I have a simple enough query that works well:
SELECT
Name, JobStatus
FROM
ScheduleRequest
WHERE
ScheduleDate >= '2018-07-11'
AND
JobStatus <> 6
I need to check for different values in the same field 'JobStatus'. When I try to alter the query like this, I'm finding only the last value of 95 is showing?
SELECT
Name, JobStatus
FROM
ScheduleRequest
WHERE
ScheduleDate >= '2018-07-11'
AND (JobStatus <> 6
OR JobStatus <> 0
OR JobStatus <> 1
OR JobStatus <> 4
OR JobStatus <> 95
)
Use NOT IN expression
SELECT
Name, JobStatus
FROM
ScheduleRequest
WHERE
ScheduleDate >= '2018-07-11'
AND JobStatus NOT IN (6, 0, 1, 4, 95)
Related
How do you rewrite this code correctly in Snowflake?
select account_code, date,
sum(box_revenue_recognition_amount) as box_revenue_recognition_amount
, sum(case when box_flg = 1 then box_sku_quantity end) as box_sku_quantity
, sum(box_revenue_recognition_refund_amount) as box_revenue_recognition_refund_amount
, sum(box_discount_amount) as box_discount_amount
, sum(box_shipping_amount) as box_shipping_amount
, sum(box_cogs) as box_cogs
, max(invoice_number) as invoice_number
, max(order_number) as order_number
, min(box_refund_date) as box_refund_date
, first (case when order_season_rank = 1 then box_type end) as box_type
, first (case when order_season_rank = 1 then box_order_season end) as box_order_season
, first (case when order_season_rank = 1 then box_product_name end) as box_product_name
, first (case when order_season_rank = 1 then box_coupon_code end) as box_coupon_code
, first (case when order_season_rank = 1 then revenue_recognition_reason end) as revenue_recognition_reason
from dedupe_sub_user_day
group by account_code, date
I have tried to apply window rule has explained in first_value Snowflake documentation to no avail with the SQLCompilation Error: ... is not a valid group by expression
select account_code, date,
first_value(case when order_season_rank = 1 then box_type end) over (order by box_type ) as box_type
first_value(case when order_season_rank = 1 then box_order_season end) over (order by box_order_season ) as box_order_season,
first_value(case when order_season_rank = 1 then box_product_name end) over (order by box_product_name ) as box_product_name,
first_value(case when order_season_rank = 1 then box_coupon_code end) over (order by box_coupon_code ) as box_coupon_code,
first_value(case when order_season_rank = 1 then revenue_recognition_reason end) over (order by revenue_recognition_reason ) as revenue_recognition_reason
, sum(box_revenue_recognition_amount) as box_revenue_recognition_amount
, sum(case when box_flg = 1 then box_sku_quantity end) as box_sku_quantity
, sum(box_revenue_recognition_refund_amount) as box_revenue_recognition_refund_amount
, sum(box_discount_amount) as box_discount_amount
, sum(box_shipping_amount) as box_shipping_amount
, sum(box_cogs) as box_cogs
, max(invoice_number) as invoice_number
, max(order_number) as order_number
, min(box_refund_date) as box_refund_date
from dedupe_sub_user_day
group by 1,2
First_value is not an aggregate function. But an window function, thus you get an error when you use it in relation to a GROUP BY. If you want to use it with a group up put an ANY_VALUE around it.
here is some data I will use below in a CTE:
with data(id, seq, val) as (
select * from values
(1, 1, 10),
(1, 2, 11),
(1, 3, 12),
(1, 4, 13),
(2, 1, 20),
(2, 2, 21),
(2, 3, 22)
)
So to show FIRST_VALUE is a window function we can just use it
select *
,first_value(val)over(partition by id order by seq) as first_val
from data
ID
SEQ
VAL
FIRST_VAL
1
1
10
10
1
2
11
10
1
3
12
10
1
4
13
10
2
1
20
20
2
2
21
20
2
3
22
20
So if we GROUP BY id, to avoid an error we have to wrap the FIRST_VALUE by an aggregate value, as given the are all equal, ANY_VALUE is a good pick, and it seems it needs to be in another layer of SQL:
select id
,count(*) as count
,any_value(first_val) as first_val
from (
select *
,first_value(val)over(partition by id order by seq) as first_val
from data
)
group by 1
order by 1;
ID |COUNT |FIRST_VAL
1 |4 |10
2 |3 |20
now MAX can be fun to use where used in relation to ROW_NUMBER() to pick the best value:
select id
,count(*) as count
,max(first_val) as first_val
from (
select *
,row_number() over (partition by id order by seq) as rn
,iff(rn=1, val, null) as first_val
from data
)
group by 1
order by 1;
but this is almost more complex than the ANY_VALUE solution, but I feel the performance would be better, but if they have the same magnitude of performance, I would always choose readable to you and your team, over a smaller performance difference.
