SSRS Expression for hiding the row when a column value = 0 - reporting-services

I'm attempting to hide a row based on a column having the value 0. The Quantity column is a decimal datatype.
I'm trying =IIf(Fields!Quantity.Value = 0 True,False) in row visibility
My error is:
error: [BC30455] Argument not specified for parameter 'TruePart' of 'Public Function IIf(Expression As Boolean, TruePart As Object, FalsePart As Object) As Object'.
class | Quantity | AcctV | ExtVal |
GENERAL | 20 | 49 | 980 |
RETAIL | 0 | 0 | 0 | <-- This should be invisible

You are missing a comma after the zero
=IIf(Fields!Quantity.Value = 0, True,False)
Actually you can simplify the whole thing and just use
=Fields!Quantity.Value = 0
as this will return true or false anyway. No need for IIF

If all row datas are zero you can hide row group visibility expression.
=IIf((Sum(Fields!Data1.Value) = 0) AND (Sum(Fields!Data2.Value) = 0) AND (Sum(Fields!Data3.Value) = 0) AND (Sum(Fields!Data3.Value) = 0) AND (Sum(Fields!Data4.Value) = 0) AND (Sum(Fields!Data5.Value) = 0) AND (Sum(Fields!Data6.Value) = 0), True,False)

Related

Storetext from a table choice correct lines to store for Selenium Ide Ui Vision Kantu

I need to storetext all lines from a table where CODICE CATASTALE have a value
I add an image to show, I need to save all line in variable with storetext with this characteristic CODICE CATASTALE have a value, in the image I add 1 - 2 - 3 - 4 to explain line to store.
This is a relative storetext when CODICE CATASTALE have a value stored the line.
Here the page
nonsolocap.it/cap?k=56040
Image
After the execution such script in Selenium IDE table variable will contain data from the table. xpath_to_all_rows_with_CODICE_CATASTALE should be replaced with corresponding xpath.
store xpath count | xpath = xpath_to_all_rows_with_CODICE_CATASTALE | n
store | 0 | j
while | ${j} < ${n} |
store | | rowElement
store | 0 | i
while | ${i} < 7 |
store text | xpath = xpath_to_all_rows_with_CODICE_CATASTALE[${j}]/td[${i}] | element
execute script | if (${i} != 0) var arr = ${rowElement}; else var arr = []; var element = ${element}; arr.push(element); return arr; | rowElement
execute script | return Number(${i}) + 1; | i
end| |
execute script | if (${j} != 0) var arr = ${table}; else var arr = []; var rowElement = ${rowElement}; arr.push(rowElement); return arr; | table
execute script | return Number(${j}) + 1; | j
end| |
use scvSave command and give a name for the target for divide raws

count different value in column, put into new columns [MySQL]

I've been looking for a tutorial everywhere but I couldn't find any specific solution to this. Does anybody know how to query from this table:
//////////////////
places // type /
//////////////////
alabama // ZX //
alabama // AQ //
africa // AQ //
vietnam // FD //
vietnam // FD //
////////////////
into this
///////////////////////////////////////////////////
places | ZX | AQ | FD
///////////////////////////////////////////////////
alabama| 1 | 2 | 0
africa | 0 | 1 | 0
vietnam| 0 | 0 | 2
///////////////////////////////////////////////////
EDIT: I edited the format, sorry for the error earlier.
Here is a possible solution that works across a variety of database engines.
-- Start: Setup Data
CREATE TABLE things (
places VARCHAR(50),
type VARCHAR(50)
);
INSERT INTO things VALUES ('alabama','ZX');
INSERT INTO things VALUES ('alabama','AQ');
INSERT INTO things VALUES ('africa','AQ');
INSERT INTO things VALUES ('vietnam','FD');
INSERT INTO things VALUES ('vietnam','FD');
-- End: Setup Data
SELECT
things.places,
SUM(
CASE
WHEN things.type = 'ZX' THEN 1
ELSE 0
END
) AS ZX_COUNT,
SUM(
CASE
WHEN things.type = 'AQ' THEN 1
ELSE 0
END
) AS AQ_COUNT,
SUM(
CASE
WHEN things.type = 'FD' THEN 1
ELSE 0
END
) AS FD_COUNT
FROM things
GROUP BY things.places
The drawback to this solution is that you need to know a priori which columns you want to have in your pivot table.
Here is an very well thought out answer to your question.

