Is a "Try / Except ValueError UNLESS" possible? - exception

Question

I'm new to python and have been trying like hell for the past few hours to figure out how to get this to work properly...
It's very simple code I'm sure, but I'm just not getting it.
It should be pretty self-explanatory below in the code, but basically I'm asking a user to input the date of an event as an 'int' and if it's not a number, then ask them to try again... UNLESS it's a "?"
while True:
date = None
street = str(input('Name of street?: ').title())
city = str(input("In what city?: ").title())
while True:
try:
year = int(input("Date of event? (or '?'): "))
if date == "?":
break
except Exception:
print("That's not a date, try again!")
continue
break
It seems that it's not even getting to see IF because it gets caught by the 'except' before it can.

Answer 1

If you're going to display help or something when a '?' is input, then just call the function to display the help where you have the break currently.
if date == "?":
display_help()
continue
Then, split reading the input and processing it into two steps.
in = input("Date of event? (or '?'): ")
if in == "?":
display_help()
continue
year = int(in)
Also, you ask for a date but then assume that a year is entered, I'd be more explicit in your promt.
"Please enter the year of the event, ex: 1998"
or whatever form you actually want it in.

Answer 2

Trying using a valueError exception. Also I think in your post you mentioned you wanted to enter a date as integer, so I replaced year with the date. If you wanted the year to be an integer you can replace the variable date with year. If you wanted to the user to enter a year, day and month then this program needs to be redesigned a bit.
date = None
street = str(input('Name of street?: ').title())
city = str(input("In what city?: ").title())
while True:
date = input("Date of event? (or '?'): ")
if date == "?":
break
else:
try:
date = int(date)
except ValueError:
print("That's not a date, try again!")
continue
break