Query with dynamic date intervals - mysql

Given a statuses table that holds information about products availability, how do I select the date that corresponds to the 1st day in the latest 20 days that the product has been active?
Yes I know the question is hard to follow. I think another way to put it would be: I want to know how many times each product has been sold in the last 20 days that it was active, meaning the product could have been active for years, but I'd only want the sales count from the latest 20 days that it had a status of "active".
It's something easily doable in the server-side (i.e. getting any collection of products from the DB, iterating them, performing n+1 queries on the statuses table, etc), but I have hundreds of thousands of items so it's imperative to do it in SQL for performance reasons.
table : products
+-------+-----------+
| id | name |
+-------+-----------+
| 1 | Apple |
| 2 | Banana |
| 3 | Grape |
+-------+-----------+
table : statuses
+-------+-------------+---------------+---------------+
| id | name | product_id | created_at |
+-------+-------------+---------------+---------------+
| 1 | active | 1 | 2018-01-01 |
| 2 | inactive | 1 | 2018-02-01 |
| 3 | active | 1 | 2018-03-01 |
| 4 | inactive | 1 | 2018-03-15 |
| 6 | active | 1 | 2018-04-25 |
| 7 | active | 2 | 2018-03-01 |
| 8 | active | 3 | 2018-03-10 |
| 9 | inactive | 3 | 2018-03-15 |
+-------+-------------+---------------+---------------+
table : items (ordered products)
+-------+---------------+-------------+
| id | product_id | order_id |
+-------+---------------+-------------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 1 | 3 |
| 4 | 1 | 4 |
| 5 | 1 | 5 |
| 6 | 2 | 3 |
| 7 | 2 | 4 |
| 8 | 2 | 5 |
| 9 | 3 | 5 |
+-------+---------------+-------------+
table : orders
+-------+---------------+
| id | created_at |
+-------+---------------+
| 1 | 2018-01-02 |
| 2 | 2018-01-15 |
| 3 | 2018-03-02 |
| 4 | 2018-03-10 |
| 5 | 2018-03-13 |
+-------+---------------+
I want my final results to look like this:
+-------+-----------+----------------------+--------------------------------+
| id | name | recent_sales_count | date_to_start_counting_sales |
+-------+-----------+----------------------+--------------------------------+
| 1 | Apple | 3 | 2018-01-30 |
| 2 | Banana | 0 | 2018-04-09 |
| 3 | Grape | 1 | 2018-03-10 |
+-------+-----------+----------------------+--------------------------------+
So this is what I mean by latest 20 active days for e.g. Apple:
It was last activated at '2018-04-25'. That's 4 days ago.
Before that, it was inactive since '2018-03-15', so all these days until '2018-04-25' don't count.
Before that, it was active since '2018-03-01'. That's more 14 days until '2018-03-15'.
Before that, inactive since '2018-02-01'.
Finally, it was active since '2018-01-01', so it should only count the missing 2 days (4 + 14 + 2 = 20) backwards from '2018-02-01', resulting in date_to_start_counting_sales = '2018-01-30'.
With the '2018-01-30' date in hand, I'm then able to count Apple orders in the last 20 active days: 3.
Hope that makes sense.
Here is a fiddle with the data provided above.

