Mysql Select Two Rows in One - mysql

I need to select in one row grouped by a same key other two values in the same field:
TABLE
attribute_id
entity_id
value
DATA
attribute_id|entity_id| value
85| 220| 4740
257| 220|image1.png
And need this result:
attibute_id 85 as SKU, attribute_id 257 as IMAGE in this result:
SKU | IMAGE
4740 | image1.png
How can I do this? TIA!

I think this does what you want:
select ts.entity_id, ts.value as sku, ti.value as image
from t ts join
t ti
on ts.entity_id = ti.entity_id and
ts.attribute_id = 85 and
ti.attribute_id = 257;
You can also solve this using conditional aggregation:
select t.entity_id,
max(case when t.attribute_id = 85 then t.value end) as sku,
max(case when t.attribute_id = 257 then t.value end) as image
from t
group by t.entity_id;

If you have attribute_id|entity_id combinations unique across the table you don't need to group data, just join like this:
http://sqlfiddle.com/#!9/1b2f60/2
SELECT a.entity_id,
a.value AS some_attribute1,
b.value AS image
FROM attribs a
LEFT JOIN attribs b
ON a.entity_id = b.entity_id
AND b.attribute_id = 257
WHERE a.attribute_id = 85

Related

How to get all entries with SQL query with join

kon
id | name
1 alex
2 peter
3 john
ticket
id | amount | kon_id | package
122 13 1 234
123 12 1 234
124 20 2 NULL
125 23 2 235
126 19 1 236
I would like to get a list of all contacts with the sum of the amount, except tickets, where the package entry is NULL.
My problem is, that I only get the contacts which have a ticket, because of the WHERE clause.
SELECT
kon.id,
kon.name,
SUM(ticket.amount)
FROM kon LEFT JOIN ticket ON kon.id = ticket.kon_id
WHERE ticket.package IS NOT NULL
GROUP BY kon.id
At the moment, the output looks like this
1 alex 44
2 peter 23
but it should look like this
1 alex 44
3 john NULL
2 peter 23
I use a MySQL Server.
Is it possible to solve this?
Replace Where with AND
SELECT
kon.id,
kon.name,
SUM(ticket.amount)
FROM kon LEFT JOIN ticket ON kon.id = ticket.kon_id AND ticket.package IS NOT NULL
GROUP BY kon.id
Check This.
SELECT
k.id,
k.name ,
coalesce (SUM(t.amount) ,0)
FROM kon k LEFT JOIN
( select id,amount,kon_id,package from ticket where package is not null ) t
ON k.id = t.kon_id
GROUP BY k.id, k.name
OutPut :
Begin Tran
Create Table #Kon (id INt , name Nvarchar(255))
Insert into #Kon
Select 1,'alex' UNION ALL
Select 2,'peter' UNION ALL
Select 3,'john'
Create Table #Ticket (id int,amount int,Kon_Id Int,Package Int)
INSERT INTO #Ticket
SELECT 122,13,1,234 UNION ALL
SELECT 123,12,1,234 UNION ALL
SELECT 124,20,2,NULL UNION ALL
SELECT 125,23,2,235 UNION ALL
SELECT 126,19,1,236
SELECT K.id, Name,SUM(amount) amount
FROM #Kon k
LEFT JOIN #Ticket T ON K.id=T.Kon_Id
GROUP BY K.id,Name
RollBAck Tran
Generally, "ticket.package IS NOT NULL" is wrong condition: your query becomes inner join from left join. If ticket.package should be NOT NULL to add from amount, it should be not in condition, but inside SUM agregate function.
working example for MS SQL
SELECT
kon.id,
min(kon.name),
SUM(case when package is NULL then 0 else ticket.amount end)
FROM #kon kon LEFT JOIN #ticket ticket ON kon.id = ticket.kon_id
GROUP BY kon.id
Answer from Mr. Bhosale is right too, but for big tables will have worse performance (the reason is subquery)
the following query return your expected result
SELECT
kon.id,
kon.name,
SUM(ticket.amount) as 'amount'
FROM kon LEFT JOIN ticket ON kon.id = ticket.kon_id
GROUP BY kon.id, kon.name
attached image shows the result
I figured out the fastest way to solve the problem. It takes about 0.2s compared to the other solutions (2s - 2min). The CAST is important, otherwise the summation of double variables is wrong (float string problem).
SELECT
kon1,
kon2,
SUM(CAST(kon3 AS DECIMAL(7,2)))
FROM (
SELECT k.id kon1, k.name kon2, t.amount kon3 FROM kon as k
LEFT JOIN ticket t ON k.id = t.ticket_kon
WHERE t.package IS NOT NULL
UNION ALL
SELECT k.id kon1, k.name kon2, NULL kon3 FROM kon k WHERE) t1
GROUP BY kon1, kon2