Two things to do in MySQL IF()

I have a problem concerning the IF() function in MySQL.
I would like to return a string and change the value of a variable. Somwhat like:
IF(#firstRow=1, "Dear" AND #firstRow:=0, "dear")
This outputs only '0' instead of 'Dear'...
I would be very thankful for some input on ways I could solve this problem!
Louis :)
AND is a boolean operator, not a "also do this other thing" operator.
"Dear" AND 0 returns 0 because 0 is treated as false in MySQL and <anything> AND false will return false.
Also because the integer/boolean value of "Dear" is 0 as well. Using a string in a numeric context just reads initial digits in the string, if any, and ignores the rest.
It's not clear what your problem is, but I guess you want to capitalize the word "dear" if the row is the first one in the result set.
Instead of being too clever by half trying to fit the side-effect into your expression, do yourself a favor and break it out into a separate column:
mysql> SELECT IF(#firstRow=1, 'Dear', 'dear'), #firstRow:=0 AS _ignoreThis
-> FROM (SELECT #firstRow:=1) AS _init
-> CROSS JOIN
-> mytable;
+---------------------------------+-------------+
| IF(#firstRow=1, 'Dear', 'dear') | _ignoreThis |
+---------------------------------+-------------+
| Dear | 0 |
| dear | 0 |
| dear | 0 |
+---------------------------------+-------------+
But if you really want to make your code as confusing and unreadable as possible, you can do something like this:
SELECT IF(#firstRow=1, CONCAT('Dear', IF(#firstRow:=0, '', '')), 'dear')
FROM (SELECT #firstRow:=1) AS _init
CROSS JOIN
...
But remember this important metric of code quality: WTFs per minute.
Use a case expression instead of IF() as the syntax is far easier to follow e.g.
select
case when #firstRow = 1 then 'Dear' else 'dear' end AS Salutation
, #firstRow := 0
from (
select 1 n union all
select 2 n union all
select 3
) d
cross join (SELECT #firstRow:=1) var
+---+------------+----------------+
| | Salutation | #firstRow := 0 |
+---+------------+----------------+
| 1 | Dear | 0 |
| 2 | dear | 0 |
| 3 | dear | 0 |
+---+------------+----------------+
Demo

Output 0 if calculations is negative, else do calculations

=MAX(IF
(Table_ExternalData_2[name]=$A$2,Table_ExternalData_2[date_booked])) - MIN(IF(Table_ExternalData_2[name]=$A$2,Table_ExternalData_2[date_booked]))
Sorry if this is such an easy question but I can't figure it out. What I'm trying to do is, if the result is negative, the output will be zero, if not then minus the columns.
| Col1 | Col2 |
| 42 | 233 |
If i minus 42 - 233, I will get -191.
How can I tell mysql that if the result is a negative, output 0 and if not then minus the two columns?
SELECT IF(Col1-Col2 =< 0, 0, Col1-Col2)
Is as simple as this?
You can use CASE WHEN (condition) THEN (true) ELSE (false) END
SELECT CASE WHEN (Col1-Col2) =< 0 THEN 0 ELSE (Col1-Col2) END AS Num1 FROM ....

How do I check to see if a value is an integer in MySQL?

