Notice: I have made a few changes to the original question as my problem was not with commas within string.
I have a function I've been working on to exclude a cell value from a new array that contains a string I am searching for. I am doing this in order to put together a list for .setHiddenValues, since .setVisibleValues is not supported/implemented yet.
Here are my requirements for the sake of clarity:
Currently working:
Able to handle numbers as well as strings
Can search for lowercase and uppercase. visibleValueStr is user inputted so it can't be so sensitive.
colValueArr may have strings with commas within.
Still working on:
visibleValueStr can be a single value or array.
Case sensitivity("apple" to match "Apple")
Not exact matches("apple" to match "apple and banana")
Here is the function I currently have with the above met/unmet conditions:
function getHiddenValueArray(colValueArr,visibleValueArr){
var flatUniqArr = colValueArr.map(function(e){return e[0].toString();})
.filter(function(e,i,a){
return (a.indexOf(e.toString())==i && visibleValueArr.indexOf(e.toString()) == -1);
})
return flatUniqArr;
}
Please let me know what other info I need. I will update this question as I continue to do my research in the meanwhile.
Clarification from comments:
User inputs input(s) on HTML form and the variable is passed on as visibleValueArr.
When using Logger.log(visibleValueArr).
[apple, banana]
When using Logger.log(colValueArr).
[[Apple],[apple][apple][apple and banana],[apple],[banana, and apple],
[apple, and banana],[orange],[orange, and banana],[kiwi],[kiwi, and orange],
[strawberry]]
So when I use:
SpreadsheetApp.newFilterCriteria().setHiddenValues(newArray).build();
newArray should be the hidden values. In this case it should be:
orange
kiwi
kiwi, and orange
strawberry
Basically anything that does not contain what visibleValueArr is.
Instead, it returns all values back, hiding them all.
When I use [Apple, Banana] the "Apple" and "Banana" values are left out of newArray as they should be, but "Apple and Banana" and "Apple, and Banana" are not"
In addition, I would also like to understand what the e,i,a in function(e,i,a) represent. I'm trying to apply .toLowerCase() in different places to see if that resolves part of my issue but I'm not sure where to do it.
Issues:
Case sensitivity("apple" to match "Apple")
Not exact matches("apple" to match "apple and banana")
Solution:
Use regex-search with case insensitivity
Modified Script:
function getHiddenValueArray(colValueArr,visibleValueArr){
/*colValueArr = [["Apple"],["apple"],["orange"],["Apple, and Banana"]];
visibleValueArr = ['apple','banana'];*/
var flatUniqArr = colValueArr.map(function(e){return e[0].toString();})
.filter(function(e,i,a){
return (a.indexOf(e)==i && !(visibleValueArr.some(function(f){
return e.search(new RegExp(f,'i'))+1;
})));
});
//Logger.log(flatUniqArr); will log orange
return flatUniqArr;
}
References:
String#search
Array#some
Array#filter
Array#map
Related
I have the below script with the purpose of retrieving the value in the google sheet which will either state TRUE or FALSE. If it states false I want this script to run the two functions below (updateWIPdata and updateDebtorsdata) but if the cell value is true I don't want those functions to run at all but the functions seem to run regardless of the value in the cell so any help would be much appreciated
function updateAll() {
var updateStatus = SpreadsheetApp.getActive().getSheetByName('Updated').getRange('C2').getValue();
Logger.log(updateStatus);
if (updateStatus = 'false') {
updateWIPdata();
updateDebtorsdata();
}
}
Probably the value is a boolean.
Also, please use == or ===
if (updateStatus == false) {
Reference:
Equality operators
The fix is simple
But you also want to improve a few things in your code
The main problem is in this line:
if (updateStatus = 'false')
You are not comparing updateStatus to false, you are assigning 'false' to updateStatus. On top of that you are assigning a string, not a boolean. The line needs to be
if (false === updateStatus)
Notice three things:
false is a boolean here, it doesn't have quotation marks around it
It's on the left side of the comparison; putting litteral values on the left side is a habbit that prevents this type of error
I'm using the === comparison operator instead of the = assignment operator
Another thing you need to do is forget about var and start using const and let. If your updateStatus was a const, you would have very quickly realized the error.