Mysql subquery issues

Here is my mysql schema and query.
http://sqlfiddle.com/#!2/73b0d/2
I want sum(each day's memo.discount), date, sum(each day's sale sum(item.sell_price)) in each row. But can't seem to find out the way. How can I do this?
Expected outcome.
total_discount | added_on | total_sale
300 | 2014-06-25 00:00:00 | 1580
230 | 2014-06-26 00:00:00 | 980
Thanks in advance.
SELECT
SUM(m.discount) AS total_discount,
m.added_on,
sub0.total_sold AS total_sale
FROM memo m
LEFT OUTER JOIN
(
SELECT DATE(memo.added_on) AS group_added_on, SUM(item.sell_price) AS total_sold
FROM memo
JOIN memo_item ON memo_item.memo_id = memo.id
JOIN item ON item.id = memo_item.item_id
WHERE memo.showroom_id = 2
GROUP BY group_added_on
) sub0
ON group_added_on = DATE(m.added_on)
WHERE m.showroom_id = 2 and m.added_on BETWEEN '2014-06-25' AND '2014-06-26'
GROUP BY m.added_on
This has a sub query that gets the sum of the selling prices for each day for the showroom_id you are interested in, then joins that back against the memo table.
How about this?
select
sum(m.discount) as total_discount,
m.added_on,
sum(item.sell_price) as total_sale
from memo m
join memo_item on memo_item.memo_id = m.id
join item on item.id = memo_item.item_id
where m.showroom_id = 2 and m.added_on between '2014-06-25' and '2014-06-26'
group by m.added_on
Edit: to use discount only from "memo" table... :
select
sum(discount) as total_discount,
added_on,
sum(subtotal_sale) as total_sale
from
(
select
m.discount,
m.added_on,
sum(item.sell_price) as subtotal_sale
from memo m
join memo_item on memo_item.memo_id = m.id
join item on item.id = memo_item.item_id
where m.showroom_id = 2 and m.added_on between '2014-06-25' and '2014-06-26'
group by m.id
) h
group by added_on

Mysql query issue with multiple table table join

Hi this is my tables
table 1 => products
id product price active
3 sample 1500 1
4 sample2 2300 2
table 2 => product_attibute_value
id product option_value
1 3 Green
2 3 Red
and table 3 => product_attribute_options
id product option_value
1 2 8
2 2 7
and my query is
SELECT typ.*
FROM products typ , attibute_value tyav
WHERE typ.active='1' AND ( tyav.option_value = 'Green' ) AND typ.id=tyav.product
GROUP BY typ.id
ORDER BY typ.price ASC
This working fine. Now I want to add product_attribute_options table also.
Now I added new query like this
SELECT typ.*
FROM products typ , attibute_value tyav, product_attibute_options tyop
WHERE typ.active='1' AND ( tyav.option_value = '7' OR tyav.option_value = 'Orange' ) OR
( tyav.option_value = '7' OR tyav.option_value = 'Orange' ) AND
typ.id=tyav.product OR typ.id=tyop.product
GROUP BY typ.id
ORDER BY typ.price ASC
I am showing option value in one page, and if i selected this option like 8 or or orange, it will show the product. this product should come from both attribute_options table and attribute_value table.
Its not coming exactly. What I did mistake in this query? Thanks in advance
Try this:
SELECT p.*
FROM products p
INNER JOIN product_attibute_value pav ON p.id = pav.product
INNER JOIN product_attibute_options pao ON p.id = pao.product
WHERE p.active = 1 AND ( pav.option_value = '7' OR pao.option_value = '7' )
GROUP BY p.id
ORDER BY p.price ASC
It is better if you use JOIN sentences and conditions on each of them.
Try this:
SELECT typ.*
FROM products typ
JOIN attibute_value tyav ON typ.id=tyav.product
JOIN product_attibute_options tyop ON typ.id=tyop.product
WHERE typ.active='1'
AND ( tyav.option_value = '7' OR tyav.option_value = 'Orange' )
GROUP BY typ.id
ORDER BY typ.price asc

