I need to run this kind of query.
INSERT INTO `book_newBookOrder` (id, volume, 5, chapterNr, sectionNr, `text`)
SELECT id, volume, bookNr, chapterNr, sectionNr, `text`
FROM book_oldBookOrder
WHERE booknr = 1;
The fixed value 5 in the INSERT INTO part breaks it.
I must be able to specify the two values as above.
So I want to select everything with bookNr = 1 in the oldbooknr table and store that as booknr 5 in the newbookorder table.
Please advise me. Thanks.
You have a syntax error: The items in the first set of brackets in the INSERT should be the field names. "5" is not a field name, that's the value you want to be inserted (I assume you wish to set this value the same in every row which gets inserted?). That should be in the SELECT:
INSERT INTO `book_newBookOrder` (id, volume, bookNr, chapterNr, sectionNr, `text`)
SELECT id, volume, 5, chapterNr, sectionNr, `text`
FROM book_oldBookOrder
WHERE booknr = 1;
Related
I am using codeigniter insert_batch($table, $data);
I have a column name as "Comment posted by the customer".
When I try to batch insert data into it. The insert query changes as:
INSERT INTO `table` (`id`, `Name`, `Status`,`Comment posted by the` `customer`, `isActive`) VALUES (),(),()...;
As seen the column splits up into 2 parts -
1.Comment posted by the
2.customer
And this throws an error. How do I overcome this? I need to insert it considering it as a single column.
Try to format the query like this
INSERT INTO table (id, Name, Status, `Comment posted by the customer`, isActive) VALUES (),(),()
UPDATE
You can omit the column names and specify the values for all columns
INSERT INTO table VALUES (), (), ()
I am using a SQLDataSource to insert information into a database.
While it is inserting it also grabs the ID of that row
INSERT INTO InkInventory(CodeNumber, InkType, PMS, Color, Description, PoundAvailable, Location, Supplier)
OUTPUT INSERTED.ID
VALUES (#CodeNumber, #InkType, #PMS, #Color, #Description, #PoundsAvailable, #Location, #Supplier)
When I use Query Builder it gives me the output perfectly, but how do I then refer to those results in my code behind, to use that number in another place?
USE AdventureWorks2012;
GO
--Display the value of LocationID in the last row in the table.
SELECT MAX(LocationID) FROM Production.Location;
GO
INSERT INTO Production.Location (Name, CostRate, Availability, ModifiedDate)
VALUES ('Damaged Goods', 5, 2.5, GETDATE());
GO
SELECT ##IDENTITY AS 'Identity';
GO
--Display the value of LocationID of the newly inserted row.
SELECT MAX(LocationID) FROM Production.Location;
GO
i want to insert the scholar's id to the tblinbox. Here is my query:
$sql = "INSERT INTO tblinbox VALUES ('','$sender','$type','$subject','$LRN','$content','$date', '$newyearLevel','','$userType','THIS_IS_FOR_THE_ID_OF_THE_SCHOLAR')
SELECT id FROM tblscholar WHERE schoYear = '$newyearLevel'";
my problem is,it is not inserting. what will i change in my query?
INSERT ... SELECT syntax does not allow for VALUES declaration. The values ARE the results returned from the SELECT.
See the documentation here: http://dev.mysql.com/doc/refman/5.6/en/insert-select.html
I honestly am not fully sure what you are trying to do with your insert. If you are trying to insert the same values held in your variables for each id value from the tblscholar table then perhaps you need to do something like this:
INSERT INTO tblinbox
/*
maybe add column definitions here to make it clearer
column definitions could look like this:
(
someField,
type,
subject,
LRN,
content,
`date`,
newyearLevel,
someOtherField,
userType,
id
)
*/
SELECT
'',
'$sender',
'$type',
'$subject',
'$LRN',
'$content',
'$date',
'$newyearLevel',
'',
'$userType',
id
FROM tblscholar
WHERE schoYear = '$newyearLevel'
An INSERT statement supports either a VALUES clause followed by a row of values, or else a SELECT query with columns to match the columns of the table you want to insert into.
But not both!
But you can add constant values into your SELECT query:
$sql = "INSERT INTO tblinbox
SELECT '','$sender','$type','$subject','$LRN','$content','$date',
'$newyearLevel','','$userType', id
FROM tblscholar WHERE schoYear = '$newyearLevel'";
considering id is the first column in your insert statement, try this
$sql = "INSERT INTO tblinbox VALUES ((SELECT id FROM tblscholar WHERE schoYear = '$newyearLevel'),'$sender','$type','$subject','$LRN','$content','$date', '$newyearLevel','','$userType')";
You can insert values either fetching values form another table or providing values as follows:
Way 1:
INSERT INTO tblinbox(coloumn_name1,coloumn_name2) VALUES (value1,value2);
Way 2:
INSERT INTO tblinbox(coloumn_name1,coloumn_name2) SELECT value1,value2 from tblscholer where schoYear= '$newyearLevel';
I have this Statement:
INSERT INTO qa_costpriceslog (item_code, invoice_code, item_costprice)
VALUES (1, 2, (SELECT item_costprice FROM qa_items WHERE item_code = 1));
I'm trying to insert a value copy the same data of item_costprice, but show me the error:
Error Code: 1136. Column count doesn't match value count at row 1
How i can solve this?
