Hi guys i have a problem displaying a data from my query code.
I want to display a data from the closest date today. Below is my sample data and my output data that i want to display.
Landing Area data
|landing_id| id_number| address |
---------------------------------
| 1 | 00012345 | Ozamiz |
| 2 | 00012346 | Tudela |
| 3 | 00012347 | Nailon |
| 4 | 00012348 | Taboo |
| 5 | 00012349 | Jimenez |
| 6 | 00012350 | Tangub |
---------------------------------
Percentage data
|percent_id| landing_id | percentage | date_added |
-----------------------------------------------------------
| 1 | 1 | 9 |2018-10-08 21:42:22 |
| 2 | 1 | 12 |2018-10-03 20:43:32 |
| 3 | 1 | 43 |2018-10-15 19:43:49 |
| 4 | 3 | 22 |2018-10-10 15:43:56 |
| 5 | 3 | 77 |2018-10-12 18:44:03 |
-----------------------------------------------------------
And this is my query code.
SELECT fish_landing.landing_id,
percentage.landing_id as percentage_landing_id,
percentage.percentage,
percentage.date_added
FROM percentage
RIGHT OUTER JOIN fish_landing ON percentage.landing_id = fish_landing.landing_id
ORDER BY fish_landing.landing_id ASC
The output of my code is this, where the date_added and the percentage is not exact.
|percent_id| percentage | date_added |
----------------------------------------------
| 1 | 9 |2018-10-08 21:42:22 |
| 2 | | |
| 3 | 22 |2018-10-10 15:43:56 |
| 4 | | |
| 5 | | |
| 6 | | |
----------------------------------------------
And the output data that I want to display is the table below, where the percentage that has a latest date_added in every landing_id will be display.
|landing_id| percentage | date_added | address |
--------------------------------------------------------
| 1 | 43 |2018-10-15 19:43:49 | Ozamiz |
| 2 | | | |
| 3 | 77 |2018-10-12 18:44:03 | Nailon |
| 4 | | | |
| 5 | | | |
| 6 | | | |
--------------------------------------------------------
I hope you can help me in my problem.
You can get maximum date_added for a landing_id in a separate derived table and use it for joining.
Try the following:
SELECT fish_landing.landing_id,
percentage.percentage,
percentage.date_added,
fish_landing.address
FROM fish_landing
LEFT JOIN percentage ON percentage.landing_id = fish_landing.landing_id
LEFT JOIN (SELECT landing_id, MAX(date_added) AS max_date_added
FROM percentage
GROUP BY landing_id) AS dt
ON dt.landing_id = percentage.landing_id AND
dt.max_date_added = percentage.date_added
ORDER BY fish_landing.landing_id ASC
Related
i have table with data like this below
| id | wallet_id | wallet_name | deposit | |
|----|-----------|-------------|---------|---|
| 1 | 12 | a_wallet | 10 | |
| 2 | 14 | c_wallet | 12 | |
| 3 | 12 | a_wallet | 24 | |
| 4 | 15 | e_wallet | 50 | |
| 5 | 14 | c_wallet | 10 | |
| 6 | 15 | e_wallet | 22 | |
i want to select and group with same wallet_id, probably something like this
| wallet_id | id | wallet_name |
|-----------|----|-------------|
| 12 | 1 | a_wallet |
| | 3 | a_wallet |
| 14 | 2 | c_wallet |
| | 5 | c_wallet |
| 15 | 4 | e_wallet |
| | 6 | e_wallet |
i already try
select wallet_id, id, wallet_name from wallet group by wallet_id
but it shows like usual select query with no grouping.
Kindly need your help, thanks
We would generally handle your requirement from the presentation layer (e.g. PHP), but if you happen to be using MySQL 8+, here is a way to do this directly from MySQL:
SELECT
CASE WHEN ROW_NUMBER() OVER (PARTITION BY wallet_id ORDER BY id) = 1
THEN wallet_id END AS wallet_id,
id,
wallet_name
FROM wallet w
ORDER BY w.wallet_id, id;
I want to ranking result with city based in mysql
table1:-users
| user_id | marks |
--------------------
| 1 | 10 |
| 5 | 10 |
| 5 | 50 |
| 3 | 15 |
| 4 | 10 |
| 2 | 10 |
| 6 | 10 |
| 6 | 50 |
| 4 | 15 |
| 4 | 10 |
table:-2 users details
| user_id | city |
--------------------
| 1 | newdelhi |
| 2 | kolkata |
| 3 | mumbai |
| 4 | newdelhi |
| 5
| 6 | newdelhi |
I want to result like this:
| user_id | points |
--------------------
| 6 | 60 |
| 4 | 35 |
| 1 | 10 |
Try this :
SELECT
users.user_id
,SUM(users.marks) AS points
FROM
users
INNER JOIN
users_details ON users.user_id = users_details.user_id
WHERE
users_details.city = 'newdelhi'
GROUP BY
user_id
How to get count of combinations from database?
I have to database tables and want to get the count of combinations. Does anybody know how to put this in a database query, therefore I haven't a db request for each trip?
