There is an INT field which I store timestamps in table.
I am trying to select rows 1 week before this timestamp
WHERE last_loc_date > DATE(NOW()) - INTERVAL 1 WEEK
Doesn't work. Any idea?
You could use unix_timestamp to calculate second argument:
WHERE last_loc_date > unix_timestamp(DATE(NOW()) - INTERVAL 1 WEEK)
Please avoid using FROM_UNIXTIME(last_loc_date) > DATE(NOW()) - INTERVAL 1 WEEK. This condition is not SARGable unless you use function-based index.
Don't use DATE(now()) if you want respect the strictly one week
WHERE last_loc_date > unix_timestamp(NOW() - INTERVAL 1 WEEK)
Related
I want to retrieve records from db according to date format YYYY,MM,dd given by me but the column type is YYYY,MM,dd hh:mm:ss.
tried to use Date format function
SELECT *
FROM tabl.error_logs
where created_at = DATE_FORMAT(NOW(),'%Y-%m-%d'- INTERVAL 3 DAY);
I expect the created date will be 2019-06-08, but the result is empty
What is the actual datatype of created_at column?
This answer is going to ignore that funkiness with the format with commas, and assume that it's not character type data, and that it's DATETIME or TIMESTAMP.
Normative pattern for predicates on DATETIME and TIMESTAMP columns is a range comparison.
For example, to get all datetimecol values on June 10th, then something like this:
WHERE t.datetimecol >= '2019-06-10 00:00:00'
AND t.datetimecol < '2019-06-11 00:00:00'
Typically, I would just pass that one date value, and let MySQL figure out the next day. If we omit the time portion, MySQL will assume 00:00:00
WHERE t.datetimecol >= '2019-06-10' + INTERVAL 0 DAY
AND t.datetimecol < '2019-06-10' + INTERVAL 1 DAY
For performance, to allow MySQL to make effective use of a range scan operation on a suitable index, we want to avoid wrapping the column reference in a function. That is, specifying DATE(t.datetimecol) in a condition in the WHERE clause is going to force MySQL to evaluate the DATE() function on every row in the table.
With references to the bare column, that allows MySQL to make use of an index, if a suitable index is available.
e.g.
SELECT e.*
FROM tabl.error_logs e
WHERE e.created_at >= DATE(NOW()) + INTERVAL -3 DAY
AND e.created_at < DATE(NOW()) + INTERVAL -2 DAY
note that we can easily test those expressions in the WHERE clause, to verify they are returning what we want, and tweak as necessary:
SELECT DATE(NOW()) + INTERVAL -3 DAY
, DATE(NOW()) + INTERVAL -2 DAY
To make your query sargable, you need ...
SELECT *
FROM tabl.error_logs
WHERE created_at >= DATE_SUB(CURDATE(), INTERVAL 3 DAY)
AND created_at < DATE_SUB(CURDATE(), INTERVAL 2 DAY)
This selects all values of created_at on or after midnight three days ago, up to but not including < midnight two days ago. It uses a range scan on an index on created_at if one is available.
You coudl use date_sub()
SELECT *
FROM tabl.error_logs
where date(created_at) = DATE_SUB(date(now()), INTERVAL 3 DAY);
if the column created_at is a date then you could avoid the date() function and let the index (if present) work for this column
SELECT *
FROM tabl.error_logs
where created_at = DATE_SUB(date(now()), INTERVAL 3 DAY);
I need to check for entries made in the last "x" days (example 30 days) and cannot get the query to work. This is what I am using:
SELECT CAL_OWNER,
CAL_TITLE,
FROM_UNIXTIME (CAL_CREATED, "%m-%d-%y") AS CREATED,
FROM_UNIXTIME (RANGE_START, "%Y-%m-%d") AS DATE2BESEEN,
CASE CAL_REFERRAL_TYPE
WHEN 1 THEN 'NoReferral'
WHEN 2 THEN 'CareyGuide'
WHEN 3 THEN 'Education'
WHEN 4 THEN 'Employment'
WHEN 5 THEN 'Housing'
WHEN 6 THEN 'Medical'
ELSE 'NA'
END
AS REFERRALS
FROM EGW_CAL
WHERE CAL_CREATED BETWEEN (NOW () - '30 day') AND NOW ()
ORDER BY REFERRALS ASC;
If I comment out the "WHERE range_start ... line the query runs fine, but pulls all data
However, if I run the complete query, it does not error, but there are no results (I have 4 entries in column cal_created in the last 3 weeks).
