Laravel Query Builder - where clause equals anything programmatically - mysql

Question

I'm using Laravel 5.6 - Query Builder.
Is it possible to make a query builder where statement that a value equals everything programmatically?
Let's say that I have this code:
$foo = 1;
DB::table('users')
->select('*')
->where('status', '=', $foo)
->get();
If $foo = 1 then it's straightforward. The query will select everything with the status of 1.
Q: Is it possible to assign something to the $foo variable so the select query returns every record regardless of the status from the DB?
Of course, I can make it happen with 2 query statements like this:
$foo = 1;
if ($foo === null) {
DB::table('users')
->select('*')
->get();
} else {
DB::table('users')
->select('*')
->where('status', '=', $foo)
->get();
}
However, I'm looking for a shorter / more effective solution. Is it possible somehow - without using raw code inside the Where statement?

Answer 1

You may try something like this:
$query = DB::table('users')->select('*');
// $foo = 'get it...';
if ($foo) {
$query->where('status', $foo);
}
$result = $query->get();
Or even more laravel-ish:
$result = DB::table('users')->select('*')
->when($foo, function ($query) use ($foo) {
return $query->where('status', $foo);
})
->get();
Check more here.