I've got a standard SQL solution, that does not use any window function as you are on MySQL 5
My solution requires 3 stacked views.
It would have been better with a CTE but your version doesn't support it. Same goes for the stacked Views... I don't like to stack views and always try to avoid it, but sometimes you have no other choice, because MySQL doesn't accept subqueries in FROM clause for Views.
CREATE VIEW VIEW_product_dates AS
(
SELECT product_id, created_at AS active_date,
(
SELECT created_at
FROM statuses ti
WHERE name = 'inactive' AND ta.created_at < ti.created_at AND ti.product_id=ta.product_id
GROUP BY product_id
) AS inactive_date
FROM statuses ta
WHERE name = 'active'
);
CREATE VIEW VIEW_product_dates_days AS
(
SELECT product_id, active_date, inactive_date, datediff(IFNULL(inactive_date, SYSDATE()),active_date) AS nb_days
FROM VIEW_product_dates
);
CREATE VIEW VIEW_product_dates_days_cumul AS
(
SELECT product_id, active_date, ifnull(inactive_date,sysdate()) AS inactive_date, nb_days,
IFNULL((SELECT SUM(V2.nb_days) + V1.nb_days
FROM VIEW_product_dates_days V2
WHERE V2.active_date >= IFNULL(V1.inactive_date, SYSDATE()) AND V1.product_id=V2.product_id
),V1.nb_days) AS cumul_days
FROM VIEW_product_dates_days V1
);
The final view produce this :
| product_id | active_date | inactive_date | nb_days | cumul_days |
|------------|----------------------|----------------------|---------|------------|
| 1 | 2018-01-01T00:00:00Z | 2018-02-01T00:00:00Z | 31 | 49 |
| 1 | 2018-03-01T00:00:00Z | 2018-03-15T00:00:00Z | 14 | 18 |
| 1 | 2018-04-25T00:00:00Z | 2018-04-29T11:28:39Z | 4 | 4 |
| 2 | 2018-03-01T00:00:00Z | 2018-04-29T11:28:39Z | 59 | 59 |
| 3 | 2018-03-10T00:00:00Z | 2018-03-15T00:00:00Z | 5 | 5 |
So it aggregates all active periods of all products, it counts the number of days for each period, and the cumulative days of all past active periods since current date.
Then we can query this final view to get the desired date for each product. I set a variable for your 20 days, so you can change that number easily if you want.
SET #cap_days = 20 ;
SELECT PD.id, Pd.name,
SUM(CASE WHEN o.created_at > PD.date_to_start_counting_sales THEN 1 ELSE 0 END) AS recent_sales_count ,
PD.date_to_start_counting_sales
FROM
(
SELECT p.*,
(CASE WHEN LowerCap.max_cumul_days IS NULL
THEN ADDDATE(ifnull(HigherCap.min_inactive_date,sysdate()),(-#cap_days))
ELSE
CASE WHEN LowerCap.max_cumul_days < #cap_days AND HigherCap.min_inactive_date IS NULL
THEN ADDDATE(ifnull(LowerCap.max_inactive_date,sysdate()),(-LowerCap.max_cumul_days))
ELSE ADDDATE(ifnull(HigherCap.min_inactive_date,sysdate()),(LowerCap.max_cumul_days-#cap_days))
END
END) as date_to_start_counting_sales
FROM products P
LEFT JOIN
(
SELECT product_id, MAX(cumul_days) AS max_cumul_days, MAX(inactive_date) AS max_inactive_date
FROM VIEW_product_dates_days_cumul
WHERE cumul_days <= #cap_days
GROUP BY product_id
) LowerCap ON P.id=LowerCap.product_id
LEFT JOIN
(
SELECT product_id, MIN(cumul_days) AS min_cumul_days, MIN(inactive_date) AS min_inactive_date
FROM VIEW_product_dates_days_cumul
WHERE cumul_days > #cap_days
GROUP BY product_id
) HigherCap ON P.id=HigherCap.product_id
) PD
LEFT JOIN items i ON PD.id = i.product_id
LEFT JOIN orders o ON o.id = i.order_id
GROUP BY PD.id, Pd.name, PD.date_to_start_counting_sales
Returns
| id | name | recent_sales_count | date_to_start_counting_sales |
|----|--------|--------------------|------------------------------|
| 1 | Apple | 3 | 2018-01-30T00:00:00Z |
| 2 | Banana | 0 | 2018-04-09T20:43:23Z |
| 3 | Grape | 1 | 2018-03-10T00:00:00Z |
FIDDLE : http://sqlfiddle.com/#!9/804f52/24

