I am trying to send email in laravel for which I am using the mail::send function.
This is my code:
$data = [
'title'=>'Some Title',
'content'=>'Content',
'email'=> 'email',
'password'=>'password',
'remarks'=>'remarks'
];
Mail::send('admin.mails.activate', $data, ['user'=>$user], function ($message) use ($user) {
$message->to($user->email, $user->name)->subject('Account Activation Email')->from('support#webmail.com');
});
I am trying to pass the $data variable to the view file and $user variable to the callback function so that I could use user's email to send an email. But it is giving me this error:
call_user_func() expects parameter 1 to be a valid callback, array must have exactly two members
Mail::send() accepts 3 arguments (view, data, callback) but you've given it 4:
Mail::send('admin.mails.activate', $data, ['user'=>$user], function ($message) use ($user) {
$message->to($user->email, $user->name)->subject('Account Activation Email')->from('support#webmail.com');
});
I assume you meant to merge the ['user' => $user] array in with $data:
Mail::send('admin.mails.activate', array_merge($data, ['user' => $user]), function ($message) use ($user) {
$message->to($user->email, $user->name)->subject('Account Activation Email')->from('support#webmail.com');
});
or alternatively:
$data = [
'title'=>'Some Title',
'content'=>'Content',
'email'=> 'email',
'password'=>'password',
'remarks'=>'remarks',
'user' => $user
];
Mail::send('admin.mails.activate', $data, function ($message) use ($user) {
$message->to($user->email, $user->name)->subject('Account Activation Email')->from('support#webmail.com');
});
this is the problem
$message->to($user->email, $user->name)
change it to
$message->to($user->email)
Related
I'm using Laravel 8 validation, and what i'm trying to do is to validate a form with some input name, unique to table Sizes column "name" where it also depends on another column speciesId that the value from $request->speciesId.
The function in Controller is looks like this
public function storeSize(Request $request)
{
$validated = $request->validate(
[
'name' => [
'required', Rule::unique('sizes')->where(function ($query) {
return $query->where('speciesId', $request->speciesId);
})
],
'speciesId' => 'required'
]
);
}
already add use Illuminate\Http\Request; and use Illuminate\Validation\Rule; but still got "ErrorException Undefined variable: request".
when i'm try to var_dump($request) or echo $request->speciesID, the variable and value is present.
my question is, why the validation function doesn't recognize the Request variable?
The error occurs because inside your function call $request is not available. You need to make it available by adding use $request to function ($query):
$validated = $request->validate([
'name' => [
'required', Rule::unique('sizes')->where(function ($query) use ($request) {
return $query->where('speciesId', $request->speciesId);
})
],
'speciesId' => 'required'
]);
Quick question.
Would it be possible to changes the JSON validation response of laravel?
This is for a custom API that I am building in Laravel.
Validation process
$validation = $this->validate(
$request, [
'user_id' => 'required',
]);
The response shows up like this in json
{
"message": "The given data was invalid.",
"errors": {
"user_id": [
"The user id field is required."
],
}
}
Preferable it would become something like this.
{
"common:" [
"status": "invalid",
"message": "Param xxxx is required",
],
}
What would be the best way to changes this?
Is it even possible?
Thank you.
You can do this, and it will be reflected globally.
Navigate to below folder and use Controller.php
app/Http/Controllers
use Illuminate\Http\Request;
Write below method in Controller.php and change response as you want.
public function validate(
Request $request,
array $rules,
array $messages = [],
array $customAttributes = [])
{
$validator = $this->getValidationFactory()
->make(
$request->all(),
$rules, $messages,
$customAttributes
);
if ($validator->fails()) {
$errors = (new \Illuminate\Validation\ValidationException($validator))->errors();
throw new \Illuminate\Http\Exceptions\HttpResponseException(response()->json(
[
'status' => false,
'message' => "Some fields are missing!",
'error_code' => 1,
'errors' => $errors
], \Illuminate\Http\JsonResponse::HTTP_UNPROCESSABLE_ENTITY));
}
}
I have tried it with Laravel 5.6, maybe this is useful for you.
#Dev Ramesh solution is still perfectly valid for placing inline within your controller.
For those of you looking to abstract this logic out into a FormRequest, FormRequest has a handy override method called failedValidation. When this is hit, you can throw your own response exception, like so...
/**
* When we fail validation, override our default error.
