I have two tables in the datbase to store client basic info (name, location, phone number) and another table to store client related transactions (date_sub, profile_sub,isPaid,date_exp,client_id) and i have an html table to view the client basic info and transaction if are available, my problem that i can't get a query to select the client info from table internetClient and from internetclientDetails at the same time, because query is only resulting when client have trans in the detail table. the two table fields are as follow:
internetClient
--------------------------------------------------------
id full_name location phone_number
-------------------------------------------------------
4 Joe Amine beirut 03776132
5 Mariam zoue beirut 03556133
and
internetclientdetails
--------------------------------------------------------------------------
incdid icid date_sub date_exp isPaid sub_price
----------------------------------------------------------------------------
6 4 2018-01-01 2018-01-30 0 2000
7 5 2017-01-01 2017-01-30 0 1000
8 4 2018-03-01 2018-03-30 1 50000
9 5 2018-05-01 2019-05-30 1 90000
// incdid > internetClientDetailsId
// icid> internetClientId
if client have trans in orderdetails, the query should return value like that:
client_id full_name date_sub date_exp isPaid sub_price
-------------------------------------------------------------------------------------
4 Joe Amine 2018-03-01 2018-03-30 1 50000
5 Mariam zoue 2018-05-01 2019-05-30 1 90000
else if the client has no id in internetOrederDetails
--------------------------------------------------------
icid full_name location phone_number
-------------------------------------------------------
4 Joe Amine beirut 03776132
5 Mariam zoue beirut 0355613
Thanks in advance
try with left join. It will display all records from internetClient and related record from internetclientdetails
Select internetClient.id, internetClient.full_name
, internetClient.location, internetClient.phone_number
, internetclientdetails.incdid, internetclientdetails.icid
, internetclientdetails.date_sub, internetclientdetails.date_exp
, internetclientdetails.isPaid, internetclientdetails.sub_price
from internetClient
left join internetclientdetails
on internetClient.id=internetclientdetails.icid group by internetclientdetails.icid order by internetclientdetails.incdid desc
if you want to get records of, only paid clients then you can try the following
Select internetClient.id, internetClient.full_name
, internetClient.location, internetClient.phone_number
, internetclientdetails.icid, internetclientdetails.incdid
, internetclientdetails.date_sub, internetclientdetails.date_exp
, internetclientdetails.isPaid, internetclientdetails.sub_price
from internetClient
left join internetclientdetails
on internetClient.id=internetclientdetails.icid
and internetclientdetails.isPaid=1 group by internetclientdetails.icid
order by internetclientdetails.incdid desc
SUMMARY
We generate a dataset containing just the ICID and max(date_sub) (alias:ICDi) We join this to the InternetClientDetails (ICD) to obtain just the max date record per client. Then left join this to the IC record; ensuring we keep all InternetClient(IC) records; and only show the related max Detail Record.
The below approach should work in most mySQL versions. It does not use an analytic which we could use to get the max date instead of the derived table provided the MySQL version you use supported it.
FINAL ANSWER:
SELECT IC.id
, IC.full_name
, IC.location
, IC.phone_number
, ICD.icid
, ICD.incdid
, ICD.date_sub
, ICD.date_exp
, ICD.isPaid
, ICD.sub_price
FROM internetClient IC
LEFT JOIN (SELECT ICDi.*
FROM internetclientdetails ICDi
INNER JOIN (SELECT max(date_sub) MaxDateSub, ICID
FROM internetclientdetails
GROUP BY ICID) mICD
ON ICDi.ICID = mICD.ICID
AND ICDi.Date_Sub = mICD.MaxDateSub
) ICD
on IC.id=ICD.icid
ORDER BY ICD.incdid desc
BREAKDOWN / EXPLANATION
The below gives us a subset of max(date_Sub) for each ICID in clientDetails. We need to so we can filter out all the records which are not the max date per clientID.
(SELECT max(date_sub) MaxDateSub, ICID
FROM internetclientdetails
GROUP BY ICID) mICD
Using that set we join to the details on the Client_ID's and the max date to eliminate all but the most recent detail for each client. We do this because we need the other detail attributes. This could be done using a join or exists. I prefer the join approach as it seems more explicit to me.
(SELECT ICDi.*
FROM internetclientdetails ICDi
INNER JOIN (SELECT max(date_sub) MaxDateSub, ICID
FROM internetclientdetails
GROUP BY ICID) mICD
ON ICDi.ICID = mICD.ICID
AND ICDi.Date_Sub = mICD.MaxDateSub
) ICD
Finally the full query joins the client to the detail keeping client even if there is no detail using a left join.
