"SELECT count(id) AS total FROM participant where dateofbooking='$datepick'";
I am using this code. But its showing only one date(selected date from php) count. but I want to select single date and it should show me upto 5 days daily wise count booking.
output should be like this:-
2018-05-20------>48
2018-05-21------>58
2018-05-22------>67
2018-05-23------>78
2018-05-24------>43
You can use DATE_ADD() :
SELECT dateofbooking, count(id) AS total
FROM participant
WHERE dateofbooking >= $datepick AND
dateofbooking <= DATE_ADD($datepick, INTERVAL 5 DAY)
GROUP BY dateofbooking;
You can group it by the date column you are using, and if you want multiple days you can add dateofbooking >= some_start_date and dateofbooking <= some_end_date
"SELECT count(id) AS total FROM participant where dateofbooking='$datepick' group by dateofbooking";
the multiple may look something like
"SELECT count(id) AS total FROM participant where dateofbooking>='$datepickstart' AND dateofbooking<='$datepickend' group by dateofbooking";
Related
how can I count last 7 days data from SQL and group them by day/date (excluding today).
I should be able to use the result as $resultday1, $resultday2, $resultday3 etc.
If there was 10 total SQL entries in day 1 (yesterday) $resultday1 should show "10".
and the days should be last 7 only, and today/current day should not consider.
The following PHP SQL script shows the total count only
SELECT COUNT(1) FROM orders WHERE username='jondoe'
database is a list of referrals made by a registered user in previous days.
a single table contains all user's referral details, table name "orders" as per above example.
This is the exact query as you want
SELECT
COUNT(*), DATE(order_date) order_date
FROM
orders
WHERE
order_date < CURDATE()
AND order_date > DATE_SUB(NOW(), INTERVAL 7 DAY)
GROUP BY order_date
ORDER BY order_date DESC;
Hi i am trying to get the count of records per day which i can do, but i also want the date to be show, for example,
Result
Date | Count
26/01/2015 20
25/01/2015 | 413
Here is an example of my data.
I would think this would work. Replace 'yourTable' with your table name
SELECT Date, COUNT(*) FROM yourTable GROUP BY Date;
Get the total count and group them by date.
SELECT `date`, COUNT(*) as Total
FROM `table`
GROUP BY `date`
ORDER BY `date`;
Hi I am not perfect in mysql queries i tried this code to get previous date record count
code snippet
SELECT id, date, COUNT(IF(date<= date-INTERVAL 1 DAY, id, NULL))
FROM table_name
GROUP BY date
this query gives me prev day value is 0.
help me out to get previous day count of id
this is what i need
date count
-------------------
2014-01-01 0
2014-01-02 13
2014-01-03 55
I suspect you rather look for something like this, to count id's from yesterday:
select
date(dt),
count(id)
from
table_name
where
date(dt) < date(now())
group by
date(dt)
Score Table
user_idx (int)
date (datetime)
score (int)
I need to find out how much total score has increased over a week from today's date. I know that I need two of the same user tables grouped by user_idx that one contains total scores from the past to today and the other contains total scores from the past to a date of a week ago.
After that, by substracting one from the other will give me the answer... but I'm struggling to write effective sql query that does it.
I've tried
SELECT BLAH BLAH
FROM (SELECT user_idx, COUNT(*) as last_week_study_amount
FROM user_table
WHERE date <= date_sub(now(),INTERVAL 1 WEEK)
GROUP BY user_idx)
AS a WHERE .....
Could you help me :( ?
Let me clear you want to get total count in last week.
Try below query
SELECT *
FROM (SELECT user_idx, COUNT(*) as last_week_study_amount
FROM user_table
WHERE date <= date_sub(now(),INTERVAL 1 WEEK)
GROUP BY user_idx)
AS a WHERE .....
SELECT (SUM(score) - last_week_score) AS increased_score,
FROM user a
JOIN (SELECT b.user_idx, COUNT(*) as last_week_score
FROM userb
WHERE date<= date_sub(now(),INTERVAL 1 WEEK)
GROUP BY b.user_idx) As c ON a.user_idx = c.user_idx
WHERE DATE(date) <= DATE(NOW())
GROUP BY a.user_idx
I ended up writing this code and I think this one is working okay... not sure if it's the best or has a critical error. I will update it if it turns out to be a bad one...
I'm having a table with posts. Like (id int, date datetime).
How can I select average posts per day count for each month with one sql request?
Thank you!
This should do it for you:
select month, avg(posts_per_day)
from (select day(date), month(date) as month, count(*) as posts_per_day
from posts group by 1,2) x
group by 1
Explanation: Because you are doing an aggregate on an aggregate, there is no getting around doing a query on a query:
The inner query calculates the number per day and captures the month.
The outer query averages this count , grouping by month.
You can get the number of posts per month like this:
SELECT COUNT(*) AS num_posts_per_month FROM table GROUP BY MONTH(date);
Now we need the number of days in a month:
SELECT COUNT(*) / DATEDIFF(MAKEDATE(YEAR(date), MONTH(date)) + INTERVAL 1 MONTH, MAKEDATE(YEAR(date), MONTH(date))) AS avg_over_month
FROM table GROUP BY MONTH(date);
This will get the average number of posts per day during the calendar month of the post. That is, averages during the current month will continue to rise until the end of the month. If you want real averages during the current month, you have to put in a conditional to get the true number of elapsed days.