*
* #param ValidatorContract $validator
*/
protected function failedValidation(\Illuminate\Contracts\Validation\Validator $validator)
{
$errors = $this->validator->errors();
throw new \Illuminate\Http\Exceptions\HttpResponseException(
response()->json([
'errors' => $errors,
'message' => 'The given data was invalid.',
'testing' => 'Whatever custom data you want here...',
], 422)
);
}
I was searching for an answer to this and I think I found a better way. There is an exception handler in a default Laravel app - \App\Exceptions\Handler - and you can override the invalidJson method:
<?php
namespace App\Exceptions;
use Illuminate\Foundation\Exceptions\Handler as ExceptionHandler;
use Illuminate\Validation\ValidationException;
class Handler extends ExceptionHandler
{
// ...
protected function invalidJson($request, ValidationException $exception)
{
$errors = [];
foreach ($exception->errors() as $field => $messages) {
foreach ($messages as $message) {
$errors[] = [
'code' => $field,
'message' => $message,
];
}
}
return response()->json([
'error' => $errors,
], $exception->status);
}
}
I'm new in larevel. I want to create route in api.php. It's my code in this file
Route::middleware('auth:api')->get('/api', function (Request $request) {
return response()->json([
'name' => 'Abigail',
'state' => 'CA'
]);
});
I need to return json but when I put url mysite.com/api/api and page redirect me to mysite.com/user. How I can avoid redirect I get correct url?
Remove auth middleware and try again like:
Route::middleware('api')->get('/api', function (Request $request) {
return response()->json([
'name' => 'Abigail',
'state' => 'CA'
]);
});
You're getting redirected because you're using the auth middleware and are not authenticated. If the route does not need authentication just do:
Route::get('/api', function (Request $request) {
return response()->json([
'name' => 'Abigail',
'state' => 'CA'
]);
});
Here is a another example to parse direct model.
Laravel 5.2
Route::middleware('api')->get('/api/users', function (Request $request) {
return \App\Users::all();
});
You will get a json object for all users table data.
I have a route group that looks like this:
Route::group(['prefix' => 'recipe','middleware'=>['auth.basic']], function (){
//Some things to do
});
When credentials are invalid Laravel outputs "Invalid credentials." How do I override this response with my own JSON response?
In AuthController, try this :
public function postLogin(Request $request)
{
$this->validate($request, [
'email' => 'required', 'password' => 'required',
]);
$credentials = [
'email' => $request->input('email'),
'password' => $request->input('password')
];
if (Auth::attempt($credentials, $request->has('remember')))
{
return redirect()->intended($this->redirectPath())
->with('success', 'You are successfully logged in');
}
return Response::json(array(
'success' => false,
'errors' => $this->getFailedLoginMessage(),
));
}
I just had a look at the Illuminate\Auth\SessionGuard. The method getBasicResponse() seems to be responsible for the response on a failed login attempt (with basic auth).
protected function getBasicResponse()
{
$headers = ['WWW-Authenticate' => 'Basic'];
return new Response('Invalid credentials.', 401, $headers);
}
How to actually overwrite it seems a little tricky though. You probably need to extend the SessionGuard Class and implement your own getBasicResponse() method. Thats the easy part, how to actually instantiate your own guard instead of the default one, I don't know yet.
I'm having an issue validation whether a submitted Email Address is Unique in the database.
When the User registers I need to validate whether the email address exists all of the other validation is working fine.
Is there a step missing when you are validating a using an Ajax form in Yii 2.
A User clicks on CTA to register on site/index
use yii\bootstrap\Modal;
use frontend\models\Register;
use yii\helpers\Html;
use yii\helpers\Url;
...
Modal::begin([
'id' => 'modal',
'size'=>'modal-lg',
'clientOptions' => ['backdrop' => 'static', 'keyboard' => FALSE],
]);
echo "<div id='modalContent'></div>";
Modal::end();
?>
<?= Html::button('Register', ['value' => Url::to(['register/create']), 'title' => 'Register', 'class' => 'btn btn-success','id'=>'modalButton']); ?>
This opens up a modal (register/create)
Model Register
class Register extends User
{
...
public function rules()
{
return [
['Email', 'filter', 'filter' => 'trim'],
['Email', 'required'],
['Email', 'email'],
['Email', 'unique', 'targetClass' => '\common\models\User', 'message' => 'This email address has already been taken.'],
];
}
public function signup()
{
$user = new User();
if ($this->validate()) {
$user->Email = $this->Email;
if ($user->save()) {
return $user;
}
} else {
return;
}
}
Register Controller
public function actionCreate()
{
$model = new Register(['scenario' => 'signup']);
if (Yii::$app->request->isAjax && $model->load(Yii::$app->request->post())) {
Yii::$app->response->format = Response::FORMAT_JSON;
Yii::error($model);
return $model->validate();
}
if ($model->load(Yii::$app->request->post())) {
if ($user = $model->signup()) {
if (Yii::$app->getUser()->login($user)) {
return $this->goHome();
}
}
}
return $this->renderAjax('create', [
'model' => $model,
]);
}
The View file
<?php $form = ActiveForm::begin(['id'=> 'register', 'enableClientValidation'=>true, 'enableAjaxValidation'=>true, 'validateOnChange'=> true, 'validationUrl' => Url::to(['register/create'])] ); ?>
<div class="form-group">
<?= $form->field($model, 'Email') ?>
</div>
Javascript file
$script = <<< JS
$('body').on('beforeSubmit', 'form#register', function (event, jqXHR, settings) {
var form = $(this);
// return false if form still have some validation errors
if (form.find('.has-error').length) {
return false;
}
// submit form
$.ajax({
url: form.attr('action'),
type: 'GET',
data: form.serialize(),
success: function (response) {
// do something with response
$(document).find('#modal').modal('hide');
}
});
return false;
});
JS;
$this->registerJs($script);
I was facing a similar issue where my email field was not triggering the "unique" rule in the javascript validation, but the "unique" rule was getting triggered on the form submit.
