I am trying to calculate the stock by product a warehouse had over time. I have the information about today's stock, and also the amount of products sold and purchased by day. So, the calculation for yesterday values would be:
Yesterday_stock=Stock-yesterday_sold_quantity+yesterday_purchased_quantity. My problem is that i should save somewhere the amount of everyday's stock in order to calculate the stock of the previous day. I found that in order to do that i could use over sql clause with order by. But unfortunately, i have sql server 2008 and this is not a choice.
The tables are:
Prdamount which holds the current stock per product (StuPrdID ) and if it is blocked for some reason.
|-------------- |------------------|---------------
| StuPrdID | StuQAmount |prdBlockingReason
|---------------|------------------|-------------
| 12345| 16 |
|---------------|------------------|--------------
| 08889| 12 | expired
|---------------|------------------|------------
Table Moves which holds information about inserts and outputs of products. If MoveCase field has value equal 1 it is an output move, if it is a 2 it is a purchased quantity. Moves table dummy data:
|-------------- |--------------------- -|--------|-------
|MoveItemCode | MoveDate |MoveCase|MoveRealQty
|---------------|---------------------- |--------|-------
| 12345 |2018-06-24 00:00:00.000| 1 |14
|---------------|-----------------------|--------|--------
| 08889 |2018-06-24 00:00:00.000| 2 |578
|---------------|-----------------------|--------|--------
and table Product with information related with data:
|-------------- |------------------|
| PrdCode | PrdDespription |
|---------------|------------------|
| 12345| Orange juice|
|---------------|------------------|
| 08889| Chocolate|
|---------------|------------------|
I want an output like this:
|------------|--------------------- -|--------|--------------|------------
|Prdcode | PrdDescription |Stock |Stock 18/07/03|Stock 18/7/02
|------------|---------------------- |--------|--------------|------------
| 12345 |Orange Juice | 80 |50 34
|----------- |-----------------------|--------|--------------|------------
| 08889 |Chocolate | 45 |82 17
|------------|-----------------------|--------|--------------|-------------
this query gives me the running stock:
select
product.PrdCode,
product.PrdDescr,
SUM(StuQAmount) as Stock
from prdamount
left join product on (product.PrdID=prdamount.StuPrdID)
where prdamount.prdBlockingReason=' '
group by product.PrdCode,product.PrdDescr
order by product.PrdCode asc
This query gives me the quantity sold by product per day:
select
moves.MoveItemCode,
prd.PrdDescr,
moves.MoveDate,
SUM(MoveRealQty) as 'sold_quantity'
from moves
left join prd on (moves.MoveItemCode=product.PrdCode)
where (moves.MoveDate>'2018-06-01' and and moves.MoveCase=1)
group by moves.MoveItemCode,product.PrdDescr,moves.MoveDate
order by moves.MoveItemCode asc,moves.MoveDate asc
And this query gives me the quantity purchases by product per day:
select
moves.MoveItemCode,
prd.PrdDescr,
moves.MoveDate,
SUM(MoveRealQty) as 'Purchased_Quantity'
from Moves
left join product on (moves.MoveItemCode=product.PrdCode)
where (moves.MoveDate>'2018-06-01' and moves.MoveCase=2)
group by moves.MoveItemCode,product.PrdDescr,moves.MoveDate
order by moves.MoveItemCode asc,moves.MoveDate asc
I tried to combine these 3 queries into one using subqueries, but it didn't work. So how can i accomplish the result that i want? Sorry if the question is silly, i am a beginner in sql
try this,
select
product.PrdCode,
moves.MoveItemCode,
product.PrdDescr,
moves.MoveDate,
SUM( case when moves.MoveCase=1 then MoveRealQty else 0 end) as 'sold_quantity',
SUM( case when moves.MoveCase=2 then MoveRealQty else 0 end) as 'Purchased_Quantity',
(select SUM(StuQAmount) from prdamount where StuPrdID = product.PrdID and prdBlockingReason=' ')
from moves
left join product on (moves.MoveItemCode=product.PrdCode)
where (moves.MoveDate>'2018-06-01')
group by moves.MoveItemCode,product.PrdDescr,moves.MoveDate, product.PrdCode
order by moves.MoveItemCode asc,moves.MoveDate asc
Related
I am trying to improve this query given that it takes a while to run. The difficulty is that the data is coming from one large table and I need to aggregate a few things. First I need to define the ids that I want to get data for. Then I need to aggregate total sales. Then I need to find metrics for some individual sales. This is what the final table should look like:
ID | Product Type | % of Call Sales | % of In Person Sales | Avg Price | Avg Cost | Avg Discount
A | prod 1 | 50 | 25 | 10 | 7 | 1
A | prod 2 | 50 | 75 | 11 | 4 | 2
So % of Call Sales for each product and ID adds up to 100. The column sums to 100, not the row. Likewise for % of In Person Sales. I need to define the IDs separately because I need it to be Region Independent. Someone could make sales in Region A or Region B, but it does not matter. We want aggregate across Regions. By aggregating the subqueries and using a where clause to get the right ids, it should cut down on memory required.
