I am trying to find the following variations. I have 10 games and individual ids associated to each game. I need to figure out the following:
distinct count of all who played all 10 games
same but for 9 games
etc
The closest formula I came up with:
SELECT distinct player_id
FROM ticket
WHERE game_code IN ('17','16') AND
create_date BETWEEN '2018-05-01'
AND '2018-05-31'
GROUP BY player_id
HAVING COUNT(*) = 2;
Related
I am trying to select the rows that have the last gameDate, todays gameDate (if exists), and the next gameDate from a table called games for any given team(s). It's structure is as follows:
awayTeam homeTeam gameDate
1 2 5/12/16
2 3 5/13/16
3 5 5/14/16
2 4 5/14/16
The problem I am facing is that the teamID can appear in two columns - awayTeam or homeTeam. I saw a lot of solutions that have the group by clause but that only appears to work for just one column. I would like to get the row which corresponds to the last gameDate for each team. For instance, (1,5) would return:
awayTeam homeTeam gameDate
1 2 5/12/15
3 5 5/14/16
Since I want the most recent games, any games from today, and the next game, I was thinking the best way to solve this would be to first get the past rows, then UNION ALL with the rows from todays date, then UNION ALL with the next game. This table is small with only about 3,000 rows. I have the below query, but it only works for homeTeam and not if it appears in awayTeam. Also, the below query takes 2.2 seconds, which seems rediculously high for a table with such a small number of rows.
SELECT g . *
FROM games g
WHERE g.gameDate = (
SELECT MAX( g2.gameDate )
FROM games g2
WHERE g2.homeTeam = g.homeTeam
AND gameDate < NOW( )
AND g.homeTeam
IN (1, 5) )
ORDER BY g.gameDate DESC
I thought about perhaps splitting this into a view so I could easily get the last time a team has played, regardless of whether they appear in the homeTeam or awayTeam column, but that seems like overkill. This is for MySQL. Thanks for your time.
This isn't pretty but it may help you. The inner most derived table gets all the teams in one column along side their dates. The next part gets each teams last game played date. Join that back to the original table and now you have the most recent last game for each team back in the original format. It's confusing to explain but really quite simple if you run each of the selects one by one working from inner to outer.
SQL Fiddle Demo
SELECT yt.*
FROM
(SELECT
Team
, MAX(GameDate) AS GameDate
FROM
(SELECT AwayTeam AS Team, GameDate
FROM YourTable
UNION ALL
SELECT HomeTeam AS Team, GameDate
FROM YourTable) a
WHERE GameDate < NOW()
GROUP BY
Team) MaxDates
JOIN YourTable yt ON (MaxDates.Team = yt.AwayTeam OR MaxDates.Team = yt.HomeTeam)
AND yt.GameDate = MaxDates.GameDate
WHERE MaxDates.team in (1,5)
I have a list of game scores for various teams and various years.
Database looks like this:
id |team|year|week|points
1 | Wildcats|2015|1|43
2 | Wildcats|2015|2|50
I want to create a display that shows each team in the database, its total points scored for the year, and the league average points for that year.
So it might look like:
Wildcats 2015 387 44.3
etc.
I was trying this, but it's not working:
SELECT g1.year, g1.team, xyz.total
FROM game g1
join (SELECT avg(points) as total, year
FROM game g2) xyz on g1.year=xyz.year
group by g1.year, g1.team
You can use a correlated subquery to get average points per year:
SELECT team, year, SUM(points) AS totalPoints,
(SELECT AVG(points)
FROM game AS g2
WHERE g2.year = g1.year) AS avgPoints
FROM game AS g1
GROUP BY team, year
Demo here
or, with joining a derived table:
SELECT g1.team, g1.year, SUM(g1.points) AS totalPoints,
g2.avgPoints
FROM game AS g1
JOIN (SELECT AVG(points) AS avgPoints, year
FROM game
GROUP BY year
) AS g2 ON g1.year = g2.year
GROUP BY team, year
Demo here
May this query is what you looking for:
select team,year,sum(points)as total,cast(avg(points)as decimal(10,1))
as average from your_table_name group by team,year
I'm having trouble trying to sum a field GROUPED BY a common user ID from TWO DIFFERENT tables.
To give you a little more info... I am trying to track player performances by date (i.e.: most points scored on ALL Nov. 14's). The database is split, one table for regular season games and one table for playoffs. So, for example, a player may have played a regular season game on May 3, 2001....but a playoff game on May 3, 2005.
So, I'm trying to build a view with the sums of every player on all dates.
What I have for a single table:
SELECT PlayerId,sum(Points) as TOT_PTS
FROM RS_games
WHERE DAY(Date)=$cur_day
AND MONTH(Date)=$cur_month
GROUP BY PlayerId
...but I can't figure how I could sum the values of each player across two tables without creating a third view as a "stepping stone".