Not sure which version of MySql you're working with, but if you can use 8.0, that version came out with a lot of functionality that makes things slightly more doable (CTE's, row_number(), partition, etc.).
My recommendation would be to create a view like in this DB-Fiddle Example, call the view on server side and iterate programatically. There are ways of doing it in SQL, but it'd be a bear to write, test and likely would be less efficient.
Assumptions:
Products cannot be sold during inactive date ranges
Statuses table will always alternate status active/inactive/active for each product. I.e. no date ranges where a certain product is both active and inactive.
View Results:
+------------+-------------+------------+-------------+
| product_id | active_date | end_date | days_active |
+------------+-------------+------------+-------------+
| 1 | 2018-01-01 | 2018-02-01 | 31 |
+------------+-------------+------------+-------------+
| 1 | 2018-03-01 | 2018-03-15 | 14 |
+------------+-------------+------------+-------------+
| 1 | 2018-04-25 | 2018-04-29 | 4 |
+------------+-------------+------------+-------------+
| 2 | 2018-03-01 | 2018-04-29 | 59 |
+------------+-------------+------------+-------------+
| 3 | 2018-03-10 | 2018-03-15 | 5 |
+------------+-------------+------------+-------------+
View:
CREATE OR REPLACE VIEW days_active AS (
WITH active_rn
AS (SELECT *, Row_number()
OVER ( partition BY NAME, product_id
ORDER BY created_at) AS rownum
FROM statuses
WHERE name = 'active'),
inactive_rn
AS (SELECT *, Row_number()
OVER ( partition BY NAME, product_id
ORDER BY created_at) AS rownum
FROM statuses
WHERE name = 'inactive')
SELECT x1.product_id,
x1.created_at AS active_date,
CASE WHEN x2.created_at IS NULL
THEN Curdate()
ELSE x2.created_at
END AS end_date,
CASE WHEN x2.created_at IS NULL
THEN Datediff(Curdate(), x1.created_at)
ELSE Datediff(x2.created_at,x1.created_at)
END AS days_active
FROM active_rn x1
LEFT OUTER JOIN inactive_rn x2
ON x1.rownum = x2.rownum
AND x1.product_id = x2.product_id ORDER BY
x1.product_id);

