Edit : Raymond Nijland has suggested and issue was at my end . i put extra group by in end
, right syntax is
SELECT
bkg.status,
count( if( bkg.status = '1', bkg.bookingId, 0 ) ) AS 'confirmed',
count( if( bkg.status = '2', bkg.bookingId, 0 ) ) AS 'Tentative'
FROM
tbl_booking bkg
thanks
I have table data for a table like this
i have a query
select bkg.status,
count(bkg.status) from tbl_booking bkg
GROUP BY
bkg.status;
that is giving results like
I want to convert that into pivot format
like
1 | 2 | 3 | 4
21| 57| 7 | 14
I tried
SELECT
bkg.status,
count( if( bkg.status = '1', bkg.bookingId, 0 ) ) AS 'confirmed',
count( if( bkg.status = '2', bkg.bookingId, 0 ) ) AS 'Tentative'
FROM
tbl_booking bkg
GROUP BY
bkg.status;
but that is giving me results like
If I tried to group by diffrent column like booking Id , result gone more different . I am getting confused about which column to be placed in sum and which column to be placed in group by
please suggest
Related
I'm listing out orders data based on this query. This query basically pulls the recurring orders data from the table. I'm also using some dropdown and a input field to search / filter query results.
SELECT
orders.id,
parent_id,
(
SELECT
COUNT(*)
FROM
orders o
WHERE
o.parent_id = orders.id
) AS recurring_order_count,
shopify_order_type,
shopify_order_id,
shopify_order_customer_ID,
coupon_code AS coupon,
FORMAT(shopify_order_total_price, 2) AS shopify_order_total_price,
FORMAT(
shopify_order_subtotal_price,
2
) AS shopify_order_subtotal_price,
FORMAT(
shopify_order_total_line_items_price,
2
) AS shopify_order_total_line_items_price,
FORMAT(commission_amount, 2) AS commission_amount,
(
CASE WHEN is_paid = 0 THEN 'No' WHEN is_paid = 1 THEN 'Yes' ELSE 'Rejected'
END
) AS is_paid,
(
CASE WHEN is_invoice_generated = 1 THEN 'Pending' ELSE 'Invoice Generated'
END
) AS is_invoice_generated,
DATE_FORMAT(
shopify_order_created_at,
'%m-%d-%Y'
) AS shopify_order_created_at,
(
CASE WHEN is_paused = 0 THEN 'Running' ELSE 'Paused'
END
) AS is_paused,
DATE_FORMAT(
shopify_recurring_date,
'%m-%d-%Y'
) AS shopify_recurring_date
FROM
`orders`
WHERE
coupon_code LIKE '%GERALD8314%' OR shopify_order_id LIKE '%GERALD8314%' OR(
CASE WHEN is_paid = 0 THEN 'No' WHEN is_paid = 1 THEN 'Yes' ELSE 'Rejected'
END
) LIKE '%GERALD8314%' OR(
CASE WHEN is_invoice_generated = 1 THEN 'Pending' ELSE 'Invoice Generated'
END
) LIKE '%GERALD8314%' OR DATE_FORMAT(
shopify_order_created_at,
'%m-%d-%Y'
) LIKE '%GERALD8314%' OR(
CASE WHEN is_paused = 0 THEN 'Running' ELSE 'Paused'
END
) LIKE '%GERALD8314%' OR DATE_FORMAT(
shopify_recurring_date,
'%m-%d-%Y'
) LIKE '%GERALD8314%' AND DATE_FORMAT(
shopify_order_created_at,
'%Y-%m-%d'
) BETWEEN ? AND ?
GROUP BY
`id`
HAVING
parent_id = 0 AND shopify_order_type = 1
ORDER BY
`id`
DESC
LIMIT 10 OFFSET 0
Is this query optimized? Is this SELECT COUNT(*) FROM orders WHERE o.parent_id = orders.id AS recurring_order_count line most expensive in terms of query execution speed? Is there anything I should take care to improve the query speed here? Please advise.
OR and LIKE with leading wildcard are terrible for performance. Consider having a FULLTEXT index across the relevant columns. If it is practical, it will be immensely faster.