Trips
| ID | Driver | Date |
|----|--------|------------|
| 1 | A | 2015-12-15 |
| 2 | A | 2015-12-16 |
| 3 | B | 2015-12-17 |
| 4 | A | 2015-12-18 |
| 5 | A | 2015-12-19 |
Passengers
| ID | PassengerID | TripID |
|----|-------------|--------|
| 1 | B | 1 |
| 2 | C | 1 |
| 3 | D | 1 |
| 4 | B | 2 |
| 5 | D | 2 |
| 6 | A | 3 |
| 7 | B | 4 |
| 8 | D | 4 |
| 9 | B | 5 |
| 10 | C | 5 |
Expected result
| Driver | B-C-D | B-D | A | B-C |
|--------|-------|-----|---|-----|
| A | 1 | 2 | - | 1 |
| B | - | - | 1 | - |
Alternative
| Driver | Passengers | Count |
|--------|------------|-------|
| A | B-C-D | 1 |
| A | B-D | 2 |
| A | B-C | 1 |
| B | A | 1 |
Has anybody an idea?
Thanks a lot!
Try this:
SELECT Driver, Passengers, COUNT(*) AS `Count`
FROM (
SELECT t.ID, t.Driver,
GROUP_CONCAT(p.PassengerID
ORDER BY p.PassengerID
SEPARATOR '-') AS Passengers
FROM Trips AS t
INNER JOIN Passengers AS p ON t.ID = p.TripID
GROUP BY t.ID, t.Driver) AS t
GROUP BY Driver, Passengers
The above query will produce the alternative result set. The other result set can only be achieved using dynamic sql.
Demo here
I have the following query which is pulling through some orders in a database:
SELECT company, amount, total FROM cscart_order_details
INNER JOIN cscart_orders
ON cscart_order_details.order_id = cscart_orders.order_id
WHERE
date(FROM_UNIXTIME(`timestamp`)) >= ADDDATE(DATE(NOW()), INTERVAL -6 DAY)
This produces the following information:
|company | | amount | | total |
================================
| NTE001 | | 1 | | 51.06 |
| NTE001 | | 1 | | 126.76 |
| NTE001 | | 1 | | 126.76 |
| EUR004 | | 1 | | 832.13 |
| EUR004 | | 1 | | 832.13 |
| EUR004 | | 1 | | 832.13 |
| EUR004 | | 1 | | 231.37 |
| EUR004 | | 1 | | 231.37 |
| EUR004 | | 2 | | 263.92 |
| EUR004 | | 1 | | 131.96 |
| B&T001 | | 1 | | 929.83 |
| B&T001 | | 1 | | 929.83 |
How do I go about combine lines? For example I would like to put all lines for the same companies together like this example:
| NTE001 | | 3 | | 304.58 |
| EUR004 | | 7 | | 3223.05 |
| B&T001 | | 2 | | 1859.66 |
EDIT: If you are down voting please let me know how I can improve this question!
so you want something like:
SELECT company,
count(amount) amount,
sum (total) total
FROM cscart_order_details
INNER JOIN cscart_orders
ON cscart_order_details.order_id = cscart_orders.order_id
WHERE date(FROM_UNIXTIME(`timestamp`)) >= ADDDATE(DATE(NOW()), INTERVAL -6 DAY)
GROUP BY company
I have a table that has some values in it, along with the time that value was taken against an associated ID from another table.
I am looking to retrieve the latest value for every item in that table, and then order by those latest values.
Here is an SQL fiddle, http://www.sqlfiddle.com/#!2/0be99
And here is text output.
'hist' table
| HIST_ID | HIST_ITEM_ID | HIST_VALUE | HIST_TIME |
|---------|--------------|------------|------------|
| 1 | 1 | 1 | 1420291000 |
| 2 | 1 | 2 | 1420292000 |
| 3 | 1 | 3 | 1420293000 |
| 4 | 1 | 5 | 1420294000 |
| 5 | 1 | 10 | 1420295000 |
| 6 | 1 | 50 | 1420296000 |
| 7 | 1 | 60 | 1420297000 |
| 8 | 1 | 77 | 1420298000 |
| 9 | 1 | 90 | 1420299000 |
| 10 | 1 | 101 | 1420300000 |
| 11 | 2 | 1 | 1420291000 |
| 12 | 2 | 3 | 1420292000 |
| 13 | 2 | 7 | 1420293000 |
| 14 | 2 | 9 | 1420294000 |
| 15 | 2 | 15 | 1420295000 |
| 16 | 2 | 21 | 1420296000 |
| 17 | 2 | 33 | 1420297000 |
| 18 | 2 | 35 | 1420298000 |
| 19 | 2 | 55 | 1420299000 |
| 20 | 2 | 91 | 1420300000 |
'items' table
| ITEM_ID | ITEM_TITLE |
|---------|------------|
| 1 | ABCD |
| 2 | XYZ123 |
So, I can do something like...
select * from hist
inner join items on hist_item_id = item_id
group by hist_item_id
order by hist_value desc
However this returns me a grouping that I cannot order. How can I order this grouping? I had a look at other similar questions on here but was unable to apply their solutions successfully to my query to produce the desire result.
The desired result here would be to return.
HIST_ITEM_ID | ITEM_TITLE | HIST_VALUE |
|------------|------------|------------|
| 1 | ABCD | 101 |
| 2 | XYZ123 | 91 |
You can use a join to get the most recent history item. Then you can join back to the history table and the item table to get additional information:
select h.*, i.item_title
from (select hist_item_id, max(hist_id) as max_hist_id
from hist
group by hist_item_id
) hh join
hist h
on h.hist_id = hh.max_hist_id join
items i
on i.item_id = hh.hist_item_id;
Here is a SQL Fiddle.
You should use MAX function and group by the item id. That would look like this:
SELECT i.item_id, i.item_title, MAX(h.hist_value)
FROM items AS i
INNER JOIN hist AS h
ON i.item_id = h.hist_item_id
GROUP BY i.item_id