So I have a List and I am able to filter to find on it which works fine for reducing the list to what I am looking for.
However, let's say I just want to get back an array of numbers, not a List, back from my search, something like:
var found = campaignTimelineBoardTemplatesModels.map((campaignTime) => {
if (campaignTime.getId() == num)
return Math.random();
});
The problem is that found is now still a List, and 2, is that I have a undefined members in this List as it seems to hold the same size as my original List.
So Map didn't do it.
All I am trying to do is get back a simple list of pure numbers that match a condition back as a pure array.
Is it possible?
Thanks,
Sean
found it, magic of reduce:
var IDs = campaignTimelineBoardTemplatesModels.reduce((result,campaignTimelineBoardTemplatesModel: CampaignTimelineBoardTemplatesModel)=>{
if (campaignTimelineBoardTemplatesModel.getCampaignTimelineId() == i_campaign_timeline_id)
result.push(campaignTimelineBoardTemplatesModel.getCampaignTimelineId());
return result;
},[])
I followed this Search demo, and am trying to expand it to only search on specified attribute names.
It works without an attribute name, and returns an array of matching ids. But if I supply anything for the attribute name then search returns an empty array. I am guessing I need some magic formating for the attribute name.
So currently I have:
function search() {
var txtArea = document.getElementById("TextAreaResult");
var searchStr = document.getElementById("SearchString").value;
var searchProperties = document.getElementById("SearchProperties").value;
if (searchStr.length == 0) {
txtArea.value = "no search string.";
return;
}
var viewer = viewerApp.getCurrentViewer();
viewer.clearSelection();
if (searchProperties.length == 0)
viewer.search(searchStr, searchCallback, searchErrorCallback);
else {
var searchPropList = searchProperties.split(',');
viewer.search(searchStr, searchCallback, searchErrorCallback, searchPropList);
}
}
where searchProperties is a user input, eg "Name", and searchPropList becomes a single element array.
The same example also covers getProperties(), which returns displayName and displayCategory for each property, but I don't see a separate internal name.
Am I missing something obvious from here or do I need to transform "Name" in some way.
Or does someone have an example that will list the true name rather than displayName?
The Autodesk.Viewing.Viewer3D.search() method is NOT case sensitive on the text parameter, but it IS case sensitive on the attributeNames parameter, and you need to use the full name of the attribute.
We're now (Aug, 25, 2016) updating the documentation.
I've been looking into how to count cells with the countif function, and how to count cells that are colored using scripts and custom functions (like this thing: http://pastebin.com/4Yr095hV), but how would i count cells with a specific string AND color?
Example, I want to count every cell containing the word "one" that has a fill color of white.
EDIT: I was told to add what i had so far, but I am not sure what was meant by that. For counting cells with a specific string I used:
=COUNTIF(A1:A247,"string")
and for counting cells that are colored i used this what was on this page: https://webapps.stackexchange.com/questions/23881/google-spreadsheet-calculating-shaded-cells
but i still don't know how to combine these two TOGETHER.
EDIT: For those looking for this answer, I've found a way to utilize the script Tom posted, and adjusted a line within it.
For Tom's script to work with "wildcards", i used something called .indexOf to always look for any cells containing the string (effectively treating it as if there is always a star before and after the string). On line 32 of his script, I altered it to this:
.map (function(e,i,a) { if (e.toString().toUpperCase().indexOf(this.toString().toUpperCase()) >= 0){ return 1 } else { return 0 } },str))
So now whenever I want to look for a White cell containing the string "Apple1", it will count it regardless of if it's written as "OrangeApple1B" or whatever. And the casing doesn't matter since it seems like this script always converts the given string to Upper Case anyways.