If some one can help I'd really appreciate it
Try using INTERVAL and either NOW() or CURDATE()..
WHERE FROM_UNIXTIME (CAL_CREATED,'%Y-%m-%d') BETWEEN CURDATE() - INTERVAL 30 DAY AND CURDATE()
curdate is just the date portion of the day
if you want to include the time use NOW()
WHERE FROM_UNIXTIME (CAL_CREATED,'%Y-%m-%d') BETWEEN NOW() - INTERVAL 30 DAY AND NOW()
you could also make a new date to use the between with
WHERE FROM_UNIXTIME (CAL_CREATED,'%Y-%m-%d') BETWEEN DATE_SUB(NOW(), INTERVAL 30 DAY) AND NOW()
SOURCE: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html
NOTE: the dates need to be formatted correctly in order for it to work
FULL QUERY:
SELECT
CAL_OWNER,
CAL_TITLE,
FROM_UNIXTIME (CAL_CREATED, '%m-%d-%y') AS CREATED_AT,
FROM_UNIXTIME (RANGE_START, '%Y-%m-%d') AS DATE2BESEEN,
CASE CAL_REFERRAL_TYPE
WHEN 1 THEN 'NoReferral'
WHEN 2 THEN 'CareyGuide'
WHEN 3 THEN 'Education'
WHEN 4 THEN 'Employment'
WHEN 5 THEN 'Housing'
WHEN 6 THEN 'Medical'
ELSE 'NA'
END AS REFERRALS
FROM EGW_CAL
WHERE FROM_UNIXTIME(CAL_CREATED,'%Y-%m-%d') BETWEEN (NOW() - INTERVAL 30 DAY) AND NOW()
ORDER BY REFERRALS ASC;
CAL_CREATED is a UNIX timestamp,
NOW() will return a MySQL timestamp.
They don't mix automatically. So use
WHERE CAL_CREATED
BETWEEN UNIX_TIMESTAMP(NOW() - INTERVAL 30 DAY) AND UNIX_TIMESTAMP(NOW());
Note:
I wouldn't recommend to go the other way
WHERE FROM_UNIXTIME(CAL_CREATED) BETWEEN ...
because MySQL can't use an index in this case.
The correct where clause uses internval:
WHERE CAL_CREATED BETWEEN NOW() - interval 30 day AND NOW()
The use of single quotes is reminiscent of Postgres. In MySQL, it ends up treating the value of now() as an integer. And it subtracts the string value "30 days" from it.
When now() is treated as an integer, it also has hours, minutes, and seconds. So you are really subtracting something like 30 seconds. Here is the documentation on now().
How do I subtract 30 days from the current datetime in mysql?
SELECT * FROM table
WHERE exec_datetime BETWEEN DATEDIFF(NOW() - 30 days) AND NOW();
SELECT * FROM table
WHERE exec_datetime BETWEEN DATE_SUB(NOW(), INTERVAL 30 DAY) AND NOW();
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-add
To anyone who doesn't want to use DATE_SUB, use CURRENT_DATE:
SELECT CURRENT_DATE - INTERVAL 30 DAY
MySQL subtract days from now:
select now(), now() - interval 1 day
Prints:
2014-10-08 09:00:56 2014-10-07 09:00:56
Other Interval Temporal Expression Unit arguments:
https://dev.mysql.com/doc/refman/5.5/en/expressions.html#temporal-intervals
select now() - interval 1 microsecond
select now() - interval 1 second
select now() - interval 1 minute
select now() - interval 1 hour
select now() - interval 1 day
select now() - interval 1 week
select now() - interval 1 month
select now() - interval 1 year
Let's not use NOW() as you're losing any query caching or optimization because the query is different every time. See the list of functions you should not use in the MySQL documentation.
In the code below, let's assume this table is growing with time. New stuff is added and you want to show just the stuff in the last 30 days. This is the most common case.
Note that the date has been added as a string. It is better to add the date in this way, from your calling code, than to use the NOW() function as it kills your caching.
