I am selecting all records between NOW() and specific X day interval and came across this odd behavior that I don't understand.
I am checking 24 hours into the future and 24 hours into the past:
select * from table where date between NOW() and NOW() + 1 interval day; //works
select * from table where date between NOW() and NOW() - 1 interval day; //no records
But if I reverse the between call:
select * from table where date between NOW() + 1 interval day AND NOW(); //no records
select * from table where date between NOW() - 1 interval day AND NOW(); //works
Why does one call into the future work, but the same call into the past not work?...and if I reverse between parameters, the opposite behavior happens - does not work 24 hours into the future but does work 24 hours into the past.
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Adding #TimBiegeleisen explanation below here written out:
date = '2018-05-30' ;
select * from table where date between NOW() and NOW() + 1 interval day;
= date >= '2018-05-30' AND 'date <= 2018-05-31'; //true
select * from table where date between NOW() and NOW() - 1 interval day; records
= date >= '2018-05-30' AND 'date <= 2018-05-29'; //false
AND
select * from table where date between NOW() + 1 interval day AND NOW();
= date >= '2018-05-31' AND date <= '2018-05-30' //false
select * from table where date between NOW() - 1 interval day AND NOW();
= date >= '2018-05-29' and date <= '2018-05-30'; //true
The BETWEEN operator is interpreted a certain way:
WHERE date BETWEEN a AND b
means this:
WHERE date >= a AND date <= b
So the following two queries are equivalent:
select * from table where date between NOW() and NOW() - interval 1 day;
select * from table where date >= NOW() and date <= NOW() - interval 1 day;
Hopefully you can see that in your second query the WHERE condition can never be true, because a date cannot simutaneously be greater than or equal to now and less than now minus one at the same time.
simply put,
For SQL:
WHERE x between a and b
meaning
x >= a
and
x <= b
therefore, we have a <= x <= b or a <= b
PS: it's just about math :)
Related
How do I fetch last week data from monday time (00:00:01) and end on sunday time (23:59:59)...
same as this current week from monday time (00:00:01) and end on sunday time (23:59:59)
WHat I tried!
$query = "SELECT users.name,count(*) as count,
campaign.campaign_name,
campaign.payout_cost*count(*) as totalPrice
FROM users
JOIN transactions on users.uid=transactions.uid
JOIN campaign on campaign.campaign_id_id=transactions.campaign_id
WHERE uid=$uid
AND `date` >= DATE_SUB(DATE(NOW()), INTERVAL DAYOFWEEK(NOW())+6 DAY)
AND `date` < DATE_SUB(DATE(NOW()), INTERVAL DAYOFWEEK(NOW())-1 DAY)
GROUP BY campaign.campaign_name_name ";
You are on the right track by avoiding functions like week() on the column -- that just messes up the optimizer. On the other hand, the uid parameter should be passed as a parameter rather than munging the query string.
You want to use the weekday() function because you want weeks to start on a Monday. Just some arcaneness of MySQL: weekday() returns 0 for Monday whereas dayofweek() returns 2 for Monday.
So, the logic for the current week would be:
date >= curdate() - interval weekday(curdate()) day and
date < curdate() + interval 7 - weekday(curdate()) day
For last week, this would be:
date >= curdate() - interval 7 + weekday(curdate()) day and
date < curdate() + interval - weekday(curdate()) day
Notes that curdate() (or current_date) returns the current date with no time component, so no date() is required.
Couple of ways to do it...
select data from tableName
where date between date_sub(now(),INTERVAL 1 WEEK) and now();
select data FROM tableName
wherdate >= curdate() - INTERVAL DAYOFWEEK(curdate())+6 DAY
AND date < curdate() - INTERVAL DAYOFWEEK(curdate())-1 DAY
You can use WEEK() function, which returns the week number for a given date, by adding
AND WEEK(date-INTERVAL 1 DAY) = WEEK(NOW()) - 1 to get current week's data starting from monday upto sunday,
and
AND WEEK(date-INTERVAL 1 DAY) = WEEK(NOW()) - 2 for the previous week's data
into the WHERE condition after WHERE uid=$uid
such as
$query = "SELECT c.campaign_name,
COUNT(*) as total_count,
SUM(c.payout_cost) as total_payout
FROM transactions t
JOIN campaign c
ON c.campaign_id = t.campaign_id
WHERE uid = $uid
AND WEEK(date - INTERVAL 1 DAY) = WEEK(NOW()) - 1
GROUP BY c.campaign_name ";
and replace WEEK(NOW()) - 1 with WEEK(NOW()) - 2, also
Demo
I have a table with multiple datetime columns in a mySQL 5.6 database.
email_id
email_sent_date (datetime)
email_replied_date (datetime)
email_bounced_date(datetime)
email_archived (datetime)
I want to retrieve all emails where the latest datetime of the group (email_sent_date,email_replied_date, email_bounced_date, email_archived) is at least 1 month ago from today.