I am still trying to find out how to incorporate this on a totally different spreadsheet though (using something like IMPORTRANGE to count cells on a TOTALLY DIFFERENT SHEET using this script)...
function countIfStringAndColor(r, str, color) {
var COLORS = {
"BLACK":"#000000",
"DARK GRAY 4":"#434343",
"DARK GRAY 3":"#666666",
"DARK GRAY 2":"#999999",
"DARK GRAY 1":"#B7B7B7",
"GRAY":"#CCCCCC"
};
var range = SpreadsheetApp
.getActive()
.getActiveSheet()
.getRange(r.toString());
color = color.indexOf("#") == 0 ? color : COLORS[color.toString().toUpperCase()];
return range
.getBackgrounds()
.reduce(function(a,b) { return a.concat(b) })
.map (function(e,i,a) { return e.toString().toUpperCase() === this.toString().toUpperCase(); },color)
.map(function(e,i,a) { return [e, this[i]] },
range
.getValues()
.reduce(function(a,b) { return a.concat(b) })
.map (function(e,i,a) { return e.toString().toUpperCase() === this.toString().toUpperCase() },str))
.filter(function(e,i,a) {return a[i][0] && a[i][1] })
.length;
}
METHOD OF OPERATION
The function takes three arguments: Range (String), String, String
The associative array 'COLORS' is supplied to convert the common names of colors to hex format. There are about 90 more colors in the list that I didn't supply for space reasons. I can get you the full list if you would like.
Grabbing the Range.
Checks to see if color is already in hex format. If not it tries to find a common name key in COLORS and return the hex value. From here out everything is toString() and toUpperCase() to help prevent errors.
The code from here out is one chain of array manipulation that will produce the solution for the function to return.
Grab the needed background colors.
.reduce, coupled with .concat (both Array Methods), is used to flatten the background color array. It changes it from a rectangular array of arrays to a one dimensional list.
.map goes through each element of the array and applies the given function. In this case we are seeing if the array element (e) is the same as the color supplied. Take note of how 'color' is called outside the closing curly bracket. It is the 'thisArg', and the 'this' inside the function is an image of it. The array is now reduced to a series of true/false elements.
This map is used to combine the two arrays, 'color' and 'str'. The indented part right below is the same steps we used to get 'color' to a series of true/false elements, but now applied to 'str'. All those operations are performed while 'str' is being called as the thisArg for the current map function. The map function then returns a single array of the form [color,str] which is made up of many elements of [true,false] [true,true] [false,false] pairs.
We are only interested in the solutions where both 'color' and 'str' are true, so we can use .filter to remove all the other elements, leaving use with an array of only [true, true] pairs.
Each [true, true] pair is a unique solution to the equation. We can just grab the length of the array to see how many solutions we have found! This is the value that is passed to the return at the beginning.
just wanted to ask, whether there is a way to keep the relations of expressions going when duplicating layers.
E.g. I have two layers, "LayerA" and "LayerB". Now I have an expression going on in "LayerB" saying, that its position always equals the position of "LayerA".
Now when I duplicate those two and get "LayerA 2" and "LayerB 2" I want the expression in "LayerB 2" to reference to "LayerA 2"'s position rather than "LayerA"'s position!
While it is no problem to simply change the expression when there is only one of them, it gets quite hard when you have multiple expressions going on ...
You might end up wanting to organize your comp differently, but, given your example (and exactly those name lengths), this position expression will work to find the appropriate 'target layer':
//base name to work from:
baseName = "Layer";
//length of that:
nameLen = baseName.length;
//this layer's name:
myName = thisLayer.name;
if (myName.length == nameLen) {
//if they are the same, then it is the original
// (non-duplicated) version
thisComp.layer("LayerA").transform.position;
} else {
//get tail string, the space and number:
tailStr = myName.substring(nameLen+1, myName.length);
//build new target layer name with "A":
targetName = myName.substring(0, (nameLen)) + "A" + tailStr
//new line pointing to target layer:
thisComp.layer(targetName).transform.position;
}