Related

Only display Card payments

I designed a till system about 6 years ago, and while the code is dismal and horrible to look at, it is still going and the cafe I designed it for has been using it all this time.
However, they have recently acquired a card machine, and so now when they want to view all the sales for the day they wnat to see cash vs card in two separate tables.
This is proving tricky and the SQL for it is stumping me - I can't get my head around it.
Here are the tables involved:
categories
+----+-------------------+---------+------------+
| id | name | display | ts |
+----+-------------------+---------+------------+
| 1 | Drinks | 1 | 2016-10-14 |
| 2 | General Snacks | 1 | 2016-10-14 |
| 3 | Lunch Options | 1 | 2016-10-14 |
| 4 | Conference Drinks | 1 | 2016-10-14 |
+----+-------------------+---------+------------+
products
+----+-----------------+-------+------+-----+---------+------------+
| id | name | price | cost | cID | display | ts |
+----+-----------------+-------+------+-----+---------+------------+
| 1 | English Tea | 0.6 | 0.09 | 1 | 1 | 2018-02-15 |
| 2 | Speciality Teas | 0.8 | 0.17 | 1 | 1 | 2018-02-15 |
| 3 | Crisps | 0.6 | 0.41 | 3 | 1 | 2018-02-15 |
| 4 | Chocolate Bar | 0.6 | 0.5 | 3 | 1 | 2018-02-15 |
+----+-----------------+-------+------+-----+---------+------------+
receipts
+----+-----+-----+----------+------------+
| id | oID | pID | quantity | ts |
+----+-----+-----+----------+------------+
| 1 | 1 | 26 | 1 | 2013-11-21 |
| 2 | 2 | 6 | 2 | 2013-11-21 |
| 3 | 3 | 2 | 1 | 2013-11-21 |
| 4 | 4 | 3 | 1 | 2013-11-21 |
+----+-----+-----+----------+------------+
sales
+----+-------+----------+------+------+--------+------------+
| id | total | tendered | flag | card | userID | ts |
+----+-------+----------+------+------+--------+------------+
| 1 | 1 | 1 | 0 | 0 | 4 | 2013-11-21 |
| 2 | 2 | 2 | 0 | 0 | 4 | 2013-11-21 |
| 3 | 0.6 | 0.6 | 0 | 0 | 4 | 2013-11-21 |
| 4 | 0.6 | 0.6 | 0 | 0 | 4 | 2013-11-21 |
+----+-------+----------+------+------+--------+------------+
Please bear in mind that I wrote this a long time ago and I'm aware that its not perfect. Just to explain the above, oID stands for orderID but really should be salesID and links to the sales table ID, and pID stands for productID and is a foreign key linking to the products table. Similarily, cID is really categoryID.
Okay So the cafe manager had requested a table that looks like the following:
+---------------+-----+------+-------+------------+-----------+
| Drinks | Qty | Cost | Price | Cost-Total | Qty-total |
+---------------+-----+------+-------+------------+-----------+
| Juice Carton | 2 | 33p | 60p | 66p | £1.20 |
| Filter Coffee | 11 | 20p | 80p | £2.20 | £8.80 |
| Sub Total | 13 | | | £2.86 | £10.00 |
| Grand Total | 13 | | | £2.86 | £10.00 |
+---------------+-----+------+-------+------------+-----------+
Which has been fine, I've used the following SQL statement to produce this:
SELECT
categories.name AS category, products.name, pID,
(SELECT SUM(quantity) FROM receipts s WHERE s.pID = r.pID AND DATE(s.ts) = CURDATE()) AS quantity,
products.price,
products.cost
FROM receipts r
LEFT JOIN products ON r.pID = products.id
LEFT JOIN categories ON products.cID = categories.id
WHERE DATE(r.ts) = CURDATE()
GROUP BY r.pID ORDER BY categories.name;
However now I need to display two tables, one for card and one for cash. Now the card payments are marked in the sales table with a 1 in the card column. So I tried writing this:
SELECT
categories.name AS category, products.name, pID,
(SELECT SUM(quantity) FROM receipts s WHERE s.pID = r.pID AND DATE(s.ts) = CURDATE()) AS quantity,
products.price,
products.cost
FROM receipts r
LEFT JOIN products ON r.pID = products.id
LEFT JOIN sales x on r.oID = x.id
LEFT JOIN categories ON products.cID = categories.id
WHERE DATE(r.ts) = CURDATE() AND x.card = 1
GROUP BY r.pID ORDER BY categories.name;
However it is just displaying the same data as the first query. I know where the problem is - its in the embedded SELECT statement (AS quantity), as I'm not specifying in there whether its a card payment or a cash payement. I thought that just by adding x.card = 1 a the end would do it, but evidentally not.
Can anyone help me fix this SQL problem? How can I get the card condition into the embedded SQL, as it is retrieving from receipts and receipts does not hold information as to wether its a card payment or not?
I'm lost as to how to proceed really. All help will be appreciated!
In it's basic form:
SELECT * FROM Sales WHERE card = 1
Will display just the card payments
This will give you any sales from today:
SELECT *
FROM
categories,
products,
sales,
reciepts,
LEFT JOIN
products ON reciepts.pID
sales ON reciepts.oID
categories ON products.cID
WHERE DATE(s.ts) = CURDATE()
AND sales.card = 1
`
So what you have there is correct. It's something else you are missing...
From what I can see so far you haven't selected the sales table which could be your issue.
Have you tried running the code in SQL management studio and seeing what the result is?

