**Table 1**
Tbcode description Amount
2 debtors 40000
3 creditors 50000
4 share_capital 10000
5 reserve 20000
**Table 2**
Tbcode description Amount
1 debtors 3000
2 creditors 7000
3 share_capital 0
4 reserve 3000
4 reserve 2000
2 creditors 300
3 share_capital 3000
4 reserve 3000
1 debtors 2000
I have to put a left outer join on table 1
In my output table I need all the columns of table 1 and the sum of amount column group by TB code.
I have written the following script:
select openingtb.TBCODE,openingtb.DESCRIPTION,openingtb.AMOUNT,count(journals.AMOUNT)
from openingtb
left outer join journals
on openingtb.tbcode = journals.TBCODE
group by journals.TBCODE.TBCODE
;
Can someone guide me as to whats wrong with the code and what could be the correct code to get the required output
it you use aggregate function, then you should group all non-aggregate fields used in select clause...
SELECT openingtb.TBCODE, openingtb.DESCRIPTION, openingtb.AMOUNT
, Count(journals.AMOUNT)
FROM openingtb
LEFT JOIN journals
ON openingtb.tbcode = journals.TBCODE
GROUP BY openingtb.TBCODE, openingtb.DESCRIPTION, openingtb.AMOUNT
;
Related
Sorry if the title is not well explained tried my best.
I currently have this transactions table which hold the records, every row has an agent and a currency assigned to it.
id
amount
agent
currency_id
1
400.00
agent1
1
2
170.00
agent5
3
3
110.00
agent4
2
4
430.00
agent5
3
5
155.00
agent1
1
6
370.00
agent2
2
7
10.00
agent2
2
8
150.00
agent1
1
9
130.00
agent3
3
10
445.00
agent4
2
And this other table called currency which holds the unique currency and name.
id
currency
1
USD
2
VES
3
EUR
The query that I want to make is a SUM and group by agent for every currency there is. I am able to do it with a single query like this but only for one currency in the WHERE clause:
SELECT a.agent,
SUM(a.amount)
FROM transactions AS a
INNER JOIN currency AS b ON b.id = a.currency_id
WHERE b.currency = 'VES'
GROUP BY a.agent
I will be getting this result which is only for the VES currency
agent
total
agent2
380.00
agent4
555.00
I am looking for one query that allow me to get the result of all 3 current existing currencies (USD, VES, EUR) this should give a result of 3 different tables
I suspect that you want a report showing all agents, currencies, and their sums. You may try using this cross join approach:
SELECT a.agent, c.currency, COALESCE(SUM(t.amount), 0) AS total
FROM (SELECT DISTINCT agent FROM transactions) a
CROSS JOIN currency c
LEFT JOIN transactions t
ON t.agent = a.agent AND
t.currency_id = c.id
GROUP BY 1, 2
ORDER BY 1, 2;
The first two tables in the join generate all combinations of agents and currencies. We join this to your transactions table and aggregate to get the totals.
I am using Php with join, I have two tables ("services" and "service_detail"), I want to get all services
but want to know which service selected or notselected by vendor
Here is my services table strcture
id service_name image
1 Abc abc.jpg
2 xyz xyz.jpg
3 OPS ops.jpg
4 tys tys.jpg
5 byp byp.jpg
Here is my services_detail table strcutre
id vendor_id service_id price
1 101 1 50
2 101 2 70
3 101 3 80
4 101 4 30
5 102 1 70
6 102 2 40
...
I tried with following query but showing only selected services, but i want to get all services with parameter ( selected or notselected)
Where i am wrong ? Here is my query
SELECT sd.vendor_id, sd.service_id, sd.price, s.service_name, s.image
FROM services_detail sd
LEFT JOIN services s
ON sd.service_id = s.id
WHERE sd.vendor_id = '101'
Move your where clause to be AND in ON clause:
AND sd.vendor_id = '101'
And interchange tables in join to get all servcies
SELECT sd.vendor_id, sd.service_id, sd.price, s.service_name, s.image,
IF (sd.vendor_id is not null, 'Opted', 'Not opted') as status
FROM services s
LEFT JOIN services_detail sd
ON sd.service_id = s.id AND sd.vendor_id = '101';
In simple words, when there is a where clause including filters on table of Left Join then it will act like INNER JOIN not LEFT JOIN.