Any ideas?
If you want the results by (DAY-MONTH) you can do:
SELECT playerID,
CONCAT (DAY(DATE), '-', MONTH(DATE)) AS DAY_MONTH,
SUM(points) AS Total_Points
FROM (
SELECT playerID, DATE, points
FROM rs_games
UNION ALL
SELECT playerID, DATE, points
FROM po_games
) a
GROUP BY 1, 2
sqlfiddle demo
This way, you would end up with a result with every playerId,dd-mm, and the sum of points that were scored in that specific day across the years.
Just to lay out what I was saying:
select
ALL_players.PlayerID as PlayerID
COALESCE(reg.Points, 0) + COALESCE(po.Points, 0) as Points
from
ALL_players
left join
(select PlayerID, DATE(Date) as Date, sum(Points) as Points
from RS_games
WHERE DAY(Date)=$cur_day AND MONTH(Date)=$cur_month
group by PlayerID) as reg
on reg.PlayerID = ALL_players.PlayerID
left join
(select PlayerID, DATE(Date) as Date, sum(Points) as Points
from PO_games group by DATE(Date), PlayerID
WHERE DAY(Date)=$cur_day AND MONTH(Date)=$cur_month
group by PlayerID) as po
on po.PlayerID = ALL_players.PlayerID
EDIT: Looking again at requirements this will need either a full outer join or some adjustment... adjusting (should be working now)
So I have this weekly vote for best players of the game. Users can vote for 3 best players, 1st gets 3 points, 2nd 2p and 3rd 1p. So it would be easy just to count all votes of all games and figure out who is the best. But the number of votes per game can be significantly different.
For example:
Vote1:
1st: 100 of total 500 votes -> 20%
Vote2:
1st: 40 of total 100 votes -> 40%
So I would want to count all votes of all games so that every game is equally important. Basically I think I just need to count percentage of votes per game and sum then together. But how can I achieve this easily?
My table is like this:
id, game_id, player3, player2, player1
Here's one way using UNION ALL to put all your players together (if I'm understanding your question correctly) -- not completely sure of your desired results, so have just left like this for now.
select player_id, sum(points)
from (
select player3 player_id, 3 points
from games
union all
select player2, 2
from games
union all
select player1, 1
from games
) t
group by player_id
SQL Fiddle Demo
I'm looking for a way to write one query to compare the results of multiple mysql subqueries, and return users that are in each query.
I have a that contains fantasy football stats for players. To simplify, in this case there are 3 columns I'm using: player, points, year.
I'm looking to run a query that returns a list of players who finished in the top 50 (based on points) in both 2010 and 2011.
I've done lots of searching around on playing with subqueries, doing joins on one table, etc but am still coming up at a loss on how to approach this.
You can do something like this:
SELECT a.player
FROM (SELECT player FROM players WHERE Year = 2010 ORDER BY points DESC LIMIT 50) a
JOIN
(SELECT player FROM players WHERE Year = 2011 ORDER BY points DESC LIMIT 50) b
ON a.player = b.player
Here is an example. I assumed that you calculate top50 based on sum of points and you have several entries for each player in each year.
select y2010.player
from (
select player, sum from (
select st1.player player, sum(st1.points) sum from stats st1 where st1.year = 2010 group by st1.player order by sum desc
) t1 limit 50 offset 0
) y2010, (
select player, sum from (
select st1.player player, sum(st1.points) sum from stats st1 where st1.year = 2011 group by st1.player order by sum desc
) t1 limit 50 offset 0
) y2011
where y2010.player = y2011.player
You can use a UNION ALL, this will get you the Top 50 in both years and put them in the same result set, no joining required:
(
select player, year, points
from players
where year = 2010
order by points desc
limit 50
)
union all
(
select player, year, points
from players
where year = 2011
order by points desc
limit 50
);
It's slightly ambiguous whether you want:
all players who finished in the top 50 in 2010, as well as all players who finished in the top 50 in 2011:
SELECT *
FROM scores
WHERE year = 2010
AND points >= (SELECT MIN(points) FROM (
SELECT points
FROM scores
WHERE year = 2010
ORDER BY points DESC
LIMIT 50
) t)
UNION ALL
SELECT *
FROM scores
WHERE year = 2011
AND points >= (SELECT MIN(points) FROM (
SELECT points
FROM scores
WHERE year = 2011
ORDER BY points DESC
LIMIT 50
) t)
all players who finished in the top 50 in both 2010 and 2011, in which case you'll need to further group the results:
SELECT player
FROM (
-- query as above
) t
GROUP BY player
HAVING COUNT(DISTINCT year) = 2