Select Count of Rows with Joined Tables

I have two tables with a one to many relationship. I join the tables by an id column. My problem is that I need a count of all matching entries from the second (tablekey_id) table but I need the information from the row marked with the boolean is_basedomain. As a note there is only one row with is_basedomain = 1 per set of rows with the same tablekey_id.
Table: tablekey
id linkdata_id timestamp
22 9495028175 2013-03-10 01:13:46
23 8392740179 2013-03-10 21:23:25
Table: searched_domains.
NOTE: tablekey_id is the foreign key to the id in the tablekey table.
id tablekey_id domain is_basedomain
1 22 somesite.com 1
2 22 yahoo.com 0
3 23 red.com 1
4 23 blue.com 0
5 23 green.com 0
Heres the query Im working with. I was trying to use a sub query but I cant seem to select only the count for the current tablekey_id so this does not work.
SELECT `tablekey_id`, `linkdata_id`, `timestamp`, `domain`, `is_basedomain`,
(SELECT COUNT(1) AS other FROM `searched_domains` AS dd
ON dd.tablekey_id = d.tablekey_id GROUP BY `tablekey_id`) AS count
FROM `tablekey` AS k
JOIN `searched_domains` AS d
ON k.id = d.tablekey_id
WHERE `is_basedomain` = 1 GROUP BY `tablekey_id`
The result that I would like to get back is:
tablekey_id linkdata_id timestamp domain is_basedomain count
22 9495028175 2013-03-10 01:13:46 somesite.com 1 2
23 8392740179 2013-03-10 21:23:25 red.com 1 3
Can anyone help me get this into one query?
You can treat the searched_domains rows that have is_basedomain=1 as a separate table in the query and join it with another instance of searched_domains (to get the count):
SELECT
d.tablekey_id,
k.linkdata_id,
k.timestamp,
d.domain,
d.is_basedomain,
COUNT(*) as 'count'
FROM
tablekey AS k
join searched_domains AS d on d.tablekey_id=k.id
join searched_domains AS d2 on d2.tablekey_id=d.tablekey_id
WHERE
d.is_basedomain = 1
GROUP BY
d.tablekey_id,
k.linkdata_id,
k.timestamp,
d.domain,
d.is_basedomain
you have an error when using ON instead use WHERE
try this
SELECT `tablekey_id`, `linkdata_id`, `timestamp`, `domain`, `is_basedomain`,
(SELECT COUNT(1) AS other FROM `searched_domains` AS dd
where dd.tablekey_id = d.tablekey_id GROUP BY `tablekey_id`) AS count
FROM `tablekey` AS k
JOIN `searched_domains` AS d
ON k.id = d.tablekey_id
WHERE `is_basedomain` = 1 GROUP BY `tablekey_id`
DEMO HERE
There is no reason to use subquery, or what is your opinion?
SELECT
`tablekey_id`,
`linkdata_id`,
`timestamp`,
`domain`,
`is_basedomain`,
COUNT(*) as count
FROM
`tablekey` AS k ,
`searched_domains` AS d
WHERE
k.id = d.tablekey_id AND
`is_basedomain` = 1
GROUP BY
`tablekey_id`,
`linkdata_id`,
`timestamp`,
`domain`,
`is_basedomain`
If you want only latest timestamp use MAX(timestamp) as timestamp and remove it from group by.

MySQL SELECT to Rank A Number out of a set of numbers

I have rows of data from a SELECT query with a few prices (say three for this example). One is our price, one is competitor1 price, one is competitor2 price. I want to add a column that spits out the rank of our price as compared to the other two prices; if our price is the lowest it would spit out the number 1 if the highest it would spit out the number it is out of.
Something like this:
Make | Model | OurPrice | Comp1Price | Comp2Price | Rank | OutOf
MFG1 MODEL1 350 100 500 2 3
MFG1 MODEL2 50 100 100 1 3
MFG2 MODEL1 100 NULL 50 2 2
MFG2 MODEL2 9999 500 NULL 2 2
-Sometimes the competitor price will be NULL as seen above, and I believe this is where my issue lies. I have tried a CASE and it works when only on one competitor but when I add a AND statement it spits out the ranks as all NULL. Is there a better way of doing this through a MySQL query?
SELECT
MT.MAKE as Make,
MT.MODEL as Model,
MT.PRICE as OurPrice,
CT1.PRICE as Comp1Price,
CT2.PRICE as Comp2Price,
CASE
WHEN MT.PRICE < CT1.PRICE AND MT.PRICE < CT2.PRICE
THEN 1 END AS Rank
(CT1.PRICE IS NOT NULL) + (CT2.PRICE IS NOT NULL) + 1 as OutOf
FROM mytable MT
LEFT JOIN competitor1table as CT1 ON CT1.MODEL = MT.MODEL
LEFT JOIN competitor2table as CT2 ON CT2.MODEL = MT.MODEL
ORDER BY CLASS
Not tested, but you can try:
SELECT
a.MAKE AS Make,
a.MODEL AS Model,
a.PRICE AS OurPrice
MAX(CASE WHEN a.compnum = 1 THEN pricelist END) AS Comp1Price,
MAX(CASE WHEN a.compnum = 2 THEN pricelist END) AS Comp2Price,
FIND_IN_SET(a.PRICE, GROUP_CONCAT(a.pricelist ORDER BY a.pricelist)) AS Rank,
COUNT(a.pricelist) AS OutOf
FROM
(
SELECT MAKE, MODEL, PRICE, PRICE AS pricelist, 0 AS compnum
FROM mytable
UNION ALL
SELECT a.MAKE, a.MODEL, a.PRICE, CT1.PRICE, 1
FROM mytable a
LEFT JOIN competitor1table CT1 ON a.MODEL = CT1.MODEL
UNION ALL
SELECT a.MAKE, a.MODEL, a.PRICE, CT2.PRICE, 2
FROM mytable a
LEFT JOIN competitor2table CT2 ON a.MODEL = CT2.MODEL
) a
GROUP BY
a.MAKE, a.MODEL
(CT1.PRICE IS NOT NULL AND CT1.PRICE < MT.PRICE) + (CT2.PRICE IS NOT NULL AND CT2.PRICE < MT.PRICE) + 1 as Rank