Use numeric literals with aliases inside a SELECT statement. No () are necessary around the SELECT component.
INSERT INTO qa_costpriceslog (item_code, invoice_code, item_costprice)
SELECT
/* Literal number values with column aliases */
1 AS item_code,
2 AS invoice_code,
item_costprice
FROM qa_items
WHERE item_code = 1;
Note that in context of an INSERT INTO...SELECT, the aliases are not actually necessary and you can just SELECT 1, 2, item_costprice, but in a normal SELECT you'll need the aliases to access the columns returned.
You can just simply e.g.
INSERT INTO modulesToSections (fk_moduleId, fk_sectionId, `order`) VALUES
((SELECT id FROM modules WHERE title="Top bar"),0,-100);
I was disappointed at the "all or nothing" answers. I needed (again) to INSERT some data and SELECT an id from an existing table.
INSERT INTO table1 (id_table2, name) VALUES ((SELECT id FROM table2 LIMIT 1), 'Example');
The sub-select on an INSERT query should use parenthesis in addition to the comma as deliminators.
For those having trouble with using a SELECT within an INSERT I recommend testing your SELECT independently first and ensuring that the correct number of columns match for both queries.
Your insert statement contains too many columns on the left-hand side or not enough columns on the right hand side. The part before the VALUES has 7 columns listed, but the second part after VALUES only has 3 columns returned: 1, 2, then the sub-query only returns 1 column.
EDIT: Well, it did before someone modified the query....
As a sidenote to the good answer of Michael Berkowski:
You can also dynamically add fields (or have them prepared if you're working with php skripts) like so:
INSERT INTO table_a(col1, col2, col3)
SELECT
col1,
col2,
CURRENT_TIMESTAMP()
FROM table_B
WHERE b.col1 = a.col1;
If you need to transfer without adding new data, you can use NULL as a placeholder.
If you have multiple string values you want to add, you can put them into a temporary table and then cross join it with the value you want.
-- Create temp table
CREATE TEMPORARY TABLE NewStrings (
NewString VARCHAR(50)
);
-- Populate temp table
INSERT INTO NewStrings (NewString) VALUES ('Hello'), ('World'), ('Hi');
-- Insert desired rows into permanent table
INSERT INTO PermanentTable (OtherID, NewString)
WITH OtherSelect AS (
SELECT OtherID AS OtherID FROM OtherTable WHERE OtherName = 'Other Name'
)
SELECT os.OtherID, ns.NewString
FROM OtherSelect os, NewStrings ns;
This way, you only have to define the strings in one place, and you only have to do the query in one place. If you used subqueries like I initially did and like Elendurwen and John suggest, you have to type the subquery into every row. But using temporary tables and a CTE in this way, you can write the query only once.
I'm dealing with a relational table and I've been wondering if there's a way to lower the number of queries I need to make when inserting data to the tables..
Here are the queries I currently use:
I insert the "main" values.
INSERT INTO products
(title, description, status, url)
VALUES
('some title', 'description of doom', 1, 'some-title');
We make it insert the value only if it doesn't exist already.
INSERT IGNORE INTO values
(value)
VALUES
('example value');
Since I'm not sure if the query was actually inserted, I get the id..
SELECT id
FROM
values
WHERE
value = 'example value';
Where "?" is the ID I got from the last query.
INSERT INTO link
( id_product, id_catalog, id_value )
VALUES
( 33, 1, ? );
This means that each extra value I need to add will cost 3 queries. So my question is: Is there a more efficient way to do this?
You can do this to at least drop one of the queries:
INSERT INTO link
( id_product, id_catalog, id_value )
VALUES
( 33, 1, (SELECT id
FROM values
WHERE value = 'example value') );
I basically am replacing the '?' with a sub select of the second query to get the id.
"Is there a more efficient way to do this?"
No. Not really. Creating three things takes three inserts.
You should be able to tell whether the insert succeeded with the ROW___COUNT() function from inside MySQL. If calling from another language (e.g. PHP), the mysql_query or equivalent function will return the row count.
You could use an INSERT INTO ... ON DUPLICATE KEY UPDATE statement.
This does, however, require that the primary key be one of the values for the insert, so it doesn't work on tables with an auto-increment.