Possible to skip the first property in json object table? - json

Question

My function to parse an array of properties to a json object looks like this:
var jsonObject = "[{"
for i in 1...table.count {
var str = ""
var insideStr = String()
for property in properties {
let filteredTable = table.value(forKey: property) as! [Any]
insideStr += "\"\(property)\": \"\(filteredTable[i - 2])\","
}
let index = insideStr.characters.index(insideStr.startIndex, offsetBy: (insideStr.count - 2))
insideStr = String(insideStr[...index])
str += "\(insideStr)}],"
jsonObject.append(str)
}
let index = jsonObject.characters.index(jsonObject.startIndex, offsetBy: (jsonObject.count - 2))
jsonObject = "\(String(jsonObject[...index]))"
return jsonObject
}catch let error { print("\(error)") }
My question is, is it possible to skip the first property because it always returns nil data?

Answer 1

You could delete the first property:
delete obj[Object.keys(obj)[0]];
otherwise slice like this:
Object.entries(obj).slice(1); //array of arrays [key,value], without the first.

Answer 2

Replace your for loop with a for...in style loop, and then add a where clause to exclude nils since you don't want to risk dealing with them.
for tableItem in table where tableItem != nil {
// Handle json here
}
Or, you can use higher order functions to remove all the nils, and then iterate through it like this:
table.filter({ $0 != nil }).forEach({ tableItem in // Do stuff with tableItem })