I am trying to learn on how to select values that only occur once.
I would like to select the names of applicants who only have one and one only application.
SELECT name FROM (SELECT COUNT(anumber) AS count FROM APPLIES
GROUP BY anumber HAVING (count = 1)) AS x;
Could you please assist me as I cannot figure out where I am going wrong with this, I am still new to using MySQL.
SELCT name FROM APPLIES
GROUP BY anumber
HAVING COUNT(anumber)=1
This should get you the names that have exactly one anumber (I am assuming anumber means application number here)
Here's a link explaining different use cases of GROUP BY and HAVING which you can refer to if you want something else - https://www.w3resource.com/sql/aggregate-functions/count-having.php
I think this should be enough. The output is all the names in table applies, that occur only once.
SELECT name FROM APPLIES
GROUP BY anumber
having count(anumber) = 1;
EDIT:
Looking at your query, you are trying to select a name from this subquery, that only has a "count":
SELECT COUNT(anumber) AS count FROM APPLIES
GROUP BY anumber HAVING (count = 1)
Related
Let's say I have a table like this -
id
number
1
1
2
1
3
1
I want to return the second largest number, and if there isn't, return NULL instead. In this case, since all the numbers in the table are the same, there isn't the second largest number, so it should return NULL.
These codes work -
SELECT IFNULL((
SELECT number
FROM (SELECT *, DENSE_RANK() OVER(ORDER BY number DESC) AS ranking
FROM test) r
WHERE ranking = 2), NULL) AS SecondHighestNumber;
However, after I changed the order of the query, it doesn't work anymore -
SELECT IFNULL(number, NULL) AS SecondHighestNumber
FROM (SELECT *, DENSE_RANK() OVER(ORDER BY number DESC) AS ranking
FROM test) r
WHERE ranking = 2;
It returns blank instead of NULL. Why?
Explanation
This is something of a byproduct of the way you are using subquery in your SELECT clause, and really without a FROM clause.
It is easy to see with a very simple example. We create an empty table. Then we select from it where id = 1 (no results as expected).
CREATE TABLE #foo (id int)
SELECT * FROM #foo WHERE id = 1; -- Empty results
But now if we take a left turn and turn that into a subquery in the select statement - we get a result!
CREATE TABLE #foo (id int)
SELECT (SELECT * FROM #foo WHERE id = 1) AS wtf; -- one record in results with value NULL
I'm not sure what else we could ask our sql engine to do for us - perhaps cough up an error and say I can't do this? Maybe return no results? We are telling it to select an empty result set as a value in the SELECT clause, in a query that doesn't have any FROM clause (personally I would like SQL to cough up and error and say I can't do this ... but it's not my call).
I hope someone else can explain this better, more accurately or technically - or even just give a name to this behavior. But in a nutshell there it is.
tldr;
So your first query has SELECT clause with an IFNULL function in it that uses a subquery ... and otherwise is a SELECT without a FROM. So this is a little weird but does what you want, as shown above. On the other hand, your second query is "normal" sql that selects from a table, filters the results, and lets you know it found nothing -- which might not be what you want but I think actually makes more sense ;)
Footnote: my "sql" here is T-SQL, but I believe this simple example would work the same in MySQL. And for what it's worth, I believe Oracle (back when I learned it years ago) actually would cough up errors here and say you can't have a SELECT clause with no FROM.
I was wondering if there's any way to add a subquery with a switch case to the form clause of my select query in order to select a table based on a condition.
For example:
select a.*
from (select (case when (table2.column = 'something')
then (table2.tablename1)
else (table2.tablename2)) as tablename
from table2
where table2.column2 = 'blabla'
limit 1
) a
I tried to write that in many variation & so far non of them worked.
On the most successful tryouts (when I got no mysql errors) it returned the name of the table as the result itself (for example: the value that's in table2.tablename2). I understand why it did that (because I selected everything from a select results...) but how can I use the tablename from the results in order to set the table on the main query?
Hope that make sense...
Any idea?