The following tables are much larger, but have been downsized for ease of the question
Table 1 - exercise_rolladex
Exercise_ID | Exercise_Name
---------------------------
1 Pushups
2 Turkish Get Ups
3 Squats
4 Ice Skater
Table 2 - exercise_planes
Exercise_Plane_ID | Exercise_Plane
----------------------------------
1 Sagittal
2 Frontal
3 Transverse
Table 3 - exercise_has_planes
Exercise_ID | Exercise_Plane_ID
-------------------------------
1 1
2 1
2 2
2 3
3 1
4 2
4 3
My question is: How can I structure a Query where I can find the Exercise_ID of each exercise which has Exercise_Plane_ID=1 AND Exercise_Plane_ID=2. In other words, find the exercises that have both Sagittal AND Frontal planes of motion.
The Correct Query
SELECT e.Exercise_Name, p.Exercise_Plane
FROM exercise_rolladex e
INNER JOIN exercise_has_planes h ON h.Exercise_ID=e.Exercise_ID
INNER JOIN exercise_planes p ON p.Exercise_Plane_ID=h.Exercise_Plane_ID
WHERE p.Exercise_Plane_ID IN(2,1)
GROUP BY e.Exercise_ID
HAVING COUNT(DISTINCT h.Exercise_Plane_ID ) >= 2
UPDATE FOLLOW UP QUESTION
How then would I include an exclusion? for example, find the exercises with plane_id 2 and 3, but exclude exercises with plane_id 1 (The correct result being "Ice Skater")
I went ahead and answered my own question:
SELECT e.Exercise_Name, p.Exercise_Plane
FROM exercise_rolladex e
INNER JOIN exercise_has_planes h ON h.Exercise_ID=e.Exercise_ID
INNER JOIN exercise_planes p ON p.Exercise_Plane_ID=h.Exercise_Plane_ID
WHERE p.Exercise_Plane_ID IN(2,3)
AND e.Exercise_ID NOT IN
(SELECT Exercise_ID FROM exercise_has_planes WHERE Exercise_Plane_ID='1')
GROUP BY e.Exercise_ID
HAVING COUNT(DISTINCT h.Exercise_Plane_ID ) >= 2
Thanks to Mr. Brownstones answer from a different question.
SQL query to exclude items on the basis of one value
You can do something like this,this will check the plan id with your given input ids and filter out there count in each exercise group if count returns more than one then it means exercise has planes,having clause will fulfill the scenario of having both planes in exercise
SELECT e.Exercise_Name,
p.Exercise_Plane
FROM exercise_rolladex e
INNER JOIN exercise_has_planes h ON h.Exercise_ID=e.Exercise_ID
INNER JOIN exercise_planes p ON p.Exercise_Plane_ID=h.Exercise_Plane_ID
WHERE p.Exercise_Plane_ID IN(2,1)
GROUP BY e.Exercise_ID
HAVING COUNT(DISTINCT h.Exercise_Plane_ID ) >= 2
Demo
I have three tables and am trying to get info from two and then perform a calculation on the third and display all the results in one query.
The (simplified) tables are:
table: employee_work
employee_id name
1 Joe
2 Bob
3 Jane
4 Michelle
table: carryover
employee_id days
1 5
2 10
3 3
table: timeoff
employee_id time_off_type days
1 Carryover 2
1 Leave 3
1 Carryover 1
2 Sick 4
2 Carryover 4
3 Leave 1
4 Sickness 4
The results I would like are:
employee_id, carryover.days, timeoff.days
1 5 3
2 10 4
3 3 0
However when I run the query, whilst I get the correct values in columns 1 and 2, I get the same number repeated in the third column for all entries.