SELECT * FROM table WHERE exec_datetime >= DATE_SUB('2012-06-12', INTERVAL 30 DAY);
You can use BETWEEN if you really just want stuff from this very second to 30 days before this very second, but that's not a common use case in my experience, so I hope the simplified query can serve you well.
You can also use
select CURDATE()-INTERVAL 30 DAY
SELECT date_format(current_date - INTERVAL 50 DAY,'%d-%b-%Y')
You can format by using date format in SQL.
If you only need the date and not the time use:
select*from table where exec_datetime
between subdate(curdate(), 30)and curdate();
Since curdate() omits the time component, it's potentially faster than now() and more "semantically correct" in cases where you're only interested in the date.
Also, subdate()'s 2-arity overload is potentially faster than using interval.
interval is meant to be for cases when you need a non-day component.
another way
SELECT COUNT(*) FROM tbl_debug WHERE TO_DAYS(`when`) < TO_DAYS(NOW())-30 ;
Is there a way in a MySQL statement to order records (through a date stamp) by >= NOW() -1 so all records from the day before today to the future are selected?
Judging by the documentation for date/time functions, you should be able to do something like:
SELECT * FROM FOO
WHERE MY_DATE_FIELD >= NOW() - INTERVAL 1 DAY
Be aware that the result may be slightly different than you expect.
NOW() returns a DATETIME.
And INTERVAL works as named, e.g. INTERVAL 1 DAY = 24 hours.
So if your script is cron'd to run at 03:00, it will miss the first three hours of records from the 'oldest' day.
To get the whole day use CURDATE() - INTERVAL 1 DAY. This will get back to the beginning of the previous day regardless of when the script is run.
Didn't see any answers correctly using DATE_ADD or DATE_SUB:
Subtract 1 day from NOW()
...WHERE DATE_FIELD >= DATE_SUB(NOW(), INTERVAL 1 DAY)
Add 1 day from NOW()
...WHERE DATE_FIELD >= DATE_ADD(NOW(), INTERVAL 1 DAY)
You're almost there: it's NOW() - INTERVAL 1 DAY
Sure you can:
SELECT * FROM table
WHERE DateStamp > DATE_ADD(NOW(), INTERVAL -1 DAY)
when search field is timestamp and you want find records from 0 hours yesterday and 0 hour today use construction
MY_DATE_TIME_FIELD between makedate(year(now()), date_format(now(),'%j')-1) and makedate(year(now()), date_format(now(),'%j'))
instead
now() - interval 1 day
I need to get the result from the table, which the date should be difference of 5 from the current date.
ie., specific_date column is present in my table. The format of the date is YYYY-MM-DD.
I need the query something like,
SELECT * FROM `table_name` WHERE DATEDIFF(NOW(), specific_date) < 5
It looks like you are trying to do this:
WHERE specific_date < (NOW() + 5 days)
First of all, think carefully about the boundary cases. These boundary cases can bite your ankles in SQL. Do you actually want
WHERE specific_date <= (NOW() + 5 days)
Do your specific_date columns timestamps contain only days (that is dates with times equal to midnight) or do they contain dates and times? If you're going to get the results you want, you need to be careful about those details.
At any rate, try this:
WHERE specific_date <= DATE_ADD(NOW(), INTERVAL 5 DAY)
This is a good way to do such a lookup. The column value stands alone on one side of the inequality predicate (the <=) so mySQL can do an index range scan if you have an index on the column.
Date arithmetic in MySQL is quite flexible. You can do
NOW() + INTERVAL 10 SECOND
NOW() - INTERVAL 2 MINUTE
NOW() + INTERVAL 4 HOUR
CURDATE() - INTERVAL 1 WEEK /* midnight one week ago */
LAST_DAY(NOW()) + INTERVAL 1 DAY - INTERVAL 1 MONTH /*first day of present month*/
NOW() - INTERVAL 1 QUARTER
CURDATE() - INTERVAL 5 YEAR
and so forth.
Have a look at the BETWEEN operator.
expr BETWEEN min AND max
Another way is to use the DATE_SUB operator
WHERE date_column > DATE_SUB(NOW(), INTERVAL 5 DAY)