IDs Query
select distinct ids from tableA as t where year>=2021 and team = 'Sales'
This should be a unique list of ids
Aggregate Call Sales and Person Sales
select ids
,sum(case when sale = 'call' then 1 else 0 end) as call_sales
,sum(case when sale = 'person' then 1 else 0 end) as person_sales
from tableA
where
ids in t.ids
group by ids
This will be as follows with the unique ids, but the total sales are from everything in that table, essentially ignoring the where clause from the first query.
ids| call_sales | person_sales
A | 100 | 50
B | 60 | 80
C | 100 | 200
Main Table as shown above
select ids
,prod_type
,cast(sum(case when sale = 'call' then 1 else 0 end)/CAST(call_sales AS DECIMAL(10, 2)) * 100 as DECIMAL(10,2)) as call_sales_percentage
,cast(sum(case when sale = 'person' then 1 else 0 end)/CAST(person_sales AS DECIMAL(10, 2)) * 100 as DECIMAL(10,2)) as person_sales_percentage
,mean(price) as price
,mean(cost) as cost
,mean(discount) as discount
from tableA as A
where
...conditions...
group by
...conditions...
You can combine the first two queries as:
select ids, sum( sale = 'call') as call_sales,
sum(sale = 'person') as person_sales
from tableA
where
ids in t.ids
group by ids
having sum(year >= 2021 and team = 'Sales') > 0;
I'm not exactly sure what the third is doing, but you can use the above as a CTE and just plug it in.
I am running the following query and at first it appears to give the sub totals for customers and shows by date each customers payment amounts only if that total for all payments is greater than $90,000.
SELECT
Customername,
Date(paymentDate),
CONCAT('$', Round(SUM(amount),2)) AS 'High $ Paying Customers'
FROM Payments
JOIN Customers
On payments.customernumber = customers.customernumber
Group by customername, Date(paymentDate) WITH ROLLUP
having sum(amount)> 90000;
But upon looking at the records for Dragon Souveniers, Ltd. and Euro+ Shopping Channel is is actually showing the paydates that have amounts individually over $90000 as well as the subtotal for that customer as a rollup. For all other customers, their individual payment dates are not reported in the result set and only their sum is if it over $90000. For example Annna's Decorations as 4 payment records and none of them are over 90000 but her sum is reported as the value for the total payments in the query with the rollup. Is this the correct interpretation?
The HAVING clause work correct, It filters all records with a total no above 90000. It also does do this for totals.
When using GROUP BY .... WITH ROLLUP, you can detect the created ROLL UP lines by using the GROUPING() function.
You should add a condition in a way that the desired columns are not filtered.
Simple example:
select a, sum(a), grouping(a<3)
from (select 1 as a
union
select 2
union select 3) x
group by a<3 with rollup;
output:
+---+--------+---------------+
| a | sum(a) | grouping(a<3) |
+---+--------+---------------+
| 3 | 3 | 0 |
| 1 | 3 | 0 |
| 1 | 6 | 1 |
+---+--------+---------------+
this shows that the last line (with grouping(i<3) == 1) is a line containing totals for a<3.