I see that within MySQL there are Cast() and Convert() functions to create integers from values, but is there any way to check to see if a value is an integer? Something like is_int() in PHP is what I am looking for.
I'll assume you want to check a string value. One nice way is the REGEXP operator, matching the string to a regular expression. Simply do
select field from table where field REGEXP '^-?[0-9]+$';
this is reasonably fast. If your field is numeric, just test for
ceil(field) = field
instead.
Match it against a regular expression.
c.f. http://forums.mysql.com/read.php?60,1907,38488#msg-38488 as quoted below:
Re: IsNumeric() clause in MySQL??
Posted by: kevinclark ()
Date: August 08, 2005 01:01PM
I agree. Here is a function I created for MySQL 5:
CREATE FUNCTION IsNumeric (sIn varchar(1024)) RETURNS tinyint
RETURN sIn REGEXP '^(-|\\+){0,1}([0-9]+\\.[0-9]*|[0-9]*\\.[0-9]+|[0-9]+)$';
This allows for an optional plus/minus sign at the beginning, one optional decimal point, and the rest numeric digits.
Suppose we have column with alphanumeric field having entries like
a41q
1458
xwe8
1475
asde
9582
.
.
.
.
.
qe84
and you want highest numeric value from this db column (in this case it is 9582) then this query will help you
SELECT Max(column_name) from table_name where column_name REGEXP '^[0-9]+$'
Here is the simple solution for it
assuming the data type is varchar
select * from calender where year > 0
It will return true if the year is numeric else false
This also works:
CAST( coulmn_value AS UNSIGNED ) // will return 0 if not numeric string.
for example
SELECT CAST('a123' AS UNSIGNED) // returns 0
SELECT CAST('123' AS UNSIGNED) // returns 123 i.e. > 0
To check if a value is Int in Mysql, we can use the following query.
This query will give the rows with Int values
SELECT col1 FROM table WHERE concat('',col * 1) = col;
The best i could think of a variable is a int Is a combination with MySQL's functions CAST() and LENGTH().
This method will work on strings, integers, doubles/floats datatypes.
SELECT (LENGTH(CAST(<data> AS UNSIGNED))) = (LENGTH(<data>)) AS is_int
see demo http://sqlfiddle.com/#!9/ff40cd/44
it will fail if the column has a single character value. if column has
a value 'A' then Cast('A' as UNSIGNED) will evaluate to 0 and
LENGTH(0) will be 1. so LENGTH(Cast('A' as UNSIGNED))=LENGTH(0) will
evaluate to 1=1 => 1
True Waqas Malik totally fogotten to test that case. the patch is.
SELECT <data>, (LENGTH(CAST(<data> AS UNSIGNED))) = CASE WHEN CAST(<data> AS UNSIGNED) = 0 THEN CAST(<data> AS UNSIGNED) ELSE (LENGTH(<data>)) END AS is_int;
Results
**Query #1**
SELECT 1, (LENGTH(CAST(1 AS UNSIGNED))) = CASE WHEN CAST(1 AS UNSIGNED) = 0 THEN CAST(1 AS UNSIGNED) ELSE (LENGTH(1)) END AS is_int;
| 1 | is_int |
| --- | ------ |
| 1 | 1 |
---
**Query #2**
SELECT 1.1, (LENGTH(CAST(1 AS UNSIGNED))) = CASE WHEN CAST(1.1 AS UNSIGNED) = 0 THEN CAST(1.1 AS UNSIGNED) ELSE (LENGTH(1.1)) END AS is_int;
| 1.1 | is_int |
| --- | ------ |
| 1.1 | 0 |
---