WHERE coupon_code LIKE '%GERALD8314%'
OR shopify_order_id LIKE '%GERALD8314%' OR( CASE WHEN is_paid = 0 THEN 'No' WHEN is_paid = 1 THEN 'Yes' ELSE 'Rejected' END ) LIKE '%GERALD8314%' OR( CASE WHEN is_invoice_generated = 1 THEN 'Pending' ELSE 'Invoice Generated' END ) LIKE '%GERALD8314%'
OR DATE_FORMAT( shopify_order_created_at, '%m-%d-%Y' ) LIKE '%GERALD8314%' OR( CASE WHEN is_paused = 0 THEN 'Running' ELSE 'Paused' END ) LIKE '%GERALD8314%'
OR DATE_FORMAT( shopify_recurring_date, '%m-%d-%Y' ) LIKE '%GERALD8314%'
AND DATE_FORMAT( shopify_order_created_at, '%Y-%m-%d' ) BETWEEN ? AND ?
Also, there may be surprises in the results. Note that you have
a OR b OR c AND d
which is the same as
a OR b OR (c AND d)
I suspect you wanted
(a OR b OR c) AND d
I think the GROUP BY is unnecessary. And the HAVING clauses can be merged into the WHERE.
GROUP BY `id`
HAVING parent_id = 0
AND shopify_order_type = 1
ORDER BY `id` DESC
This has multiple issues:
DATE_FORMAT( shopify_order_created_at, '%Y-%m-%d' ) BETWEEN ? AND ?
BETWEEN is "inclusive". The way you have written the query, it will include the entire ending day. This may not be what you wanted.
Assuming the variable is a DATE or DATETIME, it can be simplified to
shopify_order_created_at BETWEEN ? AND ?
There may be more tips; fix these then come back for more.
I get error
SQL Error (1055): Expression #7 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'ifu.amount' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by
after migrating to mysql 8.0 from 5.6. I know that it can be easily fixed by disabling ONLY_FULL_GROUP_BY flag, but I want it to be more compatible with mysql 8.0. So question is if I would add ifu.amount to GROUP BY it should work perfetcly fine and I won't miss any query results or anything? Now without GROUP BY ifu.amount MySQL code looks like:
select
`i`.`id` AS `institution_id`,
`i`.`name` AS `institution_name`,
`cr`.`check_date` AS `check_date`,
sum(
(
case when (`cr`.`status` = '1') then 1 else 0 end
)
) AS `can_accept`,
sum(
(
case when (`cr`.`status` = '0') then 1 else 0 end
)
) AS `cannot_accept`,(
sum(
(
case when (`cr`.`status` = '1') then 1 else 0 end
)
) + sum(
(
case when (`cr`.`status` = '0') then 1 else 0 end
)
)
) AS `suma`,
`ifu`.`amount` AS `amount`,
round(
(
(
(
(
sum(
(
case when (`cr`.`status` = '1') then 1 else 0 end
)
) * 100
) / (
sum(
(
case when (`cr`.`status` = '1') then 1 else 0 end
)
) + sum(
(
case when (`cr`.`status` = '0') then 1 else 0 end
)
)
)
) * `ifu`.`amount`
) * 0.01
),
2
) AS `financed_amount`
from
(
(
(
`check_results` `cr`
join `family_doctors` `fd` on((`fd`.`id` = `cr`.`doctor_id`))
)
join `institutions` `i` on((`i`.`id` = `fd`.`institution_id`))
)
join `institutions_funding` `ifu` on((`ifu`.`institution_id` = `i`.`id`))
)
where
(`cr`.`status` in (1, 0))
group by
`i`.`id`,
`i`.`name`,
`cr`.`check_date`
Thanks for help in advance!
Include amount in your group by clause.
where
(`cr`.`status` in (1, 0))
group by
`i`.`id`,
`i`.`name`,
`cr`.`check_date`,
`ifu`.`amount`
if amount is excluded on your group by clause, this will get the amount that corresponds on your id, name and check date in ascending order (default).
or
min(`ifu`.`amount`) as `amount`.
