Symfony - Select object where date = today - mysql

Question

I have a entity repository containing code
$qb = $this->createQueryBuilder('tdd');
$qb->select('tdd')
->where($qb->expr()->eq('tdd.disable_date', ':dat'))
->setParameter('dat', new \DateTime());
return $qb->getQuery()->getOneOrNullResult();
And Entity containing only one member (disable_date)
/**
* #ORM\Column(type="date", unique=true, nullable=false)
* #ORM\Id()
*/
private $disable_date;
When I try to check if today's date is in database, code above returns NULL.
Date in DB exists.
What the heck?

Answer 1

Because new DateTime() creates object similar to this:
object(DateTime)#1 (3) {
["date"]=>
string(26) "2018-04-12 07:24:34.697668"
["timezone_type"]=>
int(3)
["timezone"]=>
string(10) "US/Pacific"
}
And you trying to match exact date with time (including seconds and ms). And thats why results is null
Check date without h:i:s

Answer 2

I solved this using midnight modificator.
When you declare in doctrine a Date field, in database it will be stored as date time, but Entity uses a DateTime interface.
So if you try to compare a new \DateTime (current date and time) with the date stored en database, parsed by doctrine as date stored + current time, comparasion never will be equal.
Using the midnight modificator you are really comparing equals.
$dateInDatabase = '2020-04-22';
$parsedByDoctrine = new \DateTime($dateInDatabase); // 2020-04-22 00:00:00
$now = new \DateTime(); // 2020-04-22 17:20:00
$todayMidnight = new \DateTime('midnight'); // 2020-04-22 00:00:00
$now === $parsedInDatabase // FALSE
$todayMidnight === $parsedInDatabase // TRUE
This can be applied in the createQueryBuilder or in the findBy methods
php.net/manual/en/datetime.formats.relative.php