I wanted to ask you for your help to create a query that will let me do the following:
I have an online shop, and I have a database where I store the products each user has viewed with a timestamp. I want to visualize 'product sessions', what I mean by this is to obtain the time the user spent watching products divided by day (and also how many products were viewed during this day).
An example:
My recently viewed table with user ID
I want to create a query that will give me this output
| DAY | TIME | PRODUCTS |
----------------------------------
|2018-07-31| 00:00:04 | 2 |
----------------------------------
|2018-08-01| 02:38:56 | 5 |
So far I was only able to do this:
SELECT DATE(`added_timestamp`) AS day, COUNT(*) AS num_products
FROM tb_recently_viewed
WHERE `user_id`= 'bac240e3eefbb7dff0bc03d00f392f0d'
GROUP BY DATE(`added_timestamp`)
ORDER BY day
Which outputs the products seen in a day:
Any help would be appreciate it.
Here you go:
select
date(added_timestamp) as day,
count(*) as num_products,
timediff(max(time(added_timestamp)), min(time(added_timestamp))) as time_diff
from tb_recently_viewed
group by date(added_timestamp)
Result:
day num_products time_diff
---------- ------------ ---------
2018-07-31 2 00:00:04
2018-08-01 2 02:38:56
I have a database with an producer and product table and I'm trying to find the producer(s) with the most expensive products on average. Basically I've got to find averages for each producers products then find the producers with the most expensive averages, in which there can be more than one producer with the most expensive average if they have the same average.
I've attempted with the code below but don't understand why its not working out?
Forget to mention this is for SQL.
EDIT:Forgot to say that the result should only display the most expensive averages
SELECT producerId, average
FROM (SELECT producerId, AVG(productPrice) AS average
FROM product NATURAL JOIN producer
GROUP BY producerId) AS averages
WHERE MAX(average)
Example:
producerID | average
1 | 10
2 | 8.5
3 | 10
4 | 9
5 | 8
Result:
producerID | average
1 | 10
3 | 10
If you want to get 3 most expensive producers, use query like this:
SELECT producerId, average
FROM (
SELECT pr.producerId, AVG(pr.productPrice) AS average
FROM product AS pp INNER JOIN producer AS pr ON pp.producerId = pr.producerId
GROUP BY pr.producerId
) AS T
ORDER BY average DESC
LIMIT 3;
For further information, please see the documentation: https://dev.mysql.com/doc/refman/5.0/en/select.html
I am trying to get the maximum value out of a aggregate function, and then also get the min value out of a Price column which comes back in results.
id | discount | price
1 | 60 | 656
2 | 60 | 454
3 | 60 | 222
4 | 30 | 335
5 | 30 | 333
6 | 10 | 232
So in above table, I would like to separate Minimum Price vs Highest Discount.
This is the result I should be seeing:
id | discount | price
3 | 60 | 222
5 | 30 | 333
6 | 10 | 232
As you can see, its taken discount=60 group and separated the lowest price - 222, and the same for all other discount groups.
Could someone give me the SQL for this please, something like this -
SELECT MAX(discount) AS Maxdisc
, MIN(price) as MinPrice
,
FROM mytable
GROUP
BY discount
However, this doesnt separate the minimum price for each group. I think i need to join this table to itself to achieve that. Also, the table contains milions of rows, so the sql needs to be fast. One flat table.
This question is asked and answered with tedious regularity in SO. If only the algorithm was better at spotting duplicates. Anyway...
SELECT x.*
FROM my_table x
JOIN
( SELECT discount,MIN(price) min_price FROM my_table GROUP BY discount) y
ON y.discount = x.discount
AND y.min_price = x.price;
In your query, you cannot group by discount and then maximize the discount value.
This should get you the result you are looking for..
SELECT Max(ID) AS ID, discount, MIN(price) as MinPrice, FROM mytable GROUP BY discount
If you do not need the id, yo would do:
select discount, min(price) as minprice
from table t
group by discount;
If you want other columns in the row, you can either join back to the original table or use the substring_index()/group_concat() trick:
select substring_index(group_concat(id order by price), ',', 1) as id,
discount, min(price)
from table t
group by discount;
This will not always work because the intermediate result for group_concat() can overflow if there are too many matches within a column. This is controlled by a system parameter, which could be made bigger if necessary.