How to sum values of two tables and group by date

I am building a trading system where users need to know their running account balance by date for a specific user (uid) including how much they made from trading (results table) and how much they deposited or withdrew from their accounts (adjustments table).
Here is the sqlfiddle and tables: http://sqlfiddle.com/#!9/6bc9e4/1
Adjustments table:
+-------+-----+-----+--------+------------+
| adjid | aid | uid | amount | date |
+-------+-----+-----+--------+------------+
| 1 | 1 | 1 | 20 | 2019-08-18 |
| 2 | 1 | 1 | 50 | 2019-08-21 |
| 3 | 1 | 1 | 40 | 2019-08-21 |
| 4 | 1 | 1 | 10 | 2019-08-19 |
+-------+-----+-----+--------+------------+
Results table:
+-----+-----+-----+--------+-------+------------+
| tid | uid | aid | amount | taxes | date |
+-----+-----+-----+--------+-------+------------+
| 1 | 1 | 1 | 100 | 3 | 2019-08-19 |
| 2 | 1 | 1 | -50 | 1 | 2019-08-20 |
| 3 | 1 | 1 | 100 | 2 | 2019-08-21 |
| 4 | 1 | 1 | 100 | 2 | 2019-08-21 |
+-----+-----+-----+--------+-------+------------+
How do I get the below results for uid (1)
+--------------+------------+------------------+----------------+------------+
| ResultsTotal | TaxesTotal | AdjustmentsTotal | RunningBalance | Date |
+--------------+------------+------------------+----------------+------------+
| - | - | 20 | 20 | 2019-08-18 |
| 100 | 3 | 10 | 133 | 2019-08-19 |
| -50 | 1 | - | 84 | 2019-08-20 |
| 200 | 4 | 90 | 378 | 2019-08-21 |
+--------------+------------+------------------+----------------+------------+
Where RunningBalance is the current account balance for the particular user (uid).
Based on #Gabriel's answer, I came up with something like, but it gives me empty balance and duplicate records
SELECT SUM(ResultsTotal), SUM(TaxesTotal), SUM(AdjustmentsTotal), #runningtotal:= #runningtotal+SUM(ResultsTotal)+SUM(TaxesTotal)+SUM(AdjustmentsTotal) as Balance, date
FROM (
SELECT 0 AS ResultsTotal, 0 AS TaxesTotal, adjustments.amount AS AdjustmentsTotal, adjustments.date
FROM adjustments LEFT JOIN results ON (results.uid=adjustments.uid) WHERE adjustments.uid='1'
UNION ALL
SELECT results.amount AS ResultsTotal, taxes AS TaxesTotal, 0 as AdjustmentsTotal, results.date
FROM results LEFT JOIN adjustments ON (results.uid=adjustments.uid) WHERE results.uid='1'
) unionTable
GROUP BY DATE ORDER BY date
For what you are asking you would want to union then group the results from both tables, this should give the results you want. However, I recommend calculating the running balance outside of MySQL since this adds some complexity to our query.
Weird things could start to happen, for example, if someone already defined the #runningBalance variable as part of the queries scope.
SELECT aggregateTable.*, #runningBalance := ifNULL(#runningBalance, 0) + TOTAL
FROM (
SELECT SUM(ResultsTotal), SUM(TaxesTotal), SUM(AdjustmentsTotal)
, SUM(ResultsTotal) + SUM(TaxesTotal) + SUM(AdjustmentsTotal) as TOTAL
, date
FROM (
SELECT 0 AS ResultsTotal, 0 AS TaxesTotal, amount AS AdjustmentsTotal, date
FROM adjustments
UNION ALL
SELECT amount AS ResultsTotal, taxes AS TaxesTotal, 0 as AdjustmentsTotal, date
FROM results
) unionTable
GROUP BY date
) aggregateTable

MySQL Subselect Issue with two tables and aggregate functions into single query

I have 2 tables
Transaction table
+----+----------+-----+---------+----
| TID | CampaignID | DATE |
+----+----------+-----+---------+---+
| 1 | 5 | 2016-01-01 |
| 2 | 5 | 2016-01-01 |
| 3 | 2 | 2016-01-01 |
| 4 | 5 | 2016-01-01 |
| 5 | 1 | 2016-01-01 |
| 6 | 1 | 2016-02-02 |
| 7 | 3 | 2016-02-02 |
| 8 | 3 | 2016-02-02 |
| 9 | 5 | 2016-02-02 |
| 10| 4 | 2016-02-02 |
+----+----------+-----+---------+---+
Campaign Table
+-------------+----------------+--------------------
| CampaignID | DailyMaxImpressions | CampaignActive
+-------------+----------------+--------------------
| 1 | 5 | Y |
| 2 | 5 | Y |
| 3 | 5 | Y |
| 4 | 5 | Y |
| 5 | 1 | Y |
+-------------+----------------+--------------------
What I am trying to do is get a single random campaign where the the count in transaction table is less than the daily max impressions in the campaign table. I might also be passing a date s part of the query for the transaction table
So for CampaignId 1 there must be 4 trans of less in the transaction table and the Campaignactive must be a "Y"
Any help would be appreciated if this can be done in a single statement. ( mysql )
Thanks in advance,
Jeff Godstein
This should get it for you. The basic query is select each campaign that is active. The INNER query will pre-aggregate per campaign for the given date in question. From that, a LEFT-JOIN allows any campaign to be returned even if it does NOT exist within the subquery OR it DOES exist, but the count is less than that allowed for the date in question. The order by RAND() is obvious.
SELECT
c.CampaignID
from
Campaign c
LEFT JOIN
( select
t1.CampaignID,
count(*) as CampCount
from
Transaction t1
where
t1.Date = YourDateParameterValue
group by
t1.CampaignID ) as T
ON c.CampaignID = T.CampaignID
where
c.CampaignActive = 'Y'
AND ( t.CampaignID IS NULL
OR t.CampCount < c.DailyMaxImpressions )
order by
RAND()