COMPONENTS:
You wanted all records from InternetClient (FROM internetClient IC)
You wanted related records from InternetClientDetail (LEFT Join InternetClientDetail ICD) while retaining teh records from InternetClient.
You ONLY wanted the most current record from InternetClientDetail (INNER JOIN InternetClientDetail mICD as a derived table getting ICID and max(date))
Total record count should = total record count in InternetClient which means all relationships must be a 1:1o on the table joins -- one-to-one Optional.
Related
Struggling with an SQL query to select the 5 most recent, unique, entries in a MySQL 5.7.22 table. For example, here's the 'activity' table:
uaid nid created
9222 29722 2018-05-17 03:19:33
9221 31412 2018-05-17 03:19:19
9220 31160 2018-05-16 23:47:34
9219 31160 2018-05-16 23:47:30
9218 31020 2018-05-16 22:35:59
9217 31020 2018-05-16 22:35:54
9216 28942 2018-05-16 22:35:20
...
The desired query should return the 5 most recent, unique entries by the 'nid' attribute, in this order (but only need the nid attribute):
uaid nid created
9222 29722 2018-05-17 03:19:33
9221 31412 2018-05-17 03:19:19
9220 31160 2018-05-16 23:47:34
9218 31020 2018-05-16 22:35:59
9216 28942 2018-05-16 22:35:20
I have tried a variety of combinations of DISTINCT but none work, ie:
select distinct nid from activity order by created desc limit 5
What is the proper query to return the 5 most recent, uniq entries by nid?
Your problem is the simplest form of the top-N-per-group problem. In general, this problem is a real headache to handle in MySQL, which doesn't support analytic functions (at least not in most versions folks are using in production these days). However, since you only want the first record per group, we can do a join to subquery which finds the max created value for each nid group.
SELECT a1.*
FROM activity a1
INNER JOIN
(
SELECT nid, MAX(created) AS max_created
FROM activity
GROUP BY nid
) a2
ON a1.nid = a2.nid AND a1.created = a2.max_created;
Demo
You can use a subquery and join
select * from activity m
inner join (
select nid, min(created) min_date
from activity
group by nid
limit 5
) t on t.nid = m.nin and t.min_date = m.created
I have three tables where I want to perform a join between them.
1st table looks like (named users)
id column1
1 1
2 2
3 3
2nd table looks like (named transactions) here we have some transactions of users
user_id transaction_date transaction_expire
1 2017-03-31 2017-05-16
1 2017-02-28 2017-04-16
3rd table looks like (named user_logs) we have logs of the users based on days
user_id date some_log_data
1 2017-03-07 1505
1 2017-03-03 1201
1 2017-03-22 942
1 2017-03-31 1490
1 2017-04-05 1490
I want to know the sum of every user based on transactions something like:
user_id transaction_date transaction_expire log
1 2017-03-31 2017-05-16 2980
1 2017-02-28 2017-04-16 6628
So this is the result which I want to achieve for every use get the SUM of their log in all transactions.
By doing this query between transaction_date and transaction_expire I get some result but when I try to do the summation the result are for all of them:
SELECT t.transaction_date, t.transaction_expire, ul.log
FROM user_logs as ul
RIGHT JOIN transactions as t ON ul.user_id= t.user_id
WHERE ul.date BETWEEN t.transaction_date AND t.transaction_expire
This query gives me 7 rows which is correct but now I want to find only the sum of the logs in these two different transactions.
Your query is basically correct, but you need aggregation:
SELECT t.transaction_date, t.transaction_expire, SUM(ul.log)
FROM transactions t LEFT JOIN
user_logs ul
ON ul.user_id = t.user_id AND
ul.date BETWEEN t.transaction_date AND t.transaction_expire
GROUP BY t.transaction_date, t.transaction_expire;
Also note that the condition in the WHERE clause is moved to the ON clause. I switched the JOIN to a LEFT JOIN. I find LEFT JOIN much more intuitive than RIGHT JOIN, because it keeps all rows in the first table.
How about this
SELECT t.user_id, t.transaction_date, t.transaction_expire, SUM(IFNULL(ul.log, 0))
FROM user_logs as ul
LEFT JOIN transactions as t ON (ul.user_id= t.user_id AND
ul.date BETWEEN t.transaction_date AND t.transaction_expire)
GROUP BY t.user_id, t.transaction_date, t.transaction_expire;
Your expected result contains user_id. So, I included that. If a user doesnt have a log, this will return a 0 for the SUM. I assume this is what you wanted
I have the following three tables to look after support tickets in a small web application, but I need some help getting the data I need.
