Having issue with this query
there is 3 rows in comments table with different date-times, I want customer list with last comment created_date / updated_date.
but didn't getting last commented customer with group by customer
SELECT * FROM(
SELECT MAX(comments.`date_updated`), customer.id AS vid, comments.`date_updated` AS dts, comments.`id` AS comments_id, comments.* FROM customer
INNER JOIN comments ON comments.`customer_id` = customer.`id`
WHERE customer.`id` IN ('')
) AS v
GROUP BY v.`vid` LIMIT 0,50
You use a self join to comments table and filter row for each customer with latest date_updated
SELECT c.id AS vid, co.`date_updated` AS dts, co.`id` AS comments_id, co.*
FROM customer c
INNER JOIN comments co ON co.`customer_id` = c.`id`
LEFT JOIN comments co1 ON co.`customer_id` = co1.`customer_id` AND co.date_updated < co1.date_updated
WHERE co1.customer_id IS NULL AND c.`id` IN ('')
Or with inner join
SELECT c.id AS vid, co.`date_updated` AS dts, co.`id` AS comments_id, co.*
FROM customer c
INNER JOIN comments co ON co.`customer_id` = c.`id`
INNER JOIN (
SELECT customer_id, MAX(date_updated) date_updated
FROM comments
GROUP BY customer_id
) co1 ON co.customer_id = co1.customer_id AND co.date_updated = co1.date_updated
WHERE c.`id` IN ('')
You forgot order by clause
SELECT * FROM(
SELECT MAX(comments.`date_updated`), customer.id AS vid, comments.`date_updated` AS dts, comments.`id` AS comments_id, comments.* FROM customer
INNER JOIN comments ON comments.`customer_id` = customer.`id`
WHERE customer.`id` IN ('')
) AS v
GROUP BY v.`vid` LIMIT 0,50
ORDER BY created_date desc;
Related
SELECT t.id
, t.department
, t.owner
, t.client
, u.username as owner_name
, c.name as catagery
, d.dept_name as deptname
, t.periority
, t.status
, t.estimate
, cl.takeaway_name
from tbl_task t
JOIN tbl_user u
ON u.id = t.owner
JOIN tbl_task_catagery c
ON c.id = t.catagery
JOIN tbl_department d
ON d.id = t.department
JOIN tbl_clients cl
ON cl.id = t.client
and t.status = 0
and (t.id in (select task_id
from tbl_task_note tn
where tn.user_id = '69'
and tn.id in (select max(id)
from tbl_task_note tt
where tt.task_id = tn.task_id
)
)
)
order by t.id
Note : The above query is used for check users hold tasks. tbl_task_note table is used for check task notes for separate users task.
With this query you will get the task that have the last task_note registered, including the user, departament, client, and some other.
If it is what you need you can just do this.
select
t.id,
t.department,
t.owner,
t.client,
u.username as owner_name,
c.name as catagery,
d.dept_name as ptname,
t.periority,
t.status,
t.estimate,
cl.takeaway_name
from tbl_task t
INNER JOIN tbl_user u ON u.id=t.owner
INNER JOIN tbl_task_catagery c ON c.id=t.catagery
INNER JOIN tbl_department d ON d.id=t.department
INNER JOIN tbl_clients cl ON cl.id=t.client and t.status=0
INNER JOIN (select * from tbl_task_note where id =
(select max(id) from tbl_task_note)
)tb on tb.task_id = t.id
order by t.id
That way you can improve your query.
You shoud also ensure that your keys compared are foreign keys to get faster consults.
I have this query
select c.id, c.name, c.email, c.totalpets, min(p.date_created) as first_order,
min(p.weight) as min_weight_bought,
max(p.weight) as max_weight_bought,
count(p.ordernumber) as total_orders
from orders p
inner join customers c
on p.customer_id = c.id
where p.approved = 1
and c.totalpets >= 1
group by c.id
having total_orders > 1
Note that first_order gives me the first result of the row, right? I am trying to get customer first order and customer second order. How can i do that within this inner join?
Thanks
SELECT c1.id,
c1.name,
c1.email,
c1.totalpets,
p1.date_created
FROM orders p1
INNER JOIN customers c1
ON p1.customer_id = c1.id
WHERE
(
SELECT COUNT(*)
FROM orders p2
INNER JOIN customers c2
ON p2.customer_id = c2.id
WHERE c2.id = c1.id AND p2.date_created <= p1.date_created
) <= 2
ORDER BY c1.id;
Here is a running demo which shows a simplified version of the above query (and simplified data set) in action:
SQLFiddle
I have 4 table and i want to extract: id, nume, localitate, masina_id, nr_inmatriculare, an_fabricatie, rafinarie, marca, and sum (quantity+deliver_quantity) as total_quantity group by an_fabricatie , Order by marca, and put some having clouse.
I don’t know how to make this.