I encounter some strange results in the following query :
SET #indi_id = 768;
SET #generations = 8;
SELECT num, sosa, seq, len, dernier, ful_ful_nom
FROM fullindi
LEFT JOIN lignee_new
ON ((ful_indi_id = dernier) AND (len BETWEEN 1 AND #generations))
RIGHT JOIN numbers
ON ((sosa = num) AND (premier = #indi_id))
WHERE num BETWEEN 1 AND pow(2, #generations)
GROUP BY num
ORDER BY num;
The result looks like this :
Why the row just before a full NULL one doesn't display the existing values 'sosa', 'len', 'dernier', ful_ful_nom') but only the 'seq' value (see rows 43 and 47 in this example) ?
What am I missing?
As requested, here are data :
table lignee_new :
table fullindi :
The problem is that MySQL does really dumb things when an Aggregate function is introduced, or a GROUP BY is included, but not all of the fields are in an Aggregate Function or your GROUP BY.
You are asking it to GROUP BY num but none of the other columns in your SELECT are included in the Group BY nor are they being aggregated with a function (SUM, MAX, MIN, AVG, etc..)
In any other RDBMS this query wouldn't run and would throw an error, but MySQL just carries on. It uses the logic to decide which value it should show for each field that isn't num by just grabbing the first value it finds in it's data storage which may be different between innoDB and whatever else folks use anymore.
My guess is that in your case you have more than one record in lignee_new that has a num of 43. Since you GROUP BY num and nothing else, it just grabs values randomly from your multiple records where num=43 and displays them... which is reasonable. By not including them in an aggregate function you are pretty much saying "I don't care what you display for these other fields, just bring something back" and so MySQL does.
Remove your GROUP BY clause completely and you'll see data that makes sense. Perhaps use WHERE to further filter your records to get rid of nulls or other things you don't need (don't use GROUP BY to filter).
A simplified example:
I have a SQL table called things. Things by themselves have an id and a name. Things are part of a tree, e.g. a thing can have a parent; Exactly how to this is stored is not important, important is however that it is possible to obtain a list of thing ids from the root node to the current thing.
I have another table, called properties. A property has a thing_id column, a name column and a value column.
I now want, for the current thing, to obtain all properties, ordered by thing_id, in order of the paths from root thing to current thing.
e.g., if the current thing is nested like this: Root(1) > Vehicle(4) > Car(2) > Hybrid(3), I would want the list of properties be returned with the properties that have a thing_id==1 first, followed by the ones with thing_id == 4, then thing_id==2 and finally thing_id==3.
How can this be done using SQL? (without using N+1 selects)
In SQL this can be achieved with use of recursive query. Here is an example
DECLARE #item as varchar(10)
with CTE (main_part, sub_part, NestingLevel)
as
(
select main_part, sub_part, 1 from tblParts
where main_part = #item
union all
select tblParts.main_part, tblParts.sub_part, (NestingLevel + 1) from tblParts
inner join CTE on tblParts.main_part = CTE.sub_part
)
select * from CTE
In order to address this in MySQL you can try temporary table approach. Here is a good example of it: How to do the Recursive SELECT query in MySQL?
I saw a query once that assigned some kind of ranking to query conditions, I can't remember it now.
They way I understood it, i think variable names (s1,s2,...) were assigned to each of the conditions with a coefficient to give them different "weights" then the sum of the variables was used to sort the result.
It looked something like this:
SELECT
*
FROM
table_name
WHERE condition1='value1' as (s1*3)
OR condition2='value2' as (s2*2)
OR condition3='value3' as (s3*1)
ORDER BY (s1+s2+s3)
So, the different numbers sort of give the conditions varying degrees of importance in the ORDER, makes it perfect for doing a related product/post search.
Please, does anyone know the right structure for this query?
In MySQL, you would define the aliases in the SELECT clause and then use them in the ORDER BY. For instance:
SELECT t.*, (condition1 = 'value1') as s1,
(condition2 = 'value2') as s2, (condition3 = 'value3') as s3
FROM table t
ORDER BY (s1*3 + s2*2 + s3*1);