I have two table as table1 and table2 given below:
I want to have the value of only those table_name from table1 which has there id in print_table column in table 2.
I have implemented the following query but it returns only one value:
SELECT * FROM print_tabel_permission_admin WHERE id IN (select print_table from secondary)
Use FIND_IN_SET:
SELECT DISTINCT
t1.table_name
FROM table1 t1
INNER JOIN table2 t2
ON FIND_IN_SET(t1.id, t2.print_table) > 0;
Demo
You should probably move away from storing CSV data in your tables like this. Instead, break out the IDs in table2 onto separate rows. This will make your life easier.
I have 2 tables:
Table1- contains PhoneNumber|Name
Table2- contains PhoneNumber|Address
I want to create Table3 with PhoneNumber|Name|Address
Table1 and Table2 may have out of order or different amount of entries, therefore table1 will act as main list.
please suggest way forward. using MySQL.
Use CREATE..SELECT with a LEFT JOIN :
CREATE TABLE Table3 AS
SELECT t1.PhoneNumber,t1.name,t2.address
FROM Table1 t1
LEFT JOIN Table2 t2
ON(t1.PhoneNumber = t2.PhoneNumber)
I have 2 tables. I want to find out whether the values present in the first table is there in another table with a different field name.
Here is how it looks,
Table1
BillNo
43529179
43256787
35425676
25467778
24354758
45754748
Table2
BNo
113104808
25426577
268579679
2542135464
252525232
235263663
I have 137 records in table1 that needs to be checked against table2.
Instead of doing it one by one using the following command,
Select * from Table2 where BNo = '43529179';
This gives the result for just the mentioned value. Is there a way to check for all the values in a single query?
Thanks!
You can use a sub-select to compare against:
Select * from Table2 where BNo IN (SELECT BillNo FROM Table1);
That will "evalaute" to something like Select * from Table2 where BNo IN (113104808, 25426577, 268579679, 2542135464, 252525232, ...);
Join the tables, and check how many matching records there are:
select
count(*) as Matches
from
Table1 as t1
inner join Table2 as t2 on t2.BNo = t1.BillNo
You can also use a left join to pick out the records in table 1 that has no matching record in table 2:
select
t1.BillNo
from
Table1 as t1
left join Table2 as t2 on t2.BNo = t1.BillNo
where
t2.BNo is null
i have a db like this:
Table1:
id
id_item
table (enum: 'table2','table3','table4')
table2:
id
value
table3:
id
value
table4:
[...]
And i want to run a query like this:
SELECT t1.id, t2.value FROM table1 AS t1
LEFT JOIN table1.table as t2 ON t1.id_item=t2.id
Is it possible? or i have to select first table1 and after the value?
( sorry for my bad eng :) )
If I understood the last column in Table 1 correctly and it is just a string, you can't.
You cannot write a column into the FORM-clausal and wait for mysql to evaluate it for every row and find the correct table to join it with.
To do this you will need to create a view where you will have the data from all the tables, together with the table name as an additional column. Afterwards you can perform a join like that between Table1 and the new view
I don't know why I am confused with this query.
I have two table: Table A with 900 records and Table B with 800 records. Both table need to contain the same data but there is some mismatch.
I need to write a mysql query to insert missing 100 records from Table A to Table B.
In the end, both Table A and Table B should be identical.
I do not want to truncate all the entries first and then do a insert from another table. So please any help is appreciated.
Thank you.
It is also possible to use LEFT OUTER JOIN for that. This will avoid subquery overhead (when system might execute subquery one time for each record of outer query) like in John Woo's answer, and will avoid doing unnecessary work overwriting already existing 800 records like in user2340435's one:
INSERT INTO b
SELECT a.* FROM a
LEFT OUTER JOIN b ON b.id = a.id
WHERE b.id IS NULL;
This will first select all rows from A and B tables including all columns from both tables, but for rows which exist in A and don't exist in B all columns for B table will be NULL.
Then it filter only such latter rows (WHERE b.id IS NULL),
and at last it inserts all these rows into B table.
I think you can use IN for this. (this is a simpliplification of your query)
INSERT INTO table2 (id, name)
SELECT id, name
FROM table1
WHERE (id,name) NOT IN
(SELECT id, name
FROM table2);
SQLFiddle Demo
AS you can see on the demonstration, table2 has only 1 records but after executing the query, 2 records were inserted on table2.
If it's mysql and the tables are identical, then this should work:
REPLACE INTO table1 SELECT * FROM table2;
This will insert the missing records into Table1
INSERT INTO Table2
(Col1, Col2....)
(
SELECT Col1, Col2,... FROM Table1
EXCEPT
SELECT Col1, Col2,... FROM Table2
)
You can then run an update query to match the records that differ.
UPDATE Table2
SET
Col1= T1.Col1,
Col2= T1.Col2,
FROM
Table T1
INNER JOIN
Table2 T2
ON
T1.Col1 = T2.Col1
Code also works when a group by and having clauses are used. Tested SQL 2012 (11.0.5058) Tab1 is source with new records, Tab 2 is the destination to be updated. Tab 2 also has an Identity column. (Yes folks, real world is not as neat and clean as the lab assignments)
INSERT INTO Tab2
SELECT a.T1,a.T2,a.T3,a.T4,a.Val1,a.Val2,a.Val3,a.Val4,-9,-9,-9,-9,MIN(hits) MinHit,MAX(hits) MaxHit,SUM(count) SumCnt, count(distinct(week)) WkCnt
FROM Tab1 a
LEFT OUTER JOIN Tab2 b ON b.t1 = a.t1 and b.t2 = a.t2 and b.t3 = a.t3 and b.t4 = a.t4 and b.val1 = a.val1 and b.val2 = a.val2 and b.val3 = a.val3 and b.val4 = a.val4
WHERE b.t1 IS NULL or b.Val1 is NULL
group by a.T1,a.T2,a.T3,a.T4,a.Val1,a.Val2,a.Val3,a.Val4 having MAX(returns)<4 and COUNT(distinct(week))>2 ;