With the way you've written your case statement, it leads me to believe that there is only one row with order_season_rank = 1 when grouping by account_code and date.
If that is true, then you can use several of Snowflake's aggregate functions and you will get what you want. Rather than trying to get the first value, you could use min, max, any_value, mode (or really any aggregate function that will ignore nulls) to return the only non-null value in the aggregation.
first() this link suggests first is only supported by MS ACCESS however you've tagged the question with MYSQL, Snowflake. Could you confirm the DBMS's you are using?
by moving the first_value() function outside the aggregation it seems to work fine
What I'm looking to do is show my current performance for this month, compared with expected scheduled wins to come in and then display the total expected amount, by product type.
For clarity, I have two sub-products that I'm grouping under the same name.
My issue is that for my 'Charged' amount, it's keeping the two sub-products separate, where as the 'Scheduled' amount is working fine.
The table should look like:
Type | Charged | Scheduled | Expected
A 3 2 5
B 1 1 2
What's actually showing is:
Type | Charged | Scheduled | Expected
A 2 1 3
A 1 1 2
B 1 1 2
The code is as follows:
select
t2.product,
t1.Charged,
t2.Scheduled,
t1.charged + t2.scheduled as 'expected'
from(
select
case
when user_type = 'a1' then 'a'
when user_type = 'a2' then 'a'
else 'b'
end as 'Type',
SUM(charged) as 'Scheduled'
from
table
where
month(date) = month(now())
and
year(date) = year(now())
and status like 'scheduled'
group by 1
order by 2 desc) t2 join
(select
case
when user_type = 'a1' then 'a'
when user_type = 'a2' then 'a'
else 'b'
end as 'Type',
sum(charged) as 'Charged'
FROM table
WHERE (status = 'Complete'
AND str_to_date(concat(date_format(date, '%Y-%m'), '-01'), '%Y-%m-%d') = str_to_date(concat(date_format(now(), '%Y-%m'), '-01'), '%Y-%m-%d'))
GROUP BY user_type
ORDER BY user_type ASC) as t1 on t1.type = t2.type
I appreciate I might not be explaining this incredibly well (and that my code is probably quite clunky - I'm still fairly new!) so any help/direction would be appreciated.
Thanks!
Just some suggestion
you have a column product in main select but you have type in subquery and not product
you should not use sigle quote around column name
ad you have group by user_type but you need group by type for charged
select
t2.type,
t1.Charged,
t2.Scheduled,
t1.charged + t2.scheduled as 'expected'
from(
select
case
when user_type = 'a1' then 'a'
when user_type = 'a2' then 'a'
else 'b'
end as Type,
SUM(charged) as Scheduled
from
table
where
month(date) = month(now())
and
year(date) = year(now())
and status like 'scheduled'
group by 1
order by 2 desc) t2 join
(select
case
when user_type = 'a1' then 'a'
when user_type = 'a2' then 'a'
else 'b'
end as Type,
sum(charged) as Charged
FROM table
WHERE (status = 'Complete'
AND str_to_date(concat(date_format(date, '%Y-%m'), '-01'), '%Y-%m-%d') = str_to_date(concat(date_format(now(), '%Y-%m'), '-01'), '%Y-%m-%d'))
GROUP BY Type
ORDER BY Type ASC) as t1 on t1.type = t2.type
I am really stucked with one sql select statement.
This is output/result which I get from sql statement below:
WHAT I need: I need to have columns assignedVouchersNumber and usedVouchersNumber together in one row by msisdn. So for example if you can see "msisdn" 723709656 there are two rows now.. one with assignedVouchersNumber = 1 and second with assignedVouchersNumber = 1 too.
But I need to have it in one row with assignedVouchersNumber = 2. Do you now where is the problem?