MySQL select a row from a daterange excluding the year

I'm trying to create a MySQL query to select the daily price from a table that is between a date range from another. I only want to use 'starting-ending' months and days from the table "seasons" and I want to pass the year dynamically to the query.
This is my query: (I'm giving it the Year to exclude the one on the table)
SELECT a.season, b.base_price
FROM seasons a
JOIN pricebyseason b ON a.id=b.season_id
WHERE b.prop_id='6' AND '2015-11-29' BETWEEN DATE_FORMAT(a.starting,'2015-%m-%d') AND DATE_FORMAT(a.ending,'2016-%m-%d')
ORDER BY b.base_price DESC
It works but not with all dates.
These are the tables:
seasons (these are static date values)
+----+--------------+------------+------------+
| id | season | starting | ending |
+----+--------------+------------+------------+
| 1 | Peak Season | 2015-12-11 | 2016-01-09 |
| 2 | High Season | 2015-11-27 | 2016-04-15 |
| 3 | Mid Season | 2015-04-16 | 2015-09-01 |
| 4 | Low Season | 2015-09-02 | 2015-11-26 |
| 5 | Spring Break | 2015-03-05 | 2015-03-21 |
+----+--------------+------------+------------+
pricebyseason
+----+---------+-----------+------------+
| id | prop_id | season_id | base_price |
+----+---------+-----------+------------+
| 1 | 6 | 1 | 950 |
| 2 | 6 | 2 | 750 |
| 3 | 6 | 3 | 450 |
| 4 | 6 | 4 | 400 |
| 5 | 6 | 5 | 760 |
+----+---------+-----------+------------+
What I want to achive is query the dialy price between checkin, checkout selection
I create this sqlfiddle: http://sqlfiddle.com/#!9/4a6f4
This is a previuos query that is not working either:
SELECT a.base_price,b.season,b.starting,b.ending
FROM pricebyseason a JOIN seasons b ON a.season_id=b.id
WHERE a.prop_id='6' AND
(DATE_FORMAT(b.starting,'%m-%d') <= '12-27' OR DATE_FORMAT(b.starting,'2016-%m-%d') >= '2015-12-27')
AND
(DATE_FORMAT(b.ending,'%m-%d') >= '12-27' OR DATE_FORMAT(b.ending,'2016-%m-%d') <= '2015-12-27')
ORDER BY base_price DESC
And here are some sample dates for each season: '2016-01-08','2015-12-27','2016-04-14','2015-11-29','2016-04-15','2015-09-01','2016-09-02','2015-11-26','2016-10-10','2016-03-18','2016-06-22','2015-06-15'
Thank a lot

