECT A.*, B.*
FROM A
OUTER JOIN B ON A.ID = B.AID
But you should think this through very carefully.
Try this Logic i hope it will work for you.....
select A.*,B.* from A left join B on A.Id=B.AId where B.Id != ''