How to send JSON objects to another computer? - json

Question

Using Websockets, I am able to use 1 computer and 1 kinect v2.0 to generate JSON objects of the joints x,y, and z coordinates in real-time. The next steps is to have this data transferred to another computer, using possibly TCP/IP network. My question is to anyone who knows how this is done. Having this data transferred to another computer.
Output that needs to be transferred to another computer in real-time
namespace WebSockets.Server
{
class Program
{
// Store the subscribed clients.
static List<IWebSocketConnection> clients = new List<IWebSocketConnection>();
// Initialize the WebSocket server connection.
static Body[] bodies = new Body[6];
//static KinectSensor kinectSensor = null;
static CoordinateMapper _coordinateMapper;
static Mode _mode = Mode.Color;
static void Main(string[] args)
{
//const string SkeletonStreamName = "skeleton";
//SkeletonStreamMessage skeletonStreamMessage;// = new SkeletonStreamMessage { stream = SkeletonStreamName };
KinectSensor kinectSensor = KinectSensor.GetDefault();
BodyFrameReader bodyFrameReader = null;
bodyFrameReader = kinectSensor.BodyFrameSource.OpenReader();
ColorFrameReader colorFrameReader = null;
colorFrameReader = kinectSensor.ColorFrameSource.OpenReader();
_coordinateMapper = kinectSensor.CoordinateMapper;
kinectSensor.Open();
WebSocketServer server = new WebSocketServer("ws://localhost:8001");
server.Start(socket =>
{
socket.OnOpen = () =>
{
// Add the incoming connection to our list.
clients.Add(socket);
};
socket.OnClose = () =>
{
// Remove the disconnected client from the list.
clients.Remove(socket);
};
socket.OnMessage = message =>
{
if (message == "get-video")
{
int NUMBER_OF_FRAMES = new DirectoryInfo("Video").GetFiles().Length;
// Send the video as a list of consecutive images.
for (int index = 0; index < NUMBER_OF_FRAMES; index++)
{
foreach (var client in clients)
{
string path = "Video/" + index + ".jpg";
byte[] image = ImageUtil.ToByteArray(path);
client.Send(image);
}
// We send 30 frames per second, so sleep for 34 milliseconds.
System.Threading.Thread.Sleep(270);
}
}
else if (message == "get-bodies")
{
if (kinectSensor.IsOpen)
{
if (bodyFrameReader != null)
{
bodyFrameReader.FrameArrived += bodyFrameReader_FrameArrived;
}
}
}
else if (message == "get-color")
{
if (kinectSensor.IsOpen)
{
if (colorFrameReader != null)
{
colorFrameReader.FrameArrived += colorFrameReader_FrameArrived;
}
}
}
};
});
// Wait for a key press to close...
Console.ReadLine();
kinectSensor.Close();
}
private static void colorFrameReader_FrameArrived(object sender, ColorFrameArrivedEventArgs e)
{
//throw new NotImplementedException();
using (ColorFrame colorFrame = e.FrameReference.AcquireFrame()) {
if (colorFrame != null) {
var blob = colorFrame.Serialize();
foreach (var client in clients)
{
if (blob != null)
{
client.Send(blob);
Console.WriteLine("After color Blob sent");
}
}
}
}
}
private static void bodyFrameReader_FrameArrived(object sender, BodyFrameArrivedEventArgs e)
{
//throw new NotImplementedException();
bool dataReceived = false;
using (BodyFrame bodyFrame = e.FrameReference.AcquireFrame())
{
if (bodyFrame != null)
{
if (bodies == null)
{
bodies = new Body[bodyFrame.BodyCount];
}
// The first time GetAndRefreshBodyData is called, Kinect will allocate each Body in the array.
// As long as those body objects are not disposed and not set to null in the array,
// those body objects will be re-used.
bodyFrame.GetAndRefreshBodyData(bodies);
dataReceived = true;
}
}
if (dataReceived)
{
foreach (var client in clients)
{
var users = bodies.Where(s => s.IsTracked.Equals(true)).ToList();
if (users.Count>0){
string json = users.Serialize(_coordinateMapper, _mode);
Console.WriteLine("jsonstring: " + json);
Console.WriteLine("After body serialization and to send");
}
}
}
}
}
}

Answer 1

Try changing it from
WebSocketServer server = new WebSocketServer("ws://localhost:8001");
to
WebSocketServer server = new WebSocketServer(" ws://192.168.X.X:8001");
on the client end. Enter the IP address of the client computer and make sure both server and client are on the same network.