Complex SQL query suggestions please

I have three tables with schema as below:
Table: Apps
| ID (bigint) | USERID (Bigint)| START_TIME (datetime) |
-------------------------------------------------------------
| 1 | 13 | 2013-05-03 04:42:55 |
| 2 | 13 | 2013-05-12 06:22:45 |
| 3 | 13 | 2013-06-12 08:44:24 |
| 4 | 13 | 2013-06-24 04:20:56 |
| 5 | 13 | 2013-06-26 08:20:26 |
| 6 | 13 | 2013-09-12 05:48:27 |
Table: Hosts
| ID (bigint) | APPID (Bigint)| DEVICE_ID (Bigint) |
-------------------------------------------------------------
| 1 | 1 | 1 |
| 2 | 2 | 1 |
| 3 | 1 | 1 |
| 4 | 3 | 3 |
| 5 | 1 | 4 |
| 6 | 2 | 3 |
Table: Usage
| ID (bigint) | APPID (Bigint)| HOSTID (Bigint) | Factor (varchar) |
-------------------------------------------------------------------------------------
| 1 | 1 | 1 | Low |
| 2 | 1 | 3 | High |
| 3 | 2 | 2 | Low |
| 4 | 3 | 4 | Medium |
| 5 | 1 | 5 | Low |
| 6 | 2 | 2 | Medium |
Now if put is userid, i want to get the count of rows of table rows for each month (of all app) for each "Factor" month wise for the last 6 months.
If a DEVICE_ID appears more than once in a month (based on START_TIME, based on joining Apps and Hosts), only the latest rows of Usage (based on combination of Apps, Hosts and Usage) be considered for calculating count.
Example output of the query for the above example should be: (for input user id=13)
| MONTH | USAGE_COUNT | FACTOR |
-------------------------------------------------------------
| 5 | 0 | High |
| 6 | 0 | High |
| 7 | 0 | High |
| 8 | 0 | High |
| 9 | 0 | High |
| 10 | 0 | High |
| 5 | 2 | Low |
| 6 | 0 | Low |
| 7 | 0 | Low |
| 8 | 0 | Low |
| 9 | 0 | Low |
| 10 | 0 | Low |
| 5 | 1 | Medium |
| 6 | 1 | Medium |
| 7 | 0 | Medium |
| 8 | 0 | Medium |
| 9 | 0 | Medium |
| 10 | 0 | Medium |
How is this calculated?
For Month May 2013 (05-2013), there are two Apps from table Apps
In table Hosts , these apps are associated with device_id's 1,1,1,4,3
For this month (05-2013) for device_id=1, the latest value of start_time is: 2013-05-12 06:22:45 (from tables hosts,apps), so in table Usage, look for combination of appid=2&hostid=2 for which there are two rows one with factor Low and other Medium,
For this month (05-2013) for device_id=4, by following same procedure we get one entry i.e 0 Low
Similarly all the values are calculated.
To get the last 6 months via query i'm trying to get it with the following:
SELECT MONTH(DATE_ADD(NOW(), INTERVAL aInt MONTH)) AS aMonth
FROM
(
SELECT 0 AS aInt UNION SELECT -1 UNION SELECT -2 UNION SELECT -3 UNION SELECT -4 UNION SELECT -5
)
Please check sqlfiddle: http://sqlfiddle.com/#!2/55fc2
Because the calculation you're doing involves the same join multiple times, I started by creating a view.
CREATE VIEW `app_host_usage`
AS
SELECT a.id "appid", h.id "hostid", u.id "usageid",
a.userid, a.start_time, h.device_id, u.factor
FROM apps a
LEFT OUTER JOIN hosts h ON h.appid = a.id
LEFT OUTER JOIN `usage` u ON u.appid = a.id AND u.hostid = h.id
WHERE a.start_time > DATE_ADD(NOW(), INTERVAL -7 MONTH)
The WHERE condition is there because I made the assumption that you don't want July 2005 and July 2006 to be grouped together in the same count.
With that view in place, the query becomes
SELECT months.Month, COUNT(DISTINCT device_id), factors.factor
FROM
(
-- Get the last six months
SELECT (MONTH(NOW()) + aInt + 11) % 12 + 1 "Month" FROM
(SELECT 0 AS aInt UNION SELECT -1 UNION SELECT -2 UNION SELECT -3 UNION SELECT -4 UNION SELECT -5) LastSix
) months
JOIN
(
-- Get all known factors
SELECT DISTINCT factor FROM `usage`
) factors
LEFT OUTER JOIN
(
-- Get factors for each device...
SELECT
MONTH(start_time) "Month",
device_id,
factor
FROM app_host_usage a
WHERE userid=13
AND start_time IN (
-- ...where the corresponding usage row is connected
-- to an app row with the highest start time of the
-- month for that device.
SELECT MAX(start_time)
FROM app_host_usage a2
WHERE a2.device_id = a.device_id
GROUP BY MONTH(start_time)
)
GROUP BY MONTH(start_time), device_id, factor
) usageids ON usageids.Month = months.Month
AND usageids.factor = factors.factor
GROUP BY factors.factor, months.Month
ORDER BY factors.factor, months.Month
which is insanely complicated, but I've tried to comment explaining what each part does. See this sqlfiddle: http://sqlfiddle.com/#!2/5c871/1/0