Table 1 (ticket):
user_ID site_ID support_ID timestamp priority title
12 25 3 2014-09-26 14:09:25 0 A Test Row
12 26 4 2014-09-27 09:41:18 0 A 2nd Test Row
Table 2 (ticket_reply):
reply_ID support_ID user_ID support_reply reply_timestamp
3 3 12 some really boring text 2014-09-26 14:09:25
4 3 25 some really boring reply 2014-09-26 15:35:18
5 4 12 some really boring text 2014-09-27 09:41:18
Table 3 (ticket_status):
ticket_status_ID support_ID status_ID status_timestamp
3 3 40 2014-09-26 14:09:25
4 3 41 2014-09-26 15:35:18
5 4 40 2014-09-27 09:41:18
The 1st table holds the key ticket information, the 2nd, any replies made to the corresponding ticket, and the third tracks the change in status (statuses are held in another table, but don't need anything from there).
What I need to do is get the number of tickets where the latest status is == 40, and if this is greater than 0, get the latest reply along with the data from the first table.
I've tried multiple ways of doing this, but I am stuck. Don't really want to paste them here as they will likely confuse people, and I doubt they are even close.
This one was rather tricky, however here is a working solution for you.
This query will get the most recent support_reply value for all tickets where the most recent status_ID is 40.
SELECT
ticket_status_ID,
support_ID,
status_ID,
status_timestamp,
reply_ID,
support_reply,
reply_timestamp,
`timestamp` ticket_timestamp,
`priority` ticket_priority,
title
FROM (
SELECT * FROM (
SELECT * FROM (
SELECT
ticket_status.ticket_status_ID,
ticket_status.support_ID,
ticket_status.status_ID,
ticket_status.status_timestamp,
ts1.reply_ID,
ts1.user_ID,
ts1.support_reply,
ts1.reply_timestamp
FROM
ticket_status
INNER JOIN (SELECT * FROM ticket_reply ORDER BY reply_timestamp DESC) ts1 ON ts1.support_ID = ticket_status.support_ID
GROUP BY support_ID, status_ID
ORDER BY status_timestamp DESC
) ts2
GROUP BY ts2.support_ID
) ts3
INNER JOIN (SELECT support_ID as `ticket_support_ID`, site_ID, `timestamp`, priority, title FROM ticket) ts4 ON ts4.ticket_support_ID = ts3.support_ID
WHERE ts3.status_ID = 40
) ts5
From the example given, it looks that all timestamp are equivalent, so a query like this should be enough:
SELECT
ticket.*,
ticket_reply.*
FROM
(SELECT support_ID, MAX(status_timestamp) as max_timestamp
FROM ticket_status
GROUP BY support_ID) m
INNER JOIN ticket
ON m.support_ID=ticket.support_ID
AND m.max_timestamp=ticket.`timestamp`
INNER JOIN ticket_reply
ON m.support_ID=ticket_reply.support_ID
AND m.max_timestamp=ticket_reply.reply_timestamp
INNER JOIN ticket_status
ON m.support_ID=ticket_status.support_ID
AND m.max_timestamp=ticket_status.status_timestamp
WHERE
status_ID=40;
but depending on the logic of your application, it might happen that the last row in a table has a timestamp of 2014-09-27 09:41:18 and the last in another has for example 2014-09-27 09:41:19.
In this case, you should use a query like this one:
SELECT
ticket.*,
ticket_reply.*
FROM
(SELECT support_ID, MAX(status_timestamp) AS max_status_timestamp
FROM ticket_status
GROUP BY support_ID) m_status
INNER JOIN
(SELECT support_ID, MAX(reply_timestamp) AS max_reply_timestamp
FROM ticket_reply
GROUP BY support_ID) m_reply
ON m_status.support_ID=m_reply.support_ID
INNER JOIN
(SELECT support_ID, MAX(`timestamp`) AS max_ticket_timestamp
FROM ticket
GROUP BY support_ID) m_ticket
ON m_status.support_ID=m_ticket.support_ID
INNER JOIN ticket_status
ON ticket_status.support_ID=m_status.support_ID
AND ticket_status.status_timestamp=m_status.max_status_timestamp
INNER JOIN ticket_reply
ON ticket_reply.support_ID=m_reply.support_ID
AND ticket_reply.reply_timestamp=m_reply.max_reply_timestamp
INNER JOIN ticket
ON ticket.support_ID=m_ticket.support_ID
AND ticket.`timestamp`=m_ticket.max_ticket_timestamp
WHERE
ticket_status.status_ID=40;
Please see fiddle here.