My query is as bellow , but I think isn't correct.
select c.id, c.nume,c.localitate,l.masina_id, i.nr_inmatriculare, i.an_fabricatie,
i.rafinarie, m.marca from clienti c inner join livrari l on c.id = l.id inner join incarcari I on l.incarcare_id = l.livrari_id inner join masina m on i.id_marca = m.id, sum(select quantity, deliver_quantity) as total_quantity group by an_fabricatie having quantity >1000 order by marca;
Incarcari table
Id|livrari_id|id_marca|nr_inmatriculare|an_fabricatie|rafinarie|aviz_incarcare|quantity|
Livrari table
Id|masina_id|client_id|incarcare_id|deliver_quantity|aviz_livrare
Masini table
Id|numar_inmatriculare|marca|an_fabricatie|
Clienti table
Id|nume|localitate|date_add|date_upd|
SELECT c.id, c.nume, c.localitate, l.masina_id, i.nr_inmatriculare, i.an_fabricatie, i.rafinarie, m.marca, (SUM(i.quantity) + SUM(l.deliver_quantity)) AS total_quantity
FROM clienti c
INNER JOIN livrari l ON c.id = l.id
INNER JOIN incarcari i ON l.incarcare_id = i.livrari_id
INNER JOIN masini m ON i.id_marca = m.id
GROUP BY i.an_fabricatie, c.id, c.nume,c.localitate,l.masina_id, i.nr_inmatriculare, i.rafinarie, m.marca
HAVING i.quantity > 1000
ORDER BY m.marca DESC;
I have the following:
SELECT DISTINCT s.username, COUNT( v.id ) AS cnt
FROM `instagram_item_viewer` v
INNER JOIN `instagram_shop_picture` p ON v.item_id = p.id
INNER JOIN `instagram_shop` s ON p.shop_id = s.id
AND s.expirydate IS NULL
AND s.isLocked =0
AND v.created >= '2014-08-01'
GROUP BY (
s.id
)
ORDER BY cnt DESC
Basically I have an instagram_item_viewer with the following structure:
id viewer_id item_id created
It tracks when a user has viewed an item and what time. So basically I wanted to find shops that has the most items viewed. I tried the query above and it executed fine, however it doesn't seem to give the appropriate data, it should have more count than what it is. What am I doing wrong?
First, with a group by statement, you don't need the DISTINCT clause. The grouping takes care of making your records distinct.
You may want to reconsider the order of your tables. Since you are interested in the shops, start there.
Select s.username, count(v.id)
From instagram_shop s
INNER JOIN instagram_shop_picture p ON p.shop_id = s.shop_id
INNER JOIN instagram_item_viewer v ON v.item_id = p.id
AND v.created >= '2014-08-01'
WHERE s.expirydate IS NULL
AND s.isLocked = 0
GROUP BY s.username
Give thata shot.
As mentioned by #Lennart, if you have a sample data it would be helpful. Because otherwise there will be assumptions.
Try run this to debug (this is not the answer yet)
SELECT s.username, p.id, COUNT( v.id ) AS cnt
FROM `instagram_item_viewer` v
INNER JOIN `instagram_shop_picture` p ON v.item_id = p.id
INNER JOIN `instagram_shop` s ON p.shop_id = s.id
AND s.expirydate IS NULL
AND s.isLocked =0
AND v.created >= '2014-08-01'
GROUP BY (
s.username, p.id
)
ORDER BY cnt DESC
The problem here is the store and item viewer is too far apart (i.e. bridged via shop_picture). Thus shop_picture needs to be in the SELECT statement.
Your original query only gets the first shop_picture count for that store that is why it is less than expected
Ultimately if you still want to achieve your goal, you can expand my SQL above to
SELECT x.username, SUM(x.cnt) -- or COUNT(x.cnt) depending on what you want
FROM
(
SELECT s.username, p.id, COUNT( v.id ) AS cnt
FROM `instagram_item_viewer` v
INNER JOIN `instagram_shop_picture` p ON v.item_id = p.id
INNER JOIN `instagram_shop` s ON p.shop_id = s.id
AND s.expirydate IS NULL
AND s.isLocked =0
AND v.created >= '2014-08-01'
GROUP BY (
s.username, p.id
)
ORDER BY cnt DESC
) x
GROUP BY x.username
I have 3 tables "maintenances", "cars", "users" . I want to select all data from table maintenance with a distinct car_id and the last record for each distinct (based on max maintenance_date)
SELECT
m. * , u.username, c.Model, c.Make, c.License, c.Milage, COUNT( m.process_id ) AS count_nr
FROM
maintenances AS m
LEFT JOIN users AS u ON u.id = m.user_id
LEFT JOIN cars AS c ON c.id = m.car_id
WHERE
maintenance_date = (SELECT MAX(maintenance_date) FROM maintenances WHERE car_id = m.car_id)
The problem is that this query returns only one record which has the max date from all records. I want all records (distinct car_id and from records with the same car_id to display only values for max(maintenance_date))
This is your query:
SELECT m. * , u.username, c.Model, c.Make, c.License, c.Milage, COUNT( m.process_id ) AS count_nr
----------------------------------------------------------------^
FROM maintenances AS m LEFT JOIN
users AS u
ON u.id = m.user_id LEFT JOIN
cars AS c
ON c.id = m.car_id
WHERE maintenance_date = (SELECT MAX(maintenance_date) FROM maintenances WHERE car_id = m.car_id);
It is an aggregation query. Without a group by, only one row is returned (all the rows are in one group). So, add the group by:
SELECT m. * , u.username, c.Model, c.Make, c.License, c.Milage, COUNT( m.process_id ) AS count_nr
FROM maintenances AS m LEFT JOIN
users AS u
ON u.id = m.user_id LEFT JOIN
cars AS c
ON c.id = m.car_id
WHERE maintenance_date = (SELECT MAX(m2.maintenance_date) FROM maintenances m2 WHERE m2.car_id = m.car_id);
GROUP BY c.id
I also fixed the correlation statement, to be clear that it is correlated to the outer query.
add GROUP BY u.username .
WHERE
maintenance_date = (SELECT MAX(maintenance_date) FROM maintenances WHERE car_id = m.car_id)
GROUP BY u.username