I'm doing a select on two tables with this:
SELECT m.torneio, m.deck, m.top, m.lugar, sum( m.quantidade ) AS quantidade, m.formato AS formato, q.quantidade AS qtorneio, t.season AS season, sum( m.top ) AS totaltops, count( m.lugar = '1' ) AS venceu
FROM `metagame` AS m, quantidade AS q, torneios AS t
WHERE m.torneio = t.nome
AND m.torneio = q.nome
GROUP BY m.deck
My problem is that venceu is counting all instances instead of only the ones when lugar = 1. Why is that?
tried with sum() too with no good results too. How can i fix this?
I am surprised that count( m.lugar = '1' ) syntaxs but it does and returns the sames as count(*). You should probably change it to sum(case when lugar = 1 else 0 end) as venceu. You should also look closely at the group by to be sure it works as you expect (i suspect not).
count(x) does not accept an expression.
It's only counting how many times x is returned.
What you should do is check if m.lugar is 1 and yes add one to the counter else do nothing.
Inline checks can be done like so:
case when m.lugar = '1' then 1 else 0 end
Then add all the one you gets :
sum(case when m.lugar = '1' then 1 else 0 end)
Your final query should look like this:
SELECT
m.torneio,
m.deck,
m.top,
m.lugar,
sum( m.quantidade ) AS quantidade,
m.formato AS formato,
q.quantidade AS qtorneio,
t.season AS season,
sum( m.top ) AS totaltops,
sum(case when m.lugar = '1' then 1 else 0 end) AS venceu
FROM
`metagame` AS m,
quantidade AS q,
torneios AS t
WHERE
m.torneio = t.nome
AND m.torneio = q.nome
GROUP BY
m.deck
If I understand your question you can use this:
sum(case when m.lugar = '1' then 1 else 0 end)
or you can try having clause
SELECT column_name(s)
FROM table_name
WHERE condition
GROUP BY column_name(s)
HAVING condition
ORDER BY column_name(s);
I have a table like this. Now I want to show the total of same dates of different status in single row.
What should be the query?
Expected Result
Created | Total1 | Total2 | Total3
2017-02-28 | 1 | 1 | 2
you could use a sum for case when for each status and group by
select
created
, sum( case when story_status ='Draft' then total else 0 end ) as Draft_count
, sum( case when story_status ='Private' then total else 0 end ) as Private_count
, sum( case when story_status ='Published' then total else 0 end ) as Published_count
from my_table
group by created
This will give you one row per date created, with columns for each story_status:
SELECT
`created`,
SUM(if(`story_status` = 'Draft',`total`,0)) as `Total Draft`,
SUM(if(`story_status` = 'Private',`total`,0)) as `Total Private`,
SUM(if(`story_status` = 'Published',`total`,0)) as `Total Published`
FROM table
GROUP BY `created`
ORDER BY `created`
I am using sql server 2008
I have table in my database is like this:
And I want output like this:
As it is shown in my table I have DateField which has smalldatetime datatype and along with fruits and vegi fields. I want output like which shows data month-wise.. month comparison should be performed based on DateField of my table.
You can use something like:
select [Month] = month(DateField)
, [MonthName] = left(datename(mm, DateField), 3)
, TotalAmountApple = sum(case when fruits = 'Apple' then 1 else 0 end)
, TotalAmountOnion = sum(case when vegi = 'Onion' then 1 else 0 end)
from produce
group by month(DateField)
, left(datename(mm, DateField), 3)
order by [Month]
Full test details (no SQL Fiddle as it's experiencing issues):
create table produce
(
id int
, fruits varchar(10)
, vegi varchar(10)
, DateField smalldatetime
)
insert into produce
select 1, 'Apple', 'Chilly', '01-jan-2013'
insert into produce
select 1, 'Mango', 'Onion', '15-jan-2013'
insert into produce
select 1, 'Mango', 'Chilly', '20-jan-2013'
insert into produce
select 1, 'Apple', 'Chilly', '01-Feb-2013'
insert into produce
select 1, 'Mango', 'Onion', '15-Feb-2013'
insert into produce
select 1, 'Apple', 'Onion', '20-Feb-2013'
select [Month] = month(DateField)
, [MonthName] = left(datename(mm, DateField), 3)
, TotalAmountApple = sum(case when fruits = 'Apple' then 1 else 0 end)
, TotalAmountOnion = sum(case when vegi = 'Onion' then 1 else 0 end)
from produce
group by month(DateField)
, left(datename(mm, DateField), 3)
order by [Month]