It's awesome that you came up with a solution for your question that gets the job done, but I think what I just learned could also shed some insight on this question for others.
The key for me was learning/realizing that the "unique" validation rule must use a database lookup to verify if the user input is unique, thus it must use ajax. Other validation rules, such as "required" or "email" don't need ajax to validate. They just use javascript in the client to validate, so they are client validation, whereas the "unique" validator is actually ajax validation.
Note: my code below is not really addressing your code directly, but is intended to communicate the overall understanding and code structure that is needed to answer your question. Some of these steps you already have, but some are missing :)
First, you need a model with a field that requires a 'unique' rule, such as an email address for a user account.
In your Model
public function rules()
{
$rules = [
[['email'], 'unique'],
// ... and all your other rules ...
];
}
When using \yii\widgets\ActiveForm, client validation is enabled by default, but ajax validation is not.
So, next you need to directly turn on ajax validation in the view. This can be done either for the entire form, or just for a single field. The Yii2 Validation docs explain this best, but in my case, I chose to just enable ajax validation on my email field.
In your View
<?php $form = ActiveForm::begin(); ?>
<?= $form->field($user, 'email', ['enableAjaxValidation' => true])->textInput();
//... other form fields and such here ...
<?php ActiveForm::end(); ?>
Next, you also need to handle the ajax validation in your controller, so your controller method could look something like this:
public function actionRegister()
{
$user = new User();
$post = Yii::$app->request->post();
$userLoaded = $user->load($post);
// validate for ajax request
if (Yii::$app->request->isAjax) {
Yii::$app->response->format = Response::FORMAT_JSON;
return ActiveForm::validate($user);
}
// vaidate for normal request
if ($userLoaded && $user->validate()) {
$user->save();
return $this->redirect(['view', 'id' => $user->id]);
}
// render
return $this->render('create', ['user' => $user]);
}
And then here's the catch ... everything above is what you would need when working with a normal (non-ajax) form. In your question, you are working on a form in a modal window that is being submit via ajax, so the above controller method will not work. With ajax forms, it becomes pretty tricky to handle the ajax form validation and the ajax form submit in the same controller method.
As usual, Yii has this all figured out for us, and the validationUrl form parameter will save the day. All you have to do is create a new method in your controller that is specifically for ajax validation, and reference the controller/action URL in your form. Something like this should do the trick:
In your View
<?php $form = ActiveForm::begin([
'id' => 'form-id', // always good to set a form id, especially when working with ajax/pjax forms
'validationUrl' => ['user/validate-email'], //['controller/action'],
]); ?>
In your Controller
public function actionRegister()
{
$user = new User();
$post = Yii::$app->request->post();
// vaidate for normal request
if ($user->load($post) && $user->validate()) {
$user->save();
return $this->redirect(['view', 'id' => $user->id]);
}
// render
return $this->render('create', ['user' => $user]);
}
public function actionValidateEmail()
{
// validate for ajax request
if (Yii::$app->request->isAjax) {
Yii::$app->response->format = Response::FORMAT_JSON;
$user = new User();
$post = Yii::$app->request->post();
$user->load($post);
return ActiveForm::validate($user);
}
}
Cheers!
I managed to solve this myself by using Javascript to make an Ajax request and PHP to receive the quest and check whether the Email already exists in the database.
function checkEmail(){
var email_check;
// Get the value of the email input field
var input_value = document.getElementById('register-email').value;
// Send the value to a PHP page to check
$.ajax({
url: 'checkemail.php/',
type: 'POST',
data: {
email_check: input_value
},
success: function(response) {
// If we have a repsonse we need to check whether it is True or False
email_check = response;
if (email_check == 1) {
// If True add error class
$('.field-register-email').addClass('has-error');
$('.field-register-email .help-block').text('The email supplied has already been used');
} else {
$('.field-register-email').removeClass('has-error');
$('.field-register-email .help-block').text(' ');
}
}
});
};
This will send a POST request to the checkemail.php which will check whether the email address is in the database