How to stop sequelize from sending default value to MYSQL table? - mysql

Question

The console log:
Executing (default): INSERT INTO `testtables` (`id`,`forgot_code`,`customer_id`) VALUES (DEFAULT,610,199)
How can I stop sequelize from sending DEFAULT value into my column id ?
How can I stop sequelize from inserting into my Primary Key since it is already on auto increment ?
My code:
var TestTable= sequelize.define('testtables', {
id:{
type:Sequelize.INTEGER,
primaryKey: true,
autoIncrement: true
},
forgot_code:Sequelize.INTEGER,
customer_id:Sequelize.INTEGER
},{
timestamps: false,
});

Answer 1

A bit late reply, but I had similar issue with Percona. So the solution for us was adding a hook:
new Sequelize(database, username, password, {
dialect: 'mysql',
// FIXME: This is a temporary solution to avoid issues on Percona when Sequelize transform insert query into
// INSERT INTO [TABLE_NAME] (`id`, ...) VALUES (DEFAULT, ...)
hooks: {
beforeCreate: ((attributes) => {
if (attributes
&& attributes.dataValues
&& attributes.dataValues.hasOwnProperty('id')
) {
delete attributes.dataValues.id
}
})
},
})
Update: found this solution on DB level: https://dev.mysql.com/doc/refman/5.7/en/sql-mode.html#sqlmode_no_auto_value_on_zero

Answer 2

1.delete all node modules
2.Re install node modules( npm install)
Now, issue will be fixed. This worked for me.

Answer 3

You have to remove autoIncrement: true from your model definition. Now, inserting without providing the id value will fail. For example, the below code will fail
const User = sequelize.define('user', {
id: {
type: Sequelize.INTEGER,
primaryKey: true,
// autoIncrement: true
},
username: Sequelize.STRING,
});
sequelize.sync({ force: true })
.then(() => User.create({
username: 'test123'
}).then((user) => {
console.log(user);
}));
However if you uncomment autoIncrement: true, insert will go through