t-sql for json skip column names in a result - json

Question

I have the following t-sql query that returns json:
SELECT
CF.Name
, UCF.Value
FROM dbo.ClaimsCustomFields CF
LEFT JOIN dbo.UserCustomFields UCF
ON UCF.FieldId = CF.Id
WHERE CF.CustomerId = 2653
FOR JSON PATH;
The output of this query is next:
[
{
"Name":"zipCode",
"Value":"zip zip zipC zipCod"
},
{
"Name":"time111zone",
"Value":"UTC +2"
},
{
"Name":"tttt",
"Value":"Company organization tessss"
}
]
But I want to get the result in the following format:
[
{
"zipCode":"zip zip zipC zipCod"
},
{
"time111zone":"UTC +2"
},
{
"tttt":"Company organization tessss"
}
]
Is it possible to achive this with FOR JSON statement?

Answer 1

You basically want to generate a dynamic json, so you can try to use dynamic TSQL taking advantage of SQL Server 2017 new function STRING_AGG (more info here):
--this table contains your sample data
declare #tmp table([Name] varchar(50),[Value] varchar(50))
--this variable will contain the dynamic tsql command
declare #sql nvarchar(max)
--this temp table will hold the dynamically generated json fragments
if object_id('#tmp') is null
create table #tmp (js varchar(max))
--fill table with test data
insert into #tmp values
('zipCode' ,'zip zip zipC zipCod'),
('time111zone' ,'UTC +2'),
('tttt' ,'Company organization tessss')
--generate a TSQL command that inserts each single JSON fragment into a temp table
select #sql = string_agg('insert into #tmp(js) values((select ''' + [Value] +''' as '''
+ [Name]+''' for json path , WITHOUT_ARRAY_WRAPPER))', ';')
from #tmp
--execute the dynamic TSQL command that fills the temp table with JSON fragments
exec(#sql)
--concatenate all the JSON fragments adding square brackets
select '[' + string_agg(js,',') + ']' as result from #tmp
Results:
[{"zipCode":"zip zip zipC zipCod"},{"time111zone":"UTC +2"},{"tttt":"Company organization tessss"}]