You can try this one:
SELECT t.*, tr.support_reply, ts.status_timestamp
FROM ticket_status as ts
left join ticket_reply as tr on(ts.support_ID=tr.support_ID)
left join ticket as t on(t.support_ID=tr.support_ID)
where status_ID=40
order by status_timestamp desc
limit 1;
I have a mysql query like this :
SELECT SUM(bills.Amount) AS AmountExpense, SUM(assets.Amount) as AmountIncome
FROM bills, assets where bills.UserId = 11 and assets.UserId =11
Sample Bills table
id payee description UserId Amount
1 john advance 11 15.0
2 dave request 2 13.0
3 er request 11 12.0
Sample assets table
id payee description UserId Amount
1 john advance 11 40.2
2 dave request 2 13.0
3 ww request 11 14.00
I have a problem with AmountExpense, the record SUM record multiple time. I have successed with Amount Income. Any suggestions?
You have most likely more than one row per user on one or both of those tables. You'll need to join them after performing the aggregation. Also, please don't use old style non ANSI implicit joins:
SELECT AmountExpense, AmountIncome
FROM ( SELECT UserId,
SUM(Amount) AS AmountExpense
FROM bills
GROUP BY UserId) AS b
LEFT JOIN ( SELECT UserId,
SUM(Amount) AmountIncome
FROM assets
GROUP BY UserId) AS a
ON b.UserId = a.UserId
WHERE b.UserId = 11
If you have the possibility that users can be in either table, but not the other, then you want the equivalent of a full outer join. MySQL doesn't support that syntax, but it does support this:
select userid, sum(amountexpense) as amountexpense, sum(amountincome) as amountincome
from (select userid, amount as amountexpense, null as amountincome
from bills
union all
select userid, null, amount as amountincome
from assets
) ba
group by userid;
I have a table like this
The first table is the "Appointments" table with 'doctor_id' the second table is the "Doctors" table also with 'doctor_id'. The duplicate values from the appointments table represents how many appointment each doctor has. for example the doctor_id(50) has 6 appointments.
doctor_id(Appointments) | doctor_id(Doctors)
50 | 50
50 | 51
50 | 52
52 | 53
50 |
50 |
52 |
53 |
50 |
Now, my question is how would I show this table below (ps excluding the doctor id '51)
doctor_id (Doctors) | Count
50 | 6
52 | 2
53 | 1
This what i have tried so far, i have managed to work out how many doctors have appointments
using :
SELECT COUNT(*) FROM appointment
WHERE doctor_id > 50
I have executed other queries as well but with no luck.
Assuming doctor_id is unique in the doctors table...
SELECT d.doctor_id AS doctor_id
, COUNT(a.doctor_id) AS appointment_count
FROM doctors d
LEFT
JOIN appointments a
ON a.doctor_id = d.doctor_id
GROUP BY d.doctor_id
To get the count by doctor_id, you need to GROUP BY the doctor_id. You don't have to include doctor_id in the SELECT list, but if you only return the COUNT(), you'd just get a list of counts:
appointment_count
-----------------
6
0
2
1
With no indication of which appointment_count goes with which doctor_id. So, the usual pattern is to include what you GROUP BY in the SELECT list.
In order to return the 0 count for doctor 51, we want an outer join to the appointments table, so the row from the doctors table is returned even when there is no match.
If you only want rows for doctors that have one or more appointments, then you can just query
the appointments table. (This query won't return any "zero" count for a doctor.)
SELECT a.doctor_id
, COUNT(1) AS appointment_count
JOIN appointments a
GROUP BY a.doctor_id
Again, the GROUP BY clause is necessary to get a count of rows for each distinct value of doctor_id. That effectively collapses the rows for each doctor_id into a single row. The aggregate function operates on the "group" of rows.
You may use Group By doctor_id for counting how many times each doctor_id repeats itself :
SELECT doctor_id,COUNT(doctor_id) FROM appointment GROUP BY doctor_id
SELECT d.doctor_id, COUNT(a.doctor_id) FROM doctors d
Join appointment a
d.doctor_id =a.doctor_id
WHERE d.doctor_id > 50
GROUP BY a.doctor_id
try this code and hope this works. I am grouping the doctors appointments by the id
Given the information in the question this can be achieved using just the appointment table:
SELECT appointments.doctor_id, Count(appointments.doctor_id)
FROM appointments
GROUP BY appointments.doctor_id;
However as the question specifically asked about a JOIN the following code will work:
SELECT d.doctor_id, COUNT(a.doctor_id) AS appointment_count
FROM doctors d
JOIN appointments a
ON a.doctor_id = d.doctor_id
GROUP BY d.doctor_id;
A working sample is available at SQLFiddle: SQLFiddle