**Query #3**
SELECT "1", (LENGTH(CAST("1" AS UNSIGNED))) = CASE WHEN CAST("1" AS UNSIGNED) = 0 THEN CAST("1" AS UNSIGNED) ELSE (LENGTH("1")) END AS is_int;
| 1 | is_int |
| --- | ------ |
| 1 | 1 |
---
**Query #4**
SELECT "1.1", (LENGTH(CAST("1.1" AS UNSIGNED))) = CASE WHEN CAST("1.1" AS UNSIGNED) = 0 THEN CAST("1.1" AS UNSIGNED) ELSE (LENGTH("1.1")) END AS is_int;
| 1.1 | is_int |
| --- | ------ |
| 1.1 | 0 |
---
**Query #5**
SELECT "1a", (LENGTH(CAST("1.1" AS UNSIGNED))) = CASE WHEN CAST("1a" AS UNSIGNED) = 0 THEN CAST("1a" AS UNSIGNED) ELSE (LENGTH("1a")) END AS is_int;
| 1a | is_int |
| --- | ------ |
| 1a | 0 |
---
**Query #6**
SELECT "1.1a", (LENGTH(CAST("1.1a" AS UNSIGNED))) = CASE WHEN CAST("1.1a" AS UNSIGNED) = 0 THEN CAST("1.1a" AS UNSIGNED) ELSE (LENGTH("1.1a")) END AS is_int;
| 1.1a | is_int |
| ---- | ------ |
| 1.1a | 0 |
---
**Query #7**
SELECT "a1", (LENGTH(CAST("1.1a" AS UNSIGNED))) = CASE WHEN CAST("a1" AS UNSIGNED) = 0 THEN CAST("a1" AS UNSIGNED) ELSE (LENGTH("a1")) END AS is_int;
| a1 | is_int |
| --- | ------ |
| a1 | 0 |
---
**Query #8**
SELECT "a1.1", (LENGTH(CAST("a1.1" AS UNSIGNED))) = CASE WHEN CAST("a1.1" AS UNSIGNED) = 0 THEN CAST("a1.1" AS UNSIGNED) ELSE (LENGTH("a1.1")) END AS is_int;
| a1.1 | is_int |
| ---- | ------ |
| a1.1 | 0 |
---
**Query #9**
SELECT "a", (LENGTH(CAST("a" AS UNSIGNED))) = CASE WHEN CAST("a" AS UNSIGNED) = 0 THEN CAST("a" AS UNSIGNED) ELSE (LENGTH("a")) END AS is_int;
| a | is_int |
| --- | ------ |
| a | 0 |
see demo
What about:
WHERE table.field = "0" or CAST(table.field as SIGNED) != 0
to test for numeric and the corrolary:
WHERE table.field != "0" and CAST(table.field as SIGNED) = 0
I have tried using the regular expressions listed above, but they do not work for the following:
SELECT '12 INCHES' REGEXP '^(-|\\+){0,1}([0-9]+\\.[0-9]*|[0-9]*\\.[0-9]+|[0-9]+)$' FROM ...
The above will return 1 (TRUE), meaning the test of the string '12 INCHES' against the regular expression above, returns TRUE. It looks like a number based on the regular expression used above. In this case, because the 12 is at the beginning of the string, the regular expression interprets it as a number.
The following will return the right value (i.e. 0) because the string starts with characters instead of digits
SELECT 'TOP 10' REGEXP '^(-|\\+){0,1}([0-9]+\\.[0-9]*|[0-9]*\\.[0-9]+|[0-9]+)$' FROM ...
The above will return 0 (FALSE) because the beginning of the string is text and not numeric.
However, if you are dealing with strings that have a mix of numbers and letters that begin with a number, you will not get the results you want. REGEXP will interpret the string as a valid number when in fact it is not.
This works well for VARCHAR where it begins with a number or not..
WHERE concat('',fieldname * 1) != fieldname
may have restrictions when you get to the larger NNNNE+- numbers
for me the only thing that works is:
CREATE FUNCTION IsNumeric (SIN VARCHAR(1024)) RETURNS TINYINT
RETURN SIN REGEXP '^(-|\\+){0,1}([0-9]+\\.[0-9]*|[0-9]*\\.[0-9]+|[0-9]+)$';
from kevinclark all other return useless stuff for me in case of 234jk456 or 12 inches