Here is my query:
Select
employee_work.employee_id,
carryover.carryover,
(SELECT SUM(days) FROM timeoff WHERE timeoff.time_off_type = 'Carryover'
AND timeoff.start_date>='2013-01-01') AS taken
From
carryover Left Join
employee_work On employee_work.employee_id = carryover.employee_id Left Join
timeoff On employee_work.employee_id = timeoff.employee_id Left Join
Where
carryover.carryover > 0
Group By
employee_work.employee_id
I have tried to group by in the sub query but I then get told "Subquery returns more than one row" - how can I ensure that the sub query is respecting the join so it only looks at each employee at a time so I get my desired results?
The answer to your question is to use a correlated subquery. You don't need to mention the timeoff table twice in this case:
Select
employee_work.employee_id,
carryover.carryover,
(SELECT SUM(days)
FROM timeoff
WHERE timeoff.time_off_type = 'Carryover' and
timeoff.start_date>='2013-01-01' and
timeoff.employee_id = employee_work.employee_id
) AS taken
From
carryover Left Join
employee_work On employee_work.employee_id = carryover.employee_id
Where
carryover.carryover > 0
Group By
employee_work.employee_id;
An alternative structure is to do the grouping for all employees in the from clause. You can also remove the employee_work table, because it does not seem to be being used. (You can use carryover.employee_id for the id.)
Select co.employee_id, co.carryover, et.taken
From carryover c Left Join
(SELECT employee_id, SUM(days) as taken
FROM timeoff
WHERE timeoff.time_off_type = 'Carryover' and
timeoff.start_date>='2013-01-01'
) et
on co.employee_id = et.employee_id
Where c.carryover > 0;
I don't think the group by is necessary. If it is, then you should probably have an aggregation function in the original query.
I'm trying to make a crosstab query (with access tables), But I got lost writing the inner joins statements.
My end result suppose to be the "QueryResult".
Table1 holds the fund information,
Table2 are the type of data the funds have
Table3 is a conversion from the codes of the data to the type data in table2, and Table4 holds the data.
Table1
FundID FundName
1 Fund1
2 Fund2
3 Fund3
4 Fund4
5 Fund5
6 Fund6
7 Fund7
Table2
TypeID TypeName
1 Balance
2 Yield
3 Fees
4 Deposits
5 Withdraws
Table3
CodeID TypeID
KT111 1
KT112 2
KT113 3
KT115 3
KT116 4
KT117 4
KT118 5
KT119 5
Table 4
CodeID FundID DataVal
KT111 1 1000
KT116 2 40
KT118 3 30
KT119 3 30
KT118 2 10
KT119 2 50
KT111 2 3000
KT111 3 2000
KT112 1 1.5
KT112 2 1.0
KT112 3 0.5
P.S: Table4 holds much rows then shown here with codes which I do not need.
QueryResult
FundID Balance Yield Fees Deposits Withdraws
1 1,000 1.5 555 40 60
2 3,000 1.0 155 20 60
3 2,000 0.5 255 70 60
What is the right statement to get the query result? (I got lost on the inner joins...)
Is there also a way to sum some of the data, and show the value (without summing) of other data from table4?
Thanks!
while I am not exactly sure of all of the requirements you have, this might get you started:
TRANSFORM Sum(d.dataval) as DataValue
SELECT d.fundid
FROM
((Data d
INNER JOIN fund f ON d.fundid = f.fundid)
INNER JOIN code c ON d.codeid = c.codeid)
INNER JOIN type t on c.typeid = t.typeid
GROUP BY d.fundid
PIVOT T.Typename
Results:
fundid Balance Deposits Withdraws Yield
1 1000 1.5
2 3000 40 60 1
3 2000 60 0.5