Change table structure from mysql to sqllite - mysql

i want to change database of my simple application from mysql to sqlite, this is my sql command :
CREATE TABLE `Todo` (
`Id` int(11) NOT NULL AUTO_INCREMENT,
`Title` varchar(255) DEFAULT NULL,
`Category` varchar(255) DEFAULT NULL,
`State` varchar(255) DEFAULT NULL,
PRIMARY KEY (`Id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8;
im try to create sqllite but return me this error : Error: near "AUTO_INCREMENT": syntax error how i can fix it ?


Instead of using primary key separately, please mention it with your AUTO INCREMENT key
CREATE TABLE `Todo` (
`Id` integer primary key AUTOINCREMENT,
`Title` varchar(255) DEFAULT NULL,
`Category` varchar(255) DEFAULT NULL,
`State` varchar(255) DEFAULT NULL
)

Related

Error code: 1824 Failed to open the refernced table [table exists]

I'm trying to add a foreign key constraint, but I'm getting [Error Code: 1824: Failed to open the refrenced table 'agent_agent']
the table agent_agent exists in my database, I can't get my head around this issue.
I tried creating the constraint using the graphical mode of mysql workbench and I'm getting the same error.
select * from agent_agent; return the data, so the table exists in the DB but:
ALTER TABLE demande_contact
ADD CONSTRAINT dddd
FOREIGN KEY (agent_id_id) REFERENCES agent_agent(id);
is returning an error 1824.
Edit: Here's the 2 tables DDL
CREATE TABLE `agent_agent` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`matricule` varchar(6) NOT NULL,
`nom_et_prenom` varchar(60) NOT NULL,
`fonction` varchar(60) NOT NULL,
`structure` varchar(60) NOT NULL,
`poste_org` varchar(60) DEFAULT NULL,
`metier` varchar(3) DEFAULT NULL,
`csp` varchar(20) DEFAULT NULL,
`en_activite` tinyint(1) NOT NULL,
`timestamp` datetime(6) NOT NULL,
`updated` datetime(6) NOT NULL,
`user_id` int(11) NOT NULL,
`service` varchar(60) DEFAULT NULL,
`centre_cout` varchar(10) DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `agent_agent_user_id_bfcb5c50` (`user_id`)
) ENGINE=MyISAM AUTO_INCREMENT=628 DEFAULT CHARSET=utf8
CREATE TABLE `demande_contact` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`telephone` varchar(40) NOT NULL,
`agent_id_id` int(11) NOT NULL,
`demande_id_id` int(11) NOT NULL,
PRIMARY KEY (`id`),
KEY `demande_contact_demande_id_id_0abc00b0_fk_demande_d` (`demande_id_id`),
KEY `agent_id_id_constraint_idx` (`agent_id_id`),
CONSTRAINT `demande_contact_demande_id_id_0abc00b0_fk_demande_d` FOREIGN KEY (`demande_id_id`) REFERENCES `demande_demandetransport` (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8

MySQL Error Number 150 when creating Table with Foreign Key

I am having an issue creating a new table in my database. I've seen that the error code it is returning is to do with Foreign Key constraints.
I checked to ensure that the data type of the foreign key in the new table matched the data type of the primary key in the other table. They are both int(11).
However I am still getting an error. Am I missing something? This is my SQL script for creating the new table:
CREATE TABLE `regular_features` (
`id` INT(11) NOT NULL AUTO_INCREMENT,
`name` VARCHAR(200) DEFAULT NULL,
`day` VARCHAR(200) DEFAULT NULL,
`description` TEXT DEFAULT NULL,
`programme_id` INT(11) NOT NULL,
PRIMARY KEY (`id`),
FOREIGN KEY (`programme_id`) REFERENCES directoryprogramme(id)
) ENGINE=INNODB DEFAULT CHARSET=utf8;
This is the original table containing the primary key:
CREATE TABLE `directoryprogramme` (
`id` INT(11) NOT NULL AUTO_INCREMENT,
`name` VARCHAR(250) NOT NULL,
`broadcast_time` VARCHAR(100) NOT NULL,
`description` TEXT NOT NULL,
`days` VARCHAR(150) NOT NULL,
`contributors` VARCHAR(250) NOT NULL,
`directorycompany_id` INT(11) NOT NULL,
`directorycontact_id` VARCHAR(250) NOT NULL,
`facebook_link` VARCHAR(250) DEFAULT NULL,
`twitter_link` VARCHAR(250) DEFAULT NULL,
`wikipedia_link` VARCHAR(250) DEFAULT NULL,
`web` VARCHAR(250) DEFAULT NULL,
`imageextension` VARCHAR(10) DEFAULT NULL,
`type` VARCHAR(20) NOT NULL DEFAULT 'other',
PRIMARY KEY (`id`)
) ENGINE=MYISAM AUTO_INCREMENT=1161 DEFAULT CHARSET=utf8;
The Foreign Key will be the id of directoryprogramme

The problem is the last line of your create statement:
ENGINE=INNODB DEFAULT CHARSET=utf8;
You mix MYISAM in ald table with INNODB in your new table.
That doesn't work.
Chnage the engine in your new table to MYISAM and it works.