I would like to do something like this, even though i think I can't use this max(), but you'll get a sense of what I am trying to achieve:
SELECT *
FROM table
WHERE MAX(email_sent_date,email_replied_date, email_bounced_date, email_archived) <= CURDATE() - INTERVAL 30 DAY
How to achieve this ?
You want the function greatest(), not max():
SELECT *
FROM table
WHERE GREATEST(email_sent_date, email_replied_date, email_bounced_date, email_archive) <= CURDATE() - INTERVAL 30 DAY;
Note: If any of the values are NULL, then the row will be filtered out.
I prefer explicit comparisons because I think the logic is easier to follow:
SELECT *
FROM table
WHERE email_sent_date <= CURDATE() - INTERVAL 30 DAY AND
email_replied_date <= CURDATE() - INTERVAL 30 DAY AND
email_bounced_date <= CURDATE() - INTERVAL 30 DAY AND
email_archive <= CURDATE() - INTERVAL 30 DAY;
EDIT:
Handling NULL values requires explicit checks. Perhaps:
SELECT *
FROM table
WHERE (email_sent_date <= CURDATE() - INTERVAL 30 DAY OR email_sent_date IS NULL) AND
(email_replied_date <= CURDATE() - INTERVAL 30 DAY OR email_replied_date IS NULL) AND
(email_bounced_date <= CURDATE() - INTERVAL 30 DAY OR email_bounced_date IS NULL) AND
(email_archive <= CURDATE() - INTERVAL 30 DAY OR email_archive IS NULL);
I want to fetch all the values between followupdate = now and followupdate = now + 5days. Currently I'm using this query which is not returning today's values though it is returning the next 5 days values
SELECT * FROM leads WHERE followupdate >= NOW() AND followupdate <= NOW() + INTERVAL 5 DAY;
Try the following query:
SELECT * FROM leads WHERE followupdate >= DATE(NOW()) AND followupdate <= DATE(NOW() + INTERVAL 5 DAY);
As NOW returns the entire timestamp use DATE() to get today's date.
You can use CURDATE() to get today's date, then add 5 to it.
SELECT
*
FROM
leads
WHERE
followupdate >= CURDATE() AND followupdate <= DATE_ADD(CURDATE(), INTERVAL 5 DAY);
Is it possible to query for all dates in the future that are an increment of x days?
i.e.
SELECT *
FROM bookings
WHERE date >= CURDATE()
AND
(
date = CURDATE() + INTERVAL 6 DAY
OR date = CURDATE() + INTERVAL 12 DAY
OR date = CURDATE() + INTERVAL 18 DAY
etc.
)
Something like:
SELECT
*
FROM table
WHERE
date >= CURDATE()
AND
DATEDIFF(CURDATE(), date) % 6 = 0
Datediff returns the number of days difference, and % 6 says return the remainder when divided by six.
Yes.
Your logic is flawed, though. You probably meant
SELECT *
FROM table
WHERE
date = CURDATE() + INTERVAL 6 DAY
OR date = CURDATE() + INTERVAL 12 DAY
OR date = CURDATE() + INTERVAL 18 DAY
And don't use table names like "table" and field names like "date" (i.e. reserved words).
I want to select all dates that are between the current date and 3 months before.
I tried using this query but it isn't working right.
$sql = mysql_query("
SELECT *
FROM date
WHERE d_date BETWEEN NOW() AND NOW() - INTERVAL 3 MONTH
");
Please if you could help me write the right syntax.
You need to swap your bounaries, and it will work:
SELECT * FROM date
WHERE d_date BETWEEN now() - INTERVAL 3 MONTH AND now()
For example, this query returns true (SQLFiddle):
SELECT (now() - interval 1 month)
BETWEEN now() - interval 3 month AND now()
SELECT * FROM Table
WHERE anydate_col BETWEEN NOW() AND DATE_ADD( NOW() , INTERVAL +3 MONTH)