Correct SQL Multiply across tables - mysql
I am at the end of my rope. I am learning SQL for a class. I have tried to get something akin to the to work, but to no avail. Can someone take a look at it.
Keep in mind that I'm new to this. I am trying to get the code to make subtotal equal the sum of column qty multiplied by the sum of column donutPrice in the donut table. I can't find much except for joins and if I do that, I can't use the join as a value.
The ultimate goal is to make it kinda automated.
CREATE TABLE donut
(
donutID int(50) not null auto_increment primary key,
donutName varchar(50) not null,
donutDesc varchar(200),
donutPrice dec(8,2)
);
CREATE TABLE customer
(
customerID int(50) not null auto_increment primary key,
fname char(50) not null,
lname char(50) not null,
address varchar(50) not null,
apartment varchar(10),
city char(50) not null,
state char(2) not null,
zip dec(5) not null,
homeph varchar(10),
mobileph varchar(10),
otherph varchar(10)
);
CREATE TABLE invoice
(
orderID int(50) not null auto_increment primary key,
notes varchar(50) not null,
orderdate date not null,
customerID int(50) not null default 1,
foreign key (customerID) references customer(customerID)
);
CREATE TABLE invoice_line_item
(
donutID int(50) not null,
orderID int(50) not null,
qty dec not null,
subtotal dec(10,2),
subtotal= sum('qty'*'donutPrice') FROM (invoice_line_item, donut),
primary key (donutID, orderID),
foreign key(donutID) references donut(donutID),
foreign key(orderID) references invoice(orderID)
);
ALTER TABLE donut AUTO_INCREMENT=1;
ALTER TABLE customer AUTO_INCREMENT=1001;
ALTER TABLE invoice AUTO_INCREMENT=500;
I guess you want a result looking like this:
OrderID subtotal
1 12.50
2 15.00
27.50
You get that with a query like this:
SELECT invoice.orderID, SUM(invoice_line_item.qty * donut.donutPrice) subtotal
FROM invoice
JOIN invoice_line_item ON invoice.orderID = invoice_line_item.orderID
JOIN donut ON invoice_line_item.donutID = donut.donutID
GROUP BY invoice.orderID WITH ROLLUP
Did you cover entity-relationship data in your class? Your entities are invoice, invoice_line_item, and donut (and your other tables). The relationships between them appear in the ON clauses of the JOIN operations.
Start with a query, and get it working. Then you can create a view ... which is nothing more or less than an encapsulated query.
Related
How do I join two tables from a database in SQL?
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Didnt display results in database
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Selecting data from other table using a foreign key?
So I'm trying to get the clan tag from ranks table for a specific member_id. But I don't understand how to do that. I used INNER JOIN commands but nothing works. CREATE TABLE ranks( rank VARCHAR(8), tag VARCHAR(18) NOT NULL, PRIMARY KEY(rank) ); CREATE TABLE member( member_id INT UNSIGNED AUTO_INCREMENT, first_name VARCHAR(15) NOT NULL, last_name VARCHAR(15), ign VARCHAR(20) NOT NULL, rank VARCHAR(8) NOT NULL, joined_date DATE NOT NULL, dob DATE, sex ENUM('M','F') NOT NULL, country VARCHAR(3) NOT NULL, PRIMARY KEY(member_id), FOREIGN KEY(rank) REFERENCES ranks(rank) ); INSERT INTO ranks VALUES ('Founder','|NoMercy|King'), ('Admin','^1|NoMercy|^7'), ('TmpAdmin','^5|NoMercy|^7'), ('Pro','^1|NoMercy PRO|^7'), ('Member','^4|NoMercy|^7'), ('Banned','BANNED'); INSERT INTO member VALUES (NULL,'Reznov','NULL','REZ','Member','2017/12/22','1954/02/28','M','RUS'), (NULL,'Amanda','NULL','S3XXY|G!RL|','Pro','2018/01/05','1992/01/25','F','USA'), (NULL,'Elmasri','Navathe','INDIAN_Noob _XOX','TmpAdmin','2018/04/02','1960/08/25','M','IND'), (NULL,'Tony','Silva','Cool KiD','Member','2018/04/26','1988/02/22','M','BR'), (NULL,'Hashan','NULL','Big Papa','Member','2018/05/08','1996/06/12','M','NZ'), (NULL,'Emma','Watson','EmmaXXX','Banned','2018/06/10','1985/05/22','F','UK'); I need to output the correct tag for specific member. It should only display the tag. Please help!
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Auto_increment trigger
I need to auto_increment the primary key in a mysql database using a trigger. Unfortunately, I am not quite sure how to do this. In the sample code I have provided, I need the employee table primary key to auto_increment beginning with an empty table and a starting value of 200. Then, I need each new insert to increment by 1.Thanks for looking and I hope you are able to help me. CREATE TABLE department ( dept_name VARCHAR(50) NOT NULL Primary Key ); CREATE TABLE employee ( emp_id INT(6) unsigned Default 0 Not NULL , last_name VARCHAR(25) NOT NULL , first_name VARCHAR(40) NOT NULL , dept_name VARCHAR(50) NOT NULL , PRIMARY KEY(emp_id, dept_name) , FOREIGN KEY(dept_name) REFERENCES department (dept_name) );
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What's wrong with this SELECT Statement?
I'm getting this error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' JOIN `shirts_link` ON `shirts_link`.`shirt_id`=`shirts`.`id` JOIN `shirt_sizes' at line 1 I've been combing over it for nearly a half an hour now and can't figure it out. Can someone please point it out to me? Here's the code. SELECT `shirts`.`shirt_name`, `shirts`.`men` AS `main_photo`, GROUP_CONCAT ( `shirt_sizes`.`size_name` ) AS `sizes` FROM `shirts` JOIN `shirts_link` ON `shirts_link`.`shirt_id`=`shirts`.`id` JOIN `shirt_sizes` ON `shirt_sizes`.`id`=`shirts_link`.`size_id` JOIN `shirt_prices` ON `shirt_prices`.`id`=`shirts_link`.`price_id` WHERE `men`!='' GROUP BY `shirt_prices`.`price_cat` In case the problem goes deeper than this script, here's the other tables I'm trying to tie together. 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Where clause belongs after the entire from clause, meaning after all the joins.
You have this WHERE clause in the wrong place: WHERE `men`!='' Move it in front of your GROUP BY clause. UPDATE: Here is a reformatted version of your query: SELECT `shirts`.`shirt_name` , `shirts`.`men` AS `main_photo` , GROUP_CONCAT ( `shirt_sizes`.`size_name` ) AS `sizes` FROM `shirts` JOIN `shirts_link` ON `shirts_link`.`shirt_id`=`shirts`.`id` JOIN `shirt_sizes` ON `shirt_sizes`.`id`=`shirts_link`.`size_id` JOIN `shirt_prices` ON `shirt_prices`.`id`=`shirts_link`.`price_id' WHERE `men` != '' GROUP BY `shirt_prices`.`price_cat`