Missing Value in form when creating a table in phpmyadmin SQL

I am trying to make a table but every time I type my sql code I get an error "Missing value in form". I am sure there is no problem with the code rather something else.
Here is my code
CREATE TABLE IF NOT EXISTS `users` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`username` varchar(255) NOT NULL,
`password` varchar(255) NOT NULL,
`first_name` varchar(255) NOT NULL,
`last_name` varchar(255) NOT NULL,
`email` varchar(255) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `username` (`username`),
UNIQUE KEY `email` (`email`)
)
ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;

Field not inserting or updating , int type in sql

I am working on magento platform.I face a problem regarding values insertion to specific field: My query run perfect but one specific column not working for any query.I try my best but didn't find why .When i change the column type from int to varchar type it works.This is my table structure.
CREATE TABLE `followupemails_emaillogs` (
`id` int(8) NOT NULL AUTO_INCREMENT,
`schedule_time` datetime DEFAULT NULL,
`sent_time` datetime DEFAULT NULL,
`email_status` varchar(100) DEFAULT NULL,
`client_name` varchar(250) DEFAULT NULL,
`client_email` varchar(250) DEFAULT NULL,
`followupemails_id` int(11) DEFAULT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `id` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=30 DEFAULT CHARSET=latin1.
the "followupemails_id" column not working in insert and update query.This is one update query where record exist that id(29). UPDATE followupemails_emaillogs SET followupemails_id=5 WHERE id =29.
This is insertion query INSERT INTO followupemails_emaillogs SET followupemails_id=4, schedule_time='2013-10-23 08:10:00', email_status='pending', client_name='ayaz ali'.this works fine on fiddle but not on my sqlyog ? what could be the issue.At last i find query that work perfect
.INSERT INTO followupemails_emaillogs (followupemails_id,schedule_time,email_status,client_name,client_email) VALUES (26,'2013-10-23 08:10:00','pending','ayaz ali','mamhmood#yahoo.com');
Can anyone tell me why set query not working but second query works perfect.so that i can accept his answer.Thanks for all your help

Try like this
To Create,
CREATE TABLE followupemails_emaillogs (
id int(8) NOT NULL AUTO_INCREMENT PRIMARY KEY,
schedule_time datetime DEFAULT NULL,
sent_time datetime DEFAULT NULL,
email_status varchar(100) DEFAULT NULL,
client_name varchar(250) DEFAULT NULL,
client_email varchar(250) DEFAULT NULL,
followupemails_i int(11) DEFAULT NULL,
UNIQUE (id)
)
To Insert,
INSERT INTO followupemails_emaillogs (schedule_time,sent_time,email_status,client_name,client_email,followupemails_i)
VALUES
('2012-05-05','2012-05-06',"sent","sagar","sagar#xxxx.com",2)

the whole query is ok
CREATE TABLE `followupemails_emaillogs` (
`id` int NOT NULL AUTO_INCREMENT,
`schedule_time` datetime DEFAULT NULL,
`sent_time` datetime DEFAULT NULL,
`email_status` varchar(100) DEFAULT NULL,
`client_name` varchar(250) DEFAULT NULL,
`client_email` varchar(250) DEFAULT NULL,
`followupemails_id` int DEFAULT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `id` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=30 DEFAULT CHARSET=latin1.
but at the last there is dot which is actually error so remove the dot and create the table
latin1.
so remove the dot sign and not null in id filed use this line by default fields are null so don't use default null
id int (8) AUTO_INCREMENT
CREATE TABLE `followupemails_emaillogs` (
`id` int (8) AUTO_INCREMENT,
`schedule_time` datetime DEFAULT NULL,
`sent_time` datetime DEFAULT NULL,
`email_status` varchar(100),
`client_name` varchar(250),
`client_email` varchar(250),
`followupemails_id` int,
PRIMARY KEY (`id`),
UNIQUE KEY `id` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=30 DEFAULT CHARSET=latin1

don't need (11) in the sql query for int operator , This get for length of the nvarchar,varchar datatype column only not a int datatype,So change and write int instead of int(11) and int(8)
Try this query instead of your query
CREATE TABLE `followupemails_emaillogs` (
`id` int NOT NULL AUTO_INCREMENT,
`schedule_time` datetime DEFAULT NULL,
`sent_time` datetime DEFAULT NULL,
`email_status` varchar(100) DEFAULT NULL,
`client_name` varchar(250) DEFAULT NULL,
`client_email` varchar(250) DEFAULT NULL,
`followupemails_id` int DEFAULT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `id` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=30 DEFAULT CHARSET=latin1.

Unable to create table from query

I have the following query
CREATE TABLE grades_gra (
id_gra INT(11) NOT NULL AUTO_INCREMENT,
identifier_gra VARCHAR(2) DEFAULT NULL,
name_gra VARCHAR(250) DEFAULT NULL
PRIMARY KEY (id_gra)
)
ENGINE = INNODB AUTO_INCREMENT=1 DEFAULT CHARSET=UTF8;
When I execute it, it gives me an error invalid default vale for 'naes_gra'

You forgot a comma before primary key:
CREATE TABLE grades_gra (
id_gra INT(11) NOT NULL AUTO_INCREMENT,
identifier_gra VARCHAR(2) DEFAULT NULL,
name_gra VARCHAR(250) DEFAULT NULL,
PRIMARY KEY (id_gra)
)
ENGINE = INNODB AUTO_INCREMENT=1 DEFAULT CHARSET=UTF8;
SQLFiddle demo

Put the comma after DEFAULT NULL, before PRIMARY keyword