SQL NOT IN, != what to use? - mysql

Question

I've an csv file with plant code like X001, X005, X019...
In mysql table plantcode=username.
I want to fetch all the plantcodes from my DB table where username are not present in my CSV file and deleted =0.
mycode
<?php
$file = fopen("aa.csv","r");
echo "<pre>";
//print_r(fgetcsv($file));
?>
<tr>
<td width="10%"><label>Username</label></td>
<td width="10%"><label>service center id</label></td>
<td width="10%"><label>service center name</label></td>
</tr>
<?php
$arr= fgetcsv($file);
foreach ($arr as $k => $v) {
$q= "SELECT * FROM `service_center` WHERE `deleted` = 0 AND username NOT LIKE '$v'";
$r = mysql_query($q);
$nr = mysql_num_rows($r);
if ($nr > 0) {
WHILE ($rows = mysql_fetch_array($r)) {
?>
<td><?php echo $rows['username'] ?></td>
<td><?php echo $rows['service_center_id'] ?></td>
<td><?php echo $rows['service_center_name'] ?></td>
<?php
}
}
else{
?>
<tr>
<td><?php echo $k;?></td>
<td><?php echo $v; ?></td>
<td><?php echo "No service center found";}?></td>
</tr>
<?php
}
fclose($file);
?>
I get output for each query like this
If username=X008 then from CSV i dont get X008 for one loop and in the next loop I get X008 and ,dont get present value plant code, But I want something like this
select * from service_center WHERE username != "X001, X007.." AND deleted = 0;

Answer 1

use NOT IN($name_array)
Pass username array in NOT IN
select * from service_center WHERE username NOT IN ("X001", "X007") AND deleted = 0;