SELECT eu.msisdn,
eu.id as userId,
sum(case ev.voucherstate when '1' then 1 else 0 end) as assignedVouchersNumber,
sum(case ev.voucherstate when '2' then 1 else 0 end) as usedVouchersNumber,
ev.extra_offer_id,
ev.create_time,
ev.use_time,
ev.id as voucherId,
ev.voucherstate
FROM extra_users eu
JOIN (SELECT sn.msisdn AS telcislo,
stn.numberid
FROM stats_number sn
JOIN stats_target_number AS stn
ON ( sn.numberid = stn.numberid )
WHERE stn.targetid = 1) xy
ON eu.msisdn = xy.telcislo
JOIN extra_vouchers AS ev
ON ( eu.id = ev.extra_user_id )
WHERE ev.create_time BETWEEN '2012-07-23 00:00:00' AND '2013-08-23 23:59:59'
AND ev.use_time <= '2013-08-23 23:59:59'
AND ev.use_time >= '2012-07-23 00:00:00'
AND ev.voucherstate IN ( 1, 2 )
AND Ifnull(ev.extra_offer_id IN( 2335, 3195, 30538 ), 1)
GROUP BY eu.msisdn, ev.extra_offer_id, ev.voucherState
ORDER BY eu.msisdn ASC
You have two different extra_offer_id for same msisdn and VouchersNumber. Thats why you get two rows.
I got it... there should not be groupping by ev.voucherState in
GROUP BY eu.msisdn, ev.extra_offer_id, ev.voucherState
After then I have removed ev.voucherState it is working now.
i'm writing a query where i need resultant from select stmt based on conditions on avg() aggregate function,
but in mysql it is giving error as Error Code : 1111 ,
Invalid use of group function
select
if( avg(FLD_TKTS) > 1 and avg(FLD_TKTS) <= 2 , '1-2' , 0) as fld_avg_1_2,
if( avg(FLD_TKTS) > 3 and avg(FLD_TKTS) <= 4 , '3-4' , 0) as fld_avg_3_4
from tbl
group by region;
Is there is any other method to do this?
Query:
select
CASE WHEN avg(FLD_TKTS) > 1 and avg(FLD_TKTS) <= 2 THEN '1-2'
ELSE '0' END as fld_avg_1_2,
CASE WHEN avg(FLD_TKTS) > 3 and avg(FLD_TKTS) <= 4 THEN '3-4'
ELSE '0' END as fld_avg_3_4
from tbl
group by region
select
region,
if(fld_avg > 1 and fld_avg <= 2, '1-2', 0) as fld_avg_1_2,
if(fld_avg > 3 and fld_avg <= 4, '3-4', 0) as fld_avg_3_4
from
(
select
region,
avg(FLD_TKTS) fld_avg
from
tbl
group by
region
) a;
I think a subquery would be a good solution:
SELECT
IF( avg_fld_tkts > 1 and avg_fld_tkts <= 2 , '1-2' , 0) as fld_avg_1_2,
IF( avg_fld_tkts > 3 and avg_fld_tkts <= 4 , '3-4' , 0) as fld_avg_3_4
(
SELECT avg(FLD_TKTS) AS avg_fld_tkts
from tbl
group by region
) t1
Table:
laterecords
-----------
studentid - varchar
latetime - datetime
reason - varchar
students
--------
studentid - varchar -- Primary
class - varchar
I would like to do a query to show the following:
Sample Report
Class No of Students late 1 times 2 times 3 times 4 times 5 & more
Class A 3 1 0 2 0 0
Class B 1 0 1 0 0 0
My query below can show the first column results:
SELECT count(Distinct studentid), class FROM laterecords, students
WHERE students.studenid=laterecords.studentid AND
GROUP BY class
I can only think of getting the results for each column and store them into php arrays. Then echo them to table in HTML.
Is there any better SQL way to do the above? How to do up the mysql query ?
Try this:
SELECT
a.class,
COUNT(b.studentid) AS 'No of Students late',
SUM(b.onetime) AS '1 times',
SUM(b.twotime) AS '2 times',
SUM(b.threetime) AS '3 times',
SUM(b.fourtime) AS '4 times',
SUM(b.fiveormore) AS '5 & more'
FROM
students a
LEFT JOIN
(
SELECT
aa.studentid,
IF(COUNT(*) = 1, 1, 0) AS onetime,
IF(COUNT(*) = 2, 1, 0) AS twotime,
IF(COUNT(*) = 3, 1, 0) AS threetime,
IF(COUNT(*) = 4, 1, 0) AS fourtime,
IF(COUNT(*) >= 5, 1, 0) AS fiveormore
FROM
students aa
INNER JOIN
laterecords bb ON aa.studentid = bb.studentid
GROUP BY
aa.studentid
) b ON a.studentid = b.studentid
GROUP BY
a.class
How about :
SELECT numlates, `class`, count(numlates)
FROM
(SELECT count(laterecords.studentid) AS numlates, `class`, laterecords.studentid
FROM laterecords,
students
WHERE students.studentid=laterecords.studentid
GROUP BY laterecords.studentid, `class`) aliastbl
GROUP BY `class`, numlates