Mapping JSON Array to Spring Hibernate Database (H2) - json

Question

Hi I'm trying to map a JSON to databse table in SprinBoot.
This is my #Entity:
#Data
#AllArgsConstructor
#Entity
public class User {
#Id
#GeneratedValue( strategy = GenerationType.AUTO )
private Long id;
private String name;
private String tagline;
private String first_brewed;
#Column(length=700)
private String description;
private String image_url;
private Long ibu;
private String[] food_pairing;
public User() {}
}
And JSON looks that:
[
{
"id": 1,
"name": "Buzz",
"tagline": "A Real Bitter Experience.",
"first_brewed": "09/2007",
"description": "A light, crisp and bitter IPA brewed with English and American hops. A small batch brewed only once.",
"image_url": "https://images.punkapi.com/v2/keg.png",
"ibu": 60,
"food_pairing": [
"Spicy chicken tikka masala",
"Grilled chicken quesadilla",
"Caramel toffee cake"
]
}
]
I want to save this in to the H2 database.
Got only 1 column in the database with string of letters and numbers
My question is: How to change
private String[] food_pairing;
to show all food_pairings as a separate columns in the database?
(If I have an object in JSON i can do that in the #Entity:
#Embedded private Address address;
And then in other class:
#Embeddable public class Address {
private String street;
private String suite;
}
And I have a automatic created columns in my database. I want to do the same but not with an object in JSON only with an Array of Strings in JSON.

Answer 1

If I understand your requirement, you want to persist this array private String[] foodPairing; in one column. If so, you can proceed like below :
public class User {
....
#Transient
private String[] foodPairing;
#Column(name="food_pairing")
private String food_Pairing;
}
And before persisting your entity you can do this:
user.setFood_Paring(user.getFoodPairing().toString());
Then persist.
EDIT:
In case where you want each String in a one column, you can add 3 fields in your entity like this:
public class User {
....
#Transient
private String[] foodPairing;
#JsonIgnore
#Column(name="food_pairing1")
private String foodPairing1;
#JsonIgnore
#Column(name="food_pairing2")
private String foodPairing2;
#JsonIgnore
#Column(name="food_pairing3")
private String foodPairing3;
}
And when you persist:
user.setFoodParing1(user.getFoodPairing()[0]); //etc...