I store a serialized table in a Mysql column. The data looks like this:
a:2:{i:116;s:1:"4";i:113;s:1:"6";}
I'm trying to extract the number that's always placed before ;s:1:"6";
In the example above, the number would be 113.
I'm running Mysql 5.7, so I don't have access to new regex functions. It would have been nice to access PREG_CAPTURE and just write
PREG_CAPTURE(\'i:([0-9]+);s:1:"6";\', mycolumn, 1)
But I can't use PREG_CAPTURE and I'm stuck. Any idea?
Use substring_index.
Try this
SELECT SUBSTRING_INDEX( field1, ';s:1:"6";',1 )
Related
I am running this query through a unix command line:
SELECT X FROM TABLEX WHERE NAME LIKE 'Blablabla';
The output result should be 304768764529, however a get as return 3.047E11.
How can I, with a single query, convert the result to be the exact number, not in the scientific mode?
If using Oracle RDBMS, you can do it this way:
SELECT to_char(X)
FROM TABLEX
WHERE NAME LIKE 'Blablabla';
I'm curious why you're using LIKE without wildcards though.
I have a column in my table name as URL and it contains Multiple value like "https://www.google.com/#q=how+to+make+a+android+app"
and
http://www.bing.com/search?q=how+to+make+a+android+app&go=&qs=n&form=QBLH&pq=how+to+make+a+android+app&sc=8-15&sp=-1&sk=
I want to get data separately in output like
website = https://www.google.com
Keyword = how to make a android app.
Any Idea Plz, How can i get this in MySql.
you can use substr() function in php to cut string. In your case, you can get the characters up to the end of 'https://www.google.com'.
read more at http://ro1.php.net/substr
in case you want to do it directly in your query, you can use substr() as well. Sql syntax goes like this:
SELECT SUBSTR(column, start_position, desired_length) FROM table_name
*SELECT SUBSTR(column_name, 1, 20) FROM table_name;*
How to reference to a group using a regex in MySQL?
I tried:
REGEXP '^(.)\1$'
but it does not work.
How to do this?
(Old question, but top search result)
For MySQL 8:
SELECT REGEXP_REPLACE('stackoverflow','(.{5})(.*)','$2$1');
-- "overflowstack"
You can create capture groups with (), and you can refer to them using $1, $2, etc.
For MariaDB, capturing is done in REGEXP_REPLACE with \\1, \\2, etc. respectively.
You can't, there is no way to reference regex capturing groups in MySql.
You can solve this problem by nesting the function calls in your query. Say you have this string in your column:
'100 SOME ST,THE VILLAGES,FL 32163,USA'
and you want to capture the city name. A Capture Group like this would work if MySQL supported it (but it doesn't):
'^[0-9A-Z\s]+,\s*([a-zA-Z\s]*)'
You CAN nest function calls to strip off the part you don't want, and then grab the part you DO want like this:
SELECT REGEXP_SUBSTR(REGEXP_REPLACE(column_name, '^[0-9\\sA-Z]+,', ''), '^[0-9\\sA-Z]+') FROM table_name;
THE VILLAGES
...
I have one column name phone_number in the database table.Right now the numbers stored in the table are format like ex.+91-852-9689568.I want to format it and just want only digits.
How can i do it in MySql ? I have tried it with using functions like REGEXP but it displays error like function does not exist.And i don't want to use multiple REPLACE.
One of the options is to use mySql substring. (As long as the format doesn't change)
SELECT concat(SUBSTRING(pNo,2,2), SUBSTRING(pNo,5,3), SUBSTRING(pNo,9,7));
if you want to format via projection only, use SELECT, you will only need to use replace twice and no problem with that.
SELECT REPLACE(REPLACE(columnNAme, '-', ''), '+', '')
FROM tableName
otherwise, if you want to update the value permanently, use UPDATE
UPDATE tableName
SET columnName = REPLACE(REPLACE(columnNAme, '-', ''), '+', '')
MySQL does not have a builtin function for pattern-matching and replace.
You'll be better off fetching the whole string back to your application, and then using a more flexible string-manipulation function on it. For instance, preg_replace() in PHP.
Try the following and comment please.
Select dbo.Regex('\d+',pNo);
Select dbo.Regex('[0-9]+',pNo);
Reference on RUBLAR.
So MYSQL is not like Oracle, hence you may just use a USer defined Function to get numbers. This could get you going.
I am having the following problem:
I have a table T which has a column Name with names. The names have the following structure:
A\\B\C
You can create on yourself like this:
create table T ( Name varchar(10));
insert into T values ('A\\\\B\\C');
select * from T;
Now if I do this:
select Name from T where Name = 'A\\B\C';
That doesn't work, I need to escape the \ (backslash):
select Name from T where Name = 'A\\\\B\\C';
Fine.
But how do I do this automatically to a string Name?
Something like the following won't do it:
select replace('A\\B\C', '\\', '\\\\');
I get: A\\\BC
Any suggestions?
Many thanks in advance.
You have to use "verbatim string".After using that string your Replace function will
look like this
Replace(#"\", #"\\")
I hope it will help for you.
The literal A\\B\C must be coded as A\\\\A\\C, and the parameters of replace() need escaping too:
select 'A\\\\B\\C', replace('A\\\\B\\C', '\\', '\\\\');
output (see this running on SQLFiddle):
A\\B\C A\\\\B\\C
So there is little point in using replace. These two statements are equivalent:
select Name from T where Name = replace('A\\\\B\\C', '\\', '\\\\');
select Name from T where Name = 'A\\\\B\\C';
Usage of regular expression will solve your problem.
This below query will solve the given example.
1) S\\D\B
select * from T where Name REGEXP '[A-Z]\\\\\\\\[A-Z]\\\\[A-Z]$';
if incase the given example might have more then one char
2) D\\B\ACCC
select * from T where Name REGEXP '[A-Z]{1,5}\\\\\\\\[A-Z]{1,5}\\\\[A-Z]{1,5}$';
note: i have used 5 as the max occurrence of char considering the field size is 10 as its mentioned in the create table query.
We can still generalize it.If this still has not met your expectation feel free to ask for my help.
You're confusing what's IN the database with how you represent that data in SQL statements. When a string in the database contains a special character like \, you have to type \\ to represent that character, because \ is a special character in SQL syntax. You have to do this in INSERT statements, but you also have to do it in the parameters to the REPLACE function. There are never actually any double slashes in the data, they're just part of the UI.
Why do you think you need to double the slashes in the SQL expression? If you're typing queries, you should just double the slashes in your command line. If you're generating the query in a programming language, the best solution is to use prepared statements; the API will take care of proper encoding (prepared statements usually use a binary interface, which deals with the raw data). If, for some reason, you need to perform queries by constructing strings, the language should hopefully provide a function to escape the string. For instance, in PHP you would use mysqli_real_escape_string.
But you can't do it by SQL itself -- if you try to feed the non-escaped string to SQL, data is lost and it can't reconstruct it.
You could use LIKE:
SELECT NAME FROM T WHERE NAME LIKE '%\\\\%';
Not exactly sure by what you mean but, this should work.
select replace('A\\B\C', '\', '\\');
It's basically going to replace \ whereever